Sequelize how to transform objects list - node.js

Question

I have this code
employees = []
async function fillEmployeesList() {
await Employe.findAll().then(allEmployes => {
employees = allEmployes;
console.log('All employees: ' + allEmployes[0].nom);
});
}
And I want to transform the raw object to correct employee object, how can I do this? Because allEmployes is currently a list of sequelize object, I want it to be a list of Employee object, how? (Sorry english is not my first language)

Answer 1

you can try this
employees = []
async function fillEmployeesList() {
const allEmployees = await Employe.findAll();
employees = allEmployees.map(employee => {
return employee.toJSON();
});
}
im adding just this return employee.toJSON(); line of code.

Answer 2

If you are looking to assign employees data directly to a variable without using callback and manipulate those data as per your requirements you can do like this.
employees = []
async function fillEmployeesList() {
const allEmployees = await Employe.findAll();
employees = allEmployees.map(employee => {
return {"nom", employee.nom, "other_key": employee.name};
})
console.log(employees);//will print employees modified data
}

Answer 3

You can try this
employees = []
async function fillEmployeesList() {
await Employe.findAll({raw: true}).then(allEmployes => {
employees = allEmployes;
console.log('All employees: ' + allEmployes[0].nom);
});
}

Answer 4

If you only need the raw data and don't want to update anything, you can do like this to get the raw data.
employees = []
async function fillEmployeesList() {
await Employe.findAll({raw: true}).then(allEmployes => {
employees = allEmployes;
console.log('All employees: ' + allEmployes[0].nom);
});
}
You can read about it here. http://docs.sequelizejs.com/manual/models-usage.html#raw-queries