Scenario:
I want function A to run every minute, but not 24/7. More like 5-10 hours per week. However, a simple cron outlining these times will not do here because the 5-10 hours per week are dynamic and keep changing.
Function B will run e.g. every 30 minutes and determine whether Function A should be running or not. If so, it will switch it 'on', if not, it will switch it 'off'
Is this doable using Serverless.com (or any of the FAAS providers it uses)?
Thanks in advance!
Solution #1: Use s3 to save switch state
You can have the second function write to a file on S3 the state of the switch (ON or OFF).
Schedule the first function to run every min. But make sure it checks the content of the "switch file" from S3 before it starts executing it's logic.
Cost
It won't cost you a lot because: 60 times an hour * 24 hours a day * 31 days a month = 44,640 calls / month. If it would take an extra 100ms to read the flag and you've set the memory to 1GB then this will translate to 44,640 * (0.00001667 GB-SECOND / 10 -100ms per second-) = $0.07441488 / month.
In addition to 44,640 S3 GET request (0.001 per 1,000 requests) = 44,640 * (0.001 / 1000) = $0.04464 / month.
Solution #2: Control the cron of func1 from func2
In function 2, using the AWS CloudWatchEvents API you can create/update the rule's ScheduleExpression (e.g. "cron(* * * * * *)") that that triggers function 1. Read more here
Related
I can't figure out how to create a job that ends at a specific hour and minute
If you break your cronjob into two, it would look like:
* 8-19 * * * command
0-30/1 19 * * * command
first line runs every minute from 8-19, and second line every minute from 19-19:30.
Cron triggers are not quite suitable for these types of schedules. If you do not insist on using a Cron trigger, I recommend that you check the Daily Time Interval trigger that is designed for use-cases such as yours. I am attaching a screenshot of a Daily Time Interval Trigger configuration for your use-case.
How do I achieve this? I mean, I can make it execute every n hours using triggers. But how do I make it execute every n hours, then every n + 1 hours, then repeat this loop?
You can change trigger of cron job with updating job trigger item (Trigger).
You can create a single trigger for this. For example "5 3-6/1 * * *" which stands for "At minute 5 past every hour from 3 AM through 6 AM."
After your business logic is done receive the trigger of the cron job set a new activation time and store it via model service.
This will re-schedule the cronjob out-of-the-box.
In you case it could be helping to configure the trigger at a fixed date in the past so the automatic re-scheduling do not happen.
If I wish to run my function app at 11.15 PM to next day 1.15 AM(That mean MONDAY 11.15 PM start and TUESDAY 1.15 AM will end) and it will trigger every minute during this time.
Can anyone help me to write this CRON expression?
The timer triggers are designed for a single repeating interval. The only way to do this completely within a Function is to run the trigger once per minute, then abort if the current time isn't in the desired target time period.
Alternately, put your logic into an HTTP trigger configured to act as a webhook, then use an Azure scheduler to configure start and stop times and intervals.
You won't be able to use the scheduler free plan since it can only run once per hour, but the standard plan can run once per minute. Scheduler pricing here.
You'll have to do this in three lines I think,
15-59 23 * * *
* 0 * * *
0-15 1 * * *
This will run it from 23:15-23:59 then 00:00-00:59 then 1:00-1:15
In AWS glue service there is an option to trigger job by custom CRON expression. Before i used this (0/2 * * ? *) cron expression to trigger job for every 2 hours.
Now I need to change the cron expression to trigger every 90 minutes, i.e for every 1 and a half hour. I tried with many cron expressions but that did not triggered for every 90 minutes. Even if i give for 90 minutes, it trigged for every 1 hour.
Can anyone help me out by providing the correct cron expression to trigger job for every 90 minutes ?
You can use the following pattern which was based on Bill Weiss' answer on Server Fault. It was modified to comply with the unique syntax AWS uses (reference here):
0 0-21/3 * * ? *
30 1-22/3 * * ? *
You'll have to define two separate Glue Triggers to accomplish this, each with the same job settings.
If curious, the syntax reads:
Run every 0th minute for every third hour for 0-21 hours
Run every 30th minute for every third hour for 1-22 hours
i need to run a job 'x' times a day. job timing is every (say 'y' hours) between 8am and 8pm.
i read the documentation of cron between could not figure out how to place the "between times". any suggestion or a good tutorial should be really helpful.i could figure out this much.
Found this in a tutorial. I believe this will serve the requierment
SimpleTrigger simpleTrigger = new SimpleTrigger("simpleTrigger", "triggerGroup-s1");
simpleTrigger.setStartTime(d);
simpleTrigger.setRepeatInterval(1000*60*60*24);
simpleTrigger.setRepeatCount(15);
simpleTrigger.setEndTime(new Date(ctime + 60000L));
simpleTrigger.setPriority(10);
scheduler.scheduleJob(jobDetail, simpleTrigger);
scheduler.start();
how could i modify the expression to serve my purpose.
You have a * in your example where you need to put the start/end hours:
0 8-20/y * * *
Where you replace y with the number of hours you want between runs should be fine. If you have some strange time like "1 hour and 15 minutes between runs", it's going to be a pain - probably just easier to calculate each time and enter it explicitly.
I don't know you can express this in cron expression.
However, you can use multiple Quartz triggers to serve this purpose.