Let's say I have:
file1.tsv
Foo\tBar\tabc\t123
Bla\tWord\tabc\tqwer
Blub\tqwe\tasd\tqqq
file2.tsv
123\tzxcv\tAAA\tqaa
asd\t999\tBBB\tdef
qwe\t111\tCCC\tabc
And I want to overwrite column 3 of file1.tsv with column 3 of file2.tsv to end up with:
Foo\tBar\tAAA\t123
Bla\tWord\tBBB\tqwer
Blub\tqwe\tCCC\tqqq
What would be a good way to do this in bash?
Take a look at this awk:
awk 'FNR==NR{a[NR]=$3;next}{$3=a[FNR]}1' OFS='\t' file{2,1}.tsv > output.tsv
If you want to use just bash, with little more effort:
while IFS=$'\t' read -r a1 a2 _ a4; do
IFS=$'\t' read -ru3 _ _ b3 _
printf '%s\t%s\t%s\t%s\n' "$a1" "$a2" "$b3" "$a4"
done <file1.tsv 3<file2.tsv >output.tsv
Output:
Foo Bar AAA 123
Bla Word BBB qwer
Blub qwe CCC qqq
Another way to do this can be, with correction as pointed out by #PesaThe:
paste -d$'\t' <(cut -d$'\t' -f1,2 file1.tsv) <(cut -d$'\t' -f3 file2.tsv) <(cut -d$'\t' -f4 file1.tsv)
The output will be:
Foo Bar AAA 123
Bla Word BBB qwer
Blub qwe CCC qqq
Related
How can I write a linux command to delete the last column of tab-delimited csv?
Example input
aaa bbb ccc ddd
111 222 333 444
Expected output
aaa bbb ccc
111 222 333
It is easy to remove the fist field instead of the last. So we reverse the content, remove the first field, and then revers it again.
Here is an example for a "CSV"
rev file1 | cut -d "," -f 2- | rev
Replace the "file1" and the "," with your file name and the delimiter accordingly.
You can use cut for this. You specify a delimiter with option -d and then give the field numbers (option -f) you want to have in the output. Each line of the input gets treated individually:
cut -d$'\t' -f 1-6 < my.csv > new.csv
This is according to your words. Your example looks more like you want to strip a column in the middle:
cut -d$'\t' -f 1-3,5-7 < my.csv > new.csv
The $'\t' is a bash notation for the string containing the single tab character.
You can use below command which will delete the last column of tab-delimited csv irrespective of field numbers,
sed -r 's/(.*)\s+[^\s]+$/\1/'
for example:
echo "aaa bbb ccc ddd 111 222 333 444" | sed -r 's/(.*)\s+[^\s]+$/\1/'
I want to use awk/sed to deal with two files(a.txt and b.txt) below and get the result
cat a.txt
a UK
b Japan
c China
d Korea
e US
And cat b.txt results
c Russia
e Canada
The result that I want is as below:
a UK
b Japan
c Russia
d Korea
e Canada
With awk:
First fill aray/hash a with complete row ($0) and use first column ($1) from this row as index. Finally, print all elements of array/hash a with a loop.
awk '{a[$1]=$0} END{for(i in a) print a[i]}' file1 file2
Output:
a UK
b Japan
c Russia
d Korea
e Canada
try:
awk 'FNR==NR{A[$1]=$NF;next} {printf("%s %s\n",$1,$1 in A?A[$1]:$NF)}' b.txt a.txt
Checking here condition FNR==NR which will be TRUE only when first file(b.txt) is being read. Then creating an array named A whose index is $1 and have the value last column. Then using printf for printing 2 strings where first string is $1 and another is if $1 of a.txt is present in array A then print array A's value whose index is $1 else print last column of a.tzt itself.
EDIT: as OP had carriage characters into Input_files so please remove them by following too.
tr -d '\r' < b.txt > temp_b.txt && mv temp_b.txt b.txt
You can use the below one-liner:
join -a 1 -a 2 a.txt <( awk '{print $1, "--", $0, "--"}' < b.txt ) | sed 's/ --$//' | awk -F ' -- ' '{print $NF}'
We use awk to prefix each line in b.txt with a key and -- to give us a split point later:
<( awk '{print $1, "--", $0, "--"}' < b.txt )
Use the join command to join the files on common keys. The -a 1 option tells the command to
join -a 1 -a 2 a.txt <( awk '{print $1, "--", $0, "--"}' < b.txt )
Use sed to remove the -- parts that are on some end of lines:
sed 's/ --$//'
Use awk to print the last item on each line:
awk -F ' -- ' '{print $NF}'
$ awk 'NR==FNR{b[$1]=$2;next} {print $1, ($1 in b ? b[$1] : $2)}' b.txt a.txt
a UK
b Japan
c Russia
d Korea
e Canada
I have two files, file1 and file2. I want to compare several columns - $1,$2 ,$3 and $4 of file1 with several columns $1,$2, $3 and $4 of file2 and print those rows of file2 that do not match any row in file1.
