Converting IntVar() value to Int - python-3.x

Iam trying to convert Intvar() value to Int by
self.var1 = IntVar()
self.scale = ttk.LabeledScale(self.frame1, from_ = 3, to = 7, variable = self.var1).grid(row = 2, sticky = 'w')
value = int(self.var1)
but got an error saying
TypeError: int() argument must be a string, a bytes-like object or a number, not 'IntVar'

You need to invoke the .get method of IntVar which returns the object's value as an integer.

See inline comment for info.
self.var1 = IntVar()
self.scale = ttk.LabeledScale(self.frame1, from_ = 3, to = 7, variable =
self.var1).grid(row = 2, sticky = 'w')
value = self.var1.get() #the get() method of the IntVar object will return an int value
Hope this will help you!

Related

what am i doing wrong with tkinter application for email slicer?

making an email slicer,
some errors I'm getting are:
AttributeError: 'bool' object has no attribute 'index'
ValueError: substring not found
now, with this specific code, I'm getting no result at all, it just doesn't do anything when I click the button
root = Tk()
e = Entry(root)
e.grid(row = 6, column = 6)
s = Label(root)
s.grid(row = 1, column = 1)
wel = Label(root, text = "whats your email")
wel.grid(row = 1, column = 5)
inp = Entry(root)
inp.grid(row = 3, column = 5)
def callback(re = inp.get()):
us = re[:re.startswith("#")]
uss = re[re.startswith("#")+1:]
var = StringVar()
var.set(us + uss)
sub = Button(root, text = "submit", command = lambda:callback())
sub.grid(row = 5, column = 5)
final = Label(root, textvariable = var)
final.grid(row = 5, column = 6)
root.mainloop()
You need to
call inp.get() inside callback(), not as default value of argument
use find() instead of startswith()
call var.set(...) inside the function as well
def callback():
re = inp.get()
pos = re.find("#")
if pos >= 0:
user = re[:pos]
domain = re[pos+1:]
var.set(user+","+domain)
else:
var.set("Invalid email")
Note that above is not enough to check whether the input email is valid or not, for example two "#" in the input.

Changing a variable with a button (and a function) in Python Tkinter

I have the following code (it's partly in Dutch but I don't think that'll be an issue):
from tkinter import *
root = Tk()
woorden_en = ["mouse", "armadillo", "caterpillar", "buffalo", "dragonfly", "eel", "monkey", "lark", "manatee", "squid"]
woorden_nl = ["muis", "gordeldier", "rups", "buffel", "libelle", "paling", "aap", "leeuwerik", "zeekoe", "inktvis"]
nummer = IntVar()
nlWoord = StringVar()
enWoord = StringVar()
goedfout = StringVar()
def vorige():
nummer -= 1
def volgende():
nummer += 1
def controleer():
print("Correct!")
secondGrid = Frame(root)
secondGrid.grid(row = 2, column = 1, columnspan = 2)
labelVertaling = Label(root, text="vertaling")
textVertaling = Entry(root, width=30, textvariable = nlWoord)
runVorige = Button(secondGrid, text="vorige", command = vorige)
runVolgende = Button(secondGrid, text="volgende", command = volgende)
runControleer = Button(secondGrid, text="controleer", command = controleer)
labelWoord = Label(root, text="woord")
labelWoordEn = Label(root, textvariable = enWoord)
labelNo = Label(root, textvariable = nummer)
Correct = Label(root, textvariable = goedfout)
Correct.grid(row = 2, column = 0)
labelNo.grid(row = 0, column = 0)
labelWoord.grid(row = 0, column = 1)
labelWoordEn.grid(row = 1, column = 1)
labelVertaling.grid(row = 0, column = 2)
textVertaling.grid(row = 1, column = 2)
runVorige.grid(row = 0, column = 0, sticky = "W")
runVolgende.grid(row = 0, column = 1, sticky = "W")
runControleer.grid(row = 0, column = 2, sticky = "W")
nummer.set(1)
enWoord.set(woorden_en[0])
root.mainloop()
The start value of 'nummer' is 1, as set in the 3rd to last line. This value needs to be changed with either -1 or +1 when clicking buttons 'vorige' (previous) or 'volgende' (next). The current code in the functions give me erros. Apparently I need to use set/get functions, but I cannot find out how to make it work. Any input or help would be appreciated.
Just change your function to:
def vorige():
nummer_val = nummer.get()
nummer_val -= 1
nummer.set(nummer_val)
def volgende():
nummer_val = nummer.get()
nummer_val += 1
nummer.set(nummer_val)
This is because nummer is an IntVar() and you have to get the value of the variable using get() method. After that you have to assign it to a variable and then reduce/increase its value by 1. The first error you were getting was because the nummer was not globalized inside the function, but that was not the approach you should have taken, anyway this should fix your errors.

