Using ls command result in a loop - linux

I want to use the result of ls command in a loop to check if for example the first line is a directory, second etc.
For example I have this folder that contains one directory the script should display:
18_05_2018 is directory
enter image description here

Create a file named is_file_or_directory.sh containing:
cd "$1" || echo "Please specify a path" && exit
for i in *; do
if [[ -d $i ]]; then
echo "$i is a directory"
elif [[ -f $i ]]; then
echo "$i is a file"
else
echo "$i is not valid"
exit 1
fi
done
Make that file executable with:
sudo chmod +x is_file_or_directory.sh
Run the script specifying as a parameter the path that you want to analyze:
./is_file_or_directory.sh /root/scripts/
Output:
jeeves ~/scripts/stack # ./is_file_or_dir.sh /root/scripts/
databe.py is a file
is_file_or_dir.sh is a file
mysql_flask.py is a file
test is a directory
Here's a more detailed explanation of what is happening under the hood. The variable $1 is, in Bash, the first parameter sent to the script. In our case it is the path where the script will perform its actions. Then we use the variable $i in the loop.
$i content will be every file / folder name in the path $1. With -d and -f we check if $i is a file or a folder.

Related

How can I remove the extension of specific files in a directory?

I want to remove the extension of specific files with a given extension.
So for instance, in a directory foobar, we have foo.txt, bar.txt foobar.jpg.
Additionally, the extension that I've put in to be removed is txt
After calling the program, my output should be foo bar foobar.jpg
Here is my code so far:
#!/bin/bash
echo "Enter an extension"
read extension
echo "Enter a directory"
read directory
for file in "$directory"/*; do //
if [[ $file == *.txt ]]
then
echo "${file%.*}"
else
echo "$file"
fi
done
However when I run this on a given directory, nothing shows up.
I'm assuming that there is a problem with how I referred to the directory ( in the line where I placed a //) and I've tried to research on how to solve it but to no avail.
What am I doing wrong?
If files do exist in a valid directory you've entered then they should show up — with one exception. If you are using ~/ (shorthand home directory) then it will be treated as plain text in your for loop. The read variable should be substituted into another variable so the for loop can treat it as a directory (absolute paths should work normally as well).
#!/bin/bash
echo "Enter an extension"
read -r extension
echo "Enter a directory"
read -r directory
dir="${directory/#\~/$HOME}"
for file in "$dir"/*; do
if [[ $file == *."$extension" ]]
then
echo "${file%.*}"
else
echo "$file"
fi
done
You can simplify your for-loop:
for file in "$directory"/*; do
echo "${f%.$extension}";
done
The % instructions removes only matching characters. If nothing matches, the original string (here f) is returned.
When you write bash scripts it's more common to pass arguments to your script via command line arguments rather than by reading it from standard input via read program.
Passing arguments via command line:
#!/bin/bash
# $# - a bash variable which holds a number of arguments passed
# to script via command line arguments
# $0 holds the name of the script
if [[ $# -ne 2 ]]; then # checks if exactly 2 arguments were passed to script
echo "Usage: $0 EXTENSION DIRECTORY"
exit -1;
fi
echo $1; # first argument passed to script
echo $2; # second arugment passed to script
This approach is more efficient because a subprocess is spawn for read command to run and there is no subprocess spawn for reading command line arguments.
There is no need to manually loop through directory, you can use find command to find all files with given extension within given directory.
find /path/to/my/dir -name '*.txt'
find $DIRECTORY -name "*.$EXTENSION"
# note that single quotes in this context would prevent $EXTENSION
# variable to be resolved, so double quotes are used " "
# find searches for files inside $DIRECTORY and searches for files
# matching pattern '*.$EXTENSION'
Note that to avoid bash filename expansion sometimes it is required to wrap actual pattern in single quotes ' ' or double quotes " ". See Bash Filename Expansion
So now your script can look like this:
#!/bin/bash
if [[ $# -ne 2 ]]; then
echo "Usage: $0 EXTENSION DIRECTORY"
exit -1;
fi
$EXTENSION = $1 # for better readability
$DIRECTORY = $2
for file in `find $DIRECTORY -name "*.$EXTENSION"`; do
mv $file ${file%.$EXTENSION}
done
Construct ${file%.$EXTENSION} is called Shell Parameter Expansion it searches for occurrence of .$EXTENSION inside file variable and deletes it.
Notice that in the script it is easy to pass extension as directory and vice versa.
We can check if second argument is in fact directory, we can use following construction:
if ! [[ -d $DIRECTORY ]]; then
echo $DIRECTORY is not a dir
exit -1
fi
This way we can exit from the script earlier with more readable error.
To sum up entire script could look like this:
#!/bin/bash
if [[ $# -ne 2 ]]; then
echo "Usage: $0 EXTENSION DIRECTORY"
exit -1;
fi
EXTENSION=$1 # for better readability
DIRECTORY=$2
if ! [[ -d $DIRECTORY ]]; then
echo $DIRECTORY is not a directory.
exit -1
fi
for file in `find $DIRECTORY -name "*.$EXTENSION"`; do
mv $file ${file%.$EXTENSION}
done
Example usage:
$ ./my-script.sh txt /path/to/directory/with/files

