i can recursivly find and copy all my test-directories (with content) of the current directory:
find . -name test ! -path "./my_dest/*" -exec cp -r --parents {} /path/to/my_dest \;
But now I want to copy only that test-directories (with content), which content was changed within the last 24 houres.
What do I have to add to my line above?
Edit: I want to have the same results as my find-line above, but I want only that entries in my result, in which folders a folder or a file has been changed within the last 24hours (or something else).
The line
find . -name test ! -path "./my_dest/*" ! -ctime +0 -exec cp -r --parents {} /path/to/my_dest \;
does not do that! This line would find© only the folderchanged test-folders but not the filechanged test-folders.
You use the rsync command built specifically for this task. Here is the documentation and the manual page.
Related
I am trying to move all files with names starts with SML from directory to another.
Tried with
find /var/.../Images/ -name SML\* mv /var/.../Images/Small but doesnt work
try find /var/.../Images/ -name SML\* -exec mv {} /var/.../Images/Small/ \;
I guess you want something like this:
dir=/path/to/your/Images
mkdir -p "$dir/Small"
find "$dir" -name "SML*" -not -wholename "$dir/Small/*" -exec mv {} "$dir/Small/" \;
Since the directory you move the files to is a subdirectory of the one you seach in, you need to exclude the files already moved there. So I added -not -wholename "$dir/Small/*"
To execute a command for each found file, you need -exec .... The alternative would be to pipe your find results to a while read loop.
When using -exec, the found name can be referenced by {}.
See man find for a lot more information.
I need to find all files in a directory and it's subdirectories, but I need to keep directory structure. For example there is a file
/media/subdir1/subdir2/file.jpg
and I want to copy it to
/new-media/subdir1/subdir2/file.jpg
and the same to all files inside /media/ directory. And by the way, directories inside /new-media/ must be created if not exist.
if I use
find /media/ -name '*.jpg' -exec cp /new-media/ ????? {} \;
how can I get all subdirectories inside /media/?
The above will get you everything in /media, but to get exactly what you want you probably want to use something like:
Method 1: Copy only what you need recursively, per your requirements:
mkdir ../media2; find . -name "*.jpg" -exec cp -r --parents {} ../media2 \;
I ran this from inside the directory you want to search recursively. It does a couple things:
1 - create the new destination directory
mkdir ../media2
2 - then finds all files ending with ".jpg" recursively.
find . -name "*.jpg"
3 - uses -exec to pass the copy command to each file returned to find as a match, and subs that in as the first argument (which with the syntax of cp, is going to be your source file):
-exec cp -r --parents {} ../media2 \;
the "--parents" flag retains existing directory structure and recursively creates subsequent parent directories. Super useful right?
Method 2: there might be a better way to do this with xargs, but the above ended up being the most simple method imho. That said, if you want to think outside the box, you could simply copy the entire directory over recursively, then remove anything NOT ending with ".jpg" with something like:
cp -r media media2; find ./media '!'-name "*.jpg" -type f | xargs rm
I think this is what you want:
cp -r /media /new-media
-R, -r, --recursive
copy directories recursively
Hope this helps.
Will you be able to help me to write a script, I just want to find log files over 2GB and copy them to archive folder in same directory.I just write a find command it is not working, appreciate if someone could help me.
ex - main log folders - /vsapp/logs/
- app1,app2,app3
there are lot of logs in the app1, app2 and app3 folders.
so i want to find the logs in the logs folder which is over 2GB, and copy them to archive folder with the different name with today's date.
ex - abcd.log -----copy to -----> abcd.log-08-22-2016
My command at the moment which is not working
find $i/* -type f -size +2G -exec cp '{}' $i/$arc/{}-$date
You can do:
find /src -type f -name '*.log' -size +2G -exec cp {} /dest/{}-$(date -I) \;
Additions/Modifications i made:
-name '*.log' searches only for log files, as we are only interested in those. You can look for files with any names too if unsure, just omit -name '*.log in that case
$(date -I) is command substitution the output will be today's date in format YYYY-mm-dd, you can also define a custom format, check man date
End the -exec action of find with \;
I want to copy the recently updated multiple file into another directory.
I am having 1.xml,2.xml,3.xml.... in this directory recently someone updated file or added new file into the directory,So i want to copy those files into the destination directory ..Its like synchronization of 2 directories.
For that I have tried below commend
find home/deployment/server/services/ -type f -mtime 1 | xargs cp /home/application/
and below one also
find home/deployment/server/services/ -type f -mtime 1 -exec cp /home/application/
I am not getting any file into destination after updating 1.xml file,So I have added new file 4.xml even that also not updating in destination directory.
How to process recently updated or newly added multiple files.
Thanks in advance.
Short answer:
use xargs to mv the "find" directory into another directory
Long answer: As I recall (not tested) for exec syntax is
find . -type f --mtime 1 -exec cp {} /destination/path/ +
"{}" is an argument which came from command "find"
For xargs
find . -type f --mtime 1 | xargs -0 -I {} cp {} /destination/path/
I do this often but use \; instead of + and usually -cnewer rather than -mtime.
\; executes the cp command on files individually instead of as a group.
+ executes as a group with as many paths as xterm will take. It may do this multiple time if there are a lot of files.
the \ in front of the ; option is required or bash will think it is the end of the command.
find ./ -mtime -1 -exec cp {} /path/ \; -print
Use the -print at the end to get a list of the files that were copied.
I want to create an index.html file in each folder of my project in linux.
index.html should contain some sample code.
How can I create a file in single command?
find . -type d -exec touch {}/index.html \;
This'll create an index.html in . and all subdirectories.
cd /project_dir && find . -type d -exec touch \{\}/index.htm \;
HTH
Assuming you have a list of your project directories in a file called "projects.txt", you can do this (for bash and zsh)
for i in $(cat projects.txt)
do
touch $i/index.html
done
To create your projects.txt, you can use the find command. You could replace the cat directly with a find invocation but I thought it more clear to separate the two operations.
I know it's an old question but none of the current answers allow to add some sample code, here my solution:
#create a temp file
echo "<?php // Silence is golden" > /tmp/index.php
#for each directory copy the file
find /mydir -type d -exec cp /tmp/index.php {} \;
#Alternative : for each directory copy the file where the file is not already present
find /mydir -type d \! -exec test -e '{}/index.php' \; -exec cp /tmp/index.php {} \;
The following command will create an empty index.html file in the current directory
touch index.html
You will need to do the appropriate looping if necessary.