My .env file contains the following line:
DBENV='REMOTE'
when I was using a local database before I had it set to
DBENV='LOCAL'
But when I try to run my file, it does not recognize the change. It thinks it's still set to 'LOCAL':
In fact, when I delete the .env file altogether it still says that. I assume that means it's looking at some other .env file, but I don't know where.
The .env file is located in the root of my project's directory:
How do I get process.env to look at the correct environment file?
Are you remembering to require your .env file properly?
require('dotenv').config()
Also, are you remembering to restart your server after each change?
You are using the assignment operator (single =) in your if expression. This operator returns the value it assigned and is therefore equivalent to
process.env.DBENV = 'LOCAL'
if ('LOCAL') {
//...
}
which always evaluates to true.
Use comparison (== or ===) instead.
Related
I'm working on node project, I'm using .env file to hide some of data. The .env file worked normally, and after I added more informations it got some color letters for variable names and it won't detect my variables when i'm using:
mongodb+srv://MONGODB_USERNAME:MONGODB_PASSWORD#cluster0.ekxmb.mongodb.net/MONGODB_DATABASE_NAME?retryWrites=true&w=majority
I'm having following code in my .env file:
MONGODB_PASSWORD = testpassword;
MONGODB_USERNAME = testuser;
MONGODB_DATABASE_NAME = testdbname;
It works when I manually type in app.js file code like this:
"mongodb+srv://testuser:testpassword#cluster0.ekxmb.mongodb.net/testdbname?retryWrites=true&w=majority"
After I added some additional variables code got formed weirdly with colors on variable names.
Note: It worked with code where I'm importing variables from .env file before, but after weird .env format it won't work.
Putting a variable name in a string will just make it say that variable name. In addition, you don't have the environment variables loaded anywhere.
Install the dotenv npm package for processing the .env file. Then, add this to your code to load the config file:
require('dotenv').config();
Create variables for each of your environment variables from process.env.YOUR_VARIABLE_NAME. An easy way to do this is with destructuring:
let {MONGODB_USERNAME, MONGODB_PASSWORD, MONGODB_DATABASE_NAME} = process.env;
Properly insert these variables into the string. You can use template literals for this:
`mongodb+srv://${MONGODB_USERNAME}:${MONGODB_PASSWORD}#cluster0.ekxmb.mongodb.net/${MONGODB_DATABASE_NAME}?retryWrites=true&w=majority`
I'm a total newbie and I'm trying to do this project this is my first time, and it's almost done. I tried every method mentioned in this SO thread to move secret key from settings. In every method i got some kind of error, even from this official django doc mathod. I couldn't find where I'm making mistake.
When the secret key is inside the settings.py, everything is working super smooth. But I need to push my code in git, so i have to hide it from settings.py.
Right now im adding the details when i tried using django-environ, to keep secret key outside of settings.py.
im putting the contents inside the root project folder.
im using miniconda: 4.10.1. here is my requirement.txt.
# platform: linux-64
_libgcc_mutex=0.1=main
_openmp_mutex=4.5=1_gnu
appdirs=1.4.4=py_0
asgiref=3.3.4=pyhd3eb1b0_0
attrs=21.2.0=pyhd3eb1b0_0
black=19.10b0=py_0
ca-certificates=2021.5.30=ha878542_0
certifi=2021.5.30=py39hf3d152e_0
click=8.0.1=pyhd3eb1b0_0
django=3.2.4=pyhd3eb1b0_0
django-environ=0.4.5=py_1
importlib-metadata=3.10.0=py39h06a4308_0
krb5=1.17.1=h173b8e3_0
ld_impl_linux-64=2.35.1=h7274673_9
libedit=3.1.20210216=h27cfd23_1
libffi=3.3=he6710b0_2
libgcc-ng=9.3.0=h5101ec6_17
libgomp=9.3.0=h5101ec6_17
libpq=12.2=h20c2e04_0
libstdcxx-ng=9.3.0=hd4cf53a_17
mypy_extensions=0.4.1=py39h06a4308_0
ncurses=6.2=he6710b0_1
openssl=1.1.1k=h7f98852_0
pathspec=0.7.0=py_0
pip=21.1.2=py39h06a4308_0
psycopg2=2.8.6=py39h3c74f83_1
python=3.9.5=h12debd9_4
python_abi=3.9=1_cp39
pytz=2021.1=pyhd3eb1b0_0
readline=8.1=h27cfd23_0
regex=2021.4.4=py39h27cfd23_0
setuptools=52.0.0=py39h06a4308_0
six=1.16.0=pyh6c4a22f_0
sqlite=3.35.4=hdfb4753_0
sqlparse=0.4.1=py_0
tk=8.6.10=hbc83047_0
toml=0.10.2=pyhd3eb1b0_0
typed-ast=1.4.2=py39h27cfd23_1
typing_extensions=3.7.4.3=pyha847dfd_0
tzdata=2020f=h52ac0ba_0
wheel=0.36.2=pyhd3eb1b0_0
xz=5.2.5=h7b6447c_0
zipp=3.4.1=pyhd3eb1b0_0
zlib=1.2.11=h7b6447c_3
settings.py
import os
import environ
from pathlib import Path
env = environ.Env(
# set casting, default value
DEBUG=(bool, False)
)
# reading .env file
environ.Env.read_env()
