How can I use an operator to compose functions? - python-3.x

It's fairly straightforward to write a function that composes two other functions. (For simplicity, assume they are one parameter each.)
def compose(f, g):
fg = lambda x: f(g(x))
return fg
def add1(x):
return x + 1
def add2(x):
return x + 2
print(compose(add1, add2)(5)) # => 8
I would like to do composition using an operator, e.g., (add1 . add2)(5).
Is there a way to do that?
I tried various decorator formulations, but I couldn't get any of them to work.
def composable(f):
"""
Nothing I tried worked. I won't clutter up the question
with my failed attempts.
"""
#composable
def add1(x):
return x + 1

First only a certain amount of operator symbols are allowed in Python syntax. Dot "." is not a valid operator.
This page (the page is actually about the Python operator module, but the naming convention are the same to datamodel and the content is more organized) listed all available operators and the corresponding instance methods. For example, if you want to use "#" as the operator, you can write a decorator like this:
import functools
class Composable:
def __init__(self, func):
self.func = func
functools.update_wrapper(self, func)
def __matmul__(self, other):
return lambda *args, **kw: self.func(other.func(*args, **kw))
def __call__(self, *args, **kw):
return self.func(*args, **kw)
To test:
#Composable
def add1(x):
return x + 1
#Composable
def add2(x):
return x + 2
print((add1 # add2)(5))
# 8

Related

Operator overloading with python outside a class

class A:
def __init__(self,m1,m2):
self.m1 = m1
self.m2 = m2
def __add__(self, other):
''' add takes 2 objects basically objects on RHS and LHS of + say a + b '''
print("Inside add")
s3 = A(self.m1+other.m1,self.m2+other.m2)
return s3
def disp(self):
print('{} {}'.format(self.m1,self.m2))
def __str__(self):
return '{} {}'.format(self.m1,self.m2)
def __add__(self,other):
return self*other
a = 2+5
print(a)
Output seen is: 7
Whereas expected is 10 since I am trying to overwrite the implicit add function with multiply operation.
What happens here?
Does operator overloading works only with pytclass?
class A:
def __init__(self,m):
self.m=m
def __str__(self):
return str(self.m)
#multiply two objects
def __mul__(self,other):
t=self.m*other.m
return A(t)
#add two objects
def __add__(self,other):
t=self.m+other.m
return A(t)
obj1=A(2)
obj2=A(5)
#calling operator overloading of '*'
print(obj1*obj2)
#calling operator overloading of '+'
print(obj1+obj2)

Redefining a function for a different type [duplicate]

I know that Python does not support method overloading, but I've run into a problem that I can't seem to solve in a nice Pythonic way.
I am making a game where a character needs to shoot a variety of bullets, but how do I write different functions for creating these bullets? For example suppose I have a function that creates a bullet travelling from point A to B with a given speed. I would write a function like this:
def add_bullet(sprite, start, headto, speed):
# Code ...
But I want to write other functions for creating bullets like:
def add_bullet(sprite, start, direction, speed):
def add_bullet(sprite, start, headto, spead, acceleration):
def add_bullet(sprite, script): # For bullets that are controlled by a script
def add_bullet(sprite, curve, speed): # for bullets with curved paths
# And so on ...
And so on with many variations. Is there a better way to do it without using so many keyword arguments cause its getting kinda ugly fast. Renaming each function is pretty bad too because you get either add_bullet1, add_bullet2, or add_bullet_with_really_long_name.
To address some answers:
No I can't create a Bullet class hierarchy because thats too slow. The actual code for managing bullets is in C and my functions are wrappers around C API.
I know about the keyword arguments but checking for all sorts of combinations of parameters is getting annoying, but default arguments help allot like acceleration=0
What you are asking for is called multiple dispatch. See Julia language examples which demonstrates different types of dispatches.
However, before looking at that, we'll first tackle why overloading is not really what you want in Python.
Why Not Overloading?
First, one needs to understand the concept of overloading and why it's not applicable to Python.
