I want to know the VBA script for the Loop: Add sequence number (start number 1000 and 1001,1002,1003 so on) to the specific column and delete the another specific columns from multiple excel files into one folder. The purpose is to have the exact excel format to process the data in the special software.
I am beginner with VBA code.
Thank you for your time.
A possible solution:
Option Explicit
Sub test()
Dim LastRowC As Long, i As Long
With ThisWorkbook.Worksheets("Sheet1")
'Let us assume that values appear in Column C. Find last row of column C
LastRowC = .Cells(.Rows.Count, "C").End(xlUp).Row
'Add Values in Column B
For i = 1 To LastRowC
.Range("B" & i).Value = i + 1000
Next i
'Clear Column A
.Columns("A:A").Clear
End With
End Sub
dim i as integer
i = 1000
dim max as integer
max = 1000000
while i < max
begin
set i = i + 1
' do funky column editing , deleting, whatever
end
Related
I am trying to find the last row the same way I found the last column:
Sheets("Sheet2").Cells(1,Sheets("Sheet2").Columns.Count).End(xlToLeft).Column
I know this way but it is not as helpful as the prior would be:
u = Sheets("Sheet1").Range("A65536").End(xlUp).Row
I tried:
Sheets("Sheet2").Cells(Sheets("Sheet2",1).Rowa.Count).End(xlToUP).Column
Synopsis: I would like the below way for last row.
Sheets("Sheet2").Cells(1,Sheets("Sheet2").Columns.Count).End(xlToLeft).Column
You should use a with statement to qualify both your Rows and Columns counts. This will prevent any errors while working with older pre 2007 and newer 2007 Excel Workbooks.
Last Column
With Sheets("Sheet2")
.Cells(1, .Columns.Count).End(xlToLeft).Column
End With
Last Row
With Sheets("Sheet2")
.Range("A" & .Rows.Count).End(xlUp).Row
End With
Or
With Sheets("Sheet2")
.Cells(.Rows.Count, 1).End(xlUp).Row
End With
How is this?
dim rownum as integer
dim colnum as integer
dim lstrow as integer
dim lstcol as integer
dim r as range
'finds the last row
lastrow = ActiveSheet.UsedRange.Rows.Count
'finds the last column
lastcol = ActiveSheet.UsedRange.Columns.Count
'sets the range
set r = range(cells(rownum,colnum), cells(lstrow,lstcol))
This function should do the trick if you want to specify a particular sheet. I took the solution from user6432984 and modified it to not throw any errors. I am using Excel 2016 so it may not work for older versions:
Function findLastRow(ByVal inputSheet As Worksheet) As Integer
findLastRow = inputSheet.cellS(inputSheet.Rows.Count, 1).End(xlUp).Row
End Function
This is the code to run if you are already working in the sheet you want to find the last row of:
Dim lastRow as Integer
lastRow = cellS(Rows.Count, 1).End(xlUp).Row
I use this routine to find the count of data rows. There is a minimum of overhead required, but by counting using a decreasing scale, even a very large result requires few iterations. For example, a result of 28,395 would only require 2 + 8 + 3 + 9 + 5, or 27 times through the loop, instead of a time-expensive 28,395 times.
Even were we to multiply that by 10 (283,950), the iteration count is the same 27 times.
Dim lWorksheetRecordCountScaler as Long
Dim lWorksheetRecordCount as Long
Const sDataColumn = "A" '<----Set to column that has data in all rows (Code, ID, etc.)
'Count the data records
lWorksheetRecordCountScaler = 100000 'Begin by counting in 100,000-record bites
lWorksheetRecordCount = lWorksheetRecordCountScaler
While lWorksheetRecordCountScaler >= 1
While Sheets("Sheet2").Range(sDataColumn & lWorksheetRecordCount + 2).Formula > " "
lWorksheetRecordCount = lWorksheetRecordCount + lWorksheetRecordCountScaler
Wend
'To the beginning of the previous bite, count 1/10th of the scale from there
lWorksheetRecordCount = lWorksheetRecordCount - lWorksheetRecordCountScaler
lWorksheetRecordCountScaler = lWorksheetRecordCountScaler / 10
Wend
lWorksheetRecordCount = lWorksheetRecordCount + 1 'Final answer
This gives you the last used row in a specified column.
