Get filename from url google sheet - excel

Question

I have a problem.
How to get the filename from the url?
enter image description here

Answer 1

I wouldn't normally do this since you haven't shown us what you've tried, but I'm feeling generous.
This function should work for you. (Note that you'll need to grant permissions for it to run.)
function getFileNames() {
var sheet = SpreadsheetApp.getActive().getSheetByName("Get_File_Name");
var links = sheet.getRange("A2:A").getValues();
var filenames = [];
for (var i = 0; i < links.length; i++) {
var url = links[i][0];
if (url != "") {
var filename = SpreadsheetApp.openByUrl(links[i][0]).getName();
filenames.push([filename]);
}
}
var startRow = 2; // print in row 2 since row 1 is the header row
var fileNameColumn = 2; // Column B = column 2
var destination = sheet.getRange(startRow, fileNameColumn, filenames.length, filenames[0].length);
destination.setValues(filenames);
}

Answer 2

Another way
function getFileNames() {
var driveApp = DriveApp;
// SET THE SHEET HERE
var sheet = SpreadsheetApp.getActive().getSheetByName("Sheet1");
//SET THE URL LINK COLUMN HERE : From row 2 since row 1 is the header row till last row
var links = sheet.getRange("P2:P").getValues();
var filenames = [];
for (var i = 0; i < links.length; i++) {
var fileId = getIdFromUrl(links[i][0]);
if (fileId != "" && fileId != null) {
var getfile = DriveApp.getFileById(fileId);
var filename = getfile.getName();
Logger.log(filename);
filenames.push([filename]);
} else {
filenames.push([""]);
}
}
// SET STARTING ROW TO PRINT: From row 2 since row 1 is the header row
var startRow = 2;
// SET WHICH COLUMN TO PRINT : Column A = column 1 / Column B = column 2
// MAKE SURE THE SHEET LAST COLUMN HEADER IS FILLED + 1 (next column)
var fileNameColumn = sheet.getLastColumn() + 1;
var destination = sheet.getRange(startRow, fileNameColumn, filenames.length, filenames[0].length);
destination.setValues(filenames);
}
function getIdFromUrl(url) { return url.match(/[-\w]{25,}/); }

Answer 3

You can create a custom function in spreadsheets like this.
function getSSName(name) {
var ss = SpreadsheetApp.openByUrl(url);
return ss.getName();
}