Mongodb/mongoose omit a field in response [duplicate] - node.js

Question

I have a NodeJS application with Mongoose ODM(Mongoose 3.3.1). I want to retrieve all fields except 1 from my collection.For Example: I have a collection Product Which have 6 fields,I want to select all except a field "Image" . I used "exclude" method, but got error..
This was my code.
var Query = models.Product.find();
Query.exclude('title Image');
if (req.params.id) {
Query.where('_id', req.params.id);
}
Query.exec(function (err, product) {
if (!err) {
return res.send({ 'statusCode': 200, 'statusText': 'OK', 'data': product });
} else {
return res.send(500);
}
});
But this returns error
Express
500 TypeError: Object #<Query> has no method 'exclude'.........
Also I tried, var Query = models.Product.find().exclude('title','Image'); and var Query = models.Product.find({}).exclude('title','Image'); But getting the same error. How to exclude one/(two) particular fields from a collection in Mongoose.

Answer 1

Use query.select for field selection in the current (3.x) Mongoose builds.
Prefix a field name you want to exclude with a -; so in your case:
Query.select('-Image');
Quick aside: in JavaScript, variables starting with a capital letter should be reserved for constructor functions. So consider renaming Query as query in your code.

Answer 2

I don't know where you read about that .exclude function, because I can't find it in any documentation.
But you can exclude fields by using the second parameter of the find method.
Here is an example from the official documentation:
db.inventory.find( { type: 'food' }, { type:0 } )
This operation returns all documents where the value of the type field is food, but does not include the type field in the output.

Answer 3

Model.findOne({ _id: Your Id}, { password: 0, name: 0 }, function(err, user){
// put your code
});
this code worked in my project. Thanks!! have a nice day.

Answer 4

You could do this
const products = await Product.find().select(['-image'])

Answer 5

I am use this with async await
async (req, res) => {
try {
await User.findById(req.user,'name email',(err, user) => {
if(err || !user){
return res.status(404)
} else {
return res.status(200).json({
user,
});
}
});
} catch (error) {
console.log(error);
}

Answer 6

In the updated version of Mongoose you can use it in this way as below to get selected fields.
user.findById({_id: req.body.id}, 'username phno address').then(response => {
res.status(200).json({
result: true,
details: response
});
}).catch(err => {
res.status(500).json({ result: false });
});

Answer 7

I'm working on a feature. I store a userId array name "collectedUser" than who is collected the project. And I just want to return a field "isCollected" instead of "collectedUsers". So select is not what I want. But I got this solution.
This is after I get projects from database, I add "isCollected".
for (const item of projects) {
item.set("isCollected", item.collectedUsers.includes(userId), {
strict: false,
})
}
And this is in Decorator #Schema
#Schema({
timestamps: true,
toObject: {
virtuals: true,
versionKey: false,
transform: (doc, ret, options): Partial<Project> => {
return {
...ret,
projectManagers: undefined,
projectMembers: undefined,
collectedUsers: undefined
}
}
}
})
Finally in my controller
projects = projects.map(i => i.toObject())
It's a strange tricks that set undefined, but it really work.
Btw I'm using nestjs.

Answer 8

You can do it like this
const products = await Product.find().select({
"image": 0
});

Answer 9

For anyone looking for a way to always omit a field - more like a global option rather than doing so in the query e.g. a password field, using a getter that returns undefined also works
{
password: {
type: String,
required: true,
get: () => undefined,
},
}
NB: Getters must be enabled with option { toObject: { getters:true } }

Answer 10

you can exclude the field from the schema definition
by adding the attribute
excludedField : {
...
select: false,
...
}
whenever you want to add it to your result,
add this to your find()
find().select('+excludedFiled')