Check that two file exists in UNIX Directory

Good Morning,
I am trying to write a korn shell script to look inside a directory that contains loads of files and check that each file also exists with .orig on the end.
For example if a file inside the directory is called 'mercury_1' there must also be a file called 'mercury_1.orig'
If there isn't, it needs to move the mercury_1 file to another location. However if the .orig file exists do nothing and move onto the next file.
I am sure it is really simple but I am not that experienced in writing Linux scripts and help would be greatly appreciated!!
Here's a small ksh snippet to check if a file exists in the current directory
fname=mercury_1
if [ -f $fname ]
then
echo "file exists"
else
echo "file doesn't exit"
fi
Edit:
The updated script that does the said functionality
#/usr/bin/ksh
if [ ! $# -eq 1 ]
then
echo "provide dir"
exit
fi
dir=$1
cd $dir
#process file names not ending with orig
for fname in `ls | grep -v ".orig$"`
do
echo processing file $fname
if [ -d $fname ] #skip directory
then
continue
fi
if [ -f "$fname.orig" ] #if equiv. orig file present
then
echo "file exist"
continue
else
echo "moving"
mv $fname /tmp
fi
done
Hope its of help!
You can use the below script
script.sh :
#!/bin/sh
if [ ! $# -eq 2 ]; then
echo "error";
exit;
fi
for File in $1/*
do
Tfile=${File%%.*}
if [ ! -f $Tfile.orig ]; then
echo "$File"
mv $File $2/
fi
done
Usage:
./script.sh <search directory> <destination dir if file not present>
Here, for each file with extension stripped check if "*.orig" is present, if not then move file to different directory, else do nothing.
Extension is stripped because you don't want to repeat the same steps for *.orig files.
I tested this on OSX (basically mv should not differ to much from linux). My test directory is zbar and destination is /tmp directory
#!/bin/bash
FILES=zbar
cd $FILES
array=$(ls -p |grep -v "/") # we search for file without extension so put them in array and ignore directory
echo $array
for f in $array #loop in array and find .orig file
do
#echo $f
if [ -e "$f.orig" ]
then
echo "found $f.orig"
else
mv -f "$f" "/tmp"
fi
done

Bash script with argument that makes file executable

I need to make a bash script that checks if the file or directory exists,then if the file does,it checks the executable permission.I need to modify the script to be able to give a file executable permissions from an argument.
Example: Console input ./exist.sh +x file_name should make the file executable.
This is the unfinished code that checks if the file/directory exists and if the file is executable or not. I need to add the chmod argument part.
#!/bin/bash
file=$1
if [ -x $file ]; then
echo "The file '$file' exists and it is exxecutable"
else
echo "The file '$file' is not executable (or does not exist)"
fi
if [ -d $file ]; then
echo "There is a directory named '$file'"
else
echo "There is no directory named '$file'"
fi
If you have optional arguments to your script, you need to check for them first.
In the case of just a couple of simple arguments, it would be simpler to check for them explicitly.
MAKEEXECUTABLE=0
while [ "${1:0:1}" = "+" ]; do
case $1 in
"+x")
MAKEEXECUTABLE=1
shift
;;
*)
echo "Unknown option '$1'"
exit
esac
done
file=$1
Then after you have determined that the file is not executable
if [ $MAKEEXECUTABLE -eq 1 ]; then
chmod +x $file
fi
Should you decide to add more complex options, you may want to use something like getops:example of how to use getopts in bash
Add chmod something like:
if [ ! -x "$file" ]; then
chmod +x $file
fi
This means if file does not have execute persmission, then add execute permission for the user.