When working with languages that can discriminate data types at
compile-time, selecting among the alternatives can occur at
compile-time. The act of creating such alternative functions for
compile-time selection is usually referred to as overloading a
function. (Wikipedia)
Python is a dynamically typed language, so the concept of overloading simply does not apply to it. However, all is not lost, since we can create such alternative functions at run-time:
In programming languages that defer data type identification until
run-time the selection among alternative
functions must occur at run-time, based on the dynamically determined
types of function arguments. Functions whose alternative
implementations are selected in this manner are referred to most
generally as multimethods. (Wikipedia)
So we should be able to do multimethods in Python—or, as it is alternatively called: multiple dispatch.
Multiple dispatch
The multimethods are also called multiple dispatch:
Multiple dispatch or multimethods is the feature of some
object-oriented programming languages in which a function or method
can be dynamically dispatched based on the run time (dynamic) type of
more than one of its arguments. (Wikipedia)
Python does not support this out of the box1, but, as it happens, there is an excellent Python package called multipledispatch that does exactly that.
Solution
Here is how we might use multipledispatch2 package to implement your methods:
>>> from multipledispatch import dispatch
>>> from collections import namedtuple
>>> from types import * # we can test for lambda type, e.g.:
>>> type(lambda a: 1) == LambdaType
True
>>> Sprite = namedtuple('Sprite', ['name'])
>>> Point = namedtuple('Point', ['x', 'y'])
>>> Curve = namedtuple('Curve', ['x', 'y', 'z'])
>>> Vector = namedtuple('Vector', ['x','y','z'])
>>> #dispatch(Sprite, Point, Vector, int)
... def add_bullet(sprite, start, direction, speed):
... print("Called Version 1")
...
>>> #dispatch(Sprite, Point, Point, int, float)
... def add_bullet(sprite, start, headto, speed, acceleration):
... print("Called version 2")
...
>>> #dispatch(Sprite, LambdaType)
... def add_bullet(sprite, script):
... print("Called version 3")
...
>>> #dispatch(Sprite, Curve, int)
... def add_bullet(sprite, curve, speed):
... print("Called version 4")
...
>>> sprite = Sprite('Turtle')
>>> start = Point(1,2)
>>> direction = Vector(1,1,1)
>>> speed = 100 #km/h
>>> acceleration = 5.0 #m/s**2
>>> script = lambda sprite: sprite.x * 2
>>> curve = Curve(3, 1, 4)
>>> headto = Point(100, 100) # somewhere far away
>>> add_bullet(sprite, start, direction, speed)
Called Version 1
>>> add_bullet(sprite, start, headto, speed, acceleration)
Called version 2
>>> add_bullet(sprite, script)
Called version 3
>>> add_bullet(sprite, curve, speed)
Called version 4
1. Python 3 currently supports single dispatch
2. Take care not to use multipledispatch in a multi-threaded environment or you will get weird behavior.
Python does support "method overloading" as you present it. In fact, what you just describe is trivial to implement in Python, in so many different ways, but I would go with:
class Character(object):
# your character __init__ and other methods go here
def add_bullet(self, sprite=default, start=default,
direction=default, speed=default, accel=default,
curve=default):
# do stuff with your arguments
In the above code, default is a plausible default value for those arguments, or None. You can then call the method with only the arguments you are interested in, and Python will use the default values.
You could also do something like this:
class Character(object):
# your character __init__ and other methods go here
def add_bullet(self, **kwargs):
