Mapping lists to individual dictionary keys and values - python-3.x

Question

I have 5 lists. I would like to map these 5 lists to a list of dictionaries, each one with a key/value pair from each of the 5 lists for every dictionary instance [n]. My first thought is to set up a loop to enumerate each occurrence of a dictionary in the list of dictionaries, but not sure what that might look like. Any thoughts?
name = ["John", "Sally", "Allen", "Nick", "Charles", "Richie", "Derek"]
age = [21, 36, 33, 29, 40, 18, 35]
hometown = ["New York", "Washington", "Philadelphia", "Atlanta", "Miami", "LA", "Seattle"]
favorite_food = ["chicken", "steak", "spaghetti", "fish", "oreos", "hamburger", "cereal"]
pet = ["cat", "fish", "dog", "hamster", "dog", "cat", "snake"]
list of dictionaries such that
D[0]={'name':'John', 'age':'21', 'hometown': 'New York', 'favorite_food':
'chicken', 'pet': 'cat'}

Answer 1

You can use the built-in function zip and list/dict comprehensions for this:
name = ["John", "Sally", "Allen", "Nick", "Charles", "Richie", "Derek"]
age = [21, 36, 33, 29, 40, 18, 35]
hometown = ["New York", "Washington", "Philadelphia", "Atlanta", "Miami", "LA",
"Seattle"]
favorite_food = ["chicken", "steak", "spaghetti", "fish", "oreos", "hamburger", "cereal"]
pet = ["cat", "fish", "dog", "hamster", "dog", "cat", "snake"]
fields = ["name", "age", "hometown", "favourite_food", "pet"]
zipped = zip(name, age, hometown, favorite_food, pet)
d = [{k: v for k, v in zip(fields,el)} for el in zipped]

Answer 2

The zip function will allow you to "pair" up or tuple up several lists.
For the first three attributes, you can do this to get a tuple:
>>> for i in zip(name, age, hometown):
... print(i)
...
('John', 21, 'New York')
('Sally', 36, 'Washington')
('Allen', 33, 'Philadelphia')
('Nick', 29, 'Atlanta')
('Charles', 40, 'Miami')
('Richie', 18, 'LA')
('Derek', 35, 'Seattle')
If you make a list
L = []
you can add dictionaries to it:
>>> L=[]
>>> for i in zip(name, age, hometown):
... d = {}
... d['name']=t[0]
... d['age']=t[1]
... d['hometown']=t[2]
... L.append(d)
...
That's for the first three - extending to the whole lot should be clear.