how can i save the file based on file path? - python-3.x

Question

i create browse button and it's show me what i want
this is my code
from PyPDF2 import PdfFileReader
import tkinter as tk
from tkinter import filedialog
root = tk.Tk()
label_list = []
def get_info(path):
with open(path, 'rb') as f:
pdf = PdfFileReader(f)
info = pdf.getDocumentInfo()
label_list[0].config(text=pdf.getNumPages())
label_list[1].config(text=info.author)
label_list[2].config(text=info.creator)
label_list[3].config(text=info.producer)
label_list[4].config(text=info.subject)
label_list[5].config(text=info.title)
def browsefunc():
filename = filedialog.askopenfilename()
pathlabel.config(text=filename)
get_info(filename)
browsebutton = tk.Button(root, text="Browse", command=browsefunc)
browsebutton.pack()
pathlabel = tk.Label(root)
pathlabel.pack()
for i in range(6):
label_list.append(tk.Label(root, text=""))
label_list[i].pack()
root.mainloop()
and how can i save or move to new dir from file path browse button?
I really hope for your help

Answer 1

Sounds like you want to have the browse window open starting in a different directory location than where your python script is (the default behavior)?
If so, give the directory name as the parameter to filedialog.askopenfilename() like so:
# Example Directories
# example_path = os.path.abspath('C:/Users/MyName/Desktop')
# example_path = os.path.abspath('C:/example/cwd/mydir/')
# or
example_path = os.path.abspath('C:/Windows/Temp')
filename = filedialog.askopenfilename(initialdir=example_path)
will open the file browser in that directory.