Validate if a Prefix in sheet2 has a matching value in sheet1 - excel

I have the following issue: In one workbook I have multiple sheets.
On Sheet 2 in column "D" starting on row 2, Is a list of 300+ prefixes of 4 digits long e.g. XFTZ, GHTU, ZAQS etc.
On Sheet 1 in column "R" starting on row 3, Is a list of 1000+ values that can have the following values e.g.: AAAA1234556 and ZAQS12565865.
The first value AAAA...... is allowed, where the second value ZAQS..... Should throw an error message when running the VBA code.
The list of values in both sheets can grow over time, so I would like to avoid hard coding of records. I would expect best solution here is to use something like this:
LastRowNr = Cells(Rows.Count, 1).End(xlUp).Row

Try something like the following, replacing Sheet1 with the name in which the actual data is located
Option Explicit
Private Sub searchPrefix()
Dim RangeInArray() As Variant
Dim LastRow1 As Long
Dim LastRow2 As Long
Dim tmpSrch As String
Dim i As Long
LastRow1 = Worksheets("Sheet1").Cells(Rows.Count, 18).End(xlUp).Row
LastRow2 = Worksheets("PREFIXES").Cells(Rows.Count, 4).End(xlUp).Row
RangeInArray = Application.Transpose(Worksheets("PREFIXES").Range("D1:D" & LastRow2).Value)
For i = 3 To LastRow1
If Len(Worksheets("Sheet1").Cells(i, 18).Value) >= 3 Then
tmpSrch = Left(Worksheets("Sheet1").Cells(i, 18).Value, 4) '18: column R
If IsInArray(tmpSrch, RangeInArray) Then
Worksheets("Sheet1").Cells(i, 18).Interior.ColorIndex = xlNone
Worksheets("Sheet1").Cells(i, 18).Font.ColorIndex = 0
Worksheets("Sheet1").Cells(i, 18).Font.Bold = False
Else
Worksheets("Sheet1").Cells(i, 18).Interior.Color = RGB(252, 134, 75)
Worksheets("Sheet1").Cells(i, 18).Font.Color = RGB(181, 24, 7)
Worksheets("Sheet1").Cells(i, 18).Font.Bold = True
End If
End If
Next
End Sub
Function IsInArray(stringToBeFound As String, arr As Variant) As Boolean
IsInArray = (UBound(Filter(arr, stringToBeFound)) > -1)
End Function

Option Explicit
Sub searchPrefix()
Sheets("PREFIXES").Select
Dim CellCntnt As String
Dim tmpSrch As String
Dim isFound As Boolean
isFound = False
Dim QtySrchChar As Integer
QtySrchChar = 4
Dim Cnt As Integer
Cnt = 0
Dim Tag As Integer
Cells.Range("A1").Select
Do Until IsEmpty(ActiveCell)
Cnt = Cnt + 1
ActiveCell.Offset(1, 0).Select
Loop
For Tag = 1 To Cnt - 1
CellCntnt = Cells(1 + i, 1).Value
tmpSrch = Left(CellCntnt, QtySrchChar)
Cells.Range("G1").Select
Do Until IsEmpty(ActiveCell)
If Left(ActiveCell.Value, QtySrchChar) = tmpSrch Then
QtySrchChar = QtySrchChar + 1
tmpSrch = Left(CellCntnt, QtySrchChar)
isFound = True
MsgBox ("True Tags introduced with Std.Prefix " & tmpSrch)
End If
If isFound Then
isFound = False
MsgBox ("False Tags introduced with Std.Prefix " & tmpSrch)
Cells.Range("G1").Select
Else
ActiveCell.Offset(1, 0).Select
End If
Loop
Next Tag
End Sub

