Perforce : wanted to Multiline description - perforce

Hi I wanted to put multi line description using following command
p4 --field Description="MY CLN Header \\n my CLN complete description in two -three lines update " change -o |p4 change -i

If you can't convince your shell to pass the required linebreak and tab characters as part of the command line argument, try telling the --field option to append the second line to the first:
p4 --field Description="MY CLN Header" --field Description+="my CLN complete description in two -three lines update" change -o|p4 change -i
(edit) or, since that's buggy, you could do something like this using P4Perl:
$change = $p4->FetchChange();
$change->_Description( "MY CLN Header \n my CLN complete description in two -three lines update " );
$form = $p4->FormatChange( $change );
$p4->SaveChange( $form );

Related

Linux Bash Trying to write checklist progress "bar" of sorts. Replace the same line

Sorry if I am not giving you enough info, this is my first time posting here.
I am trying to make this in a bash script.
Downloading...............
"run bash commands and when they are done, replace the "Downloading..." text with the text bellow in the same line aka space."
Downloading............... DONE!
go to next line and show
Installing................
"run bash commands again and when they are done, replace the "Installing..." text with the text bellow in the same line aka space."
Installing................ DONE!
I hope you get what I mean. Thanks in advance.
I've tried:
#/bin/bash
tput sc # save cursor
printf "Something that I made up for this string"
sleep 1
tput rc;tput el # rc = restore cursor, el = erase to end of line
printf "Another message for testing"
sleep 1
tput rc;tput el
printf "Yet another one"
sleep 1
tput rc;tput el
But it doesn't make new lines, it just uses one line to show all text.
I'm assuming you pulled the tput code from somewhere, and I'm guessing that 'somewhere' also explained that tput is being used to overwrite the same line multiple times (as your script actually does).
From your description it doesn't sound like you need to overwrite any lines so using tput is the wrong solution.
If I understand your description correctly you should be able to do everything you want with some (relatively) simple printf commands, eg:
printf "Downloading .... " # no '\n' in the output so cursor remains at end of current line
# run your bash commands here
printf "DONE!\n" # append to end of current line and then add a new line (\n)
printf "Installing .... " # no '\n' in the output so cursor remains at end of current line
# run more bash commands here
printf "DONE!\n" # append to end of the current line and then add a new line (\n)
Keep in mind that if any of your 'bash commands' generate any output then the cursor will be moved (probably to a new line) thus messing up your output. Net result is that you'll need to make sure your 'bash commands' do not generate any output to stdout/stderr (alternatively, make sure all output - stdout/stderr - is redirected to files).
If your requirement is to have the 'bash commands' send output to the terminal then you may need to go back to using tput ... but that's going to depend on exactly how you want the output to appear.
NOTE: If this (above) does not meet your requirement then please update the question with more details.

Replace variable in bash file using sed - output lags

I'm trying to write a bash script that search and replace a specific
user input saved in config.sh using sed. This does work; however it
only works partially as shown below.
config.sh
#!/bin/bash
#
#UserName to be deleted
delUserName=""
#Source
delUserSrc=/Users/"$delUserName"
#Destination
delUserDest=/Users/John/BackUp/"$delUserName"/"$delUserName".zip
main.sh
#!/bin/bash
#
source scripts/config.sh
echo -e "\nEnter user you wish to delete: \c"
read -r UserName
sed -i '' -e "s/delUserName=.*/delUserName=$UserName/g" scripts/config.sh
echo -e "delUserName: $delUserName"
echo -e "delUserSrc: $delUserSrc"
echo -e "delUserDest: $delUserDest"
output1:
Enter user you wish to delete: Test
delUserName:
delUserSrc:/Users/
delUserDest:/Users/John/BackUp/ / .zip
output2:
Enter user you wish to delete: Test1
delUserName:Test
delUserSrc:/Users/Test
delUserDest:/Users/John/BackUp/Test/Test.zip
output3:
Enter user you wish to delete: Test1
delUserName:Test1
delUserSrc:/Users/Test1
delUserDest:/Users/John/BackUp/Test1/Test1.zip
expected output1:
Enter user you wish to delete: Test
delUserName:Test
delUserSrc:/Users/Test
delUserDest:/Users/John/BackUp/Test/Test.zip
expected output2:
Enter user you wish to delete: Test1
delUserName:Test1
delUserSrc:/Users/Test1
delUserDest:/Users/John/BackUp/Test1/Test1.zip
The script lags. sed instantaneously changed the value for $delUserName BUT The proper values for $delUserName, $delUserSrc, and $delUserDest only echo on the 2nd run. The scripts run well when all variables are in main.sh except i have to do it this way. Save the user input into $UserName. Any idea why the values don't show when run the 1st time?
Thanks
Here is what I think is happening.
The sed command replaces text in files. It does not modify the value of variables in memory. These values are assigned when you source config.sh.
So right after your sed line, you need to put this line :
source scripts/config.sh
It is the same line as above in your script. This is required there also so that your newly replaced values will be loaded in the variables so that you can display them. Once the new values are loaded in memory, then the echo statements will be able to expand the variables to that new value.