How to pass a value to an entry validatecommand

I am validating a form in tkinter using validatecommand. There are two entries, one should only accept integers and the other floats.
Here is the basic code:
import tkinter as tk
class Form(tk.Tk):
def __init__(self):
tk.Tk.__init__(self)
validCmd1 = (self.register(self.val1), "%P")
validCmd2 = (self.register(self.val2), "%P")
self.lab1 = tk.Label(self, text = "Float:")
self.lab1.grid(row = 1, column = 0, padx = 10, pady = 10)
self.ent1 = tk.Entry(self, validate = "key", validatecommand = validCmd1)
self.ent1.grid(row = 1, column = 1)
self.lab2 = tk.Label(self, text = "Integer:")
self.lab2.grid(row = 2, column = 0, padx = 10, pady = (0,10))
self.ent2 = tk.Entry(self, validate = "key", validatecommand = validCmd2)
self.ent2.grid(row = 2, column = 1)
def val1(self, value):
try:
float(value)
except:
return False
else:
return True
def val2(self, value):
try:
int(value)
except:
return False
else:
return True
app = Form()
app.mainloop()
Instead of writing two different functions for two very similar tasks, I tried to pass an integer to the validate command (1 for float, 2 for integer). I tried to use lambdas to pass values to the validation functions, first on the self.register part: self.register(lambda: self.val1(1)) but this gave TypeError: <lambda>() takes 0 positional arguments but 1 was given and the second time I tried using lambda on the validatecommand command: validatecommand = lambda: validCmd1(1) which gives TypeError: 'tuple' object is not callable.Is it possible to pass values to a validation command?
The validatecommand option takes a tuple that can have any arguments you want. For example, if you want to pass an integer it's as easy as this:
validCmd1 = (self.register(self.val), 1, "%P")
validCmd2 = (self.register(self.val), 2, "%P")
def val(self, arg, value):
print(f"val1 arg='{arg}' value='{value}'")
...
Sometimes it's easier to understand if you separate the registration of the command from the value passed in to validatecommand. For example:
vcmd = self.register(self.val)
...
self.ent1 = tk.Entry(..., validatecommand = (vcmd, 1, "%P"))
self.ent2 = tk.Entry(..., validatecommand = (vcmd, 2, "%P"))

How can I make a button input as Integer

I just started to work with python with a little to no actual programming background. As most of the newcomers I am writing a calculator. I've got some buttons for writing my numbers into a label. This works well if I set the textvariable in StringVar as the snippet below:
numbers = StringVar()
display = Label(root, font = "Arial 20", textvariable = numbers, relief = RIDGE, anchor = E)
But when I set this into IntVar it doesnt work anymore. I don't seem to be able to solve my problem. Here is some more of my code to clearify what Im doing (wrong?).
numbers = IntVar()
display = Label(root, font = "Arial 20", textvariable = numbers, relief = RIDGE, anchor = E)
display.place(x=1, y=1, width=212,height=47
def display_input (inputValue):
CurrentInput = numbers.get()
numbers.set(CurrentInput + inputValue)
btn1 = Button(root, text = '1', bd = '1', bg = 'lightsteelblue', relief = RAISED, command = lambda: display_input('1'))
btn1.place(x=1, y=96, width=71,height=47)
here you are calling the display_input function with a string (str) instead of an integer (int):
# '1' with quotes is a string, not an integer
Button(root, ..., command = lambda: display_input('1'))
This will make you attempt to update an IntVar with the result of the sum of an int with a str, which is not supported:
>>> 0 + '1'
TypeError: unsupported operand type(s) for +: 'int' and 'str'
Replacing that command with display_input(1) instead (here 1 is an int) should fix your issue.

updating tkinter window for text background changes

Trying to show a green or red background in the text field of the answer to the simple addition quizzer.
Currently in PyCHarm complains that:
Entry.grid_configure(background = "red")
TypeError: grid_configure() missing 1 required positional argument: 'self'
0
I can't seem to figure this out. Any help is appreciated.
Here's the code so far:
from tkinter import *
import random
class MainGUI:
def __init__(self):
window = Tk() # Create the window
window.title("Addition Quizzer") # Set the title
#window.width(len(window.title()))
self.number1 = random.randint(0, 9)
self.number2 = random.randint(0, 9)
Label(window, text = "+").grid(row = 2, column = 1, sticky = E)
Label(window, text = "Answer").grid(row = 3, column = 1, sticky = W)
self.firstNumber = StringVar()
Label(window, text = self.number1, justify = RIGHT).grid(row = 1, column = 2)
self.secondNumber = StringVar()
Label(window, text = self.number2, justify = RIGHT).grid(row = 2, column = 2)
self.entry = StringVar()
Entry(window, textvariable = self.entry, justify = CENTER, width = 4, background = "grey").grid(row = 3, column = 2)
Button(window, text = "Answer:", command = self.computeAnswer).grid(row = 4, column = 1, sticky = E)
self.result = StringVar()
Label(window, textvariable = self.result).grid(row = 4, column = 2)
window.mainloop() # Create the event loop
def computeAnswer(self):
self.result.set(format(self.number1 + self.number2))
if self.entry == self.result:
self.displayCorrect()
else:
self.displayIncorrect()
def displayCorrect(self):
# self.correctAnswer = "Correct"
# Label(self.window, text = self.correctAnswer, background = "green", justify = RIGHT).grid(row = 5, column = 2)
Entry.grid_configure(background = "green")
def displayIncorrect(self):
# self.incorrectAnswer = "Incorrect"
# Label(self.window, text = self.incorrectAnswer, background = "red", justify = RIGHT).grid(row = 5, column = 2)
Entry.grid_configure(background = "red")
MainGUI()
If you had read and followed this in the Help Center material, you would have reduced your code to the following, which still gets the same error message.
from tkinter import *
Entry.grid_configure()
The message refers to the fact that Python instance methods require an instance. This is usually done by calling the method on an instance instead of the class. Otherwise, an instance must be given as the first argument. Consider
mylist = []
mylist.append(1)
list.append(mylist, 2)
print(mylist)
# [1, 2]
You need to save a reference to your Entry box. Change
Entry(window, ..., background = "grey").grid(...)
to
self.entry = Entry(window, ..., background = "grey").grid(...)
I do not know if calling .grid_configure(background=color will do what you want.
This will, I am sure.
self.entry['background'] = 'red'

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