This question already has answers here:
How to grep for contents after pattern?
(8 answers)
Closed 4 years ago.
I have .env file and I am trying to parse the value from it.
I ran this
cat .env | grep PORT=
I got
PORT=3333
How do I grab the value of a specific key?
cat env | grep PORT= | cut -d '=' -f2
Let say your input looks like this :
$ cat test.txt
Port=2020
Email=me#myserver.com
Version=2.02
Then this will do :
awk -F'=' '/^Version/ { print $2}' test.txt
Output
2.02
Use eval to parse the assignment line, later variable values can be substituted with $:
eval "$(grep ^PORT= .env)"
echo $PORT
Related
This question already has answers here:
Environment variable substitution in sed
(12 answers)
Closed 5 years ago.
For some reason, the answer in the post below doesn't work for me. Any thoughts?
how to use sed to replace a string in a file with a shell variable
I'm running CentOS 6.5
`NEW="new value"
cat myfile.txt | sed -e 's/old/${NEW}' <-- just replaces 'old' with '${NEW}'
cat myfile.txt | sed -e 's/old/$NEW' <-- just replaces 'old' with '$NEW'
cat myfile.txt | sed -e "s/old/${NEW}" <-- gives the error: unknown option to `s'
try taking the 's off the sed e.g
$ new=N
$ cat > j
one
two
three
$ sed -e "s/one/${new}/" j
N
two
three
for a more complete answer try this answer
This question already has answers here:
How to use variables in a command in sed?
(4 answers)
Closed 5 years ago.
I am a beginner at Linux and I'm trying to do a project which takes every line from a file.txt and replaces the third word with the first of each line. Here is my Shell code but it doesn't seem to work. It keeps replacing the third word with $field1 and not what's in it.
#!/bin/bash
while IFS=: read -r field1;do
sed -e 's/[^:]*[^:]/$field1/3'
done < file.txt
Try this, this will replace in the same file:
#!/bin/sh
while read -r line
do
first=`echo $line | awk -F':' '{ print $1 }'`
last=`echo $line | awk -F':' '{ print $3 }'`
echo $line | sed "s/$last/$first/"
done < file.txt
Input file :
ashish:is:good
navin:is:good
how:are:you
Output :
ashish:is:ashish
navin:is:navin
how:are:how
Make note of the single quotation marks. Place them around the field1 variable and so:
sed -e 's/[^:]*[^:]/'$field1'/3'
This question already has answers here:
How do I use shell variables in an awk script?
(7 answers)
Closed 6 years ago.
I want to add a word at the end of each line in my text file which is stored in variable. whenever i execute shell script instead of concatenate content stored in variable variable itself get concatenated. Below is the example for same:
Input:
cat output2.txt
12345
att1=Ramesh^Mumbai
awk '{print $0"^$att1"}' output2.txt >output3.txt
output:
12345^att1
Desired Output:
12345^Ramesh^Mumbai
Try this:
awk -v att1='Ramesh^Mumbai' -v OFS='^' '{print $0,att1}'
-v option allows to pass variable to awk
OFS is the output field separator (that will replace the , in the print statement by ^)
man awk:
-v var=val
Assign the value val to the variable var, before execution of
the program begins. Such variable values are available to the
BEGIN block of an AWK program.
you can use this;
#!/bin/bash
att1=Ramesh^Mumbai
awk -v att1=$att1 '{print $0"^"att1}' output.txt > output3.txt
Example;
user#host:/tmp$ cat output.txt
12345
abab
dafadf
adfaf
user#host:/tmp$, ./test.sh
user#host:/tmp$ cat output3.txt
12345^Ramesh^Mumbai
abab^Ramesh^Mumbai
dafadf^Ramesh^Mumbai
adfaf^Ramesh^Mumbai
This question already has answers here:
How to convert a string to lower case in Bash
(29 answers)
Closed 9 years ago.
I found solution but it doesn't working http://www.cyberciti.biz/faq/linux-unix-shell-programming-converting-lowercase-uppercase/
[root#mg0016 tmp]# y="this Is A test"
[root#mg0016 tmp]# echo "${y^^}"
-bash: ${y^^}: bad substitution
You can use any one of the following code :
$ tr '[:lower:]' '[:upper:]' < input.txt > output.txt
or
$ sed -e 's/\(.*\)/\U\1/' input.txt > output.txt
I found following one! and it works!
[spatel#mg0016 ~]$ echo "lower" | awk '{print toupper($0)}'
LOWER
Thanks for reply all.
This question already has answers here:
Capturing multiple line output into a Bash variable
(7 answers)
Closed 3 years ago.
This code should read from wget2.html and output the links found. But it gives me output without line breaks.
How can I force cat to add line breaks?
chksitename=$(cat wget2.html | grep -e "$sitename" | sed -e "s/^.*\("$sitename".*jpg\).*$/\1/g" | sort | uniq)
echo $chksitename
The problem is not in the cat line but in the echo line. To get the line breaks, you need to use:
echo "$chksitename"
See also Capturing Multiple Line Output to a Bash Variable.
I think you can replace your cat/grep/sed with one sed:
sed -e -n "/$sitename/ s#^.*\("$sitename".*jpg\).*$#\1#pg" wget.html
And you can replace sort | uniq to sort -u.
You could try:
echo $chksitename | tr ' ' '\n'