I have a list of x,y,z points and a list of values assigned to each 3D point.
Now the question is, how can I color each point in a 3D scatter plot according to the list of values ?
The colors should be typical engineering -> RGB -> lowest blue to highest red
Thanks a lot
Basically I am searching for an equivalent to: scatter3(X,Y,Z,S,C)
See here: https://ch.mathworks.com/help/matlab/ref/scatter3.html
I tried:
col = [i/max(values)*255 for i in values]
ax.scatter(sequence_containing_x_vals, sequence_containing_y_vals, sequence_containing_z_vals,c=col, marker='o')
pyplot.show()
..but I don't get the desired result
Note the recommended way of producing scatters with colors is to supply the values directly to c:
ax.scatter(x, y, z, c=values, marker='o', cmap="Spectral")
Minimal example:
import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d import Axes3D
x = y = z = values = [1,2,3,4,5]
ax = plt.subplot(projection="3d")
sc = ax.scatter(x, y, z, c=values, marker='o', s=100, cmap="Spectral")
plt.colorbar(sc)
plt.show()
Related
I am facing a problem to plot the geometry in the python using matplotlib. I would like to have a plot which can have the equal lenth in all three axes (X, Y, Z). I have written below code but it does not show any equal axes in the obtained geometry.
How can I get the plot with equal axes?
def plotting(x, y, z, figname):
fig = plt.figure(figsize = (50,50))
ax = plt.axes(projection='3d')
ax.grid()
ax.scatter(x, y, z, c = 'r', s = 50)
ax.set_title(figname)
ax.set_xlabel('x', labelpad=20)
ax.set_ylabel('y', labelpad=20)
ax.set_zlabel('z', labelpad=20)
Matplotlib makes this very difficult. One way you could "achieve" that is by setting the same limits to xlim, ylim, zlim:
import numpy as np
import matplotlib.pyplot as plt
n = 1000
t = np.random.uniform(0, 2*np.pi, n)
p = np.random.uniform(0, 2*np.pi, n)
x = (4 + np.cos(t)) * np.cos(p)
y = (1.5 + np.cos(t)) * np.sin(p)
z = np.sin(t)
fig = plt.figure()
ax = fig.add_subplot(projection="3d")
ax.scatter(x, y, z)
ax.set_xlim(-4, 4)
ax.set_ylim(-4, 4)
ax.set_zlim(-4, 4)
plt.show()
Otherwise, your best bet is to use a different plotting library for 3D plots. Plotly allows to easily set equal aspect ratio. K3D-Jupyter and Mayavi uses equal aspect ratio by default.
I am programming in Python 3 and I have data structured like this:
coordinates = [(0.15,0.25),(0.35,0.25),(0.55,0.45),(0.65,0.10),(0.15,0.25)]
These are coordinates. Within each pair, the first number is the x coordinate and the second one the y coordinate. Some of the coordinates repeat themselves. I want to plot these data like this:
The coordinates that are most frequently found should appear either as higher intensity (i.e., brighter) points or as points with a different color (for example, red for very frequent coordinates and blue for very infrequent coordinates). Don't worry about the circle and semicircle. That's irrelevant. Is there a matplotlib plot that can do this? Scatter plots do not work because they do not report on the frequency with which each coordinate is found. They just create a cloud.