Optionally you can specify the worksheet, otherwise it will take the active sheet.
Function getLastRow(col As Integer, Optional ws As Worksheet) As Long
If ws Is Nothing Then Set ws = ActiveSheet
If ws.Cells(ws.Rows.Count, col).Value <> "" Then
getLastRow = ws.Cells(ws.Rows.Count, col).Row
Exit Function
End If
getLastRow = ws.Cells(Rows.Count, col).End(xlUp).Row
If shtRowCount = 1 Then
If ws.Cells(1, col) = "" Then
getLastRow = 0
Else
getLastRow = 1
End If
End If
End Function
Sub test()
Dim lgLastRow As Long
lgLastRow = getLastRow(2) 'Column B
End Sub
This is the best way I've seen to find the last cell.
MsgBox ActiveSheet.UsedRage.SpecialCells(xlCellTypeLastCell).Row
One of the disadvantages to using this is that it's not always accurate. If you use it then delete the last few rows and use it again, it does not always update. Saving your workbook before using this seems to force it to update though.
Using the next bit of code after updating the table (or refreshing the query that feeds the table) forces everything to update before finding the last row. But, it's been reported that it makes excel crash. Either way, calling this before trying to find the last row will ensure the table has finished updating first.
Application.CalculateUntilAsyncQueriesDone
Another way to get the last row for any given column, if you don't mind the overhead.
Function GetLastRow(col, row)
' col and row are where we will start.
' We will find the last row for the given column.
Do Until ActiveSheet.Cells(row, col) = ""
row = row + 1
Loop
GetLastRow = row
End Function
Problems with normal methods
Account for Blank Rows / Columns -
If you have blank rows or columns at the beginning of your data then methods like UsedRange.Rows.Count and UsedRange.Columns.Count will skip over these blank rows (although they do account for any blank rows / columns that might break up the data), so if you refer to ThisWorkbook.Sheets(1).UsedRange.Rows.Count you will skip lines in cases where there are blank rows at the top of your sheet, for example on this sheet:
This will skip the top row from the count and return 11:
ThisWorkbook.Sheets(1).UsedRange.Rows.Count
This code will include the blank row and return 12 instead:
ThisWorkbook.Sheets(1).UsedRange.Cells(ThisWorkbook.Sheets(1).UsedRange.Rows.Count, 1).Row
The same issue applies to columns.
Full Sheets -
Identifying the last row or column can be difficult if your sheet is full (this only matters if either your data contains over a million lines or might have values in the final rows or columns of your data). For example, if you use xlEndUp or similar and the cell you're referring to is populated then the code will skip over data, in extreme cases your entire data set can be skipped if for example the data continues from the last row of the sheet (where you start your xlEndUp) solidly up to the first row (in this case the result would be 1).
'This code works, but...
'Will not function as intended if there is data in the cell you start with (Cell A:1048576).
Dim Sht1 as Range: Set Sht1 = ThisWorkbook.Sheets(1)
Sht1.Cells(Sht1.Rows.Count, 1).End(xlUp).Row
Columns with blank rows -
The above code also assumes that your data extends the entire way down column 1, if you have blank entries in column 1 you may lose rows as the code will find the first filled row from the bottom only for column 1.
Unnecessary Looping -
Self explanatory, best to avoid looping where possible as if you're dealing with a lot of data and repeating the looping process often it can slow down your code.
Solution
Note that this is targeted at finding the last "Used" Row or Column on an entire sheet, this doesn't work if you just want the last cell in a specific range.
I've setup some Functions here
Private Function GetLastRow(Sheet As Worksheet)
'Gets last used row # on sheet.
GetLastRow = Sheet.UsedRange.Cells(Sheet.UsedRange.Rows.Count, 1).Row
End Function
Private Function GetLastCol(Sheet As Worksheet)
'Gets last used column # on sheet.
