I am getting an error when making a third class that inherits the first two classes' attributes. The first class's function will be go through but when accessing the second class's function I am gettting an error:
class3' object has no attribute 'othernum
Here is the code:
class class1():
def __init__(self):
self.number = 10000
def getNum(self):
return self.number
class class2():
def __init__(self):
self.othernum = 1111
def displaynum(self):
return self.othernum
class class3(class1, class2):
pass
newperson = class3()
print(newperson.getNum())
print(newperson.displaynum())
Found the answer.
class class3(class1, class2):
def __init__(self):
class1.__init__(self)
class2.__init__(self)
The answer presented by #Ishaan Sathaye is indeed correct. But be aware that there are several mechanisms for initializing base classes in a multiple inheritance hierarchy. See Calling parent class init with multiple inheritance, what's the right way?, in particular the section with heading All base classes are designed for cooperative inheritance.
So, if your 3 classes were designed for cooperative inheritance, we would have:
class class1():
def __init__(self):
super().__init__()
self.number = 10000
def getNum(self):
return self.number
class class2():
def __init__(self):
super().__init__()
self.othernum = 1111
def displaynum(self):
return self.othernum
class class3(class1, class2):
def __init__(self):
super().__init__()
newperson = class3()
print(newperson.getNum())
print(newperson.displaynum())
I have a few classes set up that hold values for an application. I'd like to import them into the same class, however, the values in the last class are being ignored. Here is a simple example.
class A:
def __init__(self):
self.testA = 'A'
class B:
def __init__(self):
self.testB = 'B'
class C(A, B):
def __init__(self):
super().__init__()
print(self.testA)
print(self.testB)
test = C()
The above will work only if I do not include the print(self.testB) the variable in class 'B'. I'd like to access the data from Class B as well. How? Thank you.
I'm having a problem with multiple inheritance that I can't seem to figure out. Here is a very abstracted minimal example that reproduces my error (my code is much more complex than this).
class Thing(object):
def __init__(self, x=None):
self.x = x
class Mixin(object):
def __init__(self):
self.numbers = [1,2,3]
def children(self):
return [super().__init__(x=num) for num in self.numbers]
class CompositeThing(Mixin, Thing):
def __init__(self):
super().__init__()
def test(self):
for child in self.children():
print(child.x)
obj = CompositeThing()
obj.test()
Per this, I expect the children() method to return a list of Things built up from self.numbers. Instead, I get TypeError: super(type, obj): obj must be an instance or subtype of type. Incidentally, the same thing happens if I don't call the constructor and allow children to return super() 3 times (i.e., the uninstantiated superclass). Any ideas why this might be happening?
Thanks in advance!
In line 9 of your code, it looks like you are trying to call __init__ of object. I am assuming you meant to have Mixin inherit from Thing.
class Thing(object):
def __init__(self, x=None):
self.x = x
class Mixin(Thing):
def __init__(self):
self.numbers = [1,2,3]
def children(self):
return [super().__init__(x=num) for num in self.numbers] # Now calls Thing.__init__ instead of object.__init__
class CompositeThing(Mixin, Thing):
def __init__(self):
super().__init__()
def test(self):
for child in self.children():
print(child.x)
obj = CompositeThing()
obj.test()
Actually, I figured it out. There were two problems: (1) super() doesn't work as expected inside comprehensions because comprehensions in Py3 have their own scope - this was causing the TypeError I was experiencing. (2) What I was really trying to do was create a new instance of the parent, rather than calling a method from the parent. I have posted a new question for just the latter problem for clarity.
I'm wondering if what I have created is valid and 'nice' - or actually a mess
I have a class that has a method which calls a function in another class. However, it is only 'visible' by the fact these two classes are brought together in another child class. If somebody is just looking at this method they may wonder where this is actually located - it is not clear.
Am I doing something wrong here, or something common in Python?
class A():
def __init__(self):
pass
def register_urc(self, text):
print(text)
class B(A):
def __init__(self):
A.__init__(self)
class C():
def __init__(self):
self.register_urc("Hello World")
class Z(B, C):
def __init__(self):
B.__init__(self)
C.__init__(self)
def test(self):
print("finished")
z = Z()
z.test()
What I get is:
Hello World
finished.
I assume this is working because I'm referencing Z's 'self' and passing that down to all other classes.
I'm trying to dynamically create a class using type() and assign an __init__ constructor which calls super().__init__(...); however, when super() gets called I receive the following error:
TypeError: super(type, obj): obj must be an instance or subtype of type
Here is my code:
class Item():
def __init__(self, name, description, cost, **kwargs):
self.name = name
self.description = description
self.cost = cost
self.kwargs = kwargs
class ItemBase(Item):
def __init__(self, name, description, cost):
super().__init__(name, description, cost)
def __constructor__(self, n, d, c):
super().__init__(name=n, description=d, cost=c)
item = type('Item1', (ItemBase,), {'__init__':__constructor__})
item_instance = item('MyName', 'MyDescription', 'MyCost')
Why is super() inside the __constructor__ method not understanding the object parameter; and how do I fix it?
Solution 1: Using cls = type('ClassName', ...)
Note the solution of sadmicrowave creates an infinite loop if the dynamically-created class gets inherited as self.__class__ will correspond to the child class.
An alternative way which do not have this issue is to assigns __init__ after creating the class, such as the class can be linked explicitly through closure. Example:
# Base class
class A():
def __init__(self):
print('A')
# Dynamically created class
B = type('B', (A,), {})
def __init__(self):
print('B')
super(B, self).__init__()
B.__init__ = __init__
# Child class
class C(B):
def __init__(self):
print('C')
super().__init__()
C() # print C, B, A
Solution 2: Using MyClass.__name__ = 'ClassName'
An alternative way to dynamically create class is to define a class inside the function, then reassign the __name__ and __qualname__ attributes:
class A:
def __init__(self):
print(A.__name__)
def make_class(name, base):
class Child(base):
def __init__(self):
print(Child.__name__)
super().__init__()
Child.__name__ = name
Child.__qualname__ = name
return Child
B = make_class('B', A)
class C(B):
def __init__(self):
print(C.__name__)
super().__init__()
C() # Display C B A
Here is how I solved the issue. I reference the type() method to dynamically instantiate a class with variable references as such:
def __constructor__(self, n, d, c, h):
# initialize super of class type
super(self.__class__, self).__init__(name=n, description=d, cost=c, hp=h)
# create the object class dynamically, utilizing __constructor__ for __init__ method
item = type(item_name, (eval("{}.{}".format(name,row[1].value)),), {'__init__':__constructor__})
# add new object to the global _objects object to be used throughout the world
self._objects[ item_name ] = item(row[0].value, row[2].value, row[3].value, row[4].value)
There may be a better way to accomplish this, but I needed a fix and this is what I came up with... use it if you can.