Shell Script Edit Files Line

I am not that good on linux shell script and I need little help.
I want to edit a file via script (finding the line and edit).
The Original line is:
# JVM_OPTS="$JVM_OPTS -Djava.rmi.server.hostname=< hostname >"
I want to uncomment and replaye hostname with 127.0.0.1
JVM_OPTS="$JVM_OPTS -Djava.rmi.server.hostname=127.0.0.1"
You can refer to the set command, change the filename with the name you are working at,
sed -i 's## JVM_OPTS="$JVM_OPTS -Djava.rmi.server.hostname=< hostname >"#JVM_OPTS="$JVM_OPTS -Djava.rmi.server.hostname=127.0.0.1"#' filename
Fine answers, but they don't do anything by way of TEACHING the gentleman how and why it works.
If you were using the mundane text editor, ed, you would use three commands after invoking the command "ed filename":
s/^# //
s/< hostname>/127.0.0.1/
w
So, you can use a pipe to submit those commands directly to ed, specifying "-" as its first argument so that it doesn't bother you by reporting character counts upon reading in and writing out the file:
( echo 's/^# //'; echo 's//127.0.0.1/'; echo w ) | ed - filename
You don't need to echo 'q' also because ed will automatically quit when it runs out of input or encounters "end of file" (you can simulate this on the keyboard by just hitting the CTRL-D key rather than actually typing q ).
Here's one way to do it:
sed -i -e 's/# \(JVM_OPTS=.*=\).*/\1127.0.0.1"/' path/to/file
That is, replace the line with the text captured within the group \(JVM_OPTS=.*=\), so everything from JVM_OPTS= until another = sign, and append 127.0.0.1" to the end.
If there might be other lines in the file starting with # JVM_OPTS=,
then you could make the pattern matching more strict, for example:
sed -i -e 's/# \(JVM_OPTS="$JVM_OPTS -Djava.rmi.server.hostname=\).*/\1127.0.0.1"/' path/to/file

Edit conf file linux under specific section

I have a file that I want to change from command line. The thing is that it has sections and in some different sections it has the same values that I need to change.
The file looks like:
...
[DEFAULT]
findtime = 600
maxretry = 3
[ssh]
maxretry = 6
And I want to change only the maxretry under [DEFAULT].
Maybe there is a conifuration command line that searches the section in config file and changes value named X ?
The command I wrote with sed changes all occurences and I want only the first occurence after [DEFAULT]
sudo sed -i "s/\(^maxretry =.*$\)/maxretry = ${NUMBER_OF_RETRIES}/" filename
Appreciate your help.
Thanks
One way using awk:
$ NUMBER_OF_RETRIES=5
$ awk '/^\[DEFAULT\]/{f=1;}f && /^maxretry =/{print "maxretry = "x;f=0;next}1' x=$NUMBER_OF_RETRIES file
First, we search for the DEFAULT section, and once found, set a flag. Search for the line beginning with maxretry, and if flag is set, do the replacement.
You can check a default flag, which tells you if a substitution occurred or not:
awk '!f && /^maxretry =.*$/ {$0="maxretry = 666"; f=1} 1'
Note that this will not write the change in the file, just redirect the output to a new file or do smth similar. This approach is very specific and works only for first occurrence. #Guru's answer is more generic and can work for arbitrary section (e.g. you want to replace the 2nd,3rd occurrence depending on the section). Nevertheless this example is simpler when targeting the first occurrence.

