I've found the following contract in a Node.js module:
module.exports = exports = nano = function database_module(cfg) {...}
I wonder what's the difference between module.exports and exports and why both are used here.
Even though question has been answered and accepted long ago, i just want to share my 2 cents:
You can imagine that at the very beginning of your file there is something like (just for explanation):
var module = new Module(...);
var exports = module.exports;
So whatever you do just keep in mind that module.exports and NOT exports will be returned from your module when you're requiring that module from somewhere else.
So when you do something like:
exports.a = function() {
console.log("a");
}
exports.b = function() {
console.log("b");
}
You are adding 2 functions a and b to the object to which module.exports points, so the typeof the returning result will be an object : { a: [Function], b: [Function] }
Of course, this is the same result you will get if you are using module.exports in this example instead of exports.
This is the case where you want your module.exports to behave like a container of exported values. Whereas, if you only want to export a constructor function then there is something you should know about using module.exports or exports;(Remember again that module.exports will be returned when you require something, not export).
module.exports = function Something() {
console.log('bla bla');
}
Now typeof returning result is 'function' and you can require it and immediately invoke like:
var x = require('./file1.js')(); because you overwrite the returning result to be a function.
However, using exports you can't use something like:
exports = function Something() {
console.log('bla bla');
}
var x = require('./file1.js')(); //Error: require is not a function
Because with exports, the reference doesn't point anymore to the object where module.exports points, so there is not a relationship between exports and module.exports anymore. In this case module.exports still points to the empty object {} which will be returned.
The accepted answer from another topic should also help:
Does JavaScript pass by reference?
Setting module.exports allows the database_module function to be called like a function when required. Simply setting exports wouldn't allow the function to be
exported because node exports the object module.exports references. The following code wouldn't allow the user to call the function.
module.js
The following won't work.
exports = nano = function database_module(cfg) {return;}
The following will work if module.exports is set.
module.exports = exports = nano = function database_module(cfg) {return;}
console
var func = require('./module.js');
// the following line will **work** with module.exports
func();
Basically node.js doesn't export the object that exports currently references, but exports the properties of what exports originally references. Although Node.js does export the object module.exports references, allowing you to call it like a function.
2nd least important reason
They set both module.exports and exports to ensure exports isn't referencing the prior exported object. By setting both you use exports as a shorthand and avoid potential bugs later on down the road.
Using exports.prop = true instead of module.exports.prop = true saves characters and avoids confusion.
Basically the answer lies in what really happens when a module is required via require statement. Assuming this is the first time the module is being required.
For example:
var x = require('file1.js');
contents of file1.js:
module.exports = '123';
When the above statement is executed, a Module object is created. Its constructor function is:
function Module(id, parent) {
this.id = id;
this.exports = {};
this.parent = parent;
if (parent && parent.children) {
parent.children.push(this);
}
this.filename = null;
this.loaded = false;
this.children = [];
}
As you see each module object has a property with name exports. This is what is eventually returned as part of require.
Next step of require is to wrap the contents of file1.js into an anonymous function like below:
(function (exports, require, module, __filename, __dirname) {
//contents from file1.js
module.exports = '123;
});
And this anonymous function is invoked the following way, module here refers to the Module Object created earlier.
(function (exports, require, module, __filename, __dirname) {
//contents from file1.js
module.exports = '123;
}) (module.exports,require, module, "path_to_file1.js","directory of the file1.js");
As we can see inside the function, exports formal argument refers to module.exports. In essence it's a convenience provided to the module programmer.
However this convenience need to be exercised with care. In any case if trying to assign a new object to exports ensure we do it this way.
exports = module.exports = {};
If we do it following way wrong way, module.exports will still be pointing to the object created as part of module instance.
exports = {};
As as result adding anything to the above exports object will have no effect to module.exports object and nothing will be exported or returned as part of require.