GetLastCol = Sheet.UsedRange.Cells(1, Sheet.UsedRange.Columns.Count).Column
End Function
Examples of calling these Functions:
Sub CallFunctions()
'Define the Target Worksheet we're interested in:
Dim Sht1 As Worksheet: Set Sht1 = ThisWorkbook.Sheets(1)
'Print the last row and column numbers:
Debug.Print "Last Row = "; GetLastRow(Sht1)
Debug.Print "Last Col = "; GetLastCol(Sht1)
End Sub
I preferred search last blank cell:
Il you want last empty cell of column you can do that
Dim sh as Worksheet, r as range
set sh = ActiveWorksheet 'if you want an other it's possible
'find a value
'Columns("A:D") 'to check on multiple columns
Set r = sh.Columns("A").Find(What:="*", SearchOrder:=xlByRows, SearchDirection:=xlPrevious)
'no value return first row
If r Is Nothing Then Set r = sh.Cells(1, "A") Else Set r = sh1.Cells(r.Row + 1, "A")
If this is to insert new row, find on multiple columns is a good choice because first column can contains less rows than next columns
I use the following function extensively. As pointed out above, using other methods can sometimes give inaccurate results due to used range updates, gaps in the data, or different columns having different row counts.
Example of use:
lastRow=FindRange("Sheet1","A1:A1000")
would return the last occupied row number of the entire range. You can specify any range you want from single columns to random rows, eg FindRange("Sheet1","A100:A150")
Public Function FindRange(inSheet As String, inRange As String) As Long
Set fr = ThisWorkbook.Sheets(inSheet).Range(inRange).find("*", SearchOrder:=xlByRows, SearchDirection:=xlPrevious)
If Not fr Is Nothing Then FindRange = fr.row Else FindRange = 0
End Function
First time using the site as I am new to VBA, but I am trying to write a piece of code that will look through a column of my choice, in this case column A, and go through each row and delete empty rows until the end of the dataset. I was thinking of doing a loop where I would reference the first cell in my dataset A1 and set the row number as a integer which would increase by 1 with each completion of the loop.
Private Sub CommandButton1_Click()
Dim X as Integer
Set X = 1
For X = 1 to 100
If Sheet1.Range("A":X).Value = "" Then Rows(X).EntireRow.Delete
Next X
End Sub
Thanks for any help or insights you can provide!
You want to concatenate in Range("A":X) so change : to & (or use cells).
When deleting rows you should step backwards or create a unionized range otherwise you will skip a row with every deletion you perform.
You don't want to set integers that is only for objects. There is also no benefit from using integer over long in VBA so best to just always use long as integer can give overflow errors in very large spreadsheets.
Rows(X).EntireRow.Delete is using a relative reference not an explicit one, use a with or explicitly reference every range object.
You are immediately overwriting X with the loop so you don't need to assign it a value before the loop.
Here's some code that will do what you need:
Dim lastrow As Long
Dim x As Long
With Sheet1
lastrow = .Cells(.Rows.Count, 1).End(xlUp).Row
For x = lastrow To 1 Step -1
If .Cells(x, 1).Value = "" Then
.Rows(x).EntireRow.Delete
End If
Next x
End With
You are missing your "End if". Also when looping through a range and deleting rows you need to loop bottom up because when a row is deleted it does not recalculate the range.
Sub CommandButton1_Click()
Dim x As Long
Dim lastrow As Long
lastrow = Range("A1" & Rows.Count).End(xlUp).Row
For x = lastrow To 1 Step -1
If Worksheets(1).Range("A" & x).Value = "" Then
Worksheets(1).Range("A" & x).EntireRow.Delete
End If
Next x
End Sub
I want to remove all the rows except the last one for a matching userId "james.oconnor", i have a huge excel file and there are multiple rows of same "userId" with different "account" name. i want to keep only the last row having all the "account" name for a given userId - how can i do that?
How can i turn my Excel file from to
Many Thanks, Deepak
I would add a helper column that counts the number of accounts you have in that line, e.g. =COUNTA(F2:AA:2) in cell E2 then sort the sheet by this new column in descending order (highest numbers on the top).
After that you can either go through Remove Duplicates (only filtering by the userId column) or a VLOOKUP to only keep the top ones.
Does that work for you?
