So Im trying to click this element:
//*[#id="ember1720"]
But Selenium tells me it can't find it. Im doing the operation like so: driver.find_element_by_xpath('//*[#id="ember1720"]').click()
I've tried the same program on the official python website and it works perfectly there.
First make sure the element has been loaded correctly:
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
...
WebDriverWait(driver, 20).until(
EC.presence_of_element_located((By.XPATH, """//*[#id="ember1720"]""")))
or maybe:
WebDriverWait(driver, 20).until(
EC.element_to_be_clickable((By.XPATH, """//*[#id="ember1720"]""")))
Alternatively, try to find the element by id:
driver.find_element_by_id('ember1720').click()
I've faced issues in the past where I could find the element by its ID but not by xpath.
I'm not sure if that's your exact problem, but depending on IDs like this, which seems to be auto generated are not a good practice.
Please read my blog post for the best practices for choosing the best locator.
Related
I'm new to Python selenium and today I'm stuck with an element, I don't know why but I can't find the element and sendkeys. Can anyone please explain for me why i can't find it by id / xpath / css selector ? and Also how can we find it and sendkeys ?
Here is a screenshot of the element:
and the website is : https://www.messenger.com/
PS: I've tried java_execute_script but it doesn't work, I still don't know how to use it well.
I'm use python to write selenium program. I think you can press a key F12 and check the html code.
I help you to checked the class name.
I checked the class name is _1mf , but I'm not sure what is your class name. You can check it.
enter image description here
And then, you need to use the following code to finish it.
k=driver.find_element_by_class_name("_1mf")
k.send_keys('testing')
from selenium.webdriver.common.keys import Keys
k.send_keys(Keys.RETURN)
'testing' is my input element. You can change it.
'k' is my variable. You can change it.
I'm not sure is this a correct answer.
You can also reference the following videos:
https://www.largitdata.com/course/105/
https://www.largitdata.com/course/104/
Please find below solution
inputBox = wait.until(EC.element_to_be_clickable((By.XPATH, "//div[#class='_kmc _7kpg navigationFocus']")))
actionChains = ActionChains(driver)
actionChains.move_to_element(inputBox).send_keys("Username").perform()
Note: Please add below import to your solution
from selenium import webdriver
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.action_chains import ActionChains
Hello I am trying to use selenium to find a button to click on. Below is a snippet of the HTML code i am working with.
<input type="button" id="runButton" class="button" value="Run Report" onclick="chooseRun()">
I am trying to click on the runButton with the code below.
elem = driver.find_element_by_id('runButton').click()
I am getting the following error message:
NoSuchElementException: Message: Unable to find element with css selector == [id="runButton"]
Not sure what else to try.
Most likely what you'll need to do to find your element is to use waits. You need to allow time for an element to be visible, clickable, etc. before you can interact with it. You can find information on waits here: https://selenium-python.readthedocs.io/waits.html
Taken from the above website:
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
elem = WebDriverWait(driver, 10).until(EC.presence_of_element_located((By.ID, "runButton"))
If waits do not work then it's possible that your element is inside an iframe. You will need to switch to that iframe first and then search for the element in order to find it.
You will find the iframe like you would another element and then switch to it like this:
iframe = driver.find_element_by_id("content_Iframe")
driver.switch_to.frame(iframe)
button = driver.find_element_by_id("runButton")
button.click()
Once you're done with the iframe and it's contents, you will need to switch back out of it:
driver.switch_to.default_content()
The element seems to be a dynamic element so to click() on the element you need to use element_to_be_clickable() and you can use either of the following Locator Strategies:
Using CSS_SELECTOR:
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "input.button#runButton[value='Run Report']"))).click()
Using XPATH:
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//input[#class='button' and #id='runButton'][#value='Run Report']"))).click()
Note : You have to add the following imports:
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
I am working with selenium in python 3.6 on the chrome browser. I have programmed it to the point where I can access the website I want but I am struggling to find the text box element I am searching for. When I inspect the element it has this code.
<input placeholder="" id="ember32" class="ssRegistrationField ssEmailTextboxField ember-text-field ember-view" type="email">
But when I try and use the given ID, it does not work and says that it cannot be found. Here is my code (Without the text I wish to insert of the website URL):
from selenium import webdriver
browser = webdriver.Chrome('chromedriver.exe')
browser.get('')
email = browser.find_element_by_id("ember34")
email.send_keys('')
I have just started using Selenium today and any help figuring out what is wrong would be very appreciated.
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
WebDriverWait(browser,5).until(
EC.presence_of_element_located((By.ID,'ember32')))
browser.find_element(By.ID,'ember32').send_keys('Your_Email')
The problem was the DOM has ember32 and your program is looking for ember34, Basic Typeo.
The code above will add an implicate wait for 5 seconds, search for ember32, and then time out if it cant find it.