E.g.
file1
aaa bbb ccc 1 2 3
aaa ccc eee 4 5 6
fff sss sss 7 8 9
file2
aaa bbb ccc 1 f a
mmm nnn ooo 1 d e
aaa ccc eee 4 a b
ppp qqq rrr 4 e a
sss ttt uuu 7 m n
fff sss sss 7 5 6
I want to have as output:
mmm nnn ooo 1 d e
ppp qqq rrr 4 e a
sss ttt uuu 7 m n
I have seen questions asked here for finding those that do match and printing them, but not viceversa,those that DO NOT match.
Thank you!
Use the following script:
awk '{k=$1 FS $2 FS $3 FS $4} NR==FNR{a[k]; next} !(k in a)' file1 file2
k is the concatenated value of the columns 1, 2, 3 and 4, delimited by FS (see comments), and will be used as a key in a search array a later. NR==FNR is true while reading file1. I'm creating the array a indexed by k while reading file1.
For the remaining lines of input I check with !(k in a) if the index does not exists in a. If that evaluates to true awk will print that line.
here is another approach if the files are sorted and you know the used char set.
$ function f(){ sed 's/ /~/g;s/~/ /4g' $1; }; join -v2 <(f file1) <(f file2) |
sed 's/~/ /g'
mmm nnn ooo 1 d e
aaa ccc eee 4 a b
ppp qqq rrr 4 e a
sss ttt uuu 7 m n
fff sss sss 7 5 6
create a key field by concatenating first four fields (with a ~ char, but any unused char can be used), use join to find the unmatched entries from file2 and partition the synthetic key field back.
However, the best way is to use awk solution with a slight fix
$ awk 'NR==FNR{a[$1,$2,$3,$4]; next} !(($1,$2,$3,$4) in a)' file1 file2
No doubt that the awk solution from #hek2mgl is better than this one, but for information this is also possible using uniq, sort, and rev:
rev file1 file2 | sort -k3 | uniq -u -f2 | rev
rev is reverting both files from right to left.
sort -k3 is sorting lines skipping the 2 first column.
uniq -u -f2 prints only lines that are unique (skipping the 2 first while comparing).
At last the rev is reverting back the lines.
This solution sorts the lines of both files. That might be desired or not.
The content of the file is fixed.
Example:
2016-03-28T00:02 AAA 2016-03-28T00:03 ADASDASD
2016-03-28T00:03 BBB 2016-03-28T00:04 FAFAFDAS
2016-03-28T00:05 CCC 2016-03-28T00:06 SDAFAFAS
....
Which command can I use to get all sub-strings, AAA, BBB, CCC, etc.
you can use cut and awk and perl for this.
cat >> file.data << EOF
2016-03-28T00:02 AAA 2016-03-28T00:03 ADASDASD
2016-03-28T00:03 BBB 2016-03-28T00:04 FAFAFDAS
2016-03-28T00:05 CCC 2016-03-28T00:06 SDAFAFAS
EOF
AWK
awk '{ print $2 }' file.data
AAA
BBB
CCC
CUT
cut -d " " -f2 file.data
AAA
BBB
CCC
PERL
perl -alne 'print $F[1] ' file.data
AAA
BBB
CCC
You can use cut:
cut -d' ' -f 2 file
You can use AWK for this:
jayforsythe$ cat > file
2016-03-28T00:02 AAA 2016-03-28T00:03 ADASDASD
2016-03-28T00:03 BBB 2016-03-28T00:04 FAFAFDAS
2016-03-28T00:05 CCC 2016-03-28T00:06 SDAFAFAS
jayforsythe$ awk '{ print $2 }' file
AAA
BBB
CCC
To save the result to another file, simply add the redirection operator:
jayforsythe$ awk '{ print $2 }' file > file2
my file contains lines like this
any1 aaa bbb ccc
The delimiter is space. the number of words in the line is unknown
I want to put the first word into a var1. It's simple with
awk '{print $1}'
Now I want to put the rest of the line into a var2 with awk.
How I can print the rest of the line with awk ?
Better to use read here:
s="any1 aaa bbb ccc"
read var1 var2 <<< "$s"
echo "$var1"
any1
echo "$var2"
aaa bbb ccc
For awk only solution use:
echo "$s" | awk '{print $1; print substr($0, index($0, " ")+1)}'
any1
aaa bbb ccc
$ var=$(awk '{sub(/^[^[:space:]]+[[:space:]]+/,"")}1' file)
$ echo "$var"
aaa bbb ccc
or in general to skip some number of fields use a RE interval:
$ awk '{sub(/^[[:space:]]*([^[:space:]]+[[:space:]]+){1}/,"")}1' file
aaa bbb ccc
$ awk '{sub(/^[[:space:]]*([^[:space:]]+[[:space:]]+){2}/,"")}1' file
bbb ccc
$ awk '{sub(/^[[:space:]]*([^[:space:]]+[[:space:]]+){3}/,"")}1' file
ccc
Note that doing this gets much more complicated if you have a FS that's more than a single char, and the above is just for the default FS since it additionally skips any leading blanks if present (remove the first [[:space:]]* if you have a non-default but still single-char FS).
awk solution:
awk '{$1 = ""; print $0;}'`