Initially,module.exports=exports , and the require function returns the object module.exports refers to.
if we add property to the object, say exports.a=1, then module.exports and exports still refer to the same object. So if we call require and assign the module to a variable, then the variable has a property a and its value is 1;
But if we override one of them, for example, exports=function(){}, then they are different now: exports refers to a new object and module.exports refer to the original object. And if we require the file, it will not return the new object, since module.exports is not refer to the new object.
For me, i will keep adding new property, or override both of them to a new object. Just override one is not right. And keep in mind that module.exports is the real boss.
exports and module.exports are the same unless you reassign exports within your module.
The easiest way to think about it, is to think that this line is implicitly at the top of every module.
var exports = module.exports = {};
If, within your module, you reassign exports, then you reassign it within your module and it no longer equals module.exports. This is why, if you want to export a function, you must do:
module.exports = function() { ... }
If you simply assigned your function() { ... } to exports, you would be reassigning exports to no longer point to module.exports.
If you don't want to refer to your function by module.exports every time, you can do:
module.exports = exports = function() { ... }
Notice that module.exports is the left most argument.
Attaching properties to exports is not the same since you are not reassigning it. That is why this works
exports.foo = function() { ... }
JavaScript passes objects by copy of a reference
It's a subtle difference to do with the way objects are passed by reference in JavaScript.
exports and module.exports both point to the same object. exports is a variable and module.exports is an attribute of the module object.
Say I write something like this:
exports = {a:1};
module.exports = {b:12};
exports and module.exports now point to different objects. Modifying exports no longer modifies module.exports.
When the import function inspects module.exports it gets {b:12}
I just make some test, it turns out that, inside nodejs's module code, it should something like this:
var module.exports = {};
var exports = module.exports;
so:
1:
exports = function(){}; // this will not work! as it make the exports to some other pointer
module.exports = function(){}; // it works! cause finally nodejs make the module.exports to export.
2:
exports.abc = function(){}; // works!
exports.efg = function(){}; // works!
3: but, while in this case
module.exports = function(){}; // from now on we have to using module.exports to attach more stuff to exports.
module.exports.a = 'value a'; // works
exports.b = 'value b'; // the b will nerver be seen cause of the first line of code we have do it before (or later)
To understand the differences, you have to first understand what Node.js does to every module during runtime. Node.js creates a wrapper function for every module:
(function(exports, require, module, __filename, __dirname) {
})()
Notice the first param exports is an empty object, and the third param module is an object with many properties, and one of the properties is named exports. This is what exports comes from and what module.exports comes from. The former one is a variable object, and the latter one is a property of module object.
Within the module, Node.js automatically does this thing at the beginning: module.exports = exports, and ultimately returns module.exports.
So you can see that if you reassign some value to exports, it won't have any effect to module.exports. (Simply because exports points to another new object, but module.exports still holds the old exports)
let exports = {};
const module = {};
module.exports = exports;
exports = { a: 1 }
console.log(module.exports) // {}
But if you updates properties of exports, it will surely have effect on module.exports. Because they both point to the same object.
let exports = {};
const module = {};
module.exports = exports;
exports.a = 1;
module.exports.b = 2;
console.log(module.exports) // { a: 1, b: 2 }
Also notice that if you reassign another value to module.exports, then it seems meaningless for exports updates. Every updates on exports is ignored because module.exports points to another object.
let exports = {};
const module = {};
module.exports = exports;
exports.a = 1;
module.exports = {
hello: () => console.log('hello')
}
console.log(module.exports) // { hello: () => console.log('hello')}
Here is a good description written about node modules in node.js in action book from Manning publication.
What ultimately gets exported in your application is module.exports. exports is set
up simply as a global reference to module.exports , which initially is defined as an
empty object that you can add properties to. So exports.myFunc is just shorthand
for module.exports.myFunc.
As a result, if exports is set to anything else, it breaks the reference between
module.exports and exports . Because module.exports is what really gets
exported, exports will no longer work as expected—it doesn’t reference module
.exports anymore. If you want to maintain that link, you can make module.exports
reference exports again as follows:
module.exports = exports = db;
I went through some tests and I think this may shed some light on the subject...
app.js:
var ...
