This question already has answers here:
How do you print a dollar sign $ in Dart
(2 answers)
Closed 4 years ago.
I'm currently creating an simple application with flutter(Dart). And when i want to create the AppBar widget, i cant give it names with '$'. Because, same like Kotlin..Dart is using '$' for summoning an identifier.
Any solution?
var _appbar = AppBar(
title: Text("How I Made $100"), //$ is the error
);
The dollar sign is a special character, so if you want it to be ignored you have to escape it with a \.
For example:
void main() {
print("This string contains a dollar \$ign");
}
See this gist.
Related
This question already has answers here:
Split string into array of characters?
(7 answers)
Closed 3 years ago.
can you help me on this?
I have a simple string:
str="Hello World";
I want to split it as that :
array= str.Split("",System.StringSplitOptions.RemoveEmptyEntries);
result shoud be
array[0]="H"
array[1]="e"
array[2]="l"
array[3]="l"
array[4]="o"
array[5]="W"
array[6]="o"
...
But I don't know to "wildcard" the separator..
Any Idea on this ?
Thanks
?
Just use String.ToCharArray():
SomeArray = str.ToCharArray()
This question already has an answer here:
Appending a string variable to a fixed string in Perl
(1 answer)
Closed 5 years ago.
I am trying to read input of two strings from the user keyboard, store them in two variables and concatenate the two strings together using the Perls dot operator.
Research I found online shows an example similar to what I am trying to accomplish. This example uses only one string variable in the concatenation but I think something similar should be able to concatenate multiple variables together:
$name = checkbook';
$filename = '/tmp/' . $name . '.tmp';
#$filename now contains "/tmp/checkbook.tmp"
(http://alvinalexander.com/perl/edu/articles/pl010003.shtml)
my code is displayed in the following - however, I am still getting the undesired concatenation :
$stringa=<STDIN>;
$stringb=<STDIN>;
print $stringa.$stringb;
compiled using perl (path)
output
nein
ja
nein
ja
instead of the desired output:
nein
ja
neinja
why am I not getting the concatenation output I think it should produce?
You can use "chomp" to remove the trailing string "\n", like this:
$stringa=<STDIN>;
$stringb=<STDIN>;
chomp($stringa);
chomp($stringb);
print $stringa.$stringb;
This question already has answers here:
How do I replace all occurrences of a string in JavaScript?
(78 answers)
Closed 6 years ago.
I would like to replace multiple words from below string:
\njava developer\n
How do I replace \n from start and \n from last from above string?
I used
replace('\n', '')
but it replace first \n only.
If you want to replace all \n without calling replace in a loop you have to use a regular expression. You can use it like this:
var test = "\njava developer\n";
var result = test.replace(/\n/g, '');
the g in the regular expression means replace all occurrences.
Hope this helps.
Thanks vincent!
It works for me.
I implement like this
stringToChange.toLowerCase().toString().replace(/[<b></b>\n]/g,'')
to replace
<\b>, <b> and \n
all multiple occurrences.
This question already has answers here:
How do I check if a string contains another string in Swift?
(28 answers)
Closed 7 years ago.
The answer in this question: How do I check if a string contains another string in Swift?
No longer works.
var string = "hello Swift"
if string.rangeOfString("Swift") != nil{
println("exists")
}
Will get you:
error: value of type 'String' has no member 'rangeOfString'
What is the new way to do this?
Import Foundation and you will be able to call rangeOfString.
This question already has answers here:
How can I create a UILabel with strikethrough text?
(21 answers)
Closed 8 years ago.
How can I write a string like the following:
H̶̶o̶̶w̶ ̶t̶̶o̶ ̶w̶̶r̶̶i̶̶t̶̶e̶ ̶t̶̶h̶̶i̶̶s̶ ̶t̶̶e̶̶x̶̶t̶
In my app, I need to display the past price of a product that has been replaced by a new price. Like so:
$̶8̶̶0̶̶0̶ -> $600
To get this result you should use NSAttributedString and set the attribute name NSStrikethroughStyleAttributeName. The number used as object for this key defines the style of the line over the text.
self.myLabel.attributedText = [[NSAttributedString alloc] initWithString:#"800" attributes:#{NSStrikethroughStyleAttributeName: #1}];
Cheers