struct.pack doesn't pack tightly - struct

I want to create and later send a 5 byte struct like this:
import struct
struct.pack("?i", True, 0x01020304)
>>b'\x01\x00\x00\x00\x04\x03\x02\x01'
but as you see the 1 byte boolean get's padded by 3 bytes or filled up to an integer for some reason.
what I want as a result is:
>>b'\x01\x04\x03\x02\x01'
How can I do this and why does my solution not work? It seems to be correctly used according to the documentation.

My problem was solved by an answer to this question. The = character at the start of the format string tells the pack method to not align the data but to produce a byte string of exactly the specified length. Whether a format character allows alignment or not is specified in this chapter. Somehow I missed that.

Related

Python interpret bytearray as bytes

I have a question regarding the interpretation of a string as bytes
Within python, I have the situation that one variable contains e.g. this value
"bytearray(b'\x13\x02US')"
this is unfortunately due to the behavior of a module I am using. My question is, how could i get this string into bytes?
I have tried stripping away the "bytearray(b'" and the "')" at the end, and use .encode() as a function, but the result then is:
b'\\x13\\x02US'
Which clearly escapes the \ in order to prevent the interpretation as bytes.
How could i get this converted into
b'\x13\x02US'
instead though?
Thank you very much!
You could use .decode().replace('\\', '\'), this way it replaces the double slashes with single ones. Either attache it after your .encode() function or do it on your string seperately.

Is an empty string valid base64 encoded data of zero bytes length?

One of my colleges was telling me that the empty string is not a valid base64 encoded data string. I don't think this is true (he is too lazy to parse it), but after googling around a bit and even checking the RFC I have not found any documentation that explicitly states how to properly encode a blob of zero bytes length in base64.
So, the question is: Do you have a link to some official documentation that explicitly states how zero bytes should be encoded in base64?
According to RFC 4648 Section 10, Test Vectors,
BASE64("") = ""
I would assume the inverse must hold as well.
My thought on this is that there are two possible base64 values that an empty string could produce; either an empty string, or a string that consists entirely of pad characters ('==='). Any other valid base64 string contains information. With the second case, we can apply the following rule from the RFC:
If more than the allowed number of pad characters are found at the end
of the string, e.g., a base 64 string terminated with "===", the
excess pad characters could be ignored.
As they can be ignored, they can be dropped from the resultant encoded string without consequence, once again leaving us with an empty string as the base64 representation of an empty string.

How to convert between bytes and strings in Python 3?

This is a Python 101 type question, but it had me baffled for a while when I tried to use a package that seemed to convert my string input into bytes.
As you will see below I found the answer for myself, but I felt it was worth recording here because of the time it took me to unearth what was going on. It seems to be generic to Python 3, so I have not referred to the original package I was playing with; it does not seem to be an error (just that the particular package had a .tostring() method that was clearly not producing what I understood as a string...)
My test program goes like this:
import mangler # spoof package
stringThing = """
<Doc>
<Greeting>Hello World</Greeting>
<Greeting>你好</Greeting>
</Doc>
"""
# print out the input
print('This is the string input:')
print(stringThing)
# now make the string into bytes
bytesThing = mangler.tostring(stringThing) # pseudo-code again
# now print it out
print('\nThis is the bytes output:')
print(bytesThing)
The output from this code gives this:
This is the string input:
<Doc>
<Greeting>Hello World</Greeting>
<Greeting>你好</Greeting>
</Doc>
This is the bytes output:
b'\n<Doc>\n <Greeting>Hello World</Greeting>\n <Greeting>\xe4\xbd\xa0\xe5\xa5\xbd</Greeting>\n</Doc>\n'
So, there is a need to be able to convert between bytes and strings, to avoid ending up with non-ascii characters being turned into gobbledegook.
The 'mangler' in the above code sample was doing the equivalent of this:
bytesThing = stringThing.encode(encoding='UTF-8')
There are other ways to write this (notably using bytes(stringThing, encoding='UTF-8'), but the above syntax makes it obvious what is going on, and also what to do to recover the string:
newStringThing = bytesThing.decode(encoding='UTF-8')
When we do this, the original string is recovered.
Note, using str(bytesThing) just transcribes all the gobbledegook without converting it back into Unicode, unless you specifically request UTF-8, viz., str(bytesThing, encoding='UTF-8'). No error is reported if the encoding is not specified.
In python3, there is a bytes() method that is in the same format as encode().
str1 = b'hello world'
str2 = bytes("hello world", encoding="UTF-8")
print(str1 == str2) # Returns True
I didn't read anything about this in the docs, but perhaps I wasn't looking in the right place. This way you can explicitly turn strings into byte streams and have it more readable than using encode and decode, and without having to prefex b in front of quotes.
This is a Python 101 type question,
It's a simple question but one where the answer is not so simple.
In python3, a "bytes" object represents a sequence of bytes, a "string" object represents a sequence of unicode code points.
To convert between from "bytes" to "string" and from "string" back to "bytes" you use the bytes.decode and string.encode functions. These functions take two parameters, an encoding and an error handling policy.
Sadly there are an awful lot of cases where sequences of bytes are used to represent text, but it is not necessarily well-defined what encoding is being used. Take for example filenames on unix-like systems, as far as the kernel is concerned they are a sequence of bytes with a handful of special values, on most modern distros most filenames will be UTF-8 but there is no gaurantee that all filenames will be.
If you want to write robust software then you need to think carefully about those parameters. You need to think carefully about what encoding the bytes are supposed to be in and how you will handle the case where they turn out not to be a valid sequence of bytes for the encoding you thought they should be in. Python defaults to UTF-8 and erroring out on any byte sequence that is not valid UTF-8.
print(bytesThing)
Python uses "repr" as a fallback conversion to string. repr attempts to produce python code that will recreate the object. In the case of a bytes object this means among other things escaping bytes outside the printable ascii range.
TRY THIS:
StringVariable=ByteVariable.decode('UTF-8','ignore')
TO TEST TYPE:
print(type(StringVariable))
Here 'StringVariable' represented as a string. 'ByteVariable' represent as Byte. Its not relevent to question Variables..

