I'm trying to make an AHK script, that'll search through given file and get a line from it as a variable.
File looks like this:
word - another word
word1 - another word1
Let's say that "word" is %x%
I want the script to search for %x%, get the whole line with it and split the line to %x% and %y%, where %y% is "another word".
Unfortunately, code from Determine if string exists in file wasn't working for me as I wanted to, so I hope I made things here clear enough to understand.
Easy with a regex.
Let's say fCnt contains the contents of the file.
If RegExMatch(fCnt, "Om)^\Q" x "\E - (.+)$", m)
MsgBox % "The value of y is: " m.1
Related
I am currently looking for hidden data in a jpg file but I have no clue on how to operate.
There is a jpg file containing text in a format I have never seen before :
-ne \xff\xd8\xff\xe0\x00\x10\x4a\x46\x49\x46\x00\x01\x01\x01\x00\x60\x00\x60\x00\x00\xff\xdb\x00\x43\x00\x06\x04\x04\x05\x04\x04\x06\x05\x05\x05\x06\x06\x06\x07\x09\x0e\x09\x09\x08\x08\x09\x12\x0d\x0d\x0a\x0e\x15\x12\x16\x16\x15\x12\x14\x14\x17\x1a\x21\x1c\x17\x18\x1f\x19\x14\x14\x1d\x27\x1d\x1f\x22\x23\x25\x25\x25\x16\x1c\x29\x2c\x28\x24\x2b\x21\x24\x25\x24\xff\xdb\x00\x43\x01\x06\x06\x06\x09\x08\x09\x11\x09\x09\x11\x24\x18\x14\x18\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\x24\xff\xc0\x00\x11\x08\x01\x8e\x03\x4e\x03\x01\x22\x00\x02\x11\x01\x03\x11\x01\xff\xc4\x00\x1f\x00\x00\x01\x05\x01\x01\x01\x01\x01\x01\x00\x00\x00\x00\x00\x00\x00\x00\x01\x02\x03\x04\x05\x06\x07\x08\x09\x0a\x0b\xff\xc4\x00\xb5\x10\x00\x02\x01\x03\x03\x02\x04\x03\x05\x05\x04\x04\x00\x00\x01\x7d\x01\x02\x03\x00\x04\x11\x05\x12\x21\x31\x41\x06\x13\x51\x61\x07\x22\x71\x14\x32\x81\x91\xa1\x08\x23
-ne \x42\xb1\xc1\x15\x52\xd1\xf0\x24\x33\x62\x72\x82\x09\x0a\x16\x17\x18\x19\x1a\x25\x26\x27\x28\x29\x2a\x34\x35\x36\x37\x38\x39\x3a\x43\x44\x45\x46\x47\x48\x49\x4a\x53\x54\x55\x56\x57\x58\x59\x5a\x63\x64\x65\x66\x67\x68\x69\x6a\x73\x74\x75\x76\x77\x78\x79\x7a\x83\x84\x85\x86\x87\x88\x89\x8a\x92\x93\x94\x95\x96\x97\x98\x99\x9a\xa2\xa3\xa4\xa5\xa6\xa7\xa8\xa9\xaa\xb2\xb3\xb4\xb5\xb6\xb7\xb8\xb9\xba\xc2\xc3\xc4\xc5\xc6\xc7\xc8\xc9\xca\xd2\xd3\xd4\xd5\xd6\xd7\xd8\xd9\xda\xe1\xe2\xe3\xe4\xe5\xe6\xe7\xe8\xe9\xea\xf1\xf2\xf3\xf4\xf5\xf6\xf7\xf8\xf9\xfa\xff\xc4\x00\x1f\x01\x00\x03\x01\x01\x01\x01\x01\x01\x01\x01\x01\x00\x00\x00\x00\x00\x00\x01\x02\x03\x04\x05\x06\x07\x08\x09\x0a\x0b\xff\xc4\x00\xb5\x11\x00\x02\x01\x02\x04\x04\x03\x04\x07\x05\x04\x04\x00\x01\x02\x77\x00\x01\x02\x03\x11\x04\x05\x21\x31\x06\x12\x41\x51\x07\x61\x71\x13\x22\x32\x81\x08\x14\x42\x91\xa1\xb1\xc1\x09\x23\x33\x52\xf0\x15\x62\x72\xd1\x0a\x16\x24\x34\xe1\x25\xf1\x17\x18\x19\x1a\x26\x27\x28\x29\x2a\x35\x36\x37\x38\x39\x3a\x43\x44\x45\x46\x47\x48\x49
This is just the beggining of the file as there is at least a hundred lines.
The file type given by the command file : file.jpg: ASCII text, with very long lines
I tried some of the common tools to identify any patterns or hidden data like exiftools, strings, xxd but I found nothing.
If you have any idea on what to do it would be very much appreciated.
If it's a challenge of CTF, there are some common way to find out flag.
First try to find flag in file metadata, like description of file field
you can also try tool: stegsolve.jar.
In more advance sence, stego info hidden with some math calulation, give this tool a try: zsteg
Perhaps I'm misunderstanding the problem here, but if your file actually starts with a backslash character followed by the characters x, f, f, \, x, d, 8 and so on, then what you're looking at is the binary content of a JPG file that has been converted into ASCII text.
