I'm trying to implement error handling as part of the following formula, to account for cells in each range which simply don't have a value and return a "#NUM!" error:
{=SUMPRODUCT(R2:T2,U2:W2)/SUM(R2:T2)}
So far I've had some luck using IF and ISNUMBER combined (as shown below) when splitting up the main formula above, but I'm struggling when it comes to implementing it for each section/cell range. My attempt:
{=SUMPRODUCT(IF(ISNUMBER(R3:T3),R3:T3))}
Any help would be greatly appreciated!
Your original formula, without error handling, can be entered normally. It doesn't need Ctl+Shift+Enter. Nor can it produce a #NUM error because both the SUM() and SUMPRODUCT() functions interpret non-numeric values as zero. Therefore, if you get a #NUM error that error would be created by formulas in the range R2:W2. You should introduce error handling there, not in the formula we are looking at here.
The formula here - that is your first, original formula - will produce a Division by Zero error if SUM(R2:T2) equals zero. =IFERROR(SUMPRODUCT(R2:T2,U2:W2)/SUM(R2:T2),0) would return zero in case of such an error. You can modify the formula to something like =IFERROR(SUMPRODUCT(R2:T2,U2:W2)/SUM(R2:T2),"ERROR") if you prefer.
This kind of error handler would take effect also if an unhandled error is inherited from R2:W2. My recommendation is to handle errors where they occur but if you wish for a more specific error handler in the formula we are looking at here, the formula below would let imported #NUM errors pass and only handle #DIV BY ZERO errors produced by this formula.
=SUMPRODUCT(R3:T3,U3:W3)/IF(SUM(R3:T3),SUM(R3:T3),1)
This formula divides the result of the SUMPRODUCT() function by 1 if SUM(R3:T3) equals zero. This returns a result from the formula of 0 because the SUMPRODUCT part would return zero (unless it inherits a #NUM error).
Related
Had a previous question here regarding the extraction of multiple numbers from a cell. It was answered yet I encountered an issue with the xml script/ formula in Excel.
Excel extract minimum and maximum numbers when cell has multiple numbers
Currently an error appears when a natural number is entered as the lower value when typed into B2. The formula works when it is typed as a decimal (rational), 0, or as a negative (integer and rational). If a positive number is written without a decimal, the formula outputs a #SPILL! and #VALUE! errors. (#SPILL! due to outputting the lower number correctly, yet tries to dump the larger number in the cell below)
Example of Excel Error
Is there 1) A solution for this error? and 2) Any sources I can reference to better understand this XML format? Tried to research this myself but the "//s[.<//*][.*0=0]" part of the formula is really throwing me off.
Formula for extracting smaller value:
=IF(ISERROR(FILTERXML("<t><s>"&SUBSTITUTE(B10,CHAR(10),"</s><s>")&"</s></t>","//s[.<//*][.*0=0]")),"0",FILTERXML("<t><s>"&SUBSTITUTE(B10,CHAR(10),"</s><s>")&"</s></t>","//s[.<//*][.*0=0]"))
Formula for extracting larger value:
=FILTERXML("<t><s>"&SUBSTITUTE(B10,CHAR(10),"</s><s>")&"</s></t>","//s[not(.<//*)][.*0=0]")
With new functions come better answers; have a go with:
=MAX(--TEXTSPLIT(A1,{" ",",","-","
"},,1))
Hard to show on formula here but between the 1st & 2nd line is a linefeed char. If you don't know how to input that then get your cursor next to the opening quotes of the elemnt and hit ALT+Enter.
Swap out MAX() for MIN() to get the minimum value.
A source for the linked answer and FILTERXML() could potentially be this. About the error: I do to now get the error where I'd not get that beforehand. So not sure what update this function got (if any) behind the scenes but it seems to be the [.*0=0] part which would only check if node is numeric that is causing the error.
In a for-loop after 50+ iterations I get the error With Vlookup in VBA.
And when debugging:
I tried to add the CStr() in the lookup value argument, but that did not help.
Range DB in the sheet:
Is it the two leading zeros that it cannot recognize in the table?