# here you can unpack kwargs as (key, values) and
# do stuff with them, and use some global dictionary
# to provide default values and ensure that ``key``
# is a valid argument...
# do stuff with your arguments
Another alternative is to directly hook the desired function directly to the class or instance:
def some_implementation(self, arg1, arg2, arg3):
# implementation
my_class.add_bullet = some_implementation_of_add_bullet
Yet another way is to use an abstract factory pattern:
class Character(object):
def __init__(self, bfactory, *args, **kwargs):
self.bfactory = bfactory
def add_bullet(self):
sprite = self.bfactory.sprite()
speed = self.bfactory.speed()
# do stuff with your sprite and speed
class pretty_and_fast_factory(object):
def sprite(self):
return pretty_sprite
def speed(self):
return 10000000000.0
my_character = Character(pretty_and_fast_factory(), a1, a2, kw1=v1, kw2=v2)
my_character.add_bullet() # uses pretty_and_fast_factory
# now, if you have another factory called "ugly_and_slow_factory"
# you can change it at runtime in python by issuing
my_character.bfactory = ugly_and_slow_factory()
# In the last example you can see abstract factory and "method
# overloading" (as you call it) in action
You can use "roll-your-own" solution for function overloading. This one is copied from Guido van Rossum's article about multimethods (because there is little difference between multimethods and overloading in Python):
registry = {}
class MultiMethod(object):
def __init__(self, name):
self.name = name
self.typemap = {}
def __call__(self, *args):
types = tuple(arg.__class__ for arg in args) # a generator expression!
function = self.typemap.get(types)
if function is None:
raise TypeError("no match")
return function(*args)
def register(self, types, function):
if types in self.typemap:
raise TypeError("duplicate registration")
self.typemap[types] = function
def multimethod(*types):
def register(function):
name = function.__name__
mm = registry.get(name)
if mm is None:
mm = registry[name] = MultiMethod(name)
mm.register(types, function)
return mm
return register
The usage would be
from multimethods import multimethod
import unittest
# 'overload' makes more sense in this case
overload = multimethod
class Sprite(object):
pass
class Point(object):
pass
class Curve(object):
pass
#overload(Sprite, Point, Direction, int)
def add_bullet(sprite, start, direction, speed):
# ...
#overload(Sprite, Point, Point, int, int)
def add_bullet(sprite, start, headto, speed, acceleration):
# ...
#overload(Sprite, str)
def add_bullet(sprite, script):
# ...
#overload(Sprite, Curve, speed)
def add_bullet(sprite, curve, speed):
# ...
Most restrictive limitations at the moment are:
methods are not supported, only functions that are not class members;
inheritance is not handled;
kwargs are not supported;
registering new functions should be done at import time thing is not thread-safe
A possible option is to use the multipledispatch module as detailed here:
http://matthewrocklin.com/blog/work/2014/02/25/Multiple-Dispatch
Instead of doing this:
def add(self, other):
if isinstance(other, Foo):
...
elif isinstance(other, Bar):
...
else:
raise NotImplementedError()
You can do this:
from multipledispatch import dispatch
#dispatch(int, int)
def add(x, y):
return x + y
#dispatch(object, object)
def add(x, y):
return "%s + %s" % (x, y)
With the resulting usage:
>>> add(1, 2)
3
>>> add(1, 'hello')
'1 + hello'
In Python 3.4 PEP-0443. Single-dispatch generic functions was added.
Here is a short API description from PEP.
To define a generic function, decorate it with the #singledispatch decorator. Note that the dispatch happens on the type of the first argument. Create your function accordingly:
from functools import singledispatch
#singledispatch
def fun(arg, verbose=False):
if verbose:
print("Let me just say,", end=" ")
print(arg)
To add overloaded implementations to the function, use the register() attribute of the generic function. This is a decorator, taking a type parameter and decorating a function implementing the operation for that type:
#fun.register(int)
def _(arg, verbose=False):
if verbose:
print("Strength in numbers, eh?", end=" ")
print(arg)
#fun.register(list)
def _(arg, verbose=False):
if verbose:
print("Enumerate this:")
for i, elem in enumerate(arg):
print(i, elem)
The #overload decorator was added with type hints (PEP 484).
While this doesn't change the behaviour of Python, it does make it easier to understand what is going on, and for mypy to detect errors.
