I have a question on the Mathematics Stack Exchange site where I ask about generating an exponential regression equation.
One of the answers provides a mathematical solution to my problem. The solution is written in mathematical notation:
Unfortunately, I'm not a math wiz, and I'm having trouble translating the mathematical notation to Microsoft Excel syntax.
What would the math look like in Excel?
+--------------+---------------+
| X (AGE) | Y (CONDITION) |
+--------------+---------------+
| 0 | 20 |
| 1 | 20 |
| 2 | 20 |
| 3 | 20 |
| 4 | 20 |
| 5 | 20 |
| 6 | 18 |
| 7 | 18 |
| 8 | 18 |
| 9 | 18 |
| 10 | 16 |
| 11 | 16 |
| 12 | 14 |
| 13 | 14 |
| 14 | 12 |
| 15 | 12 |
| 16 | 10 |
| 17 | 8 |
| 18 | 6 |
| 19 | 4 |
| 20 | 2 |
+--------------+---------------+
I can verify that your formula for a translates as follows into Excel:
=SUMPRODUCT(E2:E22,F2:F22)/SUMSQ(E2:E22)
where my E2:E22 is just your x and my F2:F22 is ln(21-y). It gives the same answer, 0.147233112, as doing an exponential fit and forcing the intercept to be zero (which corresponds to setting b=1 in
y-21=b*exp(ax)
as you can verify by taking logs).
The formula quoted is the same as the one mentioned here under Simple linear regression without the intercept term (single regressor)
So this begs the question of whether b should, in fact, be equal to 1 and this is outside the scope of the question.
Related
I want 04 as output in premonth . Can some one help on this? tried diff format and no luck.
enter code here
premonth = str(int(time.strftime('%m'))-1)
tried using
python date of the previous month
but due to strftime restriction I am not able to proceed.
Not the best way but this should work:
a = str(int(time.strftime('%m'))-1)
a = '0'+a if len(a)==1 else a
The following f-string will give you what you need, it also handles January correctly by using arithmetic manipulation to ensure 1 becomes 12:
f'{(int(time.strftime("%m")) + 10) % 12 + 1:02}'
Breaking that down, an f-string is a modern way to build strings from arbitrary expressions, in a way that keeps formatting and data together (unlike the old "string".format(item, item) and even older "string" % (item, item)).
Inside that f-string is a rather complex looking expression which is formatted with :02, meaning two places, zero-padded on left.
The expression is what correctly decrements your month with proper wrapping, as you can see from the following table:
+-------+-----+-----+----++-------+-----+-----+----+
| Value | +10 | %12 | +1 || Value | +10 | %12 | +1 |
+-------+-----+-----+----++-------+-----+-----+----+
| 1 | 11 | 11 | 12 || 7 | 17 | 5 | 6 |
| 2 | 12 | 0 | 1 || 8 | 18 | 6 | 7 |
| 3 | 13 | 1 | 2 || 9 | 19 | 7 | 8 |
| 4 | 14 | 2 | 3 || 10 | 20 | 8 | 9 |
| 5 | 15 | 3 | 4 || 11 | 21 | 9 | 10 |
| 6 | 16 | 4 | 5 || 12 | 22 | 10 | 11 |
+-------+-----+-----+----++-------+-----+-----+----+
and the following statement:
print(", ".join([f'{mm}->{(mm + 10) % 12 + 1:02}' for mm in range(1, 13)]))
which outputs:
1->12, 2->01, 3->02, 4->03, 5->04, 6->05, 7->06, 8->07, 9->08, 10->09, 11->10, 12->11
I want to compose sales table for purchased and sold items to see total profit. It's easy to do when items are purchased and sold individually or as a lot. But how to handle situation when one buys collection of items and sells them one by one. For example, I buy a collection (C) of a hammer and a screwdriver and sell tools separately. If I would enter data into simple table as in the image, I would get wrong profit result.
When there are only two items, I could divide their purchase price randomly, but when there are many items and not all of them are yet sold, I can't easily see if this collection already made profit or not.
I expect correct output of profit. In this case collection cost was 10 and selling price of all collection items was 13. Thus it should show profit of 3, not loss of -7. I was thinking of adding 2 new column, like IsCollection, CollectionID. Then derive a formula, which would use either simple subtraction or would check price of a whole collection and subtract it from the sum of items that belong to that collection. Deriving such formula is another question... But maybe there is an easier way of accomplishing the same
I added a column COLLECTION to identify item who belong to a collection.
Then I used SUMIF to sum sell price for items which belong at the same collection.
Then I used IF in Profit column to use summed sell price or single sell price.
You need to define in some formula a range of cell (see below).