Related

Separate each word after line breaks into new rows

My loop seems to create infinite rows and is bugging
For Each Cell In Workbooks(newBook).Sheets(1).Range("A1:A" & lRow)
Checker = Cell.Value
For Counter = 1 To Len(Checker)
If Mid(Checker, Counter, 1) = vbLf Then
holder = Right(Mid(Checker, Counter, Len(Checker)), Len(Checker))
Workbooks(newBook).Sheets(1).Range(Cell.Address).EntireRow.Insert
End If
Next
Next Cell
Use a reverse loop. For i = lRow to 1 Step -1. Also to separate word, you can use SPLIT().
Is this what you are trying?
Option Explicit
Sub Sample()
Dim ws As Worksheet
Dim lRow As Long
Dim i As Long, j As Long
Dim Ar As Variant
'~~> Change this to the relevant worksheet
Set ws = Sheet2
With ws
'~~> Find last row in Column A
lRow = .Range("A" & .Rows.Count).End(xlUp).Row
'~~> Reverse Loop in Column A
For i = lRow To 1 Step -1
'~~> Check if cell has vbLf
If InStr(1, .Cells(i, 1).Value, vbLf) Then
'~~> Split cell contents
Ar = Split(.Cells(i, 1).Value, vbLf)
'~~> Loop through the array from 2nd position
For j = LBound(Ar) + 1 To UBound(Ar)
.Rows(i + 1).Insert
.Cells(i + 1, 1).Value = Ar(j)
Next j
'~~> Replace cells contents with content from array from 1st position
.Cells(i, 1).Value = Ar(LBound(Ar))
End If
Next i
End With
End Sub
BEFORE
AFTER
This is my solution, works with 2 dimensional ranges as well and it works on Selection, so select the range with the cells you want to split and run the code.
Sub splitByNewLine()
Dim pasteCell As Range, rowCumulationTotal As Integer
rowCumulationTotal = 0
Dim arr() As Variant
arr = Selection
Selection.Clear
For i = 1 To UBound(arr)
Dim rowCumulationCurrent As Integer, maxElemsOnRow As Integer
rowCumulationCurrent = 0
maxElemsOnRow = 0
For j = 1 To UBound(arr, 2)
Dim elems() As String, elemCount As Integer
elems = Split(arr(i, j), vbLf)
elemCount = UBound(elems)
For k = 0 To elemCount
Cells(Selection.Row + i + rowCumulationTotal + k - 1, Selection.Column + j - 1) = elems(k)
If maxElemsOnRow < k Then
rowCumulationCurrent = rowCumulationCurrent + 1
maxElemsOnRow = k
End If
Next k
Next j
rowCumulationTotal = rowCumulationTotal + rowCumulationCurrent
Next i
Exit Sub
End Sub
Input:
Output:

how to hide rows that dont have data in the row

Public Sub caInvCompressRows(p_strInv As String)
Dim intRow As Integer
Dim intRowMch As Integer
Dim intCol As Integer
Dim bUsed As Boolean
Dim strTemp As String
Dim strSheet As String
Dim intSaveRow As Integer
strSheet = "cordINV-" & p_strInv
Call utlUnProtectSheet(strSheet, "alcatraz")
Sheets(strSheet).Select
Cells.Select
Rows.EntireRow.Hidden = False
Range("A1").Select
intRowMch = caINV_ROW_FIRST
While Cells(intRowMch, 1).Value <> "" Or Cells(intRowMch, 11).Value <> ""
For intRow = intRowMch + 1 To intRowMch + 6
If Cells(intRow, 1).Value = "" Then
If Cells(intRow, 11).Value = "" Then
Rows(intRow).EntireRow.Hidden = True
End If
End If
Next intRow
intRowMch = intRowMch + 9
Wend
End Sub
I want to hide rows that don't have data in them with the use of a button. each row contains three different groups of data that change which rows would need to be hidden. all data is pulled into columns C, O and AC and the rest is populated from that.
This formula checks if there is anything in row 2, simply by concatenating the whole row, trimming the result, and check if it is nothing but an empty string:
=TRIM(TEXTJOIN("";FALSE;2:2))=""
Sub HideRows()
If Range("d2").Value = "" Then
If Range("r2").Value = "" Then
If Range("af2").Value = "" Then
Rows("2:2").EntireRow.Hidden = True
End If
End If
End If
End Sub