# Build paths inside the project like this: BASE_DIR / 'subdir'.
BASE_DIR = Path(__file__).resolve().parent.parent
# Quick-start development settings - unsuitable for production
# See https://docs.djangoproject.com/en/3.2/howto/deployment/checklist/
# SECURITY WARNING: keep the secret key used in production secret!
SECRET_KEY = env('SECRET_KEY')
# False if not in os.environ
DEBUG = env('DEBUG')
im not adding the rest of settings. i dont think its important. if need please mention I.ll update.
i placed .env file in root of the project where manage.py and db.sqlite3 are placed
.env
#env file
DEBUG=on
#copied the entire line from settings.py
SECRET_KEY ='xxxx django secret key here xxxx'
while running "python manage.py runserver", i got this error.
im not sure what im missing. i got some kind of error, when i tried each method and errors are not same. sorry that i cannot explain every method and error here.
there are several questions asked in this form. but most are not answered and some are not accurately explains my situation. please mention if anything else is needed or for more clarification.
First check that you have installed django-environ and maybe you have a typing mistake in your requirements.txt it should be django-environ=0.4.5 instead of django-environ=0.4.5=py_1
you can pass the path of your .env inside read_env(env_file="relative_path_of_your_env_file")
it read a .env file into os.environ.
If not given a path to a dotenv path, does filthy magic stack backtracking
to find manage.py and then find the dotenv.
go through this code https://github.com/joke2k/django-environ/blob/master/environ/environ.py#L614
From the structure of the file tree, its clear that .env file is placed in the root folder of the project. When checking the error message, its visible that whoever is searching for .env file is checking at the same place as settings.py.
So, the short answer is if you are using django-environ to keep secret-key outside, place .env file together with settings.py in the same directory.
For a bit more elaborated content, you can refer to this link. I felt it is suitable for newbies.
When I try to create a JSCS config file:
C:\Blog\BlogWeb>jscs --auto-configure "C:\Blog\BlogWeb\temp.jscs"
I get the following error:
safeContextKeyword option requires string or array value
What parameter am I supposed to pass? What is a safecontextkeyword?
New to NPM and JSCS, please excuse ignorance.
JSCS was complaining that I didn't have a config file, so I was trying to figure out how to create one.
JSCS looks for a config file in these places, unless you manually specify it with the --config option:
jscs it will consequentially search for jscsConfig option in package.json file then for .jscsrc (which is a just JSON with comments) and .jscs.json files in the current working directory then in nearest ancestor until it hits the system root.
I fixed this by:
Create a new file named .jscsrc. Windows Explorer may not let you do this, so may need to use the command line.
Copy the following into it. It doesn't matter if this is the preset you want to use or not. The command will overwrite it.
{
"preset": "jquery",
"requireCurlyBraces": null // or false
}
Verify that it works by running a command such as:
run the command
jscs --auto-configure .jscsrc
I have the following configuration file in /etc/sysconfig/myconf:
export USER=root
export NODE_DIR=/opt/MyDir
I want to use these setting in my .js file, which located in /opt/myapplication:
var userApp = //USER in /etc/sysconfig/myconf file
var dir = //NODE_DIR in /etc/sysconfig/myconf file
Is there any way to do it without open the file and parse it contents?
As I understand the export should give me the option to read it easily in node.js, but I don't find how (In addition, when I run export -p, I don't see these variables)
EDIT: what I search is equal Node.js's command to source command in Linux (the variables is not environment variables)
If those environment variables are available when you launch the program, you can use process.env. https://nodejs.org/api/process.html#process_process_env
I have a file that is required in many other files, that are on different folders, inside the main directory.
Is there a way to just require the filename without having to write the relative path, or the absolute path? Like require('the_file'). And without having to go to npm and install it?
Create a folder inside your main directory , put the_file.js inside and set the NODE_PATH variable to this folder.
Example :
Let's say you create a ./libs folder within your main directory, you can just use :
export NODE_PATH = /.../main/lib
after that, you can require any module inside this directory using just :
var thefile = require('the_file')
To not have to do that every time, you'd have to add the variable to your .bashrc (assuming you're running a Unix system).
Or you can set a global variable inside your app.js file and store the path of your 'the_file' in it like so :
global.rootPath = __dirname;
Then you can require from any of your files using :
var thefile = require(rootPath+'/the_file')
These are the most convenient methods for me, short of creating a private npm, but there are a few other alternatives that I discovered when looking up an answer to your question, have a look here : https://gist.github.com/branneman/8048520