, routes = require('./routes')
...;
...
console.log('#routes', routes);
...
versions of /routes/index.js:
exports = function fn(){}; // outputs "#routes {}"
exports.fn = function fn(){}; // outputs "#routes { fn: [Function: fn] }"
module.exports = function fn(){}; // outputs "#routes function fn(){}"
module.exports.fn = function fn(){}; // outputs "#routes { fn: [Function: fn] }"
I even added new files:
./routes/index.js:
module.exports = require('./not-index.js');
module.exports = require('./user.js');
./routes/not-index.js:
exports = function fn(){};
./routes/user.js:
exports = function user(){};
We get the output "#routes {}"
./routes/index.js:
module.exports.fn = require('./not-index.js');
module.exports.user = require('./user.js');
./routes/not-index.js:
exports = function fn(){};
./routes/user.js:
exports = function user(){};
We get the output "#routes { fn: {}, user: {} }"
./routes/index.js:
module.exports.fn = require('./not-index.js');
module.exports.user = require('./user.js');
./routes/not-index.js:
exports.fn = function fn(){};
./routes/user.js:
exports.user = function user(){};
We get the output "#routes { user: [Function: user] }"
If we change user.js to { ThisLoadedLast: [Function: ThisLoadedLast] }, we get the output "#routes { ThisLoadedLast: [Function: ThisLoadedLast] }".
But if we modify ./routes/index.js...
./routes/index.js:
module.exports.fn = require('./not-index.js');
module.exports.ThisLoadedLast = require('./user.js');
./routes/not-index.js:
exports.fn = function fn(){};
./routes/user.js:
exports.ThisLoadedLast = function ThisLoadedLast(){};
... we get "#routes { fn: { fn: [Function: fn] }, ThisLoadedLast: { ThisLoadedLast: [Function: ThisLoadedLast] } }"
So I would suggest always use module.exports in your module definitions.
I don't completely understand what's going on internally with Node, but please comment if you can make more sense of this as I'm sure it helps.
-- Happy coding
This shows how require() works in its simplest form, excerpted from Eloquent JavaScript
Problem
It is not possible for a module to directly export a value other than the exports object, such as a function. For example, a module might want to export only the constructor of the object type it defines. Right now, it cannot do that because require always uses the exports object it creates as the exported value.
Solution
Provide modules with another variable, module, which is an object that has a property exports. This property initially points at the empty object created by require but can be overwritten with another value in order to export something else.
function require(name) {
if (name in require.cache)
return require.cache[name];
var code = new Function("exports, module", readFile(name));
var exports = {}, module = {exports: exports};
code(exports, module);
require.cache[name] = module.exports;
return module.exports;
}
require.cache = Object.create(null);
Here is the result of
console.log("module:");
console.log(module);
console.log("exports:");
console.log(exports);
console.log("module.exports:");
console.log(module.exports);
Also:
if(module.exports === exports){
console.log("YES");
}else{
console.log("NO");
}
//YES
Note:
The CommonJS specification only allows the use of the exports variable to expose public members. Therefore, the named exports pattern is the only one that is really compatible with the CommonJS specification. The use of module.exports is an extension provided by Node.js to support a broader range of module definition patterns.
var a = {},md={};
//Firstly,the exports and module.exports point the same empty Object
exp = a;//exports =a;
md.exp = a;//module.exports = a;
exp.attr = "change";
console.log(md.exp);//{attr:"change"}
//If you point exp to other object instead of point it's property to other object. The md.exp will be empty Object {}
var a ={},md={};
exp =a;
md.exp =a;
exp = function(){ console.log('Do nothing...'); };
console.log(md.exp); //{}
From the docs
The exports variable is available within a module's file-level scope, and is assigned the value of module.exports before the module is evaluated.
It allows a shortcut, so that module.exports.f = ... can be written more succinctly as exports.f = .... However, be aware that like any variable, if a new value is assigned to exports, it is no longer bound to module.exports:
It is just a variable pointing to module.exports.