Problem: you can't add profit values to obtain Total profit.
I used opencalc (but it should be almost the same in Excel).
Content of
SUM_COLL (row2):
=SUMIF($A$1:$A$22;"="&A2;$D$1:$D$22)
SUM_COLL (row3):
=SUMIF($A$1:$A$22;"="&A3;$D$1:$D$22)
and so on.
Profit (row2):
=IF(A2<>"";E2-C2;D2-C2)
Profit (row3):
=IF(A3<>"";E3-C3;D3-C3)
+------------+-----------+-------------+------------+----------+--------+
| COLLECTION | Item name | Purch Price | Sell Price | SUM_COLL | Profit |
+------------+-----------+-------------+------------+----------+--------+
| | A | 1 | 1.5 | 0 | 0.5 |
+------------+-----------+-------------+------------+----------+--------+
| | B | 2 | 2.1 | 0 | 0.1 |
+------------+-----------+-------------+------------+----------+--------+
| C | C1 | 10 | 7 | 27 | 17 |
+------------+-----------+-------------+------------+----------+--------+
| C | C2 | 10 | 6 | 27 | 17 |
+------------+-----------+-------------+------------+----------+--------+
| D | D1 | 7 | 15 | 23 | 16 |
+------------+-----------+-------------+------------+----------+--------+
| | E | 8 | 12 | 0 | 4 |
+------------+-----------+-------------+------------+----------+--------+
| C | C3 | 10 | 14 | 27 | 17 |
+------------+-----------+-------------+------------+----------+--------+
| D | D2 | 7 | 8 | 23 | 16 |
+------------+-----------+-------------+------------+----------+--------+
| | | | | 0 | 0 |
+------------+-----------+-------------+------------+----------+--------+
| | | | | 0 | 0 |
+------------+-----------+-------------+------------+----------+--------+
| | | | | 0 | 0 |
+------------+-----------+-------------+------------+----------+--------+
| | | | | 0 | 0 |
+------------+-----------+-------------+------------+----------+--------+
Update:
I added two more column to make Profit summable:
COUNT_COLL (row2):
=COUNTIF($A$1:$A$22;"="&A2)
COUNT_COLL (row3):
=COUNTIF($A$1:$A$22;"="&A3)
Profit_SUMMABLE (row2)
=IF(A2<>"";(E2-C2)/G2;D2-C2)
Profit_SUMMABLE (row3)
=IF(A3<>"";(E3-C3)/G3;D3-C3)
+------------+-----------+-------------+------------+----------+--------+------------+-----------------+
| COLLECTION | Item name | Purch Price | Sell Price | SUM_COLL | Profit | COUNT_COLL | Profit_SUMMABLE |
+------------+-----------+-------------+------------+----------+--------+------------+-----------------+
| | A | 1 | 1.5 | 0 | 0.5 | 0 | 0.5 |
+------------+-----------+-------------+------------+----------+--------+------------+-----------------+
| | B | 2 | 2.1 | 0 | 0.1 | 0 | 0.1 |
+------------+-----------+-------------+------------+----------+--------+------------+-----------------+
| C | C1 | 10 | 7 | 27 | 17 | 3 | 5.6666666667 |
+------------+-----------+-------------+------------+----------+--------+------------+-----------------+
| C | C2 | 10 | 6 | 27 | 17 | 3 | 5.6666666667 |
+------------+-----------+-------------+------------+----------+--------+------------+-----------------+
| D | D1 | 7 | 15 | 23 | 16 | 2 | 8 |
+------------+-----------+-------------+------------+----------+--------+------------+-----------------+
| | E | 8 | 12 | 0 | 4 | 0 | 4 |
+------------+-----------+-------------+------------+----------+--------+------------+-----------------+
| C | C3 | 10 | 14 | 27 | 17 | 3 | 5.6666666667 |
+------------+-----------+-------------+------------+----------+--------+------------+-----------------+
| D | D2 | 7 | 8 | 23 | 16 | 2 | 8 |
+------------+-----------+-------------+------------+----------+--------+------------+-----------------+
| | | | | 0 | 0 | 0 | 0 |
+------------+-----------+-------------+------------+----------+--------+------------+-----------------+
| | | | | 0 | 0 | 0 | 0 |
+------------+-----------+-------------+------------+----------+--------+------------+-----------------+
| | | | | 0 | 0 | 0 | 0 |
+------------+-----------+-------------+------------+----------+--------+------------+-----------------+
...