See: Type hints and PEP 484
This type of behaviour is typically solved (in OOP languages) using polymorphism. Each type of bullet would be responsible for knowing how it travels. For instance:
class Bullet(object):
def __init__(self):
self.curve = None
self.speed = None
self.acceleration = None
self.sprite_image = None
class RegularBullet(Bullet):
def __init__(self):
super(RegularBullet, self).__init__()
self.speed = 10
class Grenade(Bullet):
def __init__(self):
super(Grenade, self).__init__()
self.speed = 4
self.curve = 3.5
add_bullet(Grendade())
def add_bullet(bullet):
c_function(bullet.speed, bullet.curve, bullet.acceleration, bullet.sprite, bullet.x, bullet.y)
void c_function(double speed, double curve, double accel, char[] sprite, ...) {
if (speed != null && ...) regular_bullet(...)
else if (...) curved_bullet(...)
//..etc..
}
Pass as many arguments to the c_function that exist, and then do the job of determining which c function to call based on the values in the initial c function. So, Python should only ever be calling the one c function. That one c function looks at the arguments, and then can delegate to other c functions appropriately.
You're essentially just using each subclass as a different data container, but by defining all the potential arguments on the base class, the subclasses are free to ignore the ones they do nothing with.
When a new type of bullet comes along, you can simply define one more property on the base, change the one python function so that it passes the extra property, and the one c_function that examines the arguments and delegates appropriately. It doesn't sound too bad I guess.
It is impossible by definition to overload a function in python (read on for details), but you can achieve something similar with a simple decorator
class overload:
def __init__(self, f):
self.cases = {}
def args(self, *args):
def store_function(f):
self.cases[tuple(args)] = f
return self
return store_function
def __call__(self, *args):
function = self.cases[tuple(type(arg) for arg in args)]
return function(*args)
You can use it like this
#overload
def f():
pass
#f.args(int, int)
def f(x, y):
print('two integers')
#f.args(float)
def f(x):
print('one float')
f(5.5)
f(1, 2)
Modify it to adapt it to your use case.
A clarification of concepts
function dispatch: there are multiple functions with the same name. Which one should be called? two strategies
static/compile-time dispatch (aka. "overloading"). decide which function to call based on the compile-time type of the arguments. In all dynamic languages, there is no compile-time type, so overloading is impossible by definition
dynamic/run-time dispatch: decide which function to call based on the runtime type of the arguments. This is what all OOP languages do: multiple classes have the same methods, and the language decides which one to call based on the type of self/this argument. However, most languages only do it for the this argument only. The above decorator extends the idea to multiple parameters.
To clear up, assume that we define, in a hypothetical static language, the functions
void f(Integer x):
print('integer called')
void f(Float x):
print('float called')
void f(Number x):
print('number called')
Number x = new Integer('5')
f(x)
x = new Number('3.14')
f(x)
With static dispatch (overloading) you will see "number called" twice, because x has been declared as Number, and that's all overloading cares about. With dynamic dispatch you will see "integer called, float called", because those are the actual types of x at the time the function is called.
By passing keyword args.
def add_bullet(**kwargs):
#check for the arguments listed above and do the proper things
Python 3.8 added functools.singledispatchmethod
Transform a method into a single-dispatch generic function.
To define a generic method, decorate it with the #singledispatchmethod
decorator. Note that the dispatch happens on the type of the first
non-self or non-cls argument, create your function accordingly:
from functools import singledispatchmethod
class Negator:
#singledispatchmethod
def neg(self, arg):
raise NotImplementedError("Cannot negate a")
#neg.register
def _(self, arg: int):
return -arg
#neg.register
def _(self, arg: bool):
return not arg
negator = Negator()
for v in [42, True, "Overloading"]:
neg = negator.neg(v)
print(f"{v=}, {neg=}")
Output
v=42, neg=-42
v=True, neg=False
NotImplementedError: Cannot negate a
#singledispatchmethod supports nesting with other decorators such as
#classmethod. Note that to allow for dispatcher.register,
singledispatchmethod must be the outer most decorator. Here is the
Negator class with the neg methods being class bound:
from functools import singledispatchmethod
class Negator:
#singledispatchmethod
#staticmethod
def neg(arg):
raise NotImplementedError("Cannot negate a")
#neg.register
def _(arg: int) -> int:
return -arg
#neg.register
def _(arg: bool) -> bool:
return not arg
for v in [42, True, "Overloading"]:
neg = Negator.neg(v)
print(f"{v=}, {neg=}")
Output:
v=42, neg=-42
v=True, neg=False
NotImplementedError: Cannot negate a
The same pattern can be used for other similar decorators:
staticmethod, abstractmethod, and others.