The answer is:
import matplotlib.pyplot as plt
from scipy.stats import kde
import numpy as np
xvalues = np.random.normal(loc=0.5,scale=0.01,size=50000)
yvalues = np.random.normal(loc=0.25,scale=0.1,size=50000)
nbins=300
k = kde.gaussian_kde([xvalues,yvalues])
xi, yi = np.mgrid[0:1:nbins*1j,0:1:nbins*1j]
zi = k(np.vstack([xi.flatten(),yi.flatten()]))
fig, ax = plt.subplots()
ax.pcolormesh(xi, yi, zi.reshape(xi.shape), shading='auto', cmap=plt.cm.hot)
x = np.arange(0.0,1.01,0.01,dtype=np.float64)
y = np.sqrt((0.5*0.5)-((x-0.5)*(x-0.5)))
ax.axis([0,1,0,0.55])
ax.set_ylabel('S', fontsize=16)
ax.set_xlabel('G', fontsize=16)
ax.tick_params(labelsize=12, width=3)
ax.plot(x,y,'w--')
plt.show()
Background:
I have a list_of_x_and_y_list that contains x and y values which looks like:
[[(44800, 14888), (132000, 12500), (40554, 12900)], [(None, 193788), (101653, 78880), (3866, 160000)]]
I have another data_name_list ["data_a","data_b"] so that
"data_a" = [(44800, 14888), (132000, 12500), (40554, 12900)]
"data_b" = [(None, 193788), (101653, 78880), (3866, 160000)]
The len of list_of_x_and_y_list / or len of data_name_list is > 20.
Question:
How can I create a scatter plot for each item (being the same colour) in the data_name_list?
What I have tried:
fig = plt.figure()
ax = fig.add_subplot(1, 1, 1)
ax = plt.axes(facecolor='#FFFFFF')
prop_cycle = plt.rcParams['axes.prop_cycle']
colors = prop_cycle.by_key()['color']
print(list_of_x_and_y_list)
for x_and_y_list, data_name, color in zip(list_of_x_and_y_list, data_name_list, colors):
for x_and_y in x_and_y_list,:
print(x_and_y)
x, y = x_and_y
ax.scatter(x, y, label=data_name, color=color) # "label=data_name" creates
# a huge list as a legend!
# :(
plt.title('Matplot scatter plot')
plt.legend(loc=2)
file_name = "3kstc.png"
fig.savefig(file_name, dpi=fig.dpi)
print("Generated: {}".format(file_name))
The Problem:
The legend appears to be a very long list, which I don't know how to rectify:
Relevant Research:
Matplotlib scatterplot
Scatter Plot
Scatter plot in Python using matplotlib
The reason you get a long repeated list as a legend is because you are providing each point as a separate series, as matplotlib does not automatically group your data based on the labels.
A quick fix is to iterate over the list and zip together the x-values and the y-values of each series as two tuples, so that the x tuple contains all the x-values and the y tuple the y-values.
Then you can feed these tuples to the plt.plot method together with the labels.
I felt that the names list_of_x_and_y_list were uneccessary long and complicated, so in my code I've used shorter names.
import matplotlib.pyplot as plt
data_series = [[(44800, 14888), (132000, 12500), (40554, 12900)],
[(None, 193788), (101653, 78880), (3866, 160000)]]
data_names = ["data_a","data_b"]
fig = plt.figure()
ax = fig.add_subplot(1, 1, 1)
ax = plt.axes(facecolor='#FFFFFF')
prop_cycle = plt.rcParams['axes.prop_cycle']
colors = prop_cycle.by_key()['color']
for data, data_name, color in zip(data_series, data_names, colors):
x,y = zip(*data)
ax.scatter(x, y, label=data_name, color=color)
plt.title('Matplot scatter plot')
plt.legend(loc=1)
To only get one entry per data_name, you should add data_name only once as a label. The rest of the calls should go with label=None.