...
| TOTAL | | | | | 87.6 | | 37.6 |
+------------+-----------+-------------+------------+----------+--------+------------+-----------------+
I have following problem:
I want to give scores to a range of numbers from 1-10 for example:
| | A | B |
|---|------|----|
| 1 | 1209 | 1 |
| 2 | 401 | 7 |
| 3 | 123 | 9 |
| 4 | 49 | 10 |
| 5 | 30 | 10 |
(Not sure if B is 100% correct but roughly)
I got the B values with
=ABS(CEILING(A1;MAX($A$1:$A$32)/10)*10/MAX($A$1:$A$32)-11)
It seems to work but if I for example take numbers like
| | A | B |
|---|------|----|
| 1 | 100 | 1 |
| 2 | 90 | 2 |
| 3 | 80 | 3 |
| 4 | 70 | 4 |
| 5 | 50 | 6 |
But I want 50 to be 10.
I would like to have it scalable so I can do it with a 1-10 or 1-100 or 5-27 or whatever scale and with however many numbers in the list and whatever numbers to score from.
Thanks!
Use this formula:
=$E$1 + ROUND((MIN($A:$A)-A1)/((MAX($A:$A)-MIN($A:$A))/($E$1-$E$2)),0)
It is scalable. You put the max and min in E1 and E2.
+----+-------+-----+
| ID | STORE | QTY |
+----+-------+-----+
| | | |
| 9 | 101 | 18 |
| | | |
| 8 | 154 | 19 |
| | | |
| 7 | 111 | 13 |
| | | |
| 9 | 154 | 18 |
| | | |
| 8 | 101 | 19 |
| | | |
| 7 | 101 | 13 |
| | | |
| 9 | 111 | 18 |
| | | |
| 8 | 111 | 19 |
| | | |
| 7 | 154 | 14 |
+----+-------+-----+
Suppose that I have 3 stores, and I'd like to take STORE for every id which qty is the same for every store.
e.g id 9 is in 3 stores, in every store has 18 qty,
but id 7 is in stores but in only two store has equal qty (in store 111 and 101 - in 154 - id has 14 qty); how can I get that result using grep?
Do you think that is impossible to get that one in one expressions? I thought about regex but I don't know in which way I get Qty and compare to another row. In my file it looks like:
Extract the first and last columns by cut, count the number of uniq combinations, and output only those whose count is 3 (i.e. the value is the same for all three stores):
$ cut -d\| -f2,4 | sort | uniq -c | grep '^ *3 '
3 8 | 19
3 9 | 18
I'm trying to find a solution without macros in excel for following problem:
There is a table containing ratings of a student for different time periods.
So the rating of the student with ID=1 was 1 from January to April and 3 from Mai to June.
Two other students had a constant ranking (6 and 9) from January to June
| A | B | C |D |
---| ----|------------|------------|-------|
1 | ID | START | END |RANKING|
2 | 1 | 01.01.2014 | 30.04.2014 | 1 |
3 | 1 | 01.05.2014 | 30.06.2014 | 3 |
4 | 2 | 01.01.2014 | 30.06.2014 | 6 |
5 | 3 | 01.01.2014 | 30.06.2014 | 9 |
Next table contains IDs (y axis) and Months (x axis)
| F | G | H | I | J | K | L |
---| ----|--------|--------|--------|--------|--------|--------|
1 | ID | 201401 | 201402 | 201403 | 201404 | 201405 | 201406 |
2 | 1 | | | | | | |
3 | 2 | | | | | | |
4 | 3 | | | | | | |
And I wish to feel this second table like this:
| ID | 201401 | 201402 | 201403 | 201404 | 201405 | 201406 |
| ----|--------|--------|--------|--------|--------|--------|
| 1 | 1 | 1 | 1 | 1 | 3 | 3 |
| 2 | 6 | 6 | 6 | 6 | 6 | 6 |
| 3 | 9 | 9 | 9 | 9 | 9 | 9 |
I tried to use Index and Match, but without any good results because I haven't found a posibility to use IF (if (
Could anybody help?
You can get what you're looking for with SUMPRODUCT
Given the layout you provided, this formula should work when put in G2 and filled down and over
=SUMPRODUCT(--($A:$A=$F2),--($B:$B<=G$1),--($C:$C>G$1),$D:$D)
That looks in column A for an ID matching F2, then for every one it finds of those:
It checks the date in column B against the date in G1
It checks the date in column C against the date in G1
If all criteria match, it returns the value in Column D
This assumes you only have one entry for each period, otherwise it will sum them.
Also, you can use SUMIFS, it's a little less easy to read but I think it's slightly more efficient than SUMPRODUCT (I'm not positive, just anecdotal evidence from usage)
=SUMIFS($D:$D,$A:$A,"="&$F3,$B:$B,"<="&G$1,$C:$C,">"&G$1)
It does the exact same thing, just with different syntax.