The desired element is an Ember.js element so to click() on the element you have to induce WebDriverWait for the element_to_be_clickable() and you can use either of the following Locator Strategies:
Using CSS_SELECTOR:
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "input.ssRegistrationField.ssEmailTextboxField.ember-text-field.ember-view[id^='ember'][type='email']"))).send_keys("Max")
Using XPATH:
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//input[#class='ssRegistrationField ssEmailTextboxField ember-text-field ember-view' and starts-with(#id,'ember')][#type='email']"))).send_keys("Max")
Note : You have to add the following imports :
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
References
You can find a couple of relevant detailed discussions in:
How to click on the ember.js enabled button using Selenium and Python
Ember dropdown selenium xpath
I'm trying to check a checkbox via selenium in Chrome using python3.
This is the HTML code:
<header class="list-header">
<aside class="list-header-bulk-selection">
<input type="checkbox" class="sc-cSHVUG iAwiCZ">
::after
I'm trying to check the box by:
check_mark = driver.find_element_by_xpath("//input[#class='sc-cSHVUG iAwiCZ']")
check_mark.click()
I am able to find the location, but unfortunately I get the following error message:
ElementNotInteractableException: Message: element not interactable
(Session info: chrome=75.0.3770.142)
I think I have to access the ::after line, but I have no clue how I should do this.
Try following options to click on checkbox.
Option1:
location_once_scrolled_into_view
check_mark = driver.find_element_by_xpath("//input[#class='sc-cSHVUG iAwiCZ']")
check_mark.location_once_scrolled_into_view
check_mark.click()
Option2:
WebDriverWait and element_to_be_clickable
check_mark =WebDriverWait(driver,20).until(EC.element_to_be_clickable((By.XPATH,"//input[#class='sc-cSHVUG iAwiCZ']")))
check_mark.click()
Option3:
Java Scripts Executor
check_mark =WebDriverWait(driver,20).until(EC.element_to_be_clickable((By.XPATH,"//input[#class='sc-cSHVUG iAwiCZ']")))
driver.execute_script("arguments[0].click();", check_mark)
You need to import followings to execute above code.
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
This sc-cSHVUG iAwiCZ looks suspicious and most probably it's automatically generated each time you refresh the page. I would recommend to stick to something more "static", for example the checkbox should have some label or other text explaining what it does and you could stick to that text.
From what you've provided so far it might be better to locate this <aside> tag first and then use child axis to reach the checkbox like:
//aside[contains(#class, 'bulk-selection')]/child::input
More information:
XPath Tutorial
XPath Axes
XPath Operators & Functions
The desired element is a dynamic element so to click() on the element you have to induce WebDriverWait for the element_to_be_clickable() and you can use either of the following solutions:
Using CSS_SELECTOR:
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "header.list-header>aside.list-header-bulk-selection>input[type='checkbox']"))).click()
Using XPATH:
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//header[#class='list-header']/aside[#class='list-header-bulk-selection']/input[#type='checkbox' and #class]"))).click()
Note : You have to add the following imports :
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
Thank you guys so much. The thing was that ::after is a pseudo-element which is not interactable by selenium.
I actually solved it by accessing the checkbox and then hoovering over it (just a tiny bit) to sort of activate the HTML object. Then the checkbox was interactable.
from selenium.webdriver import ActionChains
check_mark = driver.find_element_by_xpath("//input[#class='sc-cSHVUG iAwiCZ']")
ActionChains(driver).move_to_element_with_offset(check_mark,0.001,0.001).click().perform()
I want to search a special keyword in Instagram. For example, I want to search this word:"fast food". I can send this key in search box. But, when I use submit method in Selenium by Python3, it doesn't work and give me error. This is my code:
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.common.alert import Alert
from selenium.webdriver.support.ui import WebDriverWait as wait
from selenium.webdriver.support import expected_conditions as EC
import time
driver = webdriver.Firefox()
url="https://www.instagram.com/p/pTPI-kyX7g/?tagged=resurant"
driver.get(url)
#login_button=driver.find_element_by_xpath("""/html/body/span/section/main/article/div[2]/div[2]/p/a""")
#login_button.click()
import time
driver.implicitly_wait(5)
search_button=driver.find_element_by_xpath("""/html/body/span/section/nav/div[2]/div/div/div[2]/input""")
search_button.send_keys("fast food")
search_button.submit()
This is gave error:
selenium.common.exceptions.NoSuchElementException: Message: Unable to locate element: ./ancestor-or-self::form
Could you help me?
Instead of. submit() try '.send_keys(u'\ue007')'
See: http://selenium-python.readthedocs.io/api.html#module-selenium.webdriver.common.keys
It need more clicks:
search_button=driver.find_element_by_xpath("""/html/body/span/section/nav/div[2]/div/div/div[2]/input""")
search_button.send_keys("fast")
while True:
search_button.send_keys(u'\ue007')
That is very interesting. Another solution is better. It is very important to know that, you must press 2 Enter press on Instagram search box. So, for eliminating while loop, you can use this code:
search_button.send_keys("#fast")
time.sleep(5)
search_button.send_keys(u'\ue007')
search_button.send_keys(u'\ue007')