I have many folders say "folder1", "folder2" etc
Each folder inturn has many files with different extensions
eg:
file1.txt
file2.txt
file3.txt
file4.txt
file5.txt
file6.txt
file7.txt
file8.txt
file.xlsx
file2.bin
I want to open the last file in every folder.
For instance here I want to open the file8.txt as its the last file having extension "txt"
Can anyone please let me know a generic method to do this.
I am a beginner in python.
Try this:
import glob
import os
list_of_files = glob.glob('/path/to/folder/*.txt')
latest_file = max(list_of_files, key=os.path.getctime)
print(latest_file)
f = open(latest_file, 'r')
You can run this in a loop for all folders. Let me know if it works.
Considering last means latest timestamp of file this should do :
import os
import glob
def get_latest_file(file_loc,file_nm_str):
file_lst = glob.glob(file_loc+"*" + file_nm_str + "*")
latest_file = max(file_lst, key=os.path.getctime)
return latest_file
You can modify * with required extension.
Related
I need help renaming .jpg files in my folder with the same prefix, 'cat_'. for example, 070.jpg should be renamed cat_070.jpg.
the files are located within the Cat folder:
from pathlib import Path
p = Path('C:\\Users\\me\\Jupiter_Notebooks\\Dataset\\Train\\Cat\\')
so I dont quite see how to do it? the below is wrong because it does not 'look into' the files in this directory.
p.rename(Path(p.parent, 'cat_' + p.suffix))
I have also unsuccessfully tried this:
import os
from os import rename
from os import listdir
# Get path
cwd = "C:\\Users\\me\\Jupiter_Notebooks\\Dataset\\Train\\Cat"
# Get all files in dir
onlyfiles = [f for f in listdir(cwd) if isfile(join(cwd, f))]
for file in onlyfiles:
# Get the current format
if file[-4:]==(".jpg"):
s = file[1]
# Change format and get new filename
s[1] = 'cat'
s = '_'.join(s)
# Rename file
os.rename(file, s)
print(f"Renamed {file} to {s}")
FileNotFoundError: [WinError 3] The system cannot find the path specified: 'C:\\Users\\me\\Jupiter_Notebooks\\Dataset\\Train\\Cat\\'
how can I do it? sorry I'm really a beginner here.
How about:
from pathlib import Path
img_dir = Path('C:\\Users\\me\\Jupiter_Notebooks\\Dataset\\Train\\Cat\\') # path to folder with images
for img_path in img_dir.glob('*.jpg'): # iterate over all .jpg images in img_dir
new_name = f'cat_{img_path.stem}{img_path.suffix}' # or directly: f'cat_{img_path.name}'
img_path.rename(img_dir / new_name)
print(f'Renamed `{img_path.name}` to `{new_name}`')
pathlib also supports renaming files, so the os module is not even needed here.
use pathlib. Path. iterdir() to rename all files in a directory
1) for path in pathlib. Path("a_directory"). iterdir():
2) if path. is_file():
3) old_name = path. stem. original filename.
4) old_extension = path. suffix. original file extension.
5) directory = path. parent. ...
6) new_name = "text" + old_name + old_extension.
7) path. rename(pathlib.
I have one scenario where i have to rename the files in the folder. Please find the scenario,
Example :
Elements(Main Folder)<br/>
2(subfolder-1) <br/>
sample_2_description.txt(filename1)<br/>
sample_2_video.avi(filename2)<br/>
3(subfolder2)
sample_3_tag.jpg(filename1)<br/>
sample_3_analysis.GIF(filename2)<br/>
sample_3_word.docx(filename3)<br/>
I want to modify the names of the files as,
Elements(Main Folder)<br/>
2(subfolder1)<br/>
description.txt(filename1)<br/>
video.avi(filename2)<br/>
3(subfolder2)
tag.jpg(filename1)<br/>
analysis.GIF(filename2)<br/>
word.docx(filename3)<br/>
Could anyone guide on how to write the code?