linux zip and exclude dir via bash/shell script

I am trying to write a bash/shell script to zip up a specific folder and ignore certain sub-dirs in that folder.
This is the folder I am trying to zip "sync_test5":
My bash script generates an ignore list (based on) and calls the zip function like this:
#!/bin/bash
SYNC_WEB_ROOT_BASE_DIR="/home/www-data/public_html"
SYNC_WEB_ROOT_BACKUP_DIR="sync_test5"
SYNC_WEB_ROOT_IGNORE_DIR="dir_to_ignore dir2_to_ignore"
ignorelist=""
if [ "$SYNC_WEB_ROOT_IGNORE_DIR" != "" ];
then
for ignoredir in $SYNC_WEB_ROOT_IGNORE_DIR
do
ignorelist="$ignorelist $SYNC_WEB_ROOT_BACKUP_DIR/$ignoredir/**\*"
done
fi
FILE="$SYNC_BACKUP_DIR/$DATETIMENOW.website.zip"
cd $SYNC_WEB_ROOT_BASE_DIR;
zip -r $FILE $SYNC_WEB_ROOT_BACKUP_DIR -x $ignorelist >/dev/null
echo "Done"
Now this script runs without error, however it is not ignoring/excluding the dirs I've specified.
So, I had the shell script output the command it tried to run, which was:
zip -r 12-08-2014_072810.website.zip sync_test5 -x sync_test5/dir_to_ignore/**\* sync_test5/dir2_to_ignore/**\*
Now If I run the above command directly in putty like this, it works:
So, why doesn't my shell script exclude working as intended? the command that is being executed is identical (in shell and putty directly).
Because backslash quotings in a variable after word splitting are not evaluated.
If you have a='123\4', echo $a would give
123\4
But if you do it directly like echo 123\4, you'd get
1234
Clearly the arguments you pass with the variable and without the variables are different.
You probably just meant to not quote your argument with backslash:
ignorelist="$ignorelist $SYNC_WEB_ROOT_BACKUP_DIR/$ignoredir/***"
Btw, what actual works is a non-evaluated glob pattern:
zip -r 12-08-2014_072810.website.zip sync_test5 -x 'sync_test5/dir_to_ignore/***' 'sync_test5/dir2_to_ignore/***'
You can verify this with
echo zip -r 12-08-2014_072810.website.zip sync_test5 -x sync_test5/dir_to_ignore/**\* sync_test5/dir2_to_ignore/**\*
And this is my suggestion:
#!/bin/bash
SYNC_WEB_ROOT_BASE_DIR="/home/www-data/public_html"
SYNC_WEB_ROOT_BACKUP_DIR="sync_test5"
SYNC_WEB_ROOT_IGNORE_DIR=("dir_to_ignore" "dir2_to_ignore")
IGNORE_LIST=()
if [[ -n $SYNC_WEB_ROOT_IGNORE_DIR ]]; then
for IGNORE_DIR in "${SYNC_WEB_ROOT_IGNORE_DIR[#]}"; do
IGNORE_LIST+=("$SYNC_WEB_ROOT_BACKUP_DIR/$IGNORE_DIR/***") ## "$SYNC_WEB_ROOT_BACKUP_DIR/$IGNORE_DIR/*" perhaps is enough?
done
fi
FILE="$SYNC_BACKUP_DIR/$DATETIMENOW.website.zip" ## Where is $SYNC_BACKUP_DIR set?
cd "$SYNC_WEB_ROOT_BASE_DIR";
zip -r "$FILE" "$SYNC_WEB_ROOT_BACKUP_DIR" -x "${IGNORE_LIST[#]}" >/dev/null
echo "Done"
This is what I ended up with:
#!/bin/bash
# This script zips a directory, excluding specified files, types and subdirectories.
# while zipping the directory it excludes hidden directories and certain file types
[[ "`/usr/bin/tty`" == "not a tty" ]] && . ~/.bash_profile
DIRECTORY=$(cd `dirname $0` && pwd)
if [[ -z $1 ]]; then
echo "Usage: managed_directory_compressor /your-directory/ zip-file-name"
else
DIRECTORY_TO_COMPRESS=${1%/}
ZIPPED_FILE="$2.zip"
COMPRESS_IGNORE_FILE=("\.git" "*.zip" "*.csv" "*.json" "gulpfile.js" "*.rb" "*.bak" "*.swp" "*.back" "*.merge" "*.txt" "*.sh" "bower_components" "node_modules")
COMPRESS_IGNORE_DIR=("bower_components" "node_modules")
IGNORE_LIST=("*/\.*" "\.* "\/\.*"")
if [[ -n $COMPRESS_IGNORE_FILE ]]; then
for IGNORE_FILES in "${COMPRESS_IGNORE_FILE[#]}"; do
IGNORE_LIST+=("$DIRECTORY_TO_COMPRESS/$IGNORE_FILES/*")
done
for IGNORE_DIR in "${COMPRESS_IGNORE_DIR[#]}"; do
IGNORE_LIST+=("$DIRECTORY_TO_COMPRESS/$IGNORE_DIR/")
done
fi
zip -r "$ZIPPED_FILE" "$DIRECTORY_TO_COMPRESS" -x "${IGNORE_LIST[#]}" # >/dev/null
# echo zip -r "$ZIPPED_FILE" "$DIRECTORY_TO_COMPRESS" -x "${IGNORE_LIST[#]}" # >/dev/null
echo $DIRECTORY_TO_COMPRESS "compressed as" $ZIPPED_FILE.
fi
After a few trial and error, I have managed to fix this problem by changing this line:
ignorelist="$ignorelist $SYNC_WEB_ROOT_BACKUP_DIR/$ignoredir/**\*"
to:
ignorelist="$ignorelist $SYNC_WEB_ROOT_BACKUP_DIR/$ignoredir/***"
Not sure why this worked, but it does :)

