Pig Two Computers Game - python-3.x

Question

I have an assignment where I need the computer to play a game of pig on his own and stop once 100 is rolled. So, I have two computer players going head to head, but the problem is that although the players could've had 100 total they keep going until turntotal >= 20 which in return gives the other player a chance to win because there was a point where 100 could be reached. It specifically states in our assignment to look out for this problem, but I have no clue how to go about solving this issue. Also any ways to make the code cleaner would be helpful.
def playerOne(score):
turntotal = 0
scoretotal = 0
while(scoretotal >= 0 and scoretotal <= 100):
while(scoretotal < 100):
roll = random.randint(1,6)
print('Rolled a ', roll)
if(turntotal <= 20 and roll != 1):
turntotal = turntotal + roll
scoretotal = scoretotal + roll
if(turntotal >= 20):
break
if(roll == 1):
scoretotal = scoretotal - turntotal
turntotal = 0
print('Pigged Out!!!')
break
print('Turn score =', turntotal)
turntotal = 0
return scoretotal
def printScore():
print(' ')
print("Player One score is", PlayerOneScore)
print("Player two score is", PlayerTwoScore)
print(' ')
PlayerOneScore = 0
PlayerTwoScore = 0
flipcoin = random.randint(1,2)
if(flipcoin == 1):
while(PlayerOneScore < 100 or PlayerTwoScore < 100):
printScore()
print("Player 1's turn")
PlayerOneScore += playerOne(PlayerOneScore)
if(PlayerOneScore >= 100):
break
printScore()
print("Player 2's turn")
PlayerTwoScore += playerOne(PlayerTwoScore)
if(PlayerTwoScore >= 100):
break
else:
while(PlayerOneScore < 100 or PlayerTwoScore < 100):
printScore()
print("Player 2's turn")
PlayerTwoScore += playerOne(PlayerTwoScore)
if(PlayerTwoScore >= 100):
break
printScore()
print("Player 1's turn")
PlayerOneScore += playerOne(PlayerOneScore)
if(PlayerOneScore >= 100):
break
printScore()
if(PlayerTwoScore > PlayerOneScore):
print("PLAYER 2 WINS")
else:
print("PLAYER 1 WINS")