I have an autoencoder model that looks like:
input_img = Input(shape=(128, 128, 1))
x = Conv2D(...)(input_img)
x = MaxPooling2D(...)(x)
...
out = Conv2D(1, (3, 3), activation='sigmoid')(x)
my_model = Model(input_img, decoded)
my_model.compile(optimizer='adadelta', loss=my_custom_loss)
Currently, the shape of out is the same as input_img, let's say (None, 128, 128, 1). I would like to manipulate out to have shape (None, 128, 128, 2). The contents of that extra block are irrelevant.
In case anyone is wondering why I want to do this: it's because I intend to have some extra information in the ground truth values y_true so that I can define a specific cost function, my_custom_loss. It seems like in order to do this, the shape of out must match the shape of y_true when defining the cost function...
If the contents are truly irrelevant you can pad it with zeros. It could look something like:
zeros = Lambda(lambda x: K.zeros_like(x))(out) # (None, 128, 128, 1)
out = Concatenate([out, zeros]) # (None, 128, 128, 2)
Make sure you ignore the extra padding you are adding.
Related
I'm working on a basic RNN model for a multiclass task and I'm facing some issues with output dimensions.
This is my input/output shapes:
input.shape = (50000, 2, 5) # (samples, features, feature_len)
output.shape = (50000, 17, 185) # (samples, features, feature_len) <-- one hot encoded
input[0].shape = (2, 5)
output[0].shape = (17, 185)
This is my model, using Keras functional API:
inp = tf.keras.Input(shape=(2, 5,))
x = tf.keras.layers.LSTM(128, input_shape=(2, 5,), return_sequences=True, activation='relu')(inp)
out = tf.keras.layers.Dense(185, activation='softmax')(x)
model = tf.keras.models.Model(inputs=inp, outputs=out)
This is my model.summary():
Layer (type) Output Shape Param #
=================================================================
input_1 (InputLayer) [(None, 2, 5)] 0
_________________________________________________________________
lstm (LSTM) (None, 2, 128) 68608
_________________________________________________________________
dense (Dense) (None, 2, 185) 23865
=================================================================
Total params: 92,473
Trainable params: 92,473
Non-trainable params: 0
_________________________________________________________________
Then I compile the model and run fit():
model.compile(optimizer='adam',
loss=tf.nn.softmax_cross_entropy_with_logits,
metrics='accuracy')
model.fit(x=input, y=output, epochs=5)
And I'm getting a dimension error:
ValueError: Dimensions must be equal, but are 17 and 2 for '{{node Equal}} = Equal[T=DT_INT64, incompatible_shape_error=true](ArgMax, ArgMax_1)' with input shapes: [?,17], [?,2].
The error is clear, the model output a dimension 2 and my output has dimension 17, although I understand the issue, I can't find a way of fixing it, any ideas?
I think your output shape is not "output[0].shape = (17, 185)" but "dense (Dense) (None, 2, 185) ".
You need to change your output shape or change your layer structure.
LSTM output is a list of encoder_outputs, when you specify return_sequences=True. hence; I suggest just using the last item of encoder_outputs as the input of your Dense layer. you can see the example section of this link to the documentation. It may help you.
Can you please help me on below question. I have written below code for MNIST data set.
And in summary the first output is OK for me. But i am not sure why (None, 30, 24, 32) is displayed in second layer.
when 32(3*3) filter applied on 32*26*26, output should be 32*24*24.
Thanks in advance...
model = Sequential()
model.add(Convolution2D(32, (3, 3), activation='relu', input_shape=(1,28,28), data_format='channels_first'))
model.add(Convolution2D(32,3,3))
model.summary()
Layer (type) Output Shape Param #
=================================================================
conv2d_102 (Conv2D) (None, 32, 26, 26) 320
_________________________________________________________________
conv2d_103 (Conv2D) (None, 30, 24, 32) 7520
In Line 3 - model.add(Convolution2D(32,3,3)), the 2nd parameter kernel_size has been assigned 3 and the 3rd parameter stride has been assigned 3 instead of the kernel_size being assigned (3,3) or 3 and stride being assigned 1.
For reference, Convolution2D definition from Keras docs is:
`keras.layers.Conv2D(filters, kernel_size, strides=(1, 1), padding='valid', ...)`
So, Line 3 must be modified to: model.add(Convolution2D(32,(3,3))) or model.add(Convolution2D(32,3,1)) or just model.add(Convolution2D(32,3)) to achieve the desired convolution.
Note: Also data_format must be set to channels_first in order to get output to have shape: (None,32,24,24)
suppose I have data with shape (None, 32, 24) in Keras, means batch_size=None, I have a shared weight W with shape (24, 12), for each example X with shape (32, 24) in a batch , I want do matrix multiply Y = X # W, shape of Y is (32, 12), the shape of final output is (None, 32, 12).
how can I get the final output in Keras?
