I'm trying to prepare my data to be inserted in a SQL database, so certain pieces need to be surrounded by quotes.
For Each r In Range("A2", last_data)
r.Value2 = """ & r.Value2 & """
Next r
This just populates everything with 'r.value2'. Using a single quote makes it only appear on the right side of the word.
Essentially, the sheet needs to be modified so every word is surrounded by double quotes. I had a custom code in Excel that surrounded everything with quotes but when VBA reads the cells it ignores the custom formatting.
I think you need to escape the single, double quote within the ... er... quotes:
For Each r In Range("A2", last_data)
r.Value2 = """" & r.Value2 & """"
Next r
The fact that the escape character is, unfortunately, yet another double quote character, makes things a bit confusing.
So for each double quote that you want to add, you have an escape character ("), followed by the actual double quote that you want to add. These are then surrounded by two more double quotes, denoting that it is a string value.
I'm sorry if I haven't explained this well, but I hope you get the idea.
Although, as #Comintern suggests in comments, there is most likely a better way of doing what you want.
Related
I m trying to:
Replace double spaces with single.
Clean
Trim
the same string and i use:
AmountI = Replace(Application.WorksheetFunction.Clean(Trim(.Cells(j, 9).Value)), " ", " ")
I want to know if there is a specific order of those three VBA functions or the order does not play any role in the outcome.thanks for the help!
vba.trim doesn't remove double spacing, only leading/trailing spaces. You need the worksheet version Application.Trim or WorksheetFunction.Trim to remove interim double spaces.
If you have triple spacing, a single Replace will leave you with a double space. Application.Trim will not.
You don't want Clean to process characters (i.e. spaces) that you are going to remove anyways so Trim first.
.Value2 (without currency or date information) is marginally faster processing when you don't have currency or date data; you have a string so use .Value2.
AmountI = Application.Clean(Application.Trim(.Cells(j, 9).Value2))
AmountI = Trim(Replace(Application.WorksheetFunction.Clean(.Cells(j, 9).text), " ", " "))
My logic is:
1 .Text is faster than .Value
2 Clean may close up two spaces by removing a non-printing char between them, so do this before...
3 Turn double spaces to single with replace, then
4 Remove leading and trailing spaces
I am trying to include a single double quote in a string during a concatenation within JuliaLang, as below:
tmpStr = string(tmpStr, string("graph [label=\" hi \"]; "))
The output in the text file written with writedlm is:
graph [label="" hi ""]
How can I modify the string interpolation to include only a single double quote instead of this repetition?
The extra double quotes come from writedlm. writedlm uses standard CSV escaping method, which surrounds special characters with double quotes, and uses "" to represent a single double quote. This is OK, as long as you do the inverse transformation when reading the file.
A good method to trace such problems is to create a minimal working example. In this case, something like:
writedlm("tst.tst",["\""])
Which writes tst.tst, but tst.tst now has:
""""
But when read properly:
julia> data = readdlm("tst.tst")
1×1 Array{Any,2}:
"\""
As expected.
Another option to avoid getting the extra quotes is to add quotes=false as an option to writedlm, as in the following example:
julia> writedlm(STDOUT,["\""],quotes=false)
"
I am getting really confused in Groovy. When to use what for Strings in Groovy ?
1) Single Quotes - ' '
2) Double Quotes - " "
3) Triple Quotes - '''
My code:
println("Tilak Rox")
println('Tilak Rox')
println('''Tilak Rox''')
All tend to produce same results.
When to Use What ?
I would confuse you even more, saying, that you can also use slash /, dolar-slash $/ and triple-double quotes """ with same result. =)
So, what's the difference:
Single vs Double quote: Most important difference. Single-quoted is ordinary Java-like string. Double-quoted is a GString, and it allows string-interpolation. I.e. you can have expressions embedded in it: println("${40 + 5}") prints 45, while println('${ 40 + 5}') will produce ${ 40 + 5}. This expression can be pretty complex, can reference variables or call methods.
Triple quote and triple double-quote is the way to make string multiline. You can open it on one line in your code, copy-paste big piece of xml, poem or sql expression in it and don't bother yourself with string concatenation.
Slashy / and dollar-slashy $/ strings are here to help with regular expressions. They have special escape rules for '\' and '/' respectfully.
As #tim pointed, there is a good official documentation for that, explaining small differences in escaping rules and containing examples as well.
Most probably you don't need to use multiline/slashy strings very often, as you use them in a very particular scenarios. But when you do they make a huge difference in readability of your code!
Single quotes ' are for basic Strings
Double quotes " are for templated Strings ie:
def a = 'tim'
assert "Hi $a" == 'Hi tim'
Triple single quotes ''' are for multi-line basic Strings
Triple double """ quotes are for multi-line templated strings
There's also slashy strings /hello $a/ which are templated
And dollar slashy Strings $/hello $a/$ which are multi-line and templated
They're all documented quite well in the documentation
am exporting data from access to excel using vba , and i want to excel to receive these lines:-
=COUNTIF('Sheet1'!G2:G68,"1/1")
=COUNTIF('Sheet1'!G2:G68,"1/2")
etc...
my problem is that i can't add these double quotations right,i know that to print this symbol i should put it twice like this "" but still no luck,am getting all kinds of error,can you please modify my code:=
For r = 6 To 16
.Range("B" & r).Value = "=COUNTIF('Sheet1'!C1:C67,1/" & r - 5 & ")"
Next
thanks
If you wish to embed double quotes into the string you are building you can either do it by (as you mentioned) using two pairs of double quotes to 'escape' the double quote you are attempting to add, as follows:
"=COUNTIF('Sheet1'!C1:C67,""1/" & r - 5 & """)"
...which will return:
=COUNTIF('Sheet1'!C1:C67,"1/-5")
An important point to remember is that in order to properly escape the double quote you are inserting, you dont count the double quotes that are defining the string itself as one of the two pairs; That is why in the above example there are 4 pairs at the end:
""")"
The outer two define the string itself; the inner two represent the escaped double quote character.
I always found this form somewhat confusing, and would often opt to instead insert the double quotes by using the chr function, passing in the ascii value for the double quotes character, which is 34;
"=COUNTIF('Sheet1'!C1:C67," & chr(34) & "1/" & r - 5 & chr(34) & ")"
...which will return the same result as the first example:
=COUNTIF('Sheet1'!C1:C67,"1/-5")
Hope this helps,
nim
Is it possible to remove the " character using an Excel formula?
I tried the REPLACE function like this
REPLACE(<sometext>, """, "")
and this
REPLACE((<sometext>, char(34), "")
but it doesn't work.
NB: I am using the Polish version of Excel, so it is probable, that the syntax is different than in the English version. For example, in Polish formulas we use ; instead of , as argument separator.
The quotation mark character " must be represented by two of them "" when it's inside a string, to revolve the ambiguity between this "textual" quotation mark and the "code" quotation marks that delimit the beginning and end of your string.
In short, the right formula to remove all " from the text in A1 is:
=SUBSTITUTE(A1,"""","")
with emphasis on the fact that the old_text argument has to be """" (four quotes) and not """ (three quotes) as you wrote in your question.
And maybe SUBSTITUTE is called Replace in the Polish edition? Anyhow, you have to use the Polish equivalent of SUBSTITUTE and whatever argument separator is appropriate (; or ,).
Replace doesn't work the way, you want it to.
Use SUBSTITUTE.
=SUBSTITUTE(A1, CHAR(34), "-")
OR use ; as separator for your example
=SUBSTITUTE(A1; CHAR(34); "-")