Python confusion toward class instance - python-3.x

Question

[Class of players that accept a list then proceed to find the player with the highest score.]
class Player:
def __init__(self, name, score):
self.name = name
self.score = score
def best_score(list):
i = 0
while i < len(list):
n = list[i] #list[1] = (Bratt, 250) #list[2] = Lisa 150
s = list[i].score #list 1. score = 250 #list[2].score = 150
ace = list[0] #homer 50 #homer 50
hs = 0
if s > hs: #if s(250>0): #if s(list[2].score) > hs(250): nothing suppsoed to happen
ace = n #ace(homer) = n(list1) aka bratt #ace(bratt) != n because above
hs = s #hs(0) = s(list1) = 250 #hs(250) != list[2]150
#hs is now 250
i += 1
return ace
p1 = Player('Homer', 50)
p2 = Player('Bart', 250)
p3 = Player('Lisa', 150)
ls = [p1, p2, p3]
best = Player.best_score(ls)
msg = '{} has the best score, with {} points!'.format(best.name, best.score)
print(msg) # Bart has the best score, with 250 points!
For some reasons, my code does not return the highest player score and name. Instead, it gives me the latest player score and name instead.
I have tried checking it by going through the loop and it still does not make sense where did I go wrong.

Answer 1

We can focus on this part of the code:
while i < len(list):
hs = 0
if s > hs:
ace = n
hs = s
As it's written, s > hs is the same as s > 0, so the condition will be true for all items of the list that have a score greater than zero.
To keep the greatest value, it should be defined once before entering the loop, like this:
hs = 0
while i < len(list):
if s > hs:
ace = n
hs = s
With this change, the value of hs will be keep during iterations of the while loop, and in the end it will keep the best score as hs.