Perforce: How to find the original number of a change list

In perforce changelists get renumbered on submission. So for e.g. when the changelist was created it would be numbered 777 , but on submission of changelist it would get renumbered to say 790.
My question is how do I get the new CL number (790) , if I know the old CL number 777 , or vice versa ?
If you really want the original changelist number, that can be retrieved from Perforce without having to embed the original changelist number in the description. You can use the -ztag command line option to get at it. And you can only get at it through the 'changes' command (as far as I know):
d:\sandbox>p4 submit -c 24510
Submitting change 24510.
Locking 1 files ...
edit //depot/testfile.txt#2
Change 24510 renamed change 24512 and submitted.
d:\sandbox>p4 -ztag changes -m1 //depot/testfile.txt
... change 24512
... time 1294249178
... user test.user
... client client-test.user
... status submitted
... oldChange 24510
... desc <enter description here>
<saved
As pointed out, it's probably not that useful. However, I did want to note that it's possible to get at it.
The only way I can think of is adding the original changelist number as part of the changelist description field. First, you'll need a script to store the original changelist number:
#!/bin/env perl
$id = $ARGV[0];
open (CHANGE_IN, "p4 change -o $id|");
open (CHANGE_OUT, "|p4 change -i $id");
while (<CHANGE_IN>)
{
if (/^Description:/ and not /ORIGID/)
{
s/(^Description:)(.*)$/$1 ORIGID $id. $2/;
}
print CHANGE_OUT $_;
}
close (CHANGE_IN);
close (CHANGE_OUT);
Save this as origid.pl on the Perforce server with the executable bit set. Then setup a trigger with p4 triggers.
Triggers:
add_origid change-submit //depot/... /usr/bin/origid.pl %change%
Version 2012.1 of Perforce introduced the -O (capital oh) argument to p4 describe, which allows you to query a changelist by its original number (before being renumbered by p4 submit).
I find this very helpful, since I often find myself keeping notes about a changeset before it is submitted, then forgetting to note what it was renumbered to on submission.
So if I have a note talking about change 12300, I can now see what it refers to by typing:
p4 describe -s -O 12300
and having Perforce tell me:
Change 12345 by me#myhost on 2013/10/31 00:00:00
Fix that thing I wrote that note about
Affected files ...
... //Proj/MAIN/foo.c
The ztag method mentioned earlier can be used to find the old changelist number of a submitted change:
> p4 -ztag describe -s 12345 | grep oldChange
... oldChange 12300
Adding to Eric Miller's reply, because I can't comment (not enough points):
to just emit the 1 number
p4 -ztag describe $ORIG | sed -e 's/^\.\.\. oldChange //;t-ok;d;:-ok'
e.g.
OLD=$(p4 -ztag describe $ORIG | sed -e 's/^\.\.\. oldChange //;t-ok;d;:-ok')
or if you want to look up many numbers, this will output a map of new old on each line (may be useful with the "join" command). If there is no old commit, then it re-emits the new commit.
p4 -ztag describe 782546 782547 ... | sed -e '${x;p};s/^\.\.\. change //;t-keep;b-next;:-keep;x;/./p;g;G;s/\n/ /;x;d;:-next;s/^\.\.\. oldChange //;t-ok;d;:-ok;H;x;s/ .*\n/ /;x;d;'
I tried to avoid using GNU extensions to sed.
Unless you do something like Tim suggests the old change list number will be lost on submission.
Change list numbers are only temporary until you actually submit. So if you create a new change list (777 say) and then decide to delete it, the next change list you create will be 778.
It can be a bit more elegant if you use the P4 Python module.
i.e.
import P4
p4 = P4.P4()
p4.connect() # having a valid p4 workspace/connection is on you :)
c = p4.run_describe('969696') # describe a Submitted, renumbered changelist, i.e. 969696
old_pending_cl_number = c['oldChange'] # print out prior/pending CL# if this exists.
Cheers

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