I found this link useful to answer the above question.
http://timnew.me/blog/2012/04/20/exports-vs-module-exports-in-node-js/
To add to the other posts The module system in node does
var exports = module.exports
before executing your code. So when you want to exports = foo , you probably want to do module.exports = exports = foo but using exports.foo = foo should be fine
"If you want the root of your module's export to be a function (such as a constructor) or if you want to export a complete object in one assignment instead of building it one property at a time, assign it to module.exports instead of exports." - http://nodejs.org/api/modules.html
Let's create one module with 2 ways:
One way
var aa = {
a: () => {return 'a'},
b: () => {return 'b'}
}
module.exports = aa;
Second way
exports.a = () => {return 'a';}
exports.b = () => {return 'b';}
And this is how require() will integrate module.
First way:
function require(){
module.exports = {};
var exports = module.exports;
var aa = {
a: () => {return 'a'},
b: () => {return 'b'}
}
module.exports = aa;
return module.exports;
}
Second way
function require(){
module.exports = {};
var exports = module.exports;
exports.a = () => {return 'a';}
exports.b = () => {return 'b';}
return module.exports;
}
module.exports and exports both point to the same object before the module is evaluated.
Any property you add to the module.exports object will be available when your module is used in another module using require statement. exports is a shortcut made available for the same thing. For instance:
module.exports.add = (a, b) => a+b
is equivalent to writing:
exports.add = (a, b) => a+b
So it is okay as long as you do not assign a new value to exports variable. When you do something like this:
exports = (a, b) => a+b
as you are assigning a new value to exports it no longer has reference to the exported object and thus will remain local to your module.
If you are planning to assign a new value to module.exports rather than adding new properties to the initial object made available, you should probably consider doing as given below:
module.exports = exports = (a, b) => a+b
Node.js website has a very good explanation of this.
1.exports -> use as singleton utility
2. module-exports -> use as logical objects such as service , model etc
why both are used here
I believe they just want to be clear that module.exports, exports, and nano point to the same function - allowing you to use either variable to call the function within the file. nano provides some context to what the function does.
exports won't be exported (only module.exports will), so why bother overwriting that as well?
The verbosity trade-off limits the risk of future bugs, such as using exports instead of module.exports within the file. It also provides clarification that module.exports and exports are in fact pointing to the same value.
module.exports vs exports
As long as you don't reassign module.exports or exports (and instead add values to the object they both refer to), you won't have any issues and can safely use exports to be more concise.
When assigning either to a non-object, they are now pointing to different places which can be confusing unless you intentionally want module.exports to be something specific (such as a function).
Setting exports to a non-object doesn't make much sense as you'll have to set module.exports = exports at the end to be able to use it in other files.
let module = { exports: {} };
let exports = module.exports;
exports.msg = 'hi';
console.log(module.exports === exports); // true
exports = 'yo';
console.log(module.exports === exports); // false
exports = module.exports;
console.log(module.exports === exports); // true
module.exports = 'hello';
console.log(module.exports === exports); // false
module.exports = exports;
console.log(module.exports === exports); // true
Why assign module.exports to a function?
More concise! Compare how much shorter the 2nd example is:
helloWorld1.js: module.exports.hello = () => console.log('hello world');
app1.js: let sayHello = require('./helloWorld1'); sayHello.hello; // hello world
helloWorld2.js: module.exports = () => console.log('hello world');
app2.js: let sayHello = require('./helloWorld2'); sayHello; // hello world
Each file you create is a module. module is an object. It has property called exports : {} which is empty object by default.
you can create functions/middlewares and add to this empty exports object such as exports.findById() => { ... } then require anywhere in your app and use...
controllers/user.js
exports.findById = () => {
// do something
}
require in routes.js to use:
const {findyId} = './controllers/user'
in node js module.js file is use to run the module.load system.every time when node execute a file it wrap your js file content as follow
'(function (exports, require, module, __filename, __dirname) {',+
//your js file content
'\n});'
because of this wrapping inside ur js source code you can access exports,require,module,etc..
