So far I have the following:
source_folder = 'file_location'
for file in os.listdir(source_folder):
if file.startswith('stnet_'):
os.rename(file, file.replace('stnet_a_b', '%s_' % time.ctime(os.path.getctime(file)) + 'stnet_a_b'))
The issue with is is I keep getting FileNotFoundError: [WinError 2] The system cannot find the file specified 'stnet_a_b.raw'
Can someone point out what I'm doing wrong?
Thanks.
os.listdir can only get the filenames without directory, while os.rename, os.path.getctime needs full name with directory(if your current directory is not conincidently file_location then the file will not be found).
You can use os.path.join to get the full name. And if you are on Windows you must make sure filename doesn't contain special characters which your code contains.
dir = r'file_location'
# os.chdir(dir) # in case you don't want to use os.path.join
for filename in os.listdir(dir):
print(filename)
if filename.startswith('stnet_'):
src = os.path.join(dir, filename)
ctime_str = str(time.ctime(os.path.getctime(src)))
ctime_str = ctime_str.replace(':', '').replace(' ', '') # remove special characters
fn_new = filename.replace('stnet_a_b',
'{}_'.format(ctime_str + 'stnet_a_b'))
des = os.path.join(dir, fn_new)
print('src={}, des={}'.format(src, des))
os.rename(src, des)
please try above code.
Related
I have multiple directories inside which there are multiple files.
In directory1 files have the name format:
1.2.826.0.1.3680043.2.133.1.3.49.1.124.27456-3-1-10jd0au.dcm
1.2.826.0.1.3680043.2.133.1.3.49.1.124.27456-3-2-10jd0av.dcm
....
1.2.826.0.1.3680043.2.133.1.3.49.1.124.27456-3-10-17v7m18.dcm
In directory2:
1.2.826.0.1.3680043.2.133.1.3.49.1.46.34440-4-1-r3hu3u.dcm
1.2.826.0.1.3680043.2.133.1.3.49.1.46.34440-4-2-r3hu3v.dcm
....
and so on.
How can I rename these as just 1.dcm, 2.dcm,.....in each directory?
My attempt is as follows:
for dpath, dnames, fnames in os.walk(dir_path):
for dname in dnames:
directory = os.path.join(dir_path,dname)
for filename in os.listdir(directory):
old_name = os.path.join(directory,filename)
new = filename[filename.find("-"):]
new_name = os.path.join(directory, new)
os.rename(old_name, new_name)
But this only yields:
-3-1-10jd0au.dcm
-3-10-17v7m18.dcm
You could write a function that uses a regex to extract the parts of the filename that you need, for example:
import re
def ExtractNumber(filename):
parts = re.search(r".*-.*-(.*)-.*(\..*)", filename)
return parts.group(1) + parts.group(2)
print(ExtractNumber("1.2.826.0.1.3680043.2.133.1.3.49.1.124.27456-3-1-10jd0au.dcm"))
print(ExtractNumber("1.2.826.0.1.3680043.2.133.1.3.49.1.124.27456-3-10-17v7m18.dcm"))
Outputs:
1.dcm
10.dcm
I upload a file through the form, check it, and only after checking it I want to add it to my database.
form = BookForm(request.POST, request.FILES)
file = form.files
path = file.get('book_file').temporary_file_path()
in path - '/tmp/tmpbp4klqtw.upload.pdf'
But as soon as I want to transfer this file from the temporary storage to some other folder, I get the following error:
path = os.replace(path, settings.MEDIA_ROOT)
IsADirectoryError: [Errno 21] Is a directory: '/tmp/tmpbp4klqtw.upload.pdf' -> '/home/oem/bla/bla'
Can't understand why this file is not in reality? What can I do about it? Is it possible to set some special path for the "temporary file"?
UPD:
You should use path = os.replace(path, settings.MEDIA_ROOT + '/name-of-file.pdf') – Willem Van Onsem
os.replace(…) [python-doc] expects a filename as target if you specify a file as source, so you can move this to:
os.replace(path, f'{settings.MEDIA_ROOT}/name-of-file.pdf')
you can also make use of shutil.move(…) [python-doc] to specify the directory, this function will also return the filepath of the target file:
from shutil import move
target_file = move(path, settings.MEDIA_ROOT)
I want to copy the source file to the destination folder.
In the destination folder, I am creating n number of folders (That may be nested of any depth) and I want to paste file1.pdf in any random folders inside the destination folder.
I have done the following code
import shutil
destination_folder = "path_to_the_destination_folder"
source_file = "path_to_source_file\file1.pdf"
destination_file = "f{destination_folder}\any_random_folder_from_n_nested_folders\file1.pdf"
new_file= shutil.copy(source_file, destination_file )
print(new_file)
FYI: "destination_folder\any_random_folders_from_n_nested_folders" This path is present, means it is getting created successfully , checked using os.path.isdir()
And facing this issue for some files, not for all files..