The simplest you can achieve this using the current code, is to set data_name to None at the end of the loop:
from matplotlib import pyplot as plt
from random import randint
fig = plt.figure()
ax = fig.add_subplot(1, 1, 1)
ax.set_facecolor('#FFFFFF')
# create some random data, suppose the sublists have different lengths
list_of_x_and_y_list = [[(randint(1000, 4000), randint(2000, 5000)) for col in range(randint(2, 10))]
for row in range(10)]
data_name_list = list('abcdefghij')
colors = plt.rcParams['axes.prop_cycle'].by_key()['color']
for x_and_y_list, data_name, color in zip(list_of_x_and_y_list, data_name_list, colors):
for x_and_y in x_and_y_list :
x, y = x_and_y
ax.scatter(x, y, label=data_name, color=color)
data_name = None
plt.legend(loc=2)
plt.show()
Some things can be simplified, making the code 'more pythonic', for example:
for x_and_y in x_and_y_list :
x, y = x_and_y
can be written as:
for x, y in x_and_y_list:
Another issue, is that with a lot of data calling scatter for every point could be rather slow. All the x and y belonging to the same list can be plotted together. For example using list comprehension:
for x_and_y_list, data_name, color in zip(list_of_x_and_y_list, data_name_list, colors):
xs = [x for x, y in x_and_y_list]
ys = [y for x, y in x_and_y_list]
ax.scatter(xs, ys, label=data_name, color=color)
scatter could even get a list of colors per point, but plotting all the points in one go, wouldn't allow for labels per data_name.
Very often, numpy is used to store numerical data. This has some advantages, such as vectorization for quick calculations. With numpy the code would look like:
import numpy as np
for x_and_y_list, data_name, color in zip(list_of_x_and_y_list, data_name_list, colors):
xys = np.array(x_and_y_list)
ax.scatter(xys[:,0], xys[:,1], label=data_name, color=color)
I have a subplot with a single legend entry. I am placing the legend at the bottom of the figure and using mode='expand'; however, the single legend entry is placed to the very left of the legend box. To my understanding, changing kwargs such as bbox_to_anchor changes the legend box parameters but not the parameters of the symbols/text within. Below is an example to reproduce my issue.
import numpy as np
import matplotlib.pyplot as plt
x = np.linspace(-10, 10, 21)
y = np.exp(x)
z = x **2
fig, axes = plt.subplots(nrows=1, ncols=2)
axes[0].plot(x, y, color='r', label='exponential')
axes[1].plot(x, z, color='b')
# handles, labels = axes[0].get_legend_handles_labels()
plt.subplots_adjust(bottom=0.125)
fig.legend(mode='expand', loc='lower center')
plt.show()
plt.close(fig)
This code produces . How can I change the position of the symbol and text such that they are centered in the legend box?
PS: I am aware that exponential is a bad label for this subplot since it only describes the first subfigure. But, this is just for examples-sake so that I can apply it to my actual use-case.
The legend entries are placed using a HPacker object. This does not allow to be centered. The behaviour is rather that those HPackers are "justified" (similar to the "justify" option in common word processing software).
A workaround would be to create three (or any odd number of) legend entries, such that the desired entry is in the middle. This would be accomplished via the ncol argument and the use of "dummy" entries (which might be transparent and have no associated label).
import numpy as np
import matplotlib.pyplot as plt
x = np.linspace(-10, 10, 21)
y = np.exp(x)
z = x **2
fig, axes = plt.subplots(nrows=1, ncols=2)
fig.subplots_adjust(bottom=0.125)
l1, = axes[0].plot(x, y, color='r', label='exponential')
axes[1].plot(x, z, color='b')
dummy = plt.Line2D([],[], alpha=0)
fig.legend(handles=[dummy, l1, dummy],
mode='expand', loc='lower center', ncol=3)
plt.show()
I'm trying to print the error ratio of the Hilbert matrix.
I'm trying to make the x axis 3 → 9 and the y axis rather for a large range:
8.71244799e+01 6.44297999e+02 4.50711567e+03 3.04673758e+04
2.01144882e+05 1.30525476e+06 8.35964228e+06
I'm struggling adjust the window, or plotting correctly for that.
Any help would be great!
Here is my attempt at plotting (something)
import matplotlib.pyplot as plt
plot = 6
plt.xlabel ('n')
plt.ylabel ('Error Ration')
fig = plt.figure()
ax = fig.add_subplot(111)
for a in range (0, plot, 1):
y = xratio[a]
x = plot + 3
ax.plot(x,y, mfc='orange', mec='orange', marker='.')
plt.show()
I think you just need to use:
ax.set_xlim([x_min, x_max])
ax.set_ylim([y_min, y_max])