However, I have another case where the strings begins with letters and i still get the error. It seems so random, in a loop 3/74 rows give this error. I have verified that the values do exists in the DB range (but that should not be the problem either, because when looking up something random, it does not give a rune-time error, but the result-handle from vlookup contain the error.)
Hi guys i would like to ask a very simple question,how to say "If the formula in this named range returns an error, then the value is one, else zero" in Excel?
I was thinking like "IF (A1:A200 Returns an Error, 1, 0).
I attach a screenshot so you guys could see what i am trying to do, the cells in red are the ones that contains error.
Thanks guys, your help would be very appreciated.
You can use SUMPRODUCT and ISERR (or ISERROR, see note below on the difference between these) functions. This will count the number of errors in the range:
=SUMPRODUCT(--ISERR(A1:A200))
Then, wrap it in an IF, like:
=IF(SUMPRODUCT(--ISERR(A1:A200))>0,1,0)
HERE is a good explanation of how the functions work.
NOTE: ISERR counts all errors except #N/A. If you want to also count #N/A, use the ISERROR function instead of ISERR.
Can anybody explain why this works,
=LOOKUP(1E+100,SEARCH($O$2:$O$5,J6),$O$2:$O$4)
this looks up a value in a cell from a range of cells, works as intended.
But the search(O2:O5,J6) does not work on its own?
so, SEARCH($O$2:$O$5,J6) returs #value err. I would think that this would return the position if found. If I pass in {""}, e.g. Search({"xyz","zyx","xsy"},J6) this works and makes sense but why doesn't a range work.
an explanation would be greatly appreciated.
The answer to your question is two-fold.
Firstly, most functions won't accept multiple values for a single argument. Getting them to do so requires that they be calculated as array formulas. You can force a function to do this manually by confirming it with CTRLSHIFTENTER (instead of just ENTER). You'll know it's entered as an array formula because curly braces {} will surround the formula in the formula bar. Once you've done that, go to the Formulas Tab -> Evaluate Formula to see the steps. With just the Search function, you'll probably get something like {#N/A!;#N/A!;11;#N/A!;#N/A!;}. Notice that it is an array (a list) of results from the formula, with most being errors (because the text wasn't found) and one with a proper result.
This brings us to the second part of the answer, the error-handling. Again, most functions don't handle errors well. If any part of a function errors, the whole function results in that error. You can get around this with error handling functions like ISNUMBER or IFERROR.
So now that we know that, why does LOOKUP work? Because it handles both cases as part of its built-in functionality. Lookup, as part of its built-in functionality because of the specifics of how it works, evaluates its arguments as arrays This means that if you feed it another function as an argument (like SEARCH for example), it will force that function to be evaluated as an array.. A few other functions also do this, like SUMPRODUCT and INDEX.
Secondly, LOOKUP already has built-in error handling. If there are errors within its arguments, it will return the answer closest to the first argument (but still underneath it). This is why the first argument in your provided LOOKUP function is 1E+100 which means 10^100 or basically a 1 followed by 100 zeroes. Any search result found is going to be a number smaller than that, so if it finds anything, it will return that number, because everything else will result in #N/A! and LOOKUP will ignore those errors.
I've always had trouble with this one over the years! I don't seem able to get the OR function in Excel to work.
In my model, the cell E46 should contain either a valid Postcode or the value "none". Unfortunately I have also encountered a "#value" in E46 so have written the following formula to trap this error and return "None" if encountered:
=IF(OR(E46="None",ISERROR(E46)),"None",VLOOKUP(E46, List,2,FALSE))
Trouble is, I still get #value returned by this formula when E46 contains #value even though I think I am trapping it!
All the help texts suggest I have written the formula correctly – I cannot see what I am doing wrong. Any helpful suggestions gratefully received.
You can't use OR when there might be an error in there (because the OR function will give an error in that case - from E46="None" part), try trapping the error first with nested IFs, e.g.
=IF(ISERROR(E46),"None",IF(E46="None",E46,VLOOKUP(E46, List,2,FALSE)))
You'd still get an error if E46 isn't in List......
If you have Excel 2007 or greater you can use IFERROR like
=IFERROR(IF(E46="None",E46,VLOOKUP(E46, List,2,FALSE)),"None")