I need to convert a date from string in the format "yyyy/mm/dd hh:mm:ss TZ" to UNIX time (TZ = Timezone).
What I have done so far is to convert a date in the format "yyyy/mm/dd hh:mm:ss" without a timezone to timestamp by using
dateYMD="2019/2/28 12:23:11.46"
newt=$(date -d "${dateYMD}" +"%s")
echo ${newt}
and I have the following result.
1551349391
My struggle is to find how both timezone and date/time can be converted to timestamp (unix time) . For example I need 4 variables with the same date/time as dateYMD but in 4 different timezones so that their timestamps would be different.
Here is the latest I have tried
dateYMD="2017/09/09 08:58:09"
timez=$(TZ=Australia/Sydney date -d #$(date +%s -d "${dateYMD}"))
unixTimez=$( date --date "${timez}" +"%s" )
echo ${unixTimez}
that showed me the following error
date: invalid date ‘чт фев 28 21:23:11 AEDT 2019’
You don't need to call date twice. Just call it once with TZ set to the timezone you want for that variable.
timesydney=$(TZ=Australia/Sydney date -d "$dateYMD" +%s)
timenyc=$(TZ=US/Eastern date -d "$dateYMD" +%s)
Either you do it by setting the TZ= environment variable (see answer of Barmar), or you include the time zone into the time string. This has higher priority than TZ=.
Examples:
TZ=UTC date -d '2019-01-01 12:00 CET' +'%s, %F %T %Z %z'
TZ=CET date -d '2019-01-01 12:00 CET' +'%s, %F %T %Z %z'
TZ=UTC date -d '2019-01-01 12:00 PDT' +'%s, %F %T %Z %z'
TZ=CET date -d '2019-01-01 12:00 PDT' +'%s, %F %T %Z %z'
TZ=UTC date -d '2019-01-01 12:00 +500' +'%s, %F %T %Z %z'
will print
1546340400, 2019-01-01 11:00:00 UTC +0000
1546340400, 2019-01-01 12:00:00 CET +0100
1546369200, 2019-01-01 19:00:00 UTC +0000
1546369200, 2019-01-01 20:00:00 CET +0100
1546326000, 2019-01-01 07:00:00 UTC +0000
Related
I have 2 columns with different date formats. In every row string dates are formatted differently.
I want to convert the columns to Date type. However, I am wondering if there is any built in method that will do the parsing for me:
What I tried
from datetime import datetime
newFrame = newDF.assign(Effective_Date=newDF['Effective_Date'].apply(lambda element: datetime.strptime(element,'%b %d %Y %H %M %S')), Paid_Off_Time=newDF['Paid_Off_Time'].apply(lambda element: datetime.strptime(element,'%b %d %Y %H %M %S')))
error when I run code above
line 359, in _strptime
(data_string, format))
ValueError: time data '09/08/2016' does not match format '%b %d %Y %H %M %S'
Example Date formats in .csv:
10/07/2016
10/07/2016 09:00
Data
newDF=pd.DataFrame({'Effective_Date':['10/07/2016','10/07/2016 09:00','09 August 2016'],'Paid_Off_Time':['10 July 2016','10/08/2016','10/09/2016 01:00:30']})
Effective_Date Paid_Off_Time
0 10/07/2016 10 July 2016
1 10/07/2016 09:00 10/08/2016
2 09 August 2016 10/09/2016 01:00:30
Solution
newDF.assign(Effective_Date=pd.to_datetime(newDF['Effective_Date']).dt.date,Paid_Off_Time=pd.to_datetime(newDF['Paid_Off_Time']).dt.date)
Effective_Date Paid_Off_Time
0 2016-10-07 2016-07-10
1 2016-10-07 2016-10-08
2 2016-08-09 2016-10-09
Checkout the Pandas documentation on Data Functionality for more details:
https://pandas.pydata.org/docs/user_guide/timeseries.html#converting-to-timestamps
I have an output "Wed Mar 1 00:00:00 2000". I want to convert this into the format '08/11/2019 05:45PM'. How to achieve this format?
You could use something like below
import datetime
datetime.datetime.strptime('Wed Mar 1 00:00:00 2000', '%a %b %d %H:%M:%S %Y').strftime('%d/%m/%Y %I:%M%p')
I am trying to insert some text between two date commands
Code:
date -u "+%H":00Z --date="1 hours ago" "+%a %b %d" --date="0 days ago"
Error:
date: extra operand ‘+%a %b %d’
Try 'date --help' for more information.
Expected Output:
11:00Z Fri Oct 20
With GNU date , in 2 steps:
date -d #$(date +%s --date="0 days ago") -u "+%H:00Z %a %b %d" --date="-1 hours ago"
the date command of linux return the following date format
root#root:~# date
Sat Jun 14 06:36:42 CEST 2014
The current date time stamp could be printed if I add +%s
root#root:~# date +%s
1402720624
Now If I want to print the time stamp of the date returned by the date command, I get the following error
root#Inteno:~# date -d"Sat Jun 14 06:36:42 CEST 2014" +%s
date: invalid date 'Sat Jun 14 06:36:42 CEST 2014'
How I can make the date return the time stamp of the date format Sat Jun 14 06:36:42 CEST 2014 ?
Note: I m using date from BusyBox v1.19.4
Unfortunately busybox's date has limitations but if you can consider using timestamps instead you can do:
TS=$(date '+%s')
date -d "#${TS}"
Still if CEST is your current local time, you can do:'
DATE=$(date)
date -d "$(echo "$DATE" | cut -d ' ' -f 2,3,4,6)" '+%s'
As removing the timezone would still apply.
In GNU with the command date I can do it:
date -d "+4 day"
datei=20130101
i=5
date -d "$datei +$i day"
But i like know:
how can i do it in Solaris?
with the date command
Tcl has a good free-form date scanner, if you have Tcl installed (try which tclsh). A shell function:
tcldate() {
d=${1:-now} # the date string
f=${2:-%c} # the output format
echo "puts [clock format [clock scan {$d}] -format {$f}]" | tclsh
}
In action on an ancient Solaris 8 box with bash 2.03 and tcl 8.3.3
$ tcldate
Tue Jul 23 13:27:17 2013
$ i=4
$ tcldate "$i days"
Sat Jul 27 13:27:34 2013
$ tcldate "$i days" "%Y-%m-%d"
2013-07-27
$ tcldate "20130101 + $i days" "%Y-%m-%d"
2013-01-05
This even handles daylight savings transitions:
$ tcldate "2014-03-09 00:30 + 1 hour" "%D %T %Z"
03/09/14 01:30:00 EST
$ tcldate "2014-03-09 00:30 + 2 hour" "%D %T %Z"
03/09/14 03:30:00 EDT
$ tcldate "2013-11-03 00:30 + 1 hour" "%D %T %Z"
11/03/13 01:30:00 EDT
$ tcldate "2013-11-03 00:30 + 2 hour" "%D %T %Z"
11/03/13 01:30:00 EST