If so, you need to convert this back into binary data. For example, in Linux or MacOS, you could do this by entering the following on the command line:
echo -ne '\xff\xd8\xff\xe0\x00\x10\x4a\x46\x49\x46\x00\x01...etc...' > img.jpg
echo -ne '\x42\xb1\xc1\x15\x52\xd1\xf0\x24\x33\x62\x72\x82...etc...' >> img.jpg
(Note: > sends the results to a new file, and >> appends to the end of the file)
Or alternatively in Python:
with open("img.jpg","wb") as f:
f.write(b'\xff\xd8\xff\xe0\x00\x10\x4a\x46\x49\x46\x00\x01...etc...')
f.write(b'\x42\xb1\xc1\x15\x52\xd1\xf0\x24\x33\x62\x72\x82...etc...')
# and so on for all the other lines
Either way, you should end up with a file called img.jpg containing the image you're after.
I want to print off a line from a text file along with a variable I have created on the same line. My code looks like this.
print (lines[a] + answer)
The lines [a] is a random line from a text file I have created, answer is a variable I have created when I run this code it appears like like
"What is your favorite color,
red"
I want it to print off like this
"What is your favorite color, red"
Can anyone help me?
Simple:
print("%s %s" % (lines[a].rstrip(), answer))
Look at documentation: str.strip([chars]) or even str.rstrip([chars]).
I have a file where the first line looks something like this:
"Window Size" "Param 1" Result Time
So it basically has some words separated by spaces. I need a Linux command that will read the word at a specific position, where words enclosed in quatation marks should be seen as one word (and returned without the quatation marks).
So if I execute the command with the number 1 (doesn't matter if it starts from 0), the following should be returned:
Window Size
If executed with 3, it should return:
Result
Any idea how to do this, with awk maybe?
Let's say the name of your file containing your data is test.txt. One possible solution in BASH with arrays:
eval "E=( $(cat test.txt) )"
echo ${E[0]}
echo ${E[2]}
The output is:
Window Size
Result
I'm relatively new in trying things out in the command prompt.
In the end I'd like to write a batch file that can do the following things.
Look for files whose name does not contain "foo" or "bar" with the extension "txt"
in the current directory, including all sub directories,
and search for lines starting with "create file" or "create table,"
so that all corresponding matching lines would be put into a new file named "y"
In the form of name of file in which the line was found, location of the file, and the actual line containing the string.
Start by looking at these commands.
Commands
for,
find,
findstr
Use the /? argument for help.
Batch References
SS64,
DosTips,
Rob van der Woude,
Technet
I have a text file with a list in it:
dateformatfile.ext
dateformatfile.ext
dateformatfile.ext
...
I need to add a padded number to the end of each, like so:
dateformatfile.ext 00001
dateformatfile.ext 00002
dateformatfile.ext 00003
...
There are a lot, so I need to have a command to do this somehow.
Thanks in advance.
Assuming you want to do this for every line in your file, you can use the line number like this:
:execute "% normal A \<C-R>=printf(\"%05d\", line(\".\"))\<CR>"
where
execute(...) runs the string as a command
% normal runs a normal command on every line of the file
A appends to the line
<C-R>= inserts the result of a command
printf("%05d", ...) formats the second parameters as a five-digit number
line(".") gets the number of the current line
<CR> completes the <C-R>= insertion
if your text block is sitting at the beginning of the file. which means the line you want to append "00001" is the first line of your file, try this command, I just simply check the line ending with ext, you could change it to right regex if it is needed:
:%s/ext$/\="ext ".printf("%05d", line("."))/g
if the text block is not at the beginning of the file. You just check the first line (the line you want to append 00001) of the block and get the line number, for example, line number 5:
:let b=5|%s/ext$/\="ext ".printf("%05d", line(".")-b+1)/g
Here is my take.
Position cursor on first line where you want to add the first number.
:let i=0 Define a variable to hold the count.
qm Start to record a macro into register m.
A <C-R>=printf("%05d", i)<CR><ESC> Add a space and the ouput from printf.
:let i+=1 Increment the count for the next macro execution.
q End the recording of the macro.
jVG Visual select the rest of the document where we want to add numbers.
:normal #m Execute the macro to add the numbers to the selected lines.
I think this approach has some advantages:
No ugly escaping necessary.
The count is not tied to the line number. Allowing for offsets.
Using a macro can be easily combined with the :global command. For example:
:g/ext$/ normal #m Execute macro stored in register m on lines ending in ext.
One could very easily do this using awk. The NR variable gives you the record number, and records map to lines unless the RS variable is redefined. So the following:
awk -e '{ print $0 NR }' filename should do the trick. Padding them is an exercise left up to the reader.
I would do this using macros (I like macros :D).
First, let's take care of the numbers (we'll pad them later).
Add manually the number 1 at the end of the first line.
Then record this macro on the first line :
qq - record the macro q
$ - go at the end of the line
F<space> - go backward to the last space
"ay$ - copy till the end of the line in the buffer a
j$ - go at the end of the line below
"ap - copy the buffer content
<ctrl+A> - increment the number
q - stop recording the macro
Now you can apply it a bunch of times with 1000#q (it will stop at the end of the file).
This is not really pretty but it does the job.
For the padding, I would use another ugly trick. First, use a regex to match 3 digits numbers and add a 0 before, then do the same with 2 digits numbers (add two 0 this time) and so on...
vim macros are pretty ugly but they are useful to me when I am too tired to write a oneliner (I should learn awk though). Also, they can help you remember some obscure, yet useful vim shortcuts.
If you have PERL in your environment, you can run a PERL one-liner inside your VIM session.
:%! perl -pe " $count++ ; s/$/$count/"
The caveat is that you might have to use double quotes around your perl script. On my PC, PERL will run if I use single quotes. But I cannot address variables with the dollar sign.