Python: String similar to everything - python-3.x

Question

I need to use string (or int, bool, etc.) which will be same as everything. So this code:
user_input = input()
if user_input in *magic_string_same_as_everything*:
return True
should return True everythine, no matter what will user type into console.
Thanks for your help
Edit:
I see, that I've asked verry badly.
I'm trying to get 3 user input in this for cycle:
user_input = ["", "", ""] # Name, class, difficulty
allowed_input = ["", ["mage", "hunter"], ["e", "m", "h"]]
difficulty = {"e": 1, "m": 2, "h": 3}
message = ["Please enter your heroic name",
"Choose character (mage/hunter)",
"Tell me how difficult your journey should be? (e / m / h)"]
print("Welcome to Dungeons and Pythons\n" + 31 * "_")
for i in range(3):
while True:
print(message[i], end=": ")
user_input[i] = input()
if user_input[i] in allowed_input[i]:
break
Choose of name is without restrictions.
I hope, that now my question makes a sense.

Answer 1

You could just get rid of the if-statement and return True without the check or (if you really want to use the if-statement) you type if(True) and it will always be true.

Answer 2

You want True for non empty string?
Just use user_input as bool.
user_input = input()
if user_input:
return True
In your question Name is special case, just check it like this and for the rest of input you can use range(1,3).
Alternatively switch to using regular expressions
allowed_input = ["\A\S+", "\A(mage|hunter)\Z", "\A[emh]\Z"]
for i in range(3):
while True:
print(message[i], end=": ")
user_input[i] = input()
if re.match(allowed_input[i], user_input[i]) :
break

Answer 3

Initial response
This one liner should work.
If user inputs anything, it counts as an input & prints 'True', but if user just hits 'Enter' without typing anything, it returns 'No input'
print ("True" if input("Type something:") else 'No input')
After your edited question
To achieve what you want, you can define a function that checks for the user input values & corrects them if incorrect.
import re
# for user input, a single line of code is sufficient
# Below code takes 3 inputs from user and saves them as a list. Second and third inputs are converted to lowercase to allow case insensitivity
user_input = [str(input("Welcome to Dungeons & Pythons!\n\nPlease enter username: ")), str(input("Choose character (mage/hunter): ").lower()), str(input("Choose difficulty (e/m/h):").lower())]
print (user_input) # Optional check
def input_check(user_input):
if user_input[0] != '':
print ("Your username is: ", user_input[0])
else:
user_input[0] = str(input("No username entered, please enter a valid username: "))
if re.search('mage|hunter', user_input[1]):
print ("Your character is a : ", user_input[1])
else:
user_input[1] = str(input("Incorrect character entered, please enter a valid character (mage/hunter): ").lower())
if re.search('e|m|h',user_input[2]):
print ("You have selected difficulty level {}".format('easy' if user_input[2]=='e' else 'medium' if user_input[2]=='m' else 'hard'))
else:
user_input[2] = str(input("Incorrect difficulty level selected, please choose from 'e/m/h': "))
return (user_input)
check = input_check(user_input)
print (check) # Optional check
In each of the if-else statements, the function checks each element and if no input/ incorrect input (spelling mistakes, etc.) are found, it asks the user to correct them & finally returns the updated list.
Test Output
With correct entries
[Out]: Welcome to Dungeons & Pythons!
Please enter username: dfhj4
Choose character (mage/hunter): mage
Choose difficulty (e/m/h):h
['dfhj4', 'mage', 'h']
Your username is: dfhj4
Your character is a : mage
You have selected difficulty level hard
['dfhj4', 'mage', 'h']
With incorrect entries
[Out]: Welcome to Dungeons & Pythons!
Please enter username:
Choose character (mage/hunter): sniper
Choose difficulty (e/m/h):d
['', 'sniper', 'd']
No username entered, please enter a valid username: fhk3
Incorrect character entered, please enter a valid character (mage/hunter): Hunter
Incorrect difficulty level selected, please choose from 'e/m/h': m
['fhk3', 'hunter', 'm']