Recursive directory traversal to rename a file can be based on this answer. All we are required to do is to replace the file name instead of the extension in the accepted answer.
Here is one way - split the file name by _ and use the last index of the split list as the new name
import os
import sys
directory = os.path.dirname(os.path.realpath("/path/to/parent/folder")) #get the directory of your script
for subdir, dirs, files in os.walk(directory):
for filename in files:
subdirectoryPath = os.path.relpath(subdir, directory) #get the path to your subdirectory
filePath = os.path.join(subdirectoryPath, filename) #get the path to your file
newFilePath = filePath.split("_")[-1] #create the new name by splitting the old name by _ and grabbing last index
os.rename(filePath, newFilePath) #rename your file
Hope this helps.
check below code example for the first filename1, replace path with the actual path of the file:
import os
os.rename(r'path\\sample_2_description.txt',r'path\\description.txt')
print("File Renamed!")
I have a folder has 1000 jpg files with some repeated files and the repeated files with the same name + (2) as follow:
21_201739 (2).jpg
21_201739.jpg
21_201781.jpg
and so on...
I need to find all repeated filenames, cut and move them to another folder. For example, I need to cut
21_201739.jpg & 21_201739 (2).jpg
and move them to another folder
according to my little knowledge, I used the following script
import glob
import hashlib
import os
uniq = set()
for fname in glob.glob('*.jpg'):
with open(fname,"rb") as f:
sig = hashlib.sha256(f.read()).digest()
if sig not in uniq:
uniq.add(sig)
print(fname)
else:
print(fname, " (duplicate)")
but the result was Disappointing :
21_201739 (2).jpg
21_201739.jpg (duplicate)
21_201781.jpg (duplicate)
I think I made something wrong or missed something. Please, Can you help me?
Relatively new to python ( not using it everyday ). However I am trying to simplify some things. I basically have Keys which have long names however a subset of the key ( or file name ) has the same sequence of the associated folder.{excuse the indentation, it is properly indented.} I.E
file1 would be: 101010-CDFGH-8271.dat and folder is CDFGH-82
file2 would be: 101010-QWERT-7425.dat and folder is QWERT-74
import os
import glob
import shutil
files = os.listdir("files/location")
dest_1 = os.listdir("dest/location")
for f in files:
file = f[10:21]
for d in dest_1:
dire = d
if file == dire:
shutil.move(file, dest_1)
The code runs with no errors, however nothing moves. Look forward to your reply and chance to learn.
Sorry updated the format.
Try a variation of:
basedir = "dest/location"
for fname in os.listdir("files/location"):
dirname = os.path.join(basedir, fname[10:21])
if os.path.isdir(dirname):
path = os.path.join("files/location", fname)
shutil.move(path, dirname)
Ultimate Goal: Iterate over many files in a folder to perform a specific set of tasks.
Immediate Goal: Load next file (file2) to perform tasks
Background: I am using the following code
import os
folder = '/Users/eer/Desktop/myfolder/'
for subdir, dirs, files in os.walk(folder):
for item in os.listdir(folder):
if not item.startswith('.') and os.path.isfile(os.path.join(folder, item)): #gets rid of .DS_store file
print(item)
Output: print(item)
file1.txt
file2.txt
file3.txt
(etc...)
I am using the following code to open the first file:
data_path = folder + item
file = open(data_path, "r")
#perform a set of tasks for this file
This works well for opening the first file, file1.txt and performing a set of tasks.
However, I am not sure how to load file2.txt (and eventually file3.txt and etc...)so I can continue the task performance
Questions:
1) How do I put this code in a for loop? (so I can load, and perform tasks on all the files)?
You can do the file operations in the same loop like:
import os
folder = '/Users/eer/Desktop/myfolder/'
for subdir, dirs, files in os.walk(folder):
for item in os.listdir(folder):
if not item.startswith('.') and os.path.isfile(os.path.join(folder, item)):
data_path = folder + item
with open(data_path, "r") as file:
... use file here ...