asyncio queue multi producer (sync) single consumer - python-3.x

Question

an asyncio program has two task that produce messages which are put on a queue, another task consume the queue.
one producer produce periodic task.
the other producer has to be synced with the consumer, it has to await till its own message have been consumed
import asyncio
import logging
import sys
logging.basicConfig( stream=sys.stdout,format='%(asctime)-5s: %(funcName)-15s: %(message)s',datefmt='%I:%M:%S',level=logging.INFO)
logger = logging.getLogger()
async def sync_producer(queue):
for x in range(5):
item = f"sync producer{x}"
logger.info(f"{item} ")
await queue.put(item)# <= at this point I want to await that the message have been consumed
logger.info(f"sync producer finish")
async def periodic_producer(queue):
x=0
while True:
await asyncio.sleep(1)
item = f"periodic producer {x}"
logger.info(f"{item} ")
queue.put_nowait(item)
x+=1
async def consumer(queue):
while True:
item = await queue.get()
logger.info(f"{item}")
queue.task_done()
await asyncio.sleep(1)
async def main():
queue = asyncio.Queue()
consumer_task = asyncio.create_task(consumer(queue))
periodic_producer_task = asyncio.create_task(periodic_producer(queue))
producer_task = asyncio.create_task(sync_producer(queue))
await producer_task
periodic_producer_task.cancel()
await queue.join()
consumer_task.cancel()
asyncio.run(main())
The example does not work as i want beacause await queue.put(item) does'not await queue task_done().
A possible workaround could be to put on the queue (event,item) where event = asyncio.Event() and then await event. Is that a "good" workaraound?