I am trying to write a script to login into different systems by providing system name as input and making it variable by read option. However when i try to compare it with defined Array it's throwing me error and stating command not found.
Succeeded in making use input as variable but not able to compare it properly with defined array.
Below is the code i have written.
#!/bin/bash
cluster=("namico1c.mylabserver.com","namico2c.mylabserver.com")
echo "Please enter a Cluster Name to login: "
read clname
for item in ${cluster[#]};do
echo ${item};
if ["${clname}"="${item}"]; then
ssh test#$clname
else
echo "Cluster is not correct"
fi
done
[test#namico3c ~]$ ./test.sh
Please enter a Cluster Name to login:
namico1c.mylabserver.com
namico1c.mylabserver.com,namico2c.mylabserver.com
./test.sh: line 7: [namico1c.mylabserver.com=namico1c.mylabserver.com,namico2c.mylabserver.com]: command not found
Cluster is not correct
alternative:
#!/bin/bash
cluster=("namico1c.mylabserver.com" "namico2c.mylabserver.com")
select clname in "${cluster[#]}"; do
ssh test#$clname
break
done
Related
I would like to ask the user to enter a command that will be executed, but I don't understand why I can't assign two commands to the same variable.
Here is the code:
user#localhost:~# read -ep "command: " cmd ; "$cmd"
and the result:
command: id ; date
-bash: id ; date : command not found
but if I type a single command, it works.
Thanks for your help
I'm new to bash scripting, and I'm working on a script where the user enters a username and gets a list of the associated information from /etc/passwd. Unfortunately, I seem to be having trouble populating a variable from a command. The error message I'm getting suggests the if statement isn't being entered into, but I'm not sure why.
The script currently looks like this:
#!/bin/bash
#readifs
FILE=/etc/passwd
read -p "Enter a username > " user_name
file_info=$(grep "^$user_name:" $FILE)
if [ -n "$file_info" ]; then
IFS=":" read user pw uid gid name home shell <<< "$file_info"
echo "User = '$user'"
echo "UID = '$UID'"
echo "GID = '$GID'"
echo "Full Name = '$name'"
echo "Shell = '$shell'"
else
echo "No such user '$user_name'" > &2
exit 1
fi
When I run it, using a valid username, I get the following two lines:
readifs.sh: line 20: syntax error near unexpected token `&'
readifs.sh: line 20: ` echo "No such user '$user_name'" > &2'
I'm pretty sure I'm missing something obvious, or doing something bash doesn't allow but I'm too new to catch. Can anyone point out and correct the error in my script?
Thank you to Charles Duffy for all the great feedback on not just this script, but bash scripting and Stack Overflow in general.
I was able to fix the script as I wanted. I removed the ^ and : from the file_info line, which was stopping the grep command from finding the line I wanted. I also renamed $UID and $GID to use lower case letters, and removed the space in "> &2".
Thank you again for your assistance.
I'm trying to write a bash script that search and replace a specific
user input saved in config.sh using sed. This does work; however it
only works partially as shown below.
config.sh
#!/bin/bash
#
#UserName to be deleted
delUserName=""
#Source
delUserSrc=/Users/"$delUserName"
#Destination
delUserDest=/Users/John/BackUp/"$delUserName"/"$delUserName".zip
main.sh
#!/bin/bash
#
source scripts/config.sh
echo -e "\nEnter user you wish to delete: \c"
read -r UserName
sed -i '' -e "s/delUserName=.*/delUserName=$UserName/g" scripts/config.sh
echo -e "delUserName: $delUserName"
echo -e "delUserSrc: $delUserSrc"
echo -e "delUserDest: $delUserDest"
output1:
Enter user you wish to delete: Test
delUserName:
delUserSrc:/Users/
delUserDest:/Users/John/BackUp/ / .zip
output2:
Enter user you wish to delete: Test1
delUserName:Test
delUserSrc:/Users/Test
delUserDest:/Users/John/BackUp/Test/Test.zip
output3:
Enter user you wish to delete: Test1
delUserName:Test1
delUserSrc:/Users/Test1
delUserDest:/Users/John/BackUp/Test1/Test1.zip
expected output1:
Enter user you wish to delete: Test
delUserName:Test
delUserSrc:/Users/Test
delUserDest:/Users/John/BackUp/Test/Test.zip
expected output2:
Enter user you wish to delete: Test1
delUserName:Test1
delUserSrc:/Users/Test1
delUserDest:/Users/John/BackUp/Test1/Test1.zip
The script lags. sed instantaneously changed the value for $delUserName BUT The proper values for $delUserName, $delUserSrc, and $delUserDest only echo on the 2nd run. The scripts run well when all variables are in main.sh except i have to do it this way. Save the user input into $UserName. Any idea why the values don't show when run the 1st time?
Thanks
Here is what I think is happening.
The sed command replaces text in files. It does not modify the value of variables in memory. These values are assigned when you source config.sh.
So right after your sed line, you need to put this line :
source scripts/config.sh
It is the same line as above in your script. This is required there also so that your newly replaced values will be loaded in the variables so that you can display them. Once the new values are loaded in memory, then the echo statements will be able to expand the variables to that new value.
I wanted to make a script which should take an argument and check if it is equal to a given word and then display a message accordingly. I use the bash shell of ubuntu OS. I tried something as per the tutorial - http://www.tech-recipes.com/rx/209/bournebash-shell-scripts-string-comparison/ and it failed.
#!/bin/bash
if ["$1"=="password"]
then
echo correct password
else
echo wrong password
fi
bash Script.sh password.
error message is -
[password=password]: command not found.
How to fix it ?
Whitespaces:
#!/bin/bash
if [ "$1" == "password" ]
then
echo correct password
else
echo wrong password
fi
The expression after the if is actually a command, and commands are delimited by whitespaces. So your command is ["$1"=="password"] that expands to [password==password], that obiously does not exist (/usr/bin/[password==password] anyone?).
In my corrected code, the command is [ (yes, there is a /bin/[) and the rest of the line are the arguments.
See man test for details (test is a kind-of-alias for [).
In ksh, how do I prompt a user to enter a value, and load that value into a variable within the script?
command line
echo Please enter your name:
within the script
$myName = ?
You want read:
echo Please enter your name:
read name
echo $name
See read(1) for more.
You can do it in a single line, like so:
read -p "Please enter your name:" myName
To use variable in script
echo "The name you inputed is: $myName"
echo $myName
ksh allows you to specify a prompt as part of the read command using this syntax:
read myName?"Please provide your name: "