How to create a nested loop to check if a value exists in a second list

I am trying to compare values in two lists. I want my code to compare a value in the first list and check all the entries in the second list. If there is a match then the code will print true next to the value in the first list and if not it will print false.
The problem I am having is that my code only compares values that are in the same row.
The code runs and I have tried it on a two smaller lists to make sure the data types are to same and there aren't any extra spaces or commas in the lists that would lead to a "False" output. I have also tried changing the order of the for and if statements but this doesn't work either.
Sub findvalues()
For i = 2 To 16
For j = 2 To 16
If Cells(i, 3).Value = Cells(i, 1).Value Then
Cells(i, 4).Value = "TRUE"
ElseIf Cells(i, 3).Value = Cells(j + 1, 1).Value Then
Cells(i, 4).Value = "TRUE"
Else
Cells(i, 4).Value = "FALSE"
End If
Next j
Next i
End Sub
Here are the two lists I am testing the code on
Slight mods to your code based on the data you provided in columns 1 & 3. As always, things could be improved but this should get you going ...
Sub findvalues()
Dim i As Long, j As Long, bResult As Boolean
For i = 2 To 16
strValueToLookFor = Cells(i, 1)
For j = 2 To 16
bResult = False
If strValueToLookFor = Cells(j, 3).Value Then
bResult = True
Exit For
End If
Next j
Cells(i, 6).Value = bResult
Next i
End Sub
... you may just need to flick the columns over so the first list searches on the second list or vice versa.
I don't see any need for VBA - formulas are the way to go - but to avoid two loops one could do this:
Sub findvalues()
Dim i As Long
For i = 2 To 130
Cells(i, 4).Value = IsNumeric(Application.Match(Cells(i, 1).Value, Range("C2:C130"), 0))
Next i
End Sub
Update: this does not cater for multiple matches.
There are many was to achieve that. one of them is by using IF & COUNTIF
Formula
=IF(COUNTIF($E$2:$E$6,A2)>0,"TRUE","FALSE")
Results:
VBA CODE
Option Explicit
Sub findvalues()
Dim i As Long
Dim rng As Range
With ThisWorkbook.Worksheets("Sheet1") 'Change if needed
Set rng = .Range("A2:A130") 'set rng to includes values from column A, rows 2:130
For i = 2 To 130 'Loop from row 2 to 130
'Check if the values in column C includes in the rng
If Application.WorksheetFunction.CountIf(rng, .Range("C" & i).Value) > 0 Then
.Range("D" & i).Value = "TRUE"
Else
.Range("D" & i).Value = "FALSE"
End If
Next i
End With
End Sub
VBA code to reconcile two lists.
Sub Reconciliation()
Dim endRow As Long
Dim ICount As Long
Dim Match1() As Variant
Dim Match2() As Variant
Dim ws As Worksheet
Set ws = Worksheets("Recon")
ICount = 0
endRow = ws.Cells(ws.Rows.Count, 2).End(xlUp).Row
endRow1 = ws.Cells(ws.Rows.Count, 11).End(xlUp).Row
Match1 = Sheet1.Range("b2:b" & endRow)
Match2 = Sheet1.Range("K2:K" & endRow1)
For i = LBound(Match1) To UBound(Match1)
For j = LBound(Match2) To UBound(Match2)
If Match1(i, 1) = Match2(j, 1) Then
ICount = ICount + 1
Sheet1.Range("C" & i + 1).Value = ICount
Sheet1.Range("L" & j + 1).Value = ICount
Else
End If
Next j
Next i
End Sub

Excel VBA: How to transform this kind of cells?

