Print sorted data under a heading in python 3.7 - python-3.x

Question

I want to sort data in a txt file that has the following format:
name number1 number2 number3 number4
nick 3 2 66 40
Anna 3 1 33 19
kathrine 4 4 100 258
based on fourth column (number3) but it doesn't seem to work when number3 is three digits number.
The program simply asks three times for a name. Each name enters numbers other than 0
and prints the name, how many numbers given (number1), how many of them are greater than 10 (number2), percentage of them (number 3) and the sum of all numbers given(number4).
I would like also to print data aligned under each heading.The headings doesn't need to be stored
in the file.
The code is the following
def how_to_sort_a_file():
from operator import itemgetter
with open('myfile2.txt') as f:
lines = [line.split(' ') for line in f]
output = open('myfile2(sorted).txt', 'w')
for line in sorted(lines,key=itemgetter(3), reverse=True):
output.write(' '.join(line))
output.close()
print('')
with open('myfile2(sorted).txt') as f:
##prints an empty line between lines
for line in f:
print(line)
##end function
##################################################################
##################
## main program ##
##################
file=open('myfile2.txt', 'w')
file.close()
for i in range(3):
name=input('insert your name: ')
number=int(input('insert number, 0 to terminate: '))
given_numbers=0
numbers_greater_10=0
Sum=0
while number!=0:
Sum=Sum+number
given_numbers=given_numbers+1
if number>10:
numbers_greater_10=numbers_greater_10+1
number=int(input('insert number, 0 to terminate: '))
percentage=int((numbers_greater_10)*100/given_numbers)
with open('myfile2.txt', 'a') as saveFile:
saveFile.write(name +' '+str(given_numbers)+' '+str(numbers_greater_10)+' '+ str(percentage)+' '+ str(Sum)+"\n")
how_to_sort_a_file()
I'm totally inexperienced with Python and i would appreciate any help.
Thanks a lot.

Answer 1

You can try doing this using Python's library pandas:
Read the text file into a dataframe like below:
In [1397]: df = pd.read_fwf('myfile2.txt')
In [1398]: df
Out[1398]:
name number1 number2 number3 number4
0 nick 3 2 66 40
1 Anna 3 1 33 19
2 kathrine 4 4 100 258
Now, you can simple sort on the column number3 in an ascending order:
In [1401]: df = df.sort_values('number3')
In [1402]: df
Out[1402]:
name number1 number2 number3 number4
1 Anna 3 1 33 19
0 nick 3 2 66 40
2 kathrine 4 4 100 258
You can see above that the rows are sorted by number3. Now, simply write this to a text file:
In [1403]: df.to_csv('my_output.txt', index=False)
mayankp#mayank:~/Desktop$ cat my_output.txt
name,number1,number2,number3,number4
Anna,3,1,33,19
nick,3,2,66,40
kathrine,4,4,100,258
The good part about this is that you don't have to write complex code for parsing the file.