this approach is used because there is no other way to get functionalities wrote in on js file to another.
then node execute this wrapped function using c++. at that moment exports object that passed into this function will be filled.
you can see inside this function parameters exports and module.
actually exports is a public member of module constructor function.
look at following code
copy this code into b.js
console.log("module is "+Object.prototype.toString.call(module));
console.log("object.keys "+Object.keys(module));
console.log(module.exports);
console.log(exports === module.exports);
console.log("exports is "+Object.prototype.toString.call(exports));
console.log('----------------------------------------------');
var foo = require('a.js');
console.log("object.keys of foo: "+Object.keys(foo));
console.log('name is '+ foo);
foo();
copy this code to a.js
exports.name = 'hello';
module.exports.name = 'hi';
module.exports.age = 23;
module.exports = function(){console.log('function to module exports')};
//exports = function(){console.log('function to export');}
now run using node
this is the output
module is [object Object]
object.keys id,exports,parent,filename,loaded,children,paths
{}
true
exports is [object Object]
object.keys of foo:
name is function (){console.log('function to module exports')}
function to module exports
now remove the commented line in a.js and comment the line above that line
and remove the last line of b.js and run.
in javascript world you cannot reassign object that passed as parameter but you can change function's public member when object of that function set as a parameter to another function
do remember
use module.exports on and only if you wants to get a function when you use require keyword .
in above example we var foo = require(a.js); you can see we can call foo as a function;
this is how node documentation explain it
"The exports object is created by the Module system. Sometimes this is not acceptable, many want their module to be an instance of some class. To do this assign the desired export object to module.exports."
Both module.exports and exports point to the same function database_module(cfg) {...}.
1| var a, b;
2| a = b = function() { console.log("Old"); };
3| b = function() { console.log("New"); };
4|
5| a(); // "Old"
6| b(); // "New"
You can change b on line 3 to a, the output is reverse. The conclusion is:
a and b are independent.
So module.exports = exports = nano = function database_module(cfg) {...} is equivalent to:
var f = function database_module(cfg) {...};
module.exports = f;
exports = f;
Assumed the above is module.js, which is required by foo.js. The benefits of module.exports = exports = nano = function database_module(cfg) {...} is clear now:
In foo.js, since module.exports is require('./module.js'):
var output = require('./modules.js')();
In moduls.js: You can use exports instead of module.exports.
So, you will be happy if both exports and module.exports pointing to the same thing.
exports: it's a reference to module.exports object
both exports and module.exports point to the same object
until we change the reference of exports object
Example:
if exports.a = 10 then module.exports.a = 10
if we reassign exports object explicitly inside the code like
exports = {} now its lost the reference to module.exports
How do I require all files in a folder in node.js?
need something like:
files.forEach(function (v,k){
// require routes
require('./routes/'+v);
}};
When require is given the path of a folder, it'll look for an index.js file in that folder; if there is one, it uses that, and if there isn't, it fails.
It would probably make most sense (if you have control over the folder) to create an index.js file and then assign all the "modules" and then simply require that.
yourfile.js
var routes = require("./routes");
index.js
exports.something = require("./routes/something.js");
exports.others = require("./routes/others.js");
If you don't know the filenames you should write some kind of loader.
Working example of a loader:
var normalizedPath = require("path").join(__dirname, "routes");
require("fs").readdirSync(normalizedPath).forEach(function(file) {
require("./routes/" + file);
});
// Continue application logic here
I recommend using glob to accomplish that task.
var glob = require( 'glob' )
, path = require( 'path' );
glob.sync( './routes/**/*.js' ).forEach( function( file ) {
require( path.resolve( file ) );
});
Base on #tbranyen's solution, I create an index.js file that load arbitrary javascripts under current folder as part of the exports.