You could try:
Option Explicit
Sub test()
Dim Counter As Long, i As Long, LastRow As Long
Dim LookUpValue As String
LookUpValue = "james.oconnor"
With ThisWorkbook.Worksheets("Sheet1")
LastRow = .Cells(.Rows.Count, "A").End(xlUp).Row
Counter = 0
For i = LastRow To 2 Step -1
If .Range("A" & i).Value = LookUpValue Then
Counter = Counter + 1
If Counter > 1 Then
.Rows(i).EntireRow.Delete
End If
End If
Next i
End With
End Sub
I am trying to find the last row the same way I found the last column:
Sheets("Sheet2").Cells(1,Sheets("Sheet2").Columns.Count).End(xlToLeft).Column
I know this way but it is not as helpful as the prior would be:
u = Sheets("Sheet1").Range("A65536").End(xlUp).Row
I tried:
Sheets("Sheet2").Cells(Sheets("Sheet2",1).Rowa.Count).End(xlToUP).Column
Synopsis: I would like the below way for last row.
Sheets("Sheet2").Cells(1,Sheets("Sheet2").Columns.Count).End(xlToLeft).Column
You should use a with statement to qualify both your Rows and Columns counts. This will prevent any errors while working with older pre 2007 and newer 2007 Excel Workbooks.
Last Column
With Sheets("Sheet2")
.Cells(1, .Columns.Count).End(xlToLeft).Column
End With
Last Row
With Sheets("Sheet2")
.Range("A" & .Rows.Count).End(xlUp).Row
End With
Or
With Sheets("Sheet2")
.Cells(.Rows.Count, 1).End(xlUp).Row
End With
How is this?
dim rownum as integer
dim colnum as integer
dim lstrow as integer
dim lstcol as integer
dim r as range
'finds the last row
lastrow = ActiveSheet.UsedRange.Rows.Count
'finds the last column
lastcol = ActiveSheet.UsedRange.Columns.Count
'sets the range
set r = range(cells(rownum,colnum), cells(lstrow,lstcol))
This function should do the trick if you want to specify a particular sheet. I took the solution from user6432984 and modified it to not throw any errors. I am using Excel 2016 so it may not work for older versions:
Function findLastRow(ByVal inputSheet As Worksheet) As Integer
findLastRow = inputSheet.cellS(inputSheet.Rows.Count, 1).End(xlUp).Row
End Function
This is the code to run if you are already working in the sheet you want to find the last row of:
Dim lastRow as Integer
lastRow = cellS(Rows.Count, 1).End(xlUp).Row
I use this routine to find the count of data rows. There is a minimum of overhead required, but by counting using a decreasing scale, even a very large result requires few iterations. For example, a result of 28,395 would only require 2 + 8 + 3 + 9 + 5, or 27 times through the loop, instead of a time-expensive 28,395 times.
Even were we to multiply that by 10 (283,950), the iteration count is the same 27 times.
Dim lWorksheetRecordCountScaler as Long
Dim lWorksheetRecordCount as Long
Const sDataColumn = "A" '<----Set to column that has data in all rows (Code, ID, etc.)
'Count the data records
lWorksheetRecordCountScaler = 100000 'Begin by counting in 100,000-record bites
lWorksheetRecordCount = lWorksheetRecordCountScaler
While lWorksheetRecordCountScaler >= 1
While Sheets("Sheet2").Range(sDataColumn & lWorksheetRecordCount + 2).Formula > " "
lWorksheetRecordCount = lWorksheetRecordCount + lWorksheetRecordCountScaler
Wend
'To the beginning of the previous bite, count 1/10th of the scale from there
lWorksheetRecordCount = lWorksheetRecordCount - lWorksheetRecordCountScaler
lWorksheetRecordCountScaler = lWorksheetRecordCountScaler / 10
Wend
lWorksheetRecordCount = lWorksheetRecordCount + 1 'Final answer
This gives you the last used row in a specified column.
Optionally you can specify the worksheet, otherwise it will take the active sheet.