I think your basic requirement is to have a C/C++-like syntax in Python with the least headache possible. Although I liked Alexander Poluektov's answer it doesn't work for classes.
The following should work for classes. It works by distinguishing by the number of non-keyword arguments (but it doesn't support distinguishing by type):
class TestOverloading(object):
def overloaded_function(self, *args, **kwargs):
# Call the function that has the same number of non-keyword arguments.
getattr(self, "_overloaded_function_impl_" + str(len(args)))(*args, **kwargs)
def _overloaded_function_impl_3(self, sprite, start, direction, **kwargs):
print "This is overload 3"
print "Sprite: %s" % str(sprite)
print "Start: %s" % str(start)
print "Direction: %s" % str(direction)
def _overloaded_function_impl_2(self, sprite, script):
print "This is overload 2"
print "Sprite: %s" % str(sprite)
print "Script: "
print script
And it can be used simply like this:
test = TestOverloading()
test.overloaded_function("I'm a Sprite", 0, "Right")
print
test.overloaded_function("I'm another Sprite", "while x == True: print 'hi'")
Output:
This is overload 3
Sprite: I'm a Sprite
Start: 0
Direction: Right
This is overload 2
Sprite: I'm another Sprite
Script:
while x == True: print 'hi'
You can achieve this with the following Python code:
#overload
def test(message: str):
return message
#overload
def test(number: int):
return number + 1
Either use multiple keyword arguments in the definition, or create a Bullet hierarchy whose instances are passed to the function.
I think a Bullet class hierarchy with the associated polymorphism is the way to go. You can effectively overload the base class constructor by using a metaclass so that calling the base class results in the creation of the appropriate subclass object. Below is some sample code to illustrate the essence of what I mean.
Updated
The code has been modified to run under both Python 2 and 3 to keep it relevant. This was done in a way that avoids the use Python's explicit metaclass syntax, which varies between the two versions.
To accomplish that objective, a BulletMetaBase instance of the BulletMeta class is created by explicitly calling the metaclass when creating the Bullet baseclass (rather than using the __metaclass__= class attribute or via a metaclass keyword argument depending on the Python version).
class BulletMeta(type):
def __new__(cls, classname, bases, classdict):
""" Create Bullet class or a subclass of it. """
classobj = type.__new__(cls, classname, bases, classdict)
if classname != 'BulletMetaBase':
if classname == 'Bullet': # Base class definition?
classobj.registry = {} # Initialize subclass registry.
else:
try:
alias = classdict['alias']
except KeyError:
raise TypeError("Bullet subclass %s has no 'alias'" %
classname)
if alias in Bullet.registry: # unique?
raise TypeError("Bullet subclass %s's alias attribute "
"%r already in use" % (classname, alias))
# Register subclass under the specified alias.
classobj.registry[alias] = classobj
return classobj
def __call__(cls, alias, *args, **kwargs):
""" Bullet subclasses instance factory.
Subclasses should only be instantiated by calls to the base
class with their subclass' alias as the first arg.
"""
if cls != Bullet:
raise TypeError("Bullet subclass %r objects should not to "
"be explicitly constructed." % cls.__name__)
elif alias not in cls.registry: # Bullet subclass?
raise NotImplementedError("Unknown Bullet subclass %r" %
str(alias))
# Create designated subclass object (call its __init__ method).
subclass = cls.registry[alias]
return type.__call__(subclass, *args, **kwargs)
class Bullet(BulletMeta('BulletMetaBase', (object,), {})):
# Presumably you'd define some abstract methods that all here
# that would be supported by all subclasses.
# These definitions could just raise NotImplementedError() or
# implement the functionality is some sub-optimal generic way.
# For example:
def fire(self, *args, **kwargs):
raise NotImplementedError(self.__class__.__name__ + ".fire() method")
