Extracting an xml value in Groovy - groovy

Question

I have this code
String dbresponse = '''
<rows>
<row>
<file_data>One</file_data>
<time_inserted>2019-01-30T10:29:20.543</time_inserted>
</row>
<row>
<file_data>two</file_data>
<time_inserted>2019-01-30T10:29:20.547</time_inserted>
</row>
<row>
<file_data>three</file_data>
<time_inserted>2019-01-30T10:29:20.550</time_inserted>
</row>
<row>
<file_data>four</file_data>
<time_inserted>2019-01-30T10:29:20.550</time_inserted>
</row>
<row>
<file_data>five</file_data>
<time_inserted>2019-01-30T10:29:20.553</time_inserted>
</row>
</rows>
'''
def response = new XmlSlurper().parseText(dbresponse)
def data = response.rows.row[1].file_data
print data
I have two questions:
1] With the above code why am I not getting the response of: two ?
2] How do I iterate through the entire xml doc to get this response:
one
two
three
four
five
Thanks

Answer 1

1] With the above code why am I not getting the response of: two ?
As per the Official Groovy doc it should be
def rows = new XmlSlurper().parseText(dbresponse)
println(rows.row[1].file_data)
First line is "parsing the XML an returning the root node as a GPathResult". In your case, the root node is rows
2] How do I iterate through the entire xml doc to get this response: one two three four five
println("Iterating using each() method")
rows.row.file_data.each { row ->
println(row)
}
println("Iterating using Groovy for loop")
for (fileData in rows.row.file_data) {
println(fileData)
}
println("Getting a list of necessary elements using Groovy Spread operator")
def fileDataList = rows.row*.file_data
println(fileDataList)
Output:
Iterating using each() method
One
two
three
four
five
Iterating using Groovy for loop
One
two
three
four
five
Getting a list of necessary elements using Groovy Spread operator
[One, two, three, four, five]

Answer 2

Here is how it works:
def rows = new XmlSlurper().parseText(dbresponse)
print (rows.row[1])
print (rows.row[1].file_data)
The identifier, rows, gives a handle on the object returned when parsing dbresponse (<rows> in this case). I named it rows since this is the convention slurp'ers use; it doesn't have to be.

Answer 3

You are almost there, just trivial.
In the script you posted, it was trying to extract only first row data. That's why remaining data not shown.
Here is the script you can get all the data
def response = new XmlSlurper().parseText(dbresponse)
def data = response.'**'.findAll{it.name() =='row'}*.file_data*.text()
println data
You can quickly try it online Demo