Function getLastRow(col As Integer, Optional ws As Worksheet) As Long
If ws Is Nothing Then Set ws = ActiveSheet
If ws.Cells(ws.Rows.Count, col).Value <> "" Then
getLastRow = ws.Cells(ws.Rows.Count, col).Row
Exit Function
End If
getLastRow = ws.Cells(Rows.Count, col).End(xlUp).Row
If shtRowCount = 1 Then
If ws.Cells(1, col) = "" Then
getLastRow = 0
Else
getLastRow = 1
End If
End If
End Function
Sub test()
Dim lgLastRow As Long
lgLastRow = getLastRow(2) 'Column B
End Sub
This is the best way I've seen to find the last cell.
MsgBox ActiveSheet.UsedRage.SpecialCells(xlCellTypeLastCell).Row
One of the disadvantages to using this is that it's not always accurate. If you use it then delete the last few rows and use it again, it does not always update. Saving your workbook before using this seems to force it to update though.
Using the next bit of code after updating the table (or refreshing the query that feeds the table) forces everything to update before finding the last row. But, it's been reported that it makes excel crash. Either way, calling this before trying to find the last row will ensure the table has finished updating first.
Application.CalculateUntilAsyncQueriesDone
Another way to get the last row for any given column, if you don't mind the overhead.
Function GetLastRow(col, row)
' col and row are where we will start.
' We will find the last row for the given column.
Do Until ActiveSheet.Cells(row, col) = ""
row = row + 1
Loop
GetLastRow = row
End Function
Problems with normal methods
Account for Blank Rows / Columns -
If you have blank rows or columns at the beginning of your data then methods like UsedRange.Rows.Count and UsedRange.Columns.Count will skip over these blank rows (although they do account for any blank rows / columns that might break up the data), so if you refer to ThisWorkbook.Sheets(1).UsedRange.Rows.Count you will skip lines in cases where there are blank rows at the top of your sheet, for example on this sheet:
This will skip the top row from the count and return 11:
ThisWorkbook.Sheets(1).UsedRange.Rows.Count
This code will include the blank row and return 12 instead:
ThisWorkbook.Sheets(1).UsedRange.Cells(ThisWorkbook.Sheets(1).UsedRange.Rows.Count, 1).Row
The same issue applies to columns.
Full Sheets -
Identifying the last row or column can be difficult if your sheet is full (this only matters if either your data contains over a million lines or might have values in the final rows or columns of your data). For example, if you use xlEndUp or similar and the cell you're referring to is populated then the code will skip over data, in extreme cases your entire data set can be skipped if for example the data continues from the last row of the sheet (where you start your xlEndUp) solidly up to the first row (in this case the result would be 1).
'This code works, but...
'Will not function as intended if there is data in the cell you start with (Cell A:1048576).
Dim Sht1 as Range: Set Sht1 = ThisWorkbook.Sheets(1)
Sht1.Cells(Sht1.Rows.Count, 1).End(xlUp).Row
Columns with blank rows -
The above code also assumes that your data extends the entire way down column 1, if you have blank entries in column 1 you may lose rows as the code will find the first filled row from the bottom only for column 1.
Unnecessary Looping -
Self explanatory, best to avoid looping where possible as if you're dealing with a lot of data and repeating the looping process often it can slow down your code.
Solution
Note that this is targeted at finding the last "Used" Row or Column on an entire sheet, this doesn't work if you just want the last cell in a specific range.
I've setup some Functions here
Private Function GetLastRow(Sheet As Worksheet)
'Gets last used row # on sheet.
GetLastRow = Sheet.UsedRange.Cells(Sheet.UsedRange.Rows.Count, 1).Row
End Function
Private Function GetLastCol(Sheet As Worksheet)
'Gets last used column # on sheet.