# Abstract base class's __init__ should never be called.
# If subclasses need to call super class's __init__() for some
# reason then it would need to be implemented.
def __init__(self, *args, **kwargs):
raise NotImplementedError("Bullet is an abstract base class")
# Subclass definitions.
class Bullet1(Bullet):
alias = 'B1'
def __init__(self, sprite, start, direction, speed):
print('creating %s object' % self.__class__.__name__)
def fire(self, trajectory):
print('Bullet1 object fired with %s trajectory' % trajectory)
class Bullet2(Bullet):
alias = 'B2'
def __init__(self, sprite, start, headto, spead, acceleration):
print('creating %s object' % self.__class__.__name__)
class Bullet3(Bullet):
alias = 'B3'
def __init__(self, sprite, script): # script controlled bullets
print('creating %s object' % self.__class__.__name__)
class Bullet4(Bullet):
alias = 'B4'
def __init__(self, sprite, curve, speed): # for bullets with curved paths
print('creating %s object' % self.__class__.__name__)
class Sprite: pass
class Curve: pass
b1 = Bullet('B1', Sprite(), (10,20,30), 90, 600)
b2 = Bullet('B2', Sprite(), (-30,17,94), (1,-1,-1), 600, 10)
b3 = Bullet('B3', Sprite(), 'bullet42.script')
b4 = Bullet('B4', Sprite(), Curve(), 720)
b1.fire('uniform gravity')
b2.fire('uniform gravity')
Output:
creating Bullet1 object
creating Bullet2 object
creating Bullet3 object
creating Bullet4 object
Bullet1 object fired with uniform gravity trajectory
Traceback (most recent call last):
File "python-function-overloading.py", line 93, in <module>
b2.fire('uniform gravity') # NotImplementedError: Bullet2.fire() method
File "python-function-overloading.py", line 49, in fire
raise NotImplementedError(self.__class__.__name__ + ".fire() method")
NotImplementedError: Bullet2.fire() method
You can easily implement function overloading in Python. Here is an example using floats and integers:
class OverloadedFunction:
def __init__(self):
self.router = {int : self.f_int ,
float: self.f_float}
def __call__(self, x):
return self.router[type(x)](x)
def f_int(self, x):
print('Integer Function')
return x**2
def f_float(self, x):
print('Float Function (Overloaded)')
return x**3
# f is our overloaded function
f = OverloadedFunction()
print(f(3 ))
print(f(3.))
# Output:
# Integer Function
# 9
# Float Function (Overloaded)
# 27.0
The main idea behind the code is that a class holds the different (overloaded) functions that you would like to implement, and a Dictionary works as a router, directing your code towards the right function depending on the input type(x).
PS1. In case of custom classes, like Bullet1, you can initialize the internal dictionary following a similar pattern, such as self.D = {Bullet1: self.f_Bullet1, ...}. The rest of the code is the same.
PS2. The time/space complexity of the proposed solution is fairly good as well, with an average cost of O(1) per operation.
Use keyword arguments with defaults. E.g.
def add_bullet(sprite, start=default, direction=default, script=default, speed=default):
In the case of a straight bullet versus a curved bullet, I'd add two functions: add_bullet_straight and add_bullet_curved.
Overloading methods is tricky in Python. However, there could be usage of passing the dict, list or primitive variables.
I have tried something for my use cases, and this could help here to understand people to overload the methods.
Let's take your example:
A class overload method with call the methods from different class.
def add_bullet(sprite=None, start=None, headto=None, spead=None, acceleration=None):
Pass the arguments from the remote class:
add_bullet(sprite = 'test', start=Yes,headto={'lat':10.6666,'long':10.6666},accelaration=10.6}
Or
add_bullet(sprite = 'test', start=Yes, headto={'lat':10.6666,'long':10.6666},speed=['10','20,'30']}
So, handling is being achieved for list, Dictionary or primitive variables from method overloading.
Try it out for your code.
Plum supports it in a straightforward pythonic way. Copying an example from the README below.
from plum import dispatch
#dispatch
def f(x: str):
return "This is a string!"