I am not sure if the title is correct. Please correct me if you have a better idea.
Here is my problem: Please see the picture.
This excel sheet contains only one column, let's say ColumnA. In ColumnA there are some cells repeat themselvs in the continued cells twice or three times (or even more).
I want to have the excel sheet transformed according to those repeated cells. For those items which repeat three times or more, keep only two of them.
[Shown in the right part of the picture. There are three Bs originally, target is just keep two Bs and delete the rest Bs.]
It's a very difficult task for me. To make it easier, it's no need to delete the empty rows after transformation.
Any kind of help will be highly appreciated. Thanks!
#
Update:
Please see the picture. Please dont delete the items if they show again...
EDITED - SEE BELOW Try this. Data is assumed to be in "Sheet1", and ordered data is written to "Results". I named your repeted data (A, B, C, etc) as sMarker, and values in between as sInsideTheMarker. If markers are not consecutive, the code will fail.
Private Sub ReOrderData()
Dim lLastRow As Long
Dim i As Integer
Dim a As Integer
Dim j As Integer
Dim sMarker As String
Dim sInsideTheMarker As String
'Get number of rows with data:
lLastRow = Worksheets("Sheet1").Cells(Rows.Count, 1).End(xlUp).Row
j = 0
k = 1
a = 2
'Scan all rows with data:
For i = 1 To lLastRow
If (Worksheets("Sheet1").Cells(i + 1, 1).Value = Worksheets("Sheet1").Cells(i, 1).Value) Then 'If two consecutive cells holds the same value
j = j + 1
If j = 1 Then
k = k + 1
a = 2
sMarker = Worksheets("Sheet1").Cells(i, 1).Value
Worksheets("Results").Cells(k, 1).Value = sMarker
End If
Else 'If not same values in consecutive cells
sInsideTheMarker = Worksheets("Sheet1").Cells(i, 1).Value
Worksheets("Results").Cells(k, a).Value = sInsideTheMarker
a = a + 1
j = 0
End If
Next i
End Sub
EDITION: If you want results in the same sheet ("Sheet1"), and keep the empty rows for results to look exactly as your question, try the following
Private Sub ReOrderData()
Dim lLastRow As Long
Dim i As Integer
Dim a As Integer
Dim j As Integer
Dim sMarker As String
Dim sInsideTheMarker As String
'Get number of rows with data:
lLastRow = Worksheets("Sheet1").Cells(Rows.Count, 1).End(xlUp).Row
j = 0
k = 1
a = 5
'Scan all rows with data:
For i = 1 To lLastRow
If (Worksheets("Sheet1").Cells(i + 1, 1).Value = Worksheets("Sheet1").Cells(i, 1).Value) Then 'If two consecutive cells holds the same value
j = j + 1
If j = 1 Then
k = i
a = 5
sMarker = Worksheets("Sheet1").Cells(i, 1).Value
Worksheets("Sheet1").Cells(k, 4).Value = sMarker
End If
Else 'If not same values in consecutive cells
sInsideTheMarker = Worksheets("Sheet1").Cells(i, 1).Value
Worksheets("Sheet1").Cells(k, a).Value = sInsideTheMarker
a = a + 1
j = 0
End If
Next i
End Sub
If you can delete the values that have more than two counts, then I suggest that this might work:
Sub count_macro()
Dim a As Integer
Dim b As Integer
a = 1
While Cells(a, 1) <> ""
b = WorksheetFunction.CountIf(Range("A1:A1000"), Cells(a, 1))
If b > 2 Then
Cells(a, 1).Delete Shift:=xlUp
End If
b = 0
a = a + 1
Wend
End Sub
This should do it. It takes input in column A starting in Row 2 until it ends, and ignores more than 2 same consecutive values. Then it copies them in sets and pastes them transposed. If your data is in a different column and row, change the sourceRange variable and the i variable accordingly.
Sub SETranspose()
Application.ScreenUpdating = False
Dim sourceRange As range
Dim copyRange As range
Dim myCell As range
Set sourceRange = range("A2", Cells(Rows.count, 1).End(xlUp))
Dim startCell As range
Set startCell = sourceRange(1, 1)
Dim i As Integer
Dim haveTwo As Boolean
haveTwo = True
For i = 3 To Cells(Rows.count, 1).End(xlUp).Row + 1
If Cells(i, 1).Value = startCell.Value Then
If haveTwo Then
range(startCell, Cells(i, 1)).Copy
startCell.Offset(0, 4).PasteSpecial Transpose:=True
Application.CutCopyMode = False
haveTwo = False
End If
End If
'if the letter changes or end of set, then copy the set over
'If LCase(Left(Cells(i, 1).Value, 1)) <> LCase(startCell.Value) Or _
'i = Cells(Rows.count, 1).End(xlUp).Row + 1 Then
If Len(Cells(i, 1).Value) > 1 Then
Set copyRange = Cells(i, 1)
copyRange.Copy
Cells(startCell.Row, Columns.count).End(xlToLeft).Offset(0, 1).PasteSpecial
Application.CutCopyMode = False
'Set startCell = sourceRange(i - 1, 1)
ElseIf Len(Cells(i, 1).Value) = 1 And Cells(i, 1).Value <> startCell.Value Then
Set startCell = sourceRange(i - 1, 1)
haveTwo = True
End If
Next i
'clear up data
Set sourceRange = Nothing
Set copyRange = Nothing
Set startCell = Nothing
Application.ScreenUpdating = True
End Sub

How to change my code to run it more speedy?