Looping through files in different directory given command line argument

I'm trying to extend a script that implements something like a recycling bin for files on Linux. I have the code that I'm extending at the bottom.
In my extension, when the script is presented with the command line argument -cleanup I want to loop through files that are in the /home/7/bearm/.garbage directory, and have the user decide whether they want to delete the file or not.
However, I don't know how to detect when the command line argument is there. The command line can have other parameters, I just want to loop through the files when -cleanup is used.
I also do not know how to loop through files that are in a different directory (/home/7/bearm/.garbage).
How would I go around doing these things?
set directory = '/home/7/bearm/.garbage/'
if(! -d "$directory") then
mkdir .garbage
mv .garbage /home/7/bearm/
endif
set n = 1
while ($n <= $#argv)
set file = $argv[$n]
if(-d $file) then
#do nothing
echo "Cannot trash directory $file"
else
mv $file /home/7/bearm/.garbage
echo "Trashed $file"
endif
# n++
end
du -h /home/7/bearm/.garbage
To test if arguments contains -cleanup, you can do that (tested with ash on Minix3):
if echo "$#" | grep -- "-cleanup" >/dev/null 2>&1; then
echo "-cleanup is present..."
fi
Moreover, if you want a proper solution to use long GNU style options, see http://www.sputnick-area.net/scripts/getopts_long_example.sh and http://www.sputnick-area.net/scripts/getopts_long.sh
A bash version of your pseudo script :
#!/bin/bash
directory='/home/7/bearm/.garbage/'
mkdir -p "$directory"
for arg; do
if [[ -d $arg ]]; then
#do nothing
echo "Cannot trash directory $arg" >&2
else
mv "$arg" "$directory"
echo "Trashed $arg"
fi
done
du -sh "$directory"
Feel free to improve it with -cleanup switch.

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