I'm new to python and I'm trying to keep part of the following:
'/this/is/my/path'
and I would like to keep this:
'/my/path'
My problem is that the path is dynamic and the length is not the same all the times. And practically I would like to 'delete' the first two parts.
If I use this:
os.getcwd().split("/")[2:5]
my problem is that is not dynamic and also it converts it into a list that I do not want.
Any ideas?
Related
I want to use printing command bellow in many places of my script. But I need to keep replacing "Survived" with some other string.
print(df.Survived.value_counts())
Can I automate the process by formating variable the same way as string? So if I want to replace "Survived" with "different" can I use something like:
var = 'different'
text = 'df.{}.value_counts()'.format(var)
print(text)
unfortunately this prints out "df.different.value_counts()" as as a string, while I need to print the value of df.different.value_counts()
I'm pretty sure alot of IDEs, have this option that is called refactoring, and it allows you to change a similar line of code/string on every line of code to what you need it to be.
I'm aware of VSCode's way of refactoring, is by selecting a part of the code and right click to select the option called change all occurances. This will replace the exact code on every line if it exists.
But if you want to do what you proposed, then eval('df.{}.value_counts()'.format(var)) is an option, but this is very unsecured and dangerous, so a more safer approach would be importing the ast module and using it's literal_eval function which is safer. ast.literal_eval('df.{}.value_counts()'.format(var)).
if ast.literal_eval() doesn't work then try this final solution that works.
def cat():
return 1
text = locals()['df.{}.value_counts'.format(var)]()
Found the way: print(df[var].value_counts())
I'm writing a script to scrape from another website with Python, and I am facing this question that I have yet to figure out a method to resolve it.
So say I have set to replace this particular string with something else.
word_replace_1 = 'dv'
namelist = soup.title.string.replace(word_replace_1,'11dv')
The script works fine, when the titles are dv234,dv123 etc.
The output will be 11dv234, 11dv123.
However if the titles are, dv234, mixed with dvab123, even though I did not set dvab to be replaced with anything, the script is going to replace it to 11dvab123. What should I do here?
Also, if the title is a combination of alphabits,numbers and Korean characters, say DAV123ㄱㄴㄷ,
how exactly should I make it to only spitting out DAV123, and adding - in between alphabits and numbers?
Python - making a function that would add "-" between letters
This gives me the idea to add - in between all characters, but is there a method to add - between character and number?
the only way atm I can think of is creating a table of replacing them, for example something like this
word_replace_3 = 'a1'
word_replace_4 = 'a2'
.......
and then print them out as
namelist3 = soup.title.string.replace(word_replace_3,'a-1').replace(word_replace_4,'a-2')
This is just slow and not efficient. What would be the best method to resolve this?
Thanks.
In my recently migrated from 2 to 3 Python code I have
list(reversed(zip(*positions)))
which generates the error
TypeError: 'zip' object is not reversible
I can fix this by changing the problematic code to
list(reversed(list(zip(*positions))))
but this seems like the wrong way to go about it.
What is the correct way to revers a zip in Python 3?
reversed is used to iterate on the list. It doesn't create a list on purpose, because it's often used just to iterate backwards on elements, not to create lists.
That's why you have to use list on it to create a list. And it needs a sequence to be able to get to the last element directly so you have to do list(zip()) in python 3.
Maybe you could shorten
list(reversed(list(zip(*positions))))
to
list(zip(*positions))[::-1]
it creates a list directly without the need for reverse so it's probably slightly faster too.
I want to have a matrix/cell, that has strings inside that I can access and use later as strings.
For instance, I have one variable (MyVar) and one cell (site) with names inside:
MyVar=-9999;
site={'New_York'; 'Lisbon'; 'Sydney'};
Then I want to do something like:
SitePosition=strcat(site{1},'_101'}
and then do this
save(sprintf('SitePosition%d',MyVar),);
This doesn't work at all! Is there a way to have strings in a matrix and access them in order to keep working with them if they were a string?
This:
MyVar=-9999; site={'New_York'; 'Lisbon'; 'Sydney'};
SitePosition = strcat(site{1},'_101');
save(sprintf('SitePosition%d',MyVar));
Works fine and yields SitePosition-9999.mat, note the syntax changes in lines 2 and 3.
Is there something else you're expecting?
EDIT: Based on your comment
Check out the documentation for save regarding saving specific variables
New example:
MyVar=-9999;
site={'New_York'; 'Lisbon'; 'Sydney'};
SitePosition = strcat(site{1},'_101');
save(SitePosition,'MyVar');
Creates New_York_101.mat with only the variable MyVar in it.
I am using a simple looping plugin so that my template looks like this:
{exp:loop_plus start="1" end="4" increment="1"}
<h3>{slide_{index}_title}</h3>
{/exp:loop_plus}
However, I am ending up with the following output:
<h3>{slide_1_title}</h3>
<h3>{slide_2_title}</h3>
<h3>{slide_3_title}</h3>
<h3>{slide_4_title}</h3>
Is there any way I can have dynamic variable names like this? I am not looking for alternative methods for building a slider, I simply would like to know if the dynamic variable names like this is possible. Thanks!
I'm assuming that Loop Plus (http://devot-ee.com/add-ons/loop-plus) sets the {index} part, so the question is what is defining {slide_1_title}...?
Assuming you have an entry field or variable with this defined, what you have is correct, but if it's not working, it means there's a parsing order issue.
Let's assume the code you supplied is wrapped in a {exp:channel:entries} tag pair, what happens is EE will try to parse the variable first, so will see: {slide_{index}_title} which doesn't exist. The {exp:loop_plus} add-on will then parse it, converting it to {slide_1_title} (but to late as channel:entries has already tried to parse it), which is what is finally output to the template.
So what you want to ensure is that EE parses {exp:loop_plus} before {exp:channel:entries}, do this using parse="inward" tag:
{exp:loop_plus start="1" end="4" increment="1" parse="inward"}
<h3>{slide_{index}_title}</h3>
{/exp:loop_plus}
This is a global EE parameter that EE uses to control parse order - you won't find it documented under the specific add-on. By adding the parameter, it means this child tag will get parsed before it's parent.
One way you could do it is to declare a preload_replace variable in your template and use it in your custom field name.
So something like:
{preload_replace:my_var_prefix="whatever"}
And then in your loop, you could then use:
{slide_{my_var_prefix}_title}