But it is giving me an error:
FileNotFoundError: [Errno 2] No such file or directory:
File "\AppData\Local\Programs\Python\Python39\lib\shutil.py", line 420, in copy
copyfile(src, dst, follow_symlinks=follow_symlinks)
File "\AppData\Local\Programs\Python\Python39\lib\shutil.py", line 265, in copyfile
with open(src, 'rb') as fsrc, open(dst, 'wb') as fdst:
FileNotFoundError: [Errno 2] No such file or directory
I believe, you have incorrectly specified destination folder, try this:
import shutil
destination_folder = "path_to_the_destination_folder"
source_file = "path_to_source_file\file1.pdf"
destination = f"{destination_folder}\any_random_folders_from_n_nested_folders\file1.pdf"
dest = shutil.copy(source_file, destination)
print(dest)
If this doesn't work, then check if all the directories exist and also check the permissions.
This is issue is resolved..
I just changed folder names which I was creating according to user input.
Previous folder names: f"Fld+{datetimestamp}"
Current folder names: f"Fld+{folder_counter}"
I have a folder with the following files:
[11111]Text.txt
[22222]Text.txt
[33333]Text.txt
[44444]Text.txt
I need rename the files to remove the [11111] designation from the beginning of the file name, however that results in duplicate file names.
I wrote a basic script out that will strip the [11111] from the first file, and if any duplication occurs with subsequent files it will name the file [Duplicate]_[#]_text.txt where [#] is a random number
When I ran the code, it renamed the first file correctly, and renamed the second file with the required string, but it did not continue with the other files, and instead presented the following error:
FileExistsError: [WinError 183] Cannot create a file when that file already exists: 'Destination/[33333]Text.txt' -> 'Destination/[Duplicate]_[1]Text.txt'
The code below is what I have currently, though i have tried several iterations also
Location = (Destination_Folder)
Dupe_Counter = random.randint(0,255)
for filename in os.listdir(Location):
try:
if filename.startswith("["):
os.rename(Location + filename, Location + filename[7:])
except:
os.rename(Location + filename, Location +'[Duplicate]_' + '[' + str(Dupe_Counter) +']' + filename[7:])
I'm assuming that it's not actually picking up the Dupe_Counter when creating new files, however I'm not 100% sure where i'm going wrong.
Any help appreciated.
In your Dupe_Counter you are generating a random number that can collide with the results sometimes. But on top of that, you are generating the random Dupe_Counter once only.
Try to generate a random number for each iteration.
Location = (Destination_Folder)
for filename in os.listdir(Location):
Dupe_Counter = random.randint(0,255)
try:
if filename.startswith("["):
os.rename(Location + filename, Location + filename[7:])
except:
os.rename(Location + filename, Location +'[Duplicate]_' + '[' + str(Dupe_Counter) +']' + filename[7:])
But I would recommend generating an increasing sequence for renaming the files and better understanding.
Something Like this:
Location = (Destination_Folder)
for filename in os.listdir(Location):
Dupe_Counter = 101
try:
if filename.startswith("["):
os.rename(Location + filename, Location + filename[7:])
except:
os.rename(Location + filename, Location +'[Duplicate]_' + '[' + str(Dupe_Counter) +']' + filename[7:])
Dupe_Counter += 1
Hope I've been of some help.
In an application, I can get the path to a file which resides in a directory as a string:
"/path/to/the/file.txt"
In order to write another another file into that same directory, I want to change the string "/path/to/the/file.txt" and remove the part "file.txt" to finally only get
"/path/to/the/"
as a string
I could use
string = "/path/to/the/file.txt"
string.split('/')
and then glue all the term (except the last one) together with a loop
Is there an easy way to do it?
You can use os.path.basename for getting last part of path and delete it with using replace.
import os
path = "/path/to/the/file.txt"
delete = os.path.basename(os.path.normpath(path))
print(delete) # will return file.txt
#Remove file.txt in path
path = path.replace(delete,'')
print(path)
OUTPUT :
file.txt
/path/to/the/
Let say you have an array include txt files . you can get all path like
new_path = ['file2.txt','file3.txt','file4.txt']
for get_new_path in new_path:
print(path + get_new_path)
OUTPUT :
/path/to/the/file2.txt
/path/to/the/file3.txt
/path/to/the/file4.txt
Here is what I finally used
iter = len(string.split('/'))-1
directory_path_str = ""
for i in range(0,iter):
directory_path_str = directory_path_str + srtr.split('/')[i] + "/"