I know that Apache Spark persist method saves RDDs in memory and that if there is not enough memory space, it stores the remaining partitions of the RDD in the filesystem (disk). What I can't seem to understand is the following:
Imagine we have a cluster and we want to persist an RDD. Suppose node A does not have a lot of memory space and that node B does. Let's suppose now that after running the persist command, node A runs out of memory. The question now is:
Does Apache Spark search for more memory space in node B and try to store everything in memory?
Or given that there is not enough space in node A, Spark stores the remaining partitions of the RDD in the disk of node A even if there some memory space available in node B?
Thanks for your answers.
Normally Spark doesn't search for the free space. Data is cached locally on the executor responsible for a particular partition.
The only exception is the case when you use replicated persistence mode - in that case additional copy will be place on another node.
The closest thing I could find is this To cache or not to cache. I had plenty of situations when data was mildly skewed and was getting memory related exceptions/failures when trying to cache/persist into RAM, one way around it was to use StorageLevels like MEMORY_AND_DISK, but obviously it was taking longer to cache and than read those partitions.
Also in Spark UI you can find the information about executors and how much of their memory is used for caching, you can experiment and monitor how it behaves.
Related
Currently taking a course in Spark and came across the definition of an executor:
Each executor will hold a chunk of the data to be processed. This
chunk is called a Spark partition. It is a collection of rows that
sits on one physical machine in the cluster. Executors are responsible
for carrying out the work assigned by the driver. Each executor is
responsible for two things: (1) execute code assigned by the driver,
(2) report the state of the computation back to the driver
I am wondering what will happen if the storage of the spark cluster is less than the data that needs to be processed? How executors will fetch the data to sit on the physical machine in the cluster?
The same question goes for streaming data, which unbound data. Do Spark save all the incoming data on disk?
The Apache Spark FAQ briefly mentions the two strategies Spark may adopt:
Does my data need to fit in memory to use Spark?
No. Spark's operators spill data to disk if it does not fit in memory,
allowing it to run well on any sized data. Likewise, cached datasets
that do not fit in memory are either spilled to disk or recomputed on
the fly when needed, as determined by the RDD's storage level.
Although Spark uses all available memory by default, it could be configured to run the jobs only with disk.
In section 2.6.4 Behavior with Insufficient Memory of Matei's PhD dissertation on Spark (An Architecture for Fast and General Data Processing on Large Clusters) benchmarks the performance impact due to the reduced amount of memory available.
In practice, you don't usually persist the source dataframe of 100TB, but only the aggregations or intermediate computations that are reused.
The RDDs that are cached (in total 8) are not big, only around 30G, however, on Hadoop UI, it shows that the Spark application is taking lots of memory (no active jobs are running), i.e. 1.4T, why so much?
Why it shows around 100 executors (here, i.e. vCores) even when there's no active jobs running?
Also, if cached RDDs are stored across 100 executors, are those executors preserved and no more other Spark apps can use them for running tasks any more? To rephrase the question: will preserving a little memory resource (.cache) in executors prevents other Spark app from leveraging the idle computing resource of them?
Is there any potential Spark config / zeppelin config that can cause this phenomenon?
UPDATE 1
After checking the Spark conf (zeppelin), it seems there's the default (configured by administrator by default) setting for spark.executor.memory=10G, which is probably the reason why.
However, here's a new question: Is it possible to keep only the memory needed for the cached RDDs in each executors and release the rest, instead of holding always the initially set memory spark.executor.memory=10G?
Spark configuration
Perhaps you can try to repartition(n) your RDD to a fewer n < 100 partitions before caching. A ~30GB RDD would probably fit into storage memory of ten 10GB executors. A good overview of Spark memory management can be found here. This way, only those executors that hold cached blocks will be "pinned" to your application, while the rest can be reclaimed by YARN via Spark dynamic allocation after spark.dynamicAllocation.executorIdleTimeout (default 60s).
Q: Is it possible to keep only the memory needed for the cached RDDs in each executors and release the rest, instead of holding always the initially set memory spark.executor.memory=10G?
When Spark uses YARN as its execution engine, YARN allocates the containers of a specified (by application) size -- at least spark.executor.memory+spark.executor.memoryOverhead, but may be even bigger in case of pyspark -- for all the executors. How much memory Spark actually uses inside a container becomes irrelevant, since the resources allocated to a container will be considered off-limits to other YARN applications.