// Load `*.js` under current directory as properties
// i.e., `User.js` will become `exports['User']` or `exports.User`
require('fs').readdirSync(__dirname + '/').forEach(function(file) {
if (file.match(/\.js$/) !== null && file !== 'index.js') {
var name = file.replace('.js', '');
exports[name] = require('./' + file);
}
});
Then you can require this directory from any where else.
Another option is to use the package require-dir which let's you do the following. It supports recursion as well.
var requireDir = require('require-dir');
var dir = requireDir('./path/to/dir');
I have a folder /fields full of files with a single class each, ex:
fields/Text.js -> Test class
fields/Checkbox.js -> Checkbox class
Drop this in fields/index.js to export each class:
var collectExports, fs, path,
__hasProp = {}.hasOwnProperty;
fs = require('fs');
path = require('path');
collectExports = function(file) {
var func, include, _results;
if (path.extname(file) === '.js' && file !== 'index.js') {
include = require('./' + file);
_results = [];
for (func in include) {
if (!__hasProp.call(include, func)) continue;
_results.push(exports[func] = include[func]);
}
return _results;
}
};
fs.readdirSync('./fields/').forEach(collectExports);
This makes the modules act more like they would in Python:
var text = new Fields.Text()
var checkbox = new Fields.Checkbox()
One more option is require-dir-all combining features from most popular packages.
Most popular require-dir does not have options to filter the files/dirs and does not have map function (see below), but uses small trick to find module's current path.
Second by popularity require-all has regexp filtering and preprocessing, but lacks relative path, so you need to use __dirname (this has pros and contras) like:
var libs = require('require-all')(__dirname + '/lib');
Mentioned here require-index is quite minimalistic.
With map you may do some preprocessing, like create objects and pass config values (assuming modules below exports constructors):
// Store config for each module in config object properties
// with property names corresponding to module names
var config = {
module1: { value: 'config1' },
module2: { value: 'config2' }
};
// Require all files in modules subdirectory
var modules = require('require-dir-all')(
'modules', // Directory to require
{ // Options
// function to be post-processed over exported object for each require'd module
map: function(reqModule) {
// create new object with corresponding config passed to constructor
reqModule.exports = new reqModule.exports( config[reqModule.name] );
}
}
);
// Now `modules` object holds not exported constructors,
// but objects constructed using values provided in `config`.
I know this question is 5+ years old, and the given answers are good, but I wanted something a bit more powerful for express, so i created the express-map2 package for npm. I was going to name it simply express-map, however the people at yahoo already have a package with that name, so i had to rename my package.
1. basic usage:
app.js (or whatever you call it)
var app = require('express'); // 1. include express
app.set('controllers',__dirname+'/controllers/');// 2. set path to your controllers.
require('express-map2')(app); // 3. patch map() into express
app.map({
'GET /':'test',
'GET /foo':'middleware.foo,test',
'GET /bar':'middleware.bar,test'// seperate your handlers with a comma.
});
controller usage:
//single function
module.exports = function(req,res){
};
//export an object with multiple functions.
module.exports = {
foo: function(req,res){
},
bar: function(req,res){
}
};
2. advanced usage, with prefixes:
app.map('/api/v1/books',{
'GET /': 'books.list', // GET /api/v1/books
'GET /:id': 'books.loadOne', // GET /api/v1/books/5
'DELETE /:id': 'books.delete', // DELETE /api/v1/books/5
'PUT /:id': 'books.update', // PUT /api/v1/books/5
'POST /': 'books.create' // POST /api/v1/books
});
As you can see, this saves a ton of time and makes the routing of your application dead simple to write, maintain, and understand. it supports all of the http verbs that express supports, as well as the special .all() method.
npm package: https://www.npmjs.com/package/express-map2
github repo: https://github.com/r3wt/express-map
Expanding on this glob solution. Do this if you want to import all modules from a directory into index.js and then import that index.js in another part of the application. Note that template literals aren't supported by the highlighting engine used by stackoverflow so the code might look strange here.
