NodeJS find query inside for loop results after the loops end - node.js

Question

var user_id = '98-XXXXXXXX'
Contact.find({user_id: user_id})
.exec(function (err, results) {
if (err) {
return next(err);
}
var finalArray = [];
for(var i = 0; i< results[0].Total; i++) {
if(results[0].Contacts[i].name != "SPAM") {
for(var j = 0; j < results[0].Contacts[i].phoneNumbers.length; j++){
var number = results[0].Contacts[i].phoneNumbers[j].number
number = number.replace(/ /g,'');
var user_id = number.substr(number.length - 10);
Login.find({user_id:user_id})
.exec(function(err,results) {
if(err) {
return next(err); }
var intCount = results.length;
if (intCount > 0)
{
console.log('called')
finalArray.push(results[0])
console.log(finalArray)
}
});
}
}
//console.log(i,results[0].Total - 1);
//if(i == results[0].Total - 1)
}
console.log('Ended Here',finalArray)
var responseTosend = {"message":finalArray,"user_id":user_id}
return res.send(responseTosend);
});
EndedHere[] this is coming up first empty, after that i got the result of login.find query which is correct. Any ideas how to get the finalArray after all the calculation.
Thanks in advance

Answer 1

Since the functions are returning promises within the loops, the code execution has to wait till all those promises are resolved. Consider using Promise.all or Promise.map to wait. Reference

Answer 2

As already mentioned, a structure like this, will not return the results, but the intermediate functions or objects before they are finished, since nodejs does not know it should await the results first.
const x = [1,2,3]
let results = []
for (let i = 0; i < x.length; i++){
results.push(someAsyncJobLikeADatabaseCall(x[i]))
}
// this will not return the results, but the intermediate async objects/functions
console.log(results)
Here is a better version using promises and the .map function. Notice, how we replaced the for loop with .map() (which you could see as a shorthand for .forEach + push() or for() + push(). Mongoose returns Promises if configured right, so you don't even have to manually define them and we can directly return them in .map.
const x = [1,2,3]
let results = []
async function getAsyncResults(array){
// map returns an array, this time, an array of promises
const promises = x.map(number => someAsyncJobLikeADatabaseCall(number))
// Promise.all resolves, if all promises in the array have been resolved
return Promise.all(promises)
}
try {
let results = await getAsyncResults(x)
// this will return the results you expect.
console.log(results)
} catch (err) {
console.log('Some error', err)
}