GetLastCol = Sheet.UsedRange.Cells(1, Sheet.UsedRange.Columns.Count).Column
End Function
Examples of calling these Functions:
Sub CallFunctions()
'Define the Target Worksheet we're interested in:
Dim Sht1 As Worksheet: Set Sht1 = ThisWorkbook.Sheets(1)
'Print the last row and column numbers:
Debug.Print "Last Row = "; GetLastRow(Sht1)
Debug.Print "Last Col = "; GetLastCol(Sht1)
End Sub
I preferred search last blank cell:
Il you want last empty cell of column you can do that
Dim sh as Worksheet, r as range
set sh = ActiveWorksheet 'if you want an other it's possible
'find a value
'Columns("A:D") 'to check on multiple columns
Set r = sh.Columns("A").Find(What:="*", SearchOrder:=xlByRows, SearchDirection:=xlPrevious)
'no value return first row
If r Is Nothing Then Set r = sh.Cells(1, "A") Else Set r = sh1.Cells(r.Row + 1, "A")
If this is to insert new row, find on multiple columns is a good choice because first column can contains less rows than next columns
I use the following function extensively. As pointed out above, using other methods can sometimes give inaccurate results due to used range updates, gaps in the data, or different columns having different row counts.
Example of use:
lastRow=FindRange("Sheet1","A1:A1000")
would return the last occupied row number of the entire range. You can specify any range you want from single columns to random rows, eg FindRange("Sheet1","A100:A150")
Public Function FindRange(inSheet As String, inRange As String) As Long
Set fr = ThisWorkbook.Sheets(inSheet).Range(inRange).find("*", SearchOrder:=xlByRows, SearchDirection:=xlPrevious)
If Not fr Is Nothing Then FindRange = fr.row Else FindRange = 0
End Function
I have a request for how I might go about the following operation:
I have a csv file (that I'm opening in Excel) that I am appending a block of data 50X2 (rowsXcolumns) to the csv file. With the finished csv file, I would like to automate a process where every 50 rows get selected (both columns) and the data essentially gets cut and copied to the next two available columns.
An example would be data from $A$1:$B$50 is in the csv and then a second sample is taken and the second set of data goes to $A$51:$B$100 and I would like to automatically move the second set to $C$1:$D$50 and perform that move for all samples taken.
I don't know what the best route for this operation would be (macro/VBA/etc) and would like some assistance with this, if it is easily possible.
Thank you all for your time and help.
The basic idea behind what needs to be done is:
Get the number of new columns to make (e.g. Total Rows/#rows per column)
For each new column to make, cut from the nth + 1 row to the last row, where nth row is the number of rows per column that you want (in your case, 50).
Paste the cut rows to the right of the last column that has data in it
Repeat until all columns have been made
Here is some sample code that I put together to get you started. This assumes your data starts in cell A1, and that each column should contain a maxium of 10 rows. You can change the rowsToSkip value to meet your needs. Also, please note that this is meant to get you started and requires more testing. Alter it as you see fit:
Public Sub MakeColumnsFromRows()
Dim totalCutsToMake As Integer
Dim currentColumn As Integer
Dim currentCut As Integer
Dim rowsToCut As Integer
Sheets(1).Activate
rowsToSkip = 10
totalCutsToMake = (ActiveSheet.UsedRange.Rows.Count / rowsToSkip)
currentColumn = 1
Dim RowCount As Integer
For currentCut = 1 To totalCutsToMake
RowCount = Cells(Rows.Count, currentColumn).End(xlUp).Row
Range(Cells(rowsToSkip + 1, currentColumn), Cells(RowCount, currentColumn + 1)).Select
Selection.Cut
Cells(1, currentColumn + 2).Select
ActiveSheet.Paste
currentColumn = currentColumn + 2
Next
End Sub
What this does is it first finds out how many new columns to make, then it cuts from the 11th row in each column down to the last row, then pastes those values after the last column that contains data. It does this until all new columns have been made. Please note that this leaves 10 rows of data per column. To change this to 50 you just need to change the rowsToSkip variable to 50.
Here is the before and after screenshots:
BEFORE
AFTER
How about this?
Sub move()
Dim ws As Worksheet
Dim r As Range
Dim columnCounter As Long
Dim rowCounter As Long
Set ws = Sheets("Sheet1")
columnCounter = 1
rowCounter = 51
Set r = ws.Cells(rowCounter, 1)
Do While r.Value <> vbNullString
ws.Range(r, r.Offset(49, 1)).Cut ws.Cells(1, columnCounter)
columnCounter = columnCounter + 2
rowCounter = rowCounter + 50
Set r = ws.Cells(rowCounter, 1)
Loop
End Sub