I've one workbook with 170K rows, I will delete all rows when the result between cells is 0,
For those operation, normally I use the code below, but with 170K (the rows will be deleted are 90K) the code run very slowly.
Someone know another way more performance.
Thank
Last = Cells(Rows.Count, "K").End(xlUp).Row
For i = Last To 2 Step -1
If (Cells(i, "K").Value + Cells(i, "L").Value) < 1 Then
Cells(i, "A").EntireRow.Delete
End If
Next i
As long as your fine putting the data on a new tab, the code below will do everything you need in 1.5 seconds.
Sub ExtractRows()
Dim vDataTable As Variant
Dim vNewDataTable As Variant
Dim vHeaders As Variant
Dim lastRow As Long
Dim i As Long, j As Long
Dim Counter1 As Long, Counter2 As Long
With Worksheets(1)
lastRow = .Cells(Rows.Count, "K").End(xlUp).row
vHeaders = .Range("A1:L1").Value2
vDataTable = .Range("A2:L" & lastRow).Value2
End With
For i = 1 To UBound(vDataTable)
If vDataTable(i, 11) + vDataTable(i, 12) > 0 Then
Counter1 = Counter1 + 1
End If
Next
ReDim vNewDataTable(1 To Counter1, 1 To 12)
For i = 1 To UBound(vDataTable)
If vDataTable(i, 11) + vDataTable(i, 12) > 0 Then
Counter2 = Counter2 + 1
For j = 1 To 12
vNewDataTable(Counter2, j) = vDataTable(i, j)
Next j
End If
Next
Worksheets.Add After:=Worksheets(1)
With Worksheets(2)
.Range("A1:L1") = vHeaders
.Range("A2:L" & Counter1 + 1) = vNewDataTable
End With
End Sub
Here, my approach for your problem according to rwilson's idea.
I already tested it. It very very reduce executing time. Try it.
Sub deleteRow()
Dim newSheet As Worksheet
Dim lastRow, newRow As Long
Dim sheetname As String
Dim startTime As Double
sheetname = "sheetname"
With Sheets(sheetname)
Set newSheet = ThisWorkbook.Worksheets.Add(After:=Sheets(.Name))
'Firstly copy header
newSheet.Rows(1).EntireRow.Value = .Rows(1).EntireRow.Value
lastRow = .Cells(.Rows.Count, "K").End(xlUp).row
newRow = 2
For row = 2 To lastRow Step 1
If (.Cells(row, "K").Value + .Cells(row, "L").Value) >= 1 Then
newSheet.Rows(newRow).EntireRow.Value = .Rows(row).EntireRow.Value
newRow = newRow + 1
End If
Next row
End With
Application.DisplayAlerts = False
Sheets(sheetname).Delete
Application.DisplayAlerts = True
newSheet.Name = sheetname
End Sub
Here is a non-VBA option you can try:
In column M compute the sum of columns K and L
Highlight column M and the click Find and select > Find
Type in 0 in the Find what box and also select values in the Look in box
Select Find all and in the box that shows the found items select all entires (click in the box and press CTRL + A)
On the ribbon select Delete and then Delete sheet rows
Now manually delete column M
I haven't tried this with 170k+ rows but maybe worth assessing performance versus the VBA loop.
thank at all for your ideas but the really fast code is: use an array tu populate whit the correct date and replare all table of the end sort the table:
Sub Macro13(control As IRibbonControl)
Dim avvio As Date
Dim arresto As Date
Dim tempo As Date
Application.ScreenUpdating = False
Application.Calculation = xlManual
avvio = Now()
Dim sh As Worksheet
Dim arng As Variant
Dim arrdb As Variant
Dim UR As Long, x As Long, y As Long
Dim MyCol As Integer
Set sh = Sheets("Rol_db")
MyCol = 1
sh.Select
UR = sh.Cells(Rows.Count, MyCol).End(xlUp).Row
ReDim arrdb(2 To UR, 1 To 12) As Variant
For x = 2 To UR
If Cells(x, 11) + Cells(x, 12) > 0 Then
For y = 1 To 12
arrdb(x, y) = Cells(x, y)
Next y
Else
For y = 1 To 12
arrdb(x, y) = ""
Next y
End If
Next x
sh.Range("A2:L" & UR) = arrdb
arresto = Now()
tempo = arresto - avvio
Debug.Print "Delete empty rows " & tempo
Range("A2:L" & UR).Sort key1:=Range("A2:L" & UR), _
order1:=xlAscending, Header:=xlNo
Range("A4").Select
ActiveWindow.FreezePanes = True
conclusioni:
Application.ScreenUpdating = True
Application.Calculation = xlCalculationAutomatic
End Sub
time for my sheet 170K 00:00:07.
as soon as I have a minute I feel a loop of the columns

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