python 3: how to make strip() work for bytes

I've contered a Python 2 code to Python 3.
In doing so, I've changed
print 'String: ' + somestring
into
print(b'String: '+somestring)
because I was getting the following error:
Can't convert 'bytes' object to str implicitly
But then now I can't implement string attributes such as strip(), because they are no longer treated as strings...
global name 'strip' is not defined
for
if strip(somestring)=="":
How should I solve this dilemma between switching string to bytes and being able to use string attributes? Is there a workaround?
Please help me out and thank you in advance..
There are two issues here, one of which is the actual issue, the other is confusing you, but not an actual issue. Firstly:
Your string is a bytes object, ie a string of 8-bit bytes. Python 3 handles this differently from text, which is Unicode. Where do you get the string from? Since you want to treat it as text, you should probably convert it to a str-object, which is used to handle text. This is typically done with the .decode() function, ie:
somestring.decode('UTF-8')
Although calling str() also works:
str(somestring, 'UTF8')
(Note that your decoding might be something else than UTF8)
However, this is not your actual question. Your actual question is how to strip a bytes string. And the asnwer is that you do that the same way as you string a text-string:
somestring.strip()
There is no strip() builtin in either Python 2 or Python 3. There is a strip-function in the string module in Python 2:
from string import strip
But it hasn't been good practice to use that since strings got a strip() method, which is like ten years or so now. So in Python 3 it is gone.
>>> b'foo '.strip()
b'foo'
Works just fine.
If what you're dealing with is text, though, you probably should just have an actual str object, not a bytes object.
I believe you can use the "str" function to cast it to a string
print str(somestring).strip()
or maybe
print str(somestring, "utf-8").strip()
However, if the object is already a string, you don't get a new one. So if you're not sure whether an object is a string and need it to be and call str(obj), you won't create another if it's already a string.
x='123'
id(x)
2075707536496
y=str(x)
id(y)
2075707536496

Quick variable question

I have an EditText object (et_travel) on my screen that's asking for miles traveled. I grab that data like this:
float travel = Float.parseFloat(et_travel.getText().toString());
if(travel > 40000){
I just discover that if someone puts 40000 in the EditText, everything works fine, but if they put 40,000 (adding a comma to the number), I force close on the float travel = ...statement.
How can I evaluate the number without having a problem from the user adding a comma?
Is this in Java? It appears to be, but I'm wondering if I'm mistaken. Regardless, I would suggest you remove all of the characters from the string that are not of a numeric type. A way to do this may be using a regular expression.
A way to do this in Java may be the following:
String input = et_travel.getText().toString();
input = input.replaceAll("[^0-9]", "");
float travel = Float.parseFloat(input);
...
This way, you strip anything that is a non-numeric value from the string first, and then attempt to do your work. Obviously do some error checking before this (like input is not null and such). One change that is needed however is that you may need to maintain the '.' character (if you're given non-integer values). This would require changing the first regex a bit.
Check here: http://download.oracle.com/javase/1.5.0/docs/api/java/lang/String.html#replaceAll(java.lang.String, java.lang.String)
What you need is some validation on the input. Before converting the string into a float parse the string. If there are any ','s then remove them. If there is just junk then reject the input, otherwise someone could put a word or anything else in the input and cause havoc in your program.
Check out
inputType to restrict user input
android:inputType="number"

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