Trying to find dates in a string, but code doesnt work when I use "/" as a date separator. Also if i enter multiple dates. it returns only one.
I'd like to use all valid date separators viz "/" "-" "." and get all the dates in the string.
Also i'd like to use all the date formats like ddmmyy mmddyy yymmdd yyyymmdd ddmmyyyy mmddyyyy.
str = " here is some text in 31-01-2019 my string 01/02/2019 for fun 02.02.2019"
match = re.search('\d{2}-\d{2}-\d{4}', str)
date = dt.strptime(match.group(), '%d-%m-%Y').date()
print(date)
re.findall(r'\b\d{2}[-\./]\d{2}[-\./]\d{2}\b|\b\d{4}[-\./]\d{2}[-\./]\d{2}\b|\b\d{2}[-\./]\d{2}[-\./]\d{4}\b',lsstr)
output : ['31-01-2019', '01/02/2019', '02.02.2019']
Use this regexp to find all the dates present in the string.
Related
For example:
2021-08-18T22:24:49-06:00
I want to print this to a more readable format like: 8/18/21 10:24pm
I have tried using the built in DateTime function but it returns an error. Can someone point me in the right direction? I have checked other answers but they all relate to using the aforementioned funciton.
Looking at how your data is formatted and it seems your data is formatted "yyyy-mm-ddThh:mm:ss";so, here is my attempt:
Formula in C1:
=--SUBSTITUTE(LEFT(A1,16),"T"," ")
Then I just formatted the resulting datetime-stamp with:
m/d/yy hh:mm AM/PM
So it remains a numeric value to do your calculations with if needed.
Give a try to below formula-
=TEXT(FILTERXML("<t><s>"&SUBSTITUTE(A1,"T","</s><s>")&"</s></t>","//s[1]")+FILTERXML("<t><s>"&SUBSTITUTE(FILTERXML("<t><s>"&SUBSTITUTE(A1,"T","</s><s>")&"</s></t>","//s[2]"),"-","</s><s>")&"</s></t>","//s[1]"),"M/dd/yyyy hh:mm AM/PM")
The date is in ISO 8601 format. This will parse out the different parts of the date string and convert to a date, assuming that your string is in A1:
=DATEVALUE(LEFT(A1,10))
+TIMEVALUE(MID(A1,12,8))
+TIMEVALUE(RIGHT(A1, 5))
*INT(MID(A1, 20, 1) & 1)
The first part grabs the date, the second part grabs the time, the third part captures the date offset, and the last part captures the sign. If you want to format that, you can do it with the cell formatting or wrap it in TEXT:
=TEXT(
DATEVALUE(LEFT(A1,10))
+TIMEVALUE(MID(A1,12,8))
+TIMEVALUE(RIGHT(A1, 5))
*INT(MID(A1, 20, 1) & 1),
"yyyy-mm-dd hh:mm:ss"
)
Note that if you need to support UTC, that is indicated by Z instead of a time offset, and you would need to modify the formula slightly. If your data always has the same time offset, you could just hardcode it, instead of parsing it out.
i have a set of data for couple of days and the names of the data files like this
name='Newyork20200915'
which is for the 15th of September and i want to export only the date to excel like shown below
So how can i get the date from the name string ?
Thanks in advance
Assuming that the other part of name will not contain any digits besides the date, you can use regexp to get all the digits from the character array:
name = 'Newyork20200915'
date_only = regexp(name, '\d*', 'match')
Next, you can convert this date string to a serial date number using datenum, by providing the format in which the date is currently. And then use datestr to format it to your desired format.
date_formatted = datestr(datenum(date_only, 'yyyymmdd'), 'dd. mmm')
date_formatted =
'15. Sep'
A file is given to me in such a way that the date is included in the file name.
I have written a code to retrieve the file based on the date.
The file name, which cannot be changed, is xxxx_MM-DD-YYYY.
For half of the month my code works. e.g of the file name is xxxx_05-15-2020, the user can enter in the date, 05-15-2020, and it will be retrieved.
If the user puts in 05-03-2020 , Excel changes this format to 05/03/2020, and based on the new format, the code will not work as it is looking for "-" separators and not "/".
How can I choose MM-DD-YYYY formatting?
The following should work regardless whether your date is stored as a date type variable or string type variable:
dateString = Replace(dateVar, "/", "-")
If you need to convert the date to a date type variable, you could use cDate like this
cDate(dateString)
Assuming your date is stored as a date type variable, you could format it this way:
Format(dateVar, "dd-mm-yyyy")
Read more about the Format function here
In Matlab, how can I convert a date into a numeric date?
For example, I want to convert '31-Jan-1990' to '19900131'.
You can use datestr to change the date format to 19900131, and then use str2double to convert it to a number:
numDate = str2double(datestr('31-Jan-1990','yyyymmdd'))
numDate =
19900131
If you want to keep the date as a string just remove str2double from the above code.
Here are two functions that are the most helpful and appropriate ones for this situation:
datenum and datestr
The first step is to convert your string to Matlab's date number, which can be later converted to any string format, or even do calculation for date or time. Here we use additional argument to help on conversion. You may also check here for format you like to construct.
daynum = datenum('31-Jan-1990','dd-mm-YYYY')
The second step is then straightforward. You use the date number to translate to the string with the format you want.
datestr(daynum,'YYYYmmdd');
You can sure combine both functions together
datestr(datenum('31-Jan-1990','dd-mm-YYYY'),'YYYYmmdd')
The result
>> datestr(datenum('31-Jan-1990','dd-mm-YYYY'),'YYYYmmdd')
ans =
'19900131'
Finally, use str2num to achieve what you want.
I'm new to Stata, and I'm wondering how can I change a string variable which contains a date to a date format.
The data in the variable looks like this:
yyyy-mm-dd
Should I first remove the dashes so that Stata can recognize the format in order to later use gen var = date() ?
Thank you for your help.
The Stata date function is smart about removing separator characters. See help datetime_translation under the section "the date function"
If your dates are in v1 and in the form yyyy-mm-dd you can specify the commands:
generate v2 = date(v1, "YMD")
format %td v2
The YMD is called a mask, and it tells Stata the order in which the parts of the date are specified. The second line will assign the variable the Stata daily date format, which means that when you look at that variable in the data, it will be shown in human readable form. The date is stored, however, as the number of days since January 1, 1960.
The best way to experiment with the date function is to use the display command. The first line will display an integer representing the number of days since January 1, 1960. The second line will display the date in a human readable format.
display date("2013-08-14", "YMD")
display %td date("2013-08-14", "YMD")
you can look here to see how to convert to data in Stata or do like this
tostring datedx, replace
generate str4 dxyr1= substr(datedx,1,4)
generate str2 dxmo1 = substr(datedx,6,7)
generate str2 dxda1 = substr(datedx,9,10)
destring dx*, replace
gen datedx1 = mdy(dxmo1, dxda1, dxyr1)