I try to get the batch_size with inputs.get_shape()[0] and use it in range() function to do the matrix multiply, use K.stack to get the final output, but batch_size is NoneType, range() doesn't support it.
I was trying to port CRNN model to Keras.
But, I got stuck while connecting output of Conv2D layer to LSTM layer.
Output from CNN layer will have a shape of ( batch_size, 512, 1, width_dash) where first one depends on batch_size, and last one depends on input width of input ( this model can accept variable width input )
For eg: an input with shape [2, 1, 32, 829] was resulting output with shape of (2, 512, 1, 208)
Now, as per Pytorch model, we have to do squeeze(2) followed by permute(2, 0, 1)
it will result a tensor with shape [208, 2, 512 ]
I was trying to implement this is Keras, but I was not able to do that because, in Keras we can not alter batch_size dimension in a keras.models.Sequential model
Can someone please guide me how to port above part of this model to Keras?
Current state of ported CNN layer
You don't need to permute the batch axis in Keras. In a pytorch model you need to do it because a pytorch LSTM expects an input shape (seq_len, batch, input_size). However in Keras, the LSTM layer expects (batch, seq_len, input_size).
So after defining the CNN and squeezing out axis 2, you just need to permute the last two axes. As a simple example (in 'channels_first' Keras image format),
model = Sequential()
model.add(Conv2D(512, 3, strides=(32, 4), padding='same', input_shape=(1, 32, None)))
model.add(Reshape((512, -1)))
model.add(Permute((2, 1)))
model.add(LSTM(32))
You can verify the shapes with model.summary():
_________________________________________________________________
Layer (type) Output Shape Param #
=================================================================
conv2d_4 (Conv2D) (None, 512, 1, None) 5120
_________________________________________________________________
reshape_3 (Reshape) (None, 512, None) 0
_________________________________________________________________
permute_4 (Permute) (None, None, 512) 0
_________________________________________________________________
lstm_3 (LSTM) (None, 32) 69760
=================================================================
Total params: 74,880
Trainable params: 74,880
Non-trainable params: 0
_________________________________________________________________
I'm a bit new to Keras and deep learning. I'm currently trying to replicate this paper but when I'm compiling the first model (without the LSTMs) I get the following error:
"ValueError: Error when checking target: expected dense_3 to have shape (None, 120, 40) but got array with shape (8, 40, 1)"
The description of the model is this:
Input (length T is appliance specific window size)
Parallel 1D convolution with filter size 3, 5, and 7
respectively, stride=1, number of filters=32,
activation type=linear, border mode=same
Merge layer which concatenates the output of
parallel 1D convolutions
Dense layer, output_dim=128, activation type=ReLU
Dense layer, output_dim=128, activation type=ReLU
Dense layer, output_dim=T , activation type=linear
My code is this:
from keras import layers, Input
from keras.models import Model
# the window sizes (seq_length?) are 40, 1075, 465, 72 and 1246 for the kettle, dish washer,
# fridge, microwave, oven and washing machine, respectively.
def ae_net(T):
input_layer = Input(shape= (T,))
branch_a = layers.Conv1D(32, 3, activation= 'linear', padding='same', strides=1)(input_layer)
branch_b = layers.Conv1D(32, 5, activation= 'linear', padding='same', strides=1)(input_layer)
branch_c = layers.Conv1D(32, 7, activation= 'linear', padding='same', strides=1)(input_layer)
merge_layer = layers.concatenate([branch_a, branch_b, branch_c], axis=1)
dense_1 = layers.Dense(128, activation='relu')(merge_layer)
dense_2 =layers.Dense(128, activation='relu')(dense_1)
output_dense = layers.Dense(T, activation='linear')(dense_2)
model = Model(input_layer, output_dense)
return model
model = ae_net(40)
model.compile(loss= 'mean_absolute_error', optimizer='rmsprop')
model.fit(X, y, batch_size= 8)
where X and y are numpy arrays of 8 sequences of a length of 40 values. So X.shape and y.shape are (8, 40, 1). It's actually one batch of data. The thing is I cannot understand how the output would be of shape (None, 120, 40) and what these sizes would mean.
As you noted, your shapes contain batch_size, length and channels: (8,40,1)
Your three convolutions are, each one, creating a tensor like (8,40,32).
Your concatenation in the axis=1 creates a tensor like (8,120,32), where 120 = 3*40.
Now, the dense layers only work on the last dimension (the channels in this case), leaving the length (now 120) untouched.
Solution
Now, it seems you do want to keep the length at the end. So you won't need any flatten or reshape layers. But you will need to keep the length 40, though.
You're probably doing the concatenation in the wrong axis. Instead of the length axis (1), you should concatenate in the channels axis (2 or -1).
So, this should be your concatenate layer:
merge_layer = layers.Concatenate()([branch_a, branch_b, branch_c])
#or layers.Concatenate(axis=-1)([branch_a, branch_b, branch_c])
This will output (8, 40, 96), and the dense layers will transform the 96 in something else.