#dispatch
def f(x: int):
return "This is an integer!"
>>> f("1")
'This is a string!'
>>> f(1)
'This is an integer!'
You can also try this code. We can try any number of arguments
# Finding the average of given number of arguments
def avg(*args): # args is the argument name we give
sum = 0
for i in args:
sum += i
average = sum/len(args) # Will find length of arguments we given
print("Avg: ", average)
# call function with different number of arguments
avg(1,2)
avg(5,6,4,7)
avg(11,23,54,111,76)

Class as decorators and scope of a function over the element in the class, in python

When using a class decorator over a function, how can a function access self._count element inside the class. I understand that the decorators takes a callable and returns a callable. But can a function have scope to an inner element of a class decorator?
class decorate_class:
def __init__(self, f):
self._func = f
self._count = 0
def __call__(self, *args, **kargs):
self._count += 1
return self._func(*args, **kargs)
#decorate_class
def callname(name):
print("Hello, {0}".format(name))
Now when i call the function with a parameter i am supposed to track the count of the number of calls being made. But what i don't understand is, how can callname function access self._count??
callname('Abhishek') # o/p --> Hello, Abhishek
callname('Ashley') # o/p --> Hello, Ashley
callname._count # o/p --> 2 ( But how can callname access _count?)
Can someone help me understand this? The scopes in particular.
As in example:
class decorate_class:
def __init__(self, f):
self._func = f
self._count = 0
def __call__(self, *args, **kargs):
self._count += 1
return self._func(*args, **kargs)
#decorate_class
def callname(name):
print("Hello, {0}".format(name))
callname('bobo')
callname('dodo')
callname('will return 3')
print('It returns ->> ', callname._count)
result:
Hello, bobo
Hello, dodo
Hello, will return 3
It returns ->> 3
Explanation
As you decorate your function you basicly each time are calling decorate_class by passing you'r function callname and the __call__ method is called when the instance is called and it holds in memory _count that you'r callname function inherits from __init__.
I hope it's clearer now :)

Apply decorator to all method of sub classes for timeit

I have a method decorator looking like
def debug_run(fn):
from functools import wraps
#wraps(fn)
def wrapper(self, *args, **kw):
# log some stuff
# timeit fn
res = fn(self, *args, **kw)
return wrapper
Right now I used to use it apply on each method that I want to debug. Now i'm trying to apply to all class method using a class decorator looking like.
Rather doing
class A():
#debug_run
def f(self):
pass
I do
#decallmethods(debug_run)
class A():
def f(self):
pass
def decallmethods(decorator):
def dectheclass(cls):
for name, m in inspect.getmembers(cls, inspect.ismethod):
if name in getattr(cls, 'METHODS_TO_INSPECT', []):
setattr(cls, name, decorator(m))
return cls
return dectheclass
Trying to apply to decorator to the base class, not working as expected. no log to the console. Now i wonder if this approach is the good or I should used something else (apply the debug decorator to selected method from base class to all sub classes).
[EDIT]
Finally found why no logs were printed
Why is there a difference between inspect.ismethod and inspect.isfunction from python 2 -> 3?
Here a complete example reflecting my code
import inspect
import time
import logging as logger
from functools import wraps
logger.basicConfig(format='LOGGER - %(asctime)s %(message)s', level=logger.DEBUG)
def debug_run(fn):
#wraps(fn)
def wrapper(self, *args, **kw):
logger.debug(
"call method %s of instance %s with %r and %s "
% (fn.__name__, self, args, kw))
time1 = time.time()
res = fn(self, *args, **kw)
time2 = time.time()
logger.debug(
"%s function %0.3f ms" % (fn, (time2-time1)*1000.0))
return res
return wrapper
def decallmethods(decorator):
def dectheclass(cls):
for name, m in inspect.getmembers(
cls, predicate=lambda x: inspect.isfunction(x) or inspect.ismethod(x)):
methods_to_inspect = getattr(cls, 'METHODS_TO_INSPECT', [])
if name in methods_to_inspect:
setattr(cls, name, decorator(m))
return cls
return dectheclass
class B(object):
METHODS_TO_INSPECT = ["bfoo1", "bfoo2", "foo"]
def __str__(self):
return "%s:%s" % (repr(self), id(self))
def bfoo1(self):
pass
def bfoo2(self):
pass
def foo(self):
pass
def run(self):
print("print - Base run doing nothing")
class C(object):
pass
#decallmethods(debug_run)
class A(B, C):
METHODS_TO_INSPECT = ["bfoo1", "bfoo2", "foo", "run"]
def foo(self):
print("print - A foo")
def run(self):
self.bfoo1()
self.bfoo2()
self.foo()
a = A()
b = B()
a.run()
b.run()
In this case applying decallmethods to B, will not affect the A so i must to apply to both A and B thus to all sub classes of B.