Spark assumes that your data is equally distributed on all the executors and tasks. That's the reason why you set memory per task. So to make Spark to consume less memory, your data has to be evenly distributed:
If you are reading from Parquet files or CSVs, make sure that they have similar sizes. Running repartition() causes shuffling, which if the data is so skewed may cause other problems if executors don't have enough resources
Cache won't help to release memory on the executors because it doesn't redistribute the data
Can you please see under "Event Timeline" on the Stages "how big are the green bars?" Normally that's tied to the data distribution, so that's a way to see how much data is loaded (proportionally) on every task and how much they are doing. As all tasks have same memory assigned, you can see graphically if resources are wasted (in case there are mostly tiny bars and few big bars). A sample of wasted resources can be seen on the image below
There are different ways to create evenly distributed files for your process. I mention some possibilities, but for sure there are more:
Using Hive and DISTRIBUTE BY clause: you need to use a field that is equally balanced in order to create as many files (and with proper size) as expected
If the process creating those files is a Spark process reading from a DB, try to create as many connections as files you need and use a proper field to populate Spark partitions. That is achieved, as explained here and here with partitionColumn, lowerBound, upperBound and numPartitions properties
Repartition may work, but see if coalesce also make sense in your process or in the previous one generating the files you are reading from
Intend to read data from an Oracle DB with pyspark (running in local mode) and store locally as parquet. Is there a way to tell whether a spark session dataframe will be able to hold the amount of data from the query (which will be the whole table, ie. select * from mytable)? Are there common solutions for if the data would not be able to fit in a dataframe?
* Saw a similar question here, but was a little confused by the discussion in the comments
As you are running on local, So I assume it is not on a cluster. You can not say exactly how much memory would require? However, you can go close to it. You check your respective table size that how much disk space it's using. Suppose you mytable has occupied 1GB of Hard disk then spark would be required RAM more than that, because Spark's engine required some memory for its own processing. Try to have 2GB extra, for safer side than actual table size.
To check you table size in Oracle, You can use below query:
select segment_name,segment_type,bytes/1024/1024 MB
from dba_segments
where segment_type='TABLE' and segment_name='<yourtablename>';
It will give you a result in MB.
To configure JVM related parameter in Apache-Spark you can check this.
It doesn't matter how big the table is if you are running spark in a distributed manner. You would need to worry about the memory if:-
You are reading the data in the driver and then doing a broadcast.
Caching the dataframe for some computation.
Usually for your spark application a DAG gets generated and if you are using JDBC source then the workers will read the data directly and use the shuffle space and off-heap to disk for memory intensive computation.
I'm relatively new to spark and I have a few questions related to the tuning optimizations with respect to the spark submit command.
I have followed : How to tune spark executor number, cores and executor memory?
and I understand how to utilise maximum resources out of my spark cluster.
However, I was recently asked how to define the number of cores, memory and cores when I have a relatively smaller operation to do as if I give maximum resources, it is going to be underutilised .
For instance,
if I have to just do a merge job (read files from hdfs and write one single huge file back to hdfs using coalesce) for about 60-70 GB (assume each file is of 128 mb in size which is the block size of HDFS) of data(in avro format without compression), what would be the ideal memory, no of executor and cores required for this?
Assume I have the configurations of my nodes same as the one mentioned in the link above.
I can't understand the concept of how much memory will be used up by the entire job provided there are no joins, aggregations etc.
The amount of memory you will need depends on what you run before the write operation. If all you're doing is reading data combining it and writing it out, then you will need very little memory per cpu because the dataset is never fully materialized before writing it out. If you're doing joins/group-by/other aggregate operations all of those will require much ore memory. The exception to this rule is that spark isn't really tuned for large files and generally is much more performant when dealing with sets of reasonably sized files. Ultimately the best way to get your answers is to run your job with the default parameters and see what blows up.
When I do sc.textFile("abc.txt")
Spark creates RDD in RAM (memory).
So does the cluster collective memory should be greater than size of the file “abc.txt”?
My worker nodes have disk space so could I use disk space while reading texfile to create RDD? If so how to do it?
How to work on big data which doesn’t fit into memory?
When I do sc.textFile("abc.txt") Spark creates RDD in RAM (memory).
The above point is not certainly true. In Spark, their is something called transformations and something called actions. sc.textFile("abc.txt") is transformation operation and it does not simply load data straight away unless you trigger any action eg count().
To give you a collective answer to your all questions, I would urge you to understand how spark execution works. Their is something called logical and physical plans.As part of physical plan, it does cost calculation(available resource calculation across the cluster(s)) before it starts the jobs. if you understand them, you will get clear idea on all your questions.
You first assumption is incorrect:
Spark creates RDD in RAM (memory).
Spark doesn't create RDDs "in-memory". It uses memory but it is not limited to in-memory data processing. So:
So does the cluster collective memory should be greater than size of the file “abc.txt”?
No
My worker nodes have disk space so could I use disk space while reading texfile to create RDD? If so how to do it?
No special steps are required.
How to work on big data which doesn’t fit into memory?
See above.