need some help here.. I am looking to retrieve Gender from Sheet 2 corresponding to the name in Sheet 1.
Step 1 - Match the name in sheet 1 to sheet 2 (not all names in sheet 1 will be in sheet 2, mark NA for non matching names)
Step 2 - Look for the corresponding gender in sheet 2.
Step 3 - Retrieve the column header or the last number in the column header (1,2,3...6)
Sheet 1
Name
Gender
w
???
e
r
t
y
u
i
q
w
e
r
Sheet 2
Name
Male 1
Female 2
other 3
other 4
other 5
Do not know 6
w
1
0
0
0
0
0
a
0
0
0
0
0
1
q
1
0
0
0
0
0
r
0
1
0
0
0
0
e
1
0
0
0
0
0
t
0
0
0
0
1
0
y
0
0
0
0
0
1
u
0
1
0
0
0
0
with Office 365 we can use FILTER:
=IFERROR(FILTER($F$1:$K$1,INDEX($F$2:$K$9,MATCH(A2,$E$2:$E$9,0),0)=1),"No Match")
With older versions we can use another INDEX/MATCH:
=IFERROR(INDEX($F$1:$K$1,MATCH(1,INDEX($F$2:$K$9,MATCH(A2,$E$2:$E$9,0),0),0)),"No Match")
I have dataframe that has 50 columns each column have either 0 or 1. How do I return all rows that have an equal (tie) in the number of 0 and 1 (25 "0" and 25 "1").
An example on a 4 columns:
A B C D
1 1 0 0
1 1 1 0
1 0 1 0
0 0 0 0
based on the above example it should return the first and the third row.
A B C D
1 1 0 0
1 0 1 0
Because you have four columns, we assume you must have atleast two sets of 1 in a row. So, please try
df[df.mean(1).eq(0.5)]
I have a schedule that my team fills out daily in a google sheet. On a seperate tab, I would like a running count per day per schedule code per agent.
Linking a sample spreadsheet here. In this example, I'm trying to input a countif that returns
2019-01-27 T 5 6 0 4
2019-01-27 C 3.5 0 0 7
2019-01-27 LC 0 0 0 0
2019-01-27 S 0 0 0 0
2019-01-27 L 0.5 0 0 1
2019-01-27 M 0.5 0 0 1
2019-01-27 SP 0 0 0 0
2019-01-27 U 0 0 0 0
2019-01-27 MCX 2 0 0 2
2019-01-27 OCX 0 0 0 0
2019-01-27 TR 0 0 0 0
But I cannot for the life of me get a countifs function to work. Any help is much appreciated!
https://docs.google.com/spreadsheets/d/1gp0ZrcYLJfEnUHxgxagAl99X_MCjEIdvwFyfSdGngSE/edit?usp=sharing
Combine INDIRECT with MATCH:
=COUNTIF(INDIRECT("'Mon 1/27'!F"&MATCH(D$1,'Mon 1/27'!$A$1:$A$5,0)&":AG"&MATCH(D$1,'Mon 1/27'!$A$1:$A$5,0)),$B2)
INDIRECT
MATCH
Here is how it works:
MATCH(D$1,'Mon 1/27'!$A$1:$A$5,0) will search the row number of the agent, referenced to cell A1
INDIRECT("'Mon 1/27'!A"&MATCH(D$1,'Mon 1/27'!$A$1:$A$5,0)&":AG"&MATCH(D$1,'Mon 1/27'!$A$1:$A$5,0)) will return a range referenced always to columns F and AF but with the row number returned in step 1, ie, F3:AG3,F4:AG4, and son.
COUNTIF will just count the criteria in the range from step 2.
Hope this helps.
IMPORTANT: In the expected output you posted, the MCX result for Barack Obama is 2, but my formula gets 4. Are you sure your output is right?
how to remove outermost logic?
such as
input column D result
And(OR(A,B),C)
output column E binary number
OR(A,B)
A B C result(D)after extract(E)
0 0 0 0 0
0 0 1 0 0
0 1 0 0 1
0 1 1 1 1
1 0 0 0 1
1 0 1 1 1
1 1 0 0 1
1 1 1 1 1
i tried in excel
=IF(NOT(AND(D2,C2))=TRUE,1,0)
but can not remove outermost logic
result after extract
0 0 0 =IF(AND(OR(A2,B2),C2)=TRUE,1,0) =IF(OR(A2,B2)=TRUE,1,0) =IF(NOT(AND(D2,C2))=TRUE,1,0)
0 0 1 =IF(AND(OR(A3,B3),C3)=TRUE,1,0) =IF(OR(A3,B3)=TRUE,1,0) =IF(NOT(AND(D3,C3))=TRUE,1,0)
0 1 0 =IF(AND(OR(A4,B4),C4)=TRUE,1,0) =IF(OR(A4,B4)=TRUE,1,0) =IF(NOT(AND(D4,C4))=TRUE,1,0)
0 1 1 =IF(AND(OR(A5,B5),C5)=TRUE,1,0) =IF(OR(A5,B5)=TRUE,1,0) =IF(NOT(AND(D5,C5))=TRUE,1,0)
1 0 0 =IF(AND(OR(A6,B6),C6)=TRUE,1,0) =IF(OR(A6,B6)=TRUE,1,0) =IF(NOT(AND(D6,C6))=TRUE,1,0)
1 0 1 =IF(AND(OR(A7,B7),C7)=TRUE,1,0) =IF(OR(A7,B7)=TRUE,1,0) =IF(NOT(AND(D7,C7))=TRUE,1,0)
1 1 0 =IF(AND(OR(A8,B8),C8)=TRUE,1,0) =IF(OR(A8,B8)=TRUE,1,0) =IF(NOT(AND(D8,C8))=TRUE,1,0)
1 1 1 =IF(AND(OR(A9,B9),C9)=TRUE,1,0) =IF(OR(A9,B9)=TRUE,1,0) =IF(NOT(AND(D9,C9))=TRUE,1,0)
By "remove the outermost logic", I assume you want to remove the IF function.
One thing to note is that in a formula like =IF(AND(OR(A2,B2),C2)=TRUE,1,0) you never need the =TRUE test. =IF(AND(OR(A2,B2),C2),1,0) will work exactly the same.
There are a couple of ways to convert a boolean (i.e. true/false value) into an integer without the explicit IF. One is --AND(OR(A2,B2),C2). Another is int(AND(OR(A2,B2),C2)).
Sorry for bad english,
I've some cell with 0 value and 1 value in my microsoft excel, and i want to show 0 values with not valid and 1 values with valid without affecting the formula.
My current excel :
x A B C D E F
1 1 0 0 0 1 0
2 0 1 1 0 0 1
3 1 0 1 0 0 1
4 0 1 1 1 1 1
5 0 0 1 0 1 0
What i want :
valid notvalid notvalid notvalid valid notvalid
0 1 1 0 0 1
1 0 1 0 0 1
0 1 1 1 1 1
0 0 1 0 1 0
Use a custom number format (ctrl+1) of [Color13][=1]v\ali\d;[Color9][=0]\notv\ali\d;; on the cells.
In addition to the valid/notvalid display text, I've added dark blue font for the valids and dark red for notvalid.
Considering you are now working in Worksheet1, if you don't want to edit the formula you currently have in cells A1:F5, you can:
either go to/create Worksheet2 and select the cell A1 OR select the cell A7 in Worksheet1.
write in Worksheet1!A7 or Worksheet2!A1 the following formula:
=IF(Worksheet1!A1=1,"valid","notvalid")
copy the formula dragging the fill handle as needed.
I hope I understood well what you would like to do.