How to convert list of list into dictionary object? - python-3.x

Question

I have a list of lists that looks like this:
[[['1',
'1#1`']],
[['2', '2#2.com']],
[['3', '3#3.com']],
[['4', '4#4.com']],
[['5', '5#5.com']],
[['6', '6#6']],
[['7', '7#7']],
[['8', '8#8']],
[['8.5', '8.5#8.5']],
[['9', '9#9']],
[['10', '10#10']],
[['11', '11#11']],
[['12', '12#12']],
[['13', '13#13.com']],
[['14', '14#14.com']],
[['15', '15#15.com']],
[['16', '16#16.com']],
[['17', '17#17.com']],
[['18#18.com', '18']],
[['19', '19#19.com']]]
is there anyway I can clean up the list by making it into a dictionary object like so:
[{id:1,email:1#1},{id:2,email:2#2.com}]
Ideally if there are any emails in the id spot they flipped to the email spot?

Answer 1

You can use a list comprehension:
In [1]: mylist = [[['1',
...: '1#1`']],
...: [['2', '2#2.com']],
...: [['3', '3#3.com']],
...: [['4', '4#4.com']],
...: [['5', '5#5.com']],
...: [['6', '6#6']],
...: [['7', '7#7']],
...: [['8', '8#8']],
...: [['8.5', '8.5#8.5']],
...: [['9', '9#9']],
...: [['10', '10#10']],
...: [['11', '11#11']],
...: [['12', '12#12']],
...: [['13', '13#13.com']],
...: [['14', '14#14.com']],
...: [['15', '15#15.com']],
...: [['16', '16#16.com']],
...: [['17', '17#17.com']],
...: [['18#18.com', '18']],
...: [['19', '19#19.com']]]
In [2]: [{'id': i, 'email': e} for i, e in (pair[0] if '#' not in pair[0][0] else reversed(pair[0]) for pair in mylist)]
Out[2]:
[{'id': '1', 'email': '1#1`'},
{'id': '2', 'email': '2#2.com'},
{'id': '3', 'email': '3#3.com'},
{'id': '4', 'email': '4#4.com'},
{'id': '5', 'email': '5#5.com'},
{'id': '6', 'email': '6#6'},
{'id': '7', 'email': '7#7'},
{'id': '8', 'email': '8#8'},
{'id': '8.5', 'email': '8.5#8.5'},
{'id': '9', 'email': '9#9'},
{'id': '10', 'email': '10#10'},
{'id': '11', 'email': '11#11'},
{'id': '12', 'email': '12#12'},
{'id': '13', 'email': '13#13.com'},
{'id': '14', 'email': '14#14.com'},
{'id': '15', 'email': '15#15.com'},
{'id': '16', 'email': '16#16.com'},
{'id': '17', 'email': '17#17.com'},
{'id': '18', 'email': '18#18.com'},
{'id': '19', 'email': '19#19.com'}]
If you have arbitrary nesting, you can try this:
def flatten(lst):
for sub in lst:
if isinstance(sub, list):
yield from flatten(sub)
else:
yield sub
[{'id': i, 'email': e} for i, e in (pair if '#' not in pair[0] else reversed(pair) for pair in zip(*[flatten(mylist)]*2))]