const glob = require("glob");
let allOfThem = {};
glob.sync(`${__dirname}/*.js`).forEach((file) => {
/* see note about this in example below */
allOfThem = { ...allOfThem, ...require(file) };
});
module.exports = allOfThem;
Full Example
Directory structure
globExample/example.js
globExample/foobars/index.js
globExample/foobars/unexpected.js
globExample/foobars/barit.js
globExample/foobars/fooit.js
globExample/example.js
const { foo, bar, keepit } = require('./foobars/index');
const longStyle = require('./foobars/index');
console.log(foo()); // foo ran
console.log(bar()); // bar ran
console.log(keepit()); // keepit ran unexpected
console.log(longStyle.foo()); // foo ran
console.log(longStyle.bar()); // bar ran
console.log(longStyle.keepit()); // keepit ran unexpected
globExample/foobars/index.js
const glob = require("glob");
/*
Note the following style also works with multiple exports per file (barit.js example)
but will overwrite if you have 2 exports with the same
name (unexpected.js and barit.js have a keepit function) in the files being imported. As a result, this method is best used when
your exporting one module per file and use the filename to easily identify what is in it.
Also Note: This ignores itself (index.js) by default to prevent infinite loop.
*/
let allOfThem = {};
glob.sync(`${__dirname}/*.js`).forEach((file) => {
allOfThem = { ...allOfThem, ...require(file) };
});
module.exports = allOfThem;
globExample/foobars/unexpected.js
exports.keepit = () => 'keepit ran unexpected';
globExample/foobars/barit.js
exports.bar = () => 'bar run';
exports.keepit = () => 'keepit ran';
globExample/foobars/fooit.js
exports.foo = () => 'foo ran';
From inside project with glob installed, run node example.js
$ node example.js
foo ran
bar run
keepit ran unexpected
foo ran
bar run
keepit ran unexpected
One module that I have been using for this exact use case is require-all.
It recursively requires all files in a given directory and its sub directories as long they don't match the excludeDirs property.
It also allows specifying a file filter and how to derive the keys of the returned hash from the filenames.
Require all files from routes folder and apply as middleware. No external modules needed.
// require
const { readdirSync } = require("fs");
// apply as middleware
readdirSync("./routes").map((r) => app.use("/api", require("./routes/" + r)));
I'm using node modules copy-to module to create a single file to require all the files in our NodeJS-based system.
The code for our utility file looks like this:
/**
* Module dependencies.
*/
var copy = require('copy-to');
copy(require('./module1'))
.and(require('./module2'))
.and(require('./module3'))
.to(module.exports);
In all of the files, most functions are written as exports, like so:
exports.function1 = function () { // function contents };
exports.function2 = function () { // function contents };
exports.function3 = function () { // function contents };
So, then to use any function from a file, you just call:
var utility = require('./utility');
var response = utility.function2(); // or whatever the name of the function is
Can use : https://www.npmjs.com/package/require-file-directory
Require selected files with name only or all files.
No need of absoulute path.
Easy to understand and use.
Using this function you can require a whole dir.
const GetAllModules = ( dirname ) => {
if ( dirname ) {
let dirItems = require( "fs" ).readdirSync( dirname );
return dirItems.reduce( ( acc, value, index ) => {
if ( PATH.extname( value ) == ".js" && value.toLowerCase() != "index.js" ) {
let moduleName = value.replace( /.js/g, '' );
acc[ moduleName ] = require( `${dirname}/${moduleName}` );
}
return acc;
}, {} );
}
}
// calling this function.
let dirModules = GetAllModules(__dirname);
Create an index.js file in your folder with this code :
const fs = require('fs')
const files = fs.readdirSync('./routes')
for (const file of files) {
require('./'+file)
}
And after that you can simply load all the folder with require("./routes")
If you include all files of *.js in directory example ("app/lib/*.js"):
In directory app/lib
example.js:
module.exports = function (example) { }
example-2.js:
module.exports = function (example2) { }
In directory app create index.js
index.js:
module.exports = require('./app/lib');