It is possible to have such mechanism that permit to apply decallmethods to all sub classes methods ?
look at this:
How can I decorate all functions of a class without typing it over and over for each method added? Python
delnan has a good answer,
only add this rule to his answer
if name in getattr(cls, 'METHODS_TO_INSPECT', []):

addition between classes using radd method

I have two different classes, and I want to define the addition of them only in one class, and define both __add__ and __radd__ for that class (in my example below, that's ExampleClass2. I DO NOT want to create an __add__ method that works for ExampleClass1 to add ExampleClass2.
As it is right now it just ignores it. I also tried with raising error, but that didn't work either.
class ExampleClass1:
def __init__(self, data):
self.data = data
def __add__(self, other):
if isinstance(other, int):
print('other was an int')
class ExampleClass2:
def __init__(self, data):
self.data = data
def __add__(self, other):
if isinstance(other, ExampleClass1):
print("it's working")
__radd__ = __add__
a = ExampleClass1('q')
b = ExampleClass2('w')
a+b
__radd__ is only called if the left object does not have an __add__ method, or that method does not know how to add the two objects (which it flags by returning NotImplemented). Both classes have an __add__ method, which do not return NotImplemented. Therefore the __radd__ method would never be called.
Suppose you are implementing a class that you want to act like a number via operator overloading. So you implement add in your class, and now expressions like myobj + 4 can work as you want and yield some result. This is because myobj + 4 is interpreted as myobj.__add__(4), and your custom method can do whatever it means to add 4 to your custom class.
However, what about an expression like 4 + myobj which is really (4).__add__(myobj)? The 4 is an instance of a Python built-in type and its add method doesn't know anything about your new type, so it will return a special value NotImplemented. (The interpreter recognizes this special value coming from add and raises a TypeError exception which kills your program, which is the behavior you'd actually see, rather than the special value being returned.)
It would suck for operator overloading if myobj + 4 was valid but 4 + myobj was invalid. That's arbitrary and restrictive — addition is supposed to be commutative. Enter __radd__. Python will first try (4).__add__(myobj), and if that returns NotImplemented Python will check if the right-hand operand implements radd, and if it does, it will call myobj.__radd__(4) rather than raising a TypeError. And now everything can proceed as usual, as your class can handle the case and implement your behavior, rather than the built-in type's add which is fixed and doesn't know about your class.
Example:
class X:
def __init__(self, num):
self.num = num
def __str__(self):
return str(self.num)
def __add__(self, other):
return self.num + other.num
__radd__ = __add__
class Y:
def __init__(self, num):
self.num = num
def __str__(self):
return str(self.num)
x = X(5)
y = Y(10)
print(x+y)
print(y+x)
These functions __radd__ are only called if the left operand does
not support the corresponding operation and the operands are of
different types. For example,
class X:
def __init__(self, num):
self.num = num
class Y:
def __init__(self, num):
self.num = num
def __radd__(self, other_obj):
return Y(self.num+other_obj.num)
def __str__(self):
return str(self.num)
>>> x = X(2)
>>> y = Y(3)
>>> print(x+y)
5
>>>
>>> print(y+x)
---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-60-9d7469decd6e> in <module>()
----> 1 print(y+x)
TypeError: unsupported operand type(s) for +: 'Y' and 'X'

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