Most frequent observation per row with two ranked tie-breakers - excel

I have a dataset in Excel where i would like a formula to find the most frequent observation (from column B to column F) for each row. However, if there are any ties there are two tie-breakers, ranked in the following order: The first tie-breaker is, that if the number 4 is tied as the most frequent observations in any row the result in that row should be 4. The second tie-breaker is that if there is a tie (where 4 is not tied for the most frequent observation) it should show the value in Column G.
In the picture below I have made a rough sketch of (to the left) the data I have now and (to the right) the outcome i want.
Picture of dataset:
What formula would I need to write, in order to get the result i would like?
Thanks in advance,
Anders

See if this works for you:
=IF(ISNA(MODE.MULT(MyData)),IF(ISNA(MATCH(4,MyData,0)),Fruit,4),IF(ISERR(INDEX(MODE.MULT(MyData),2)),MODE.MULT(MyData),IF(ISNA(MATCH(4,MODE.MULT(MyData),0)),Fruit,4)))
entered as an array formula CTRL-SHIFT-ENTER.
Here MyData is a placeholder for a row of data. In your example, MyData will be a single row from columns B-F; for case A, MyData={1,1,1,1,2}. Fruit is a placeholder the corresponding value from column G. You can replace MyData with B2:F2 and Fruit with G2 then copy and paste to other locations.
Here's how it works. The formula uses Excel's MULT.MODE function, which returns as many mode values as there are in the data.
MULT.MODE returns N/A when there are no repeated elements in MyData. This is the situation for your cases D and E. This means there is an N-way tie, so we need to apply the tie breaking rules. This is done by using the MATCH function to see if 4 is found in MyData; if it is, return 4, otherwise return Fruit.
If MyData has repeated elements, MULT.MODE returns an array containing the mode or modes found. If there is no tie, MULT.MODE returns a single element, otherwise the array will have at least two elements. To test for ties, we attempt access to the 2nd element of the array with use INDEX(MULT.MODE(MyData),2). This will throw an error if there is no tie.
If there is no tie, detect the resulting error with ISERR. With no tie, we return the result of MULT.MODE.
If there is a tie, no error occurs. In that case, we use MATCH to look for 4 in the results of MULT.MODE. If 4 is found, we return 4; if not return Fruit.
Hope that helps.

#xidgel: This is a great answer, but you'll also have to account for the case where all observations are the same.
=IF(ISNA(MODE.MULT(MyData)),
IF(ISNA(MATCH(4,MyData,0)),Fruit,4),
IF(ROWS(MODE.MULT(MyData))<2,
IF(AND(COUNTIF(MyData,"<>"&MODE.MULT(MyData))=0,MODE.MULT(MyData)<>4),Fruit,MODE.MULT(MyData)),
IF(ISNA(MATCH(4,MODE.MULT(MyData),0)),Fruit,4)))
entered as an array formula CTRL-SHIFT-ENTER.

Related

How to find the 3 highest values and respective category for a cell

Here is an example of the data I'm trying to organize:
I'm looking for a way to automatically see the top 3 categories (column) for each Name# (row). The size of the category is determined by the number below the category.
Ideally, I'd also like to see a percentage breakdown (from the total) for each category. For example, in row "Name3" 2 categories make up a significantly larger portion of the total values. However, without this percentage breakdown, the 3 top values would seem to be comparable, when they are in fact, not.
Interested to see how this would all work with duplicate numbers, too.
I've tried Excel's rank function, but this doesn't tell me the categories that have the 3 largest sizes, just the 3 highest values.
With Office 365:
=FILTER(SORTBY($B$1:$H$1,B2:H2,-1),SORT(B2:H2,1,-1,TRUE)>=LARGE(B2:H2,3))
And copy down.
If there are ties it will expand the results to include it. It finds the third highest value and returns everything that is equal to or greater than it.
This approach spills all the results at once (array version). In cell J2, you can put the following formula:
=LET(D, A1:H5, A, TAKE(D,,1), DROP(REDUCE("", DROP(A,1), LAMBDA(ac,aa,
VSTACK(ac, TAKE(SORT(DROP(FILTER(D, (A=aa) + (A="")),,1),2,-1,1),1,3)))),1))
It assumes as per input data the cell A1 is empty (if not it can be adjusted accordingly). Here is the output:
An alternative that doesn't require previous assumption (but it is not really a hard one) is the following:
=LET(names, A2:A5, Data, B2:H5, colors, B1:H1, DROP(REDUCE("", names,
LAMBDA(ac,n, VSTACK(ac, TAKE(SORT(VSTACK(colors, INDEX(Data, XMATCH(n,names),0))
,2,-1,TRUE),1,3)))),1))
The non-array version can be obtained from previous approach, and expand it down:
=TAKE(SORT(VSTACK($B$1:$H$1,INDEX($B$2:$H$5, XMATCH(A2,$A$2:$A$5),0)),2,-1,TRUE),1,3)
Explanation
To spill the entire solution it uses DROP/REDUCE/VSTACK pattern. Check my answer to the following question: how to transform a table in Excel from vertical to horizontal but with different length.
For the first formula we filter for a given element of A name (aa) via FILTER the input data (D) to select rows where the name is empty (to consider the header) OR (plus (+) condition) the name is equal to aa. We remove via DROP the first column of the filter result (names column). Next we SORT by the second row (the first rows are the colors) in descending order (-1) by column (last input parameter of SORT we can use TRUE or 1). Finally, we use TAKE to take the first three columns and the first row.
For the second approach, we select the values for a given row (names equals n) and use INDEX to select the entire row (column index 0), then we form an array via VSTACK to add as first row the colors and use the similar logic as in previous approach for sorting and select the corresponding rows and column (colors).
Notes:
If you don't have VSTACK function available, then you can replace it as follow: CHOOSE({1;2}, arr1,arr2) and substitute arr1, arr2, wit the corresponding arrays.
In the second formula instead of INDEX/XMATCH you can use: DROP(FILTER(Data, names=n),,1), it is a matter of personal preference.

In Excel, How do I return a list of values that match a description?

My question is that I want to return a list of values in column B in sheet 2 (or in this case NBA Players) that contain the value "PG" in cell A3 in sheet 1, from column A in sheet 2. Not only do I want it to match "PG" but I also want the value to have a salary (Column C) that is between $7100 (Cell B2 in Sheet 1) and $8000 (Cell C2) in Sheet 1). Any help would be appreciated.
you are either going to need to use an array formula or a function that returns array like calculations. I will suggest using the AGGREGATE function. Avoid using full comm/row references within an array formula or a function performing array like calculations or you may wind up bogging down your system with excessive calculations.
The AGGREGATE function is made up a several individual functions. Depending which one you choose, it will perform array operations. I am going to suggest that formula 14. What the following example will do is generate a list of results sorted from smallest to largest that ignores error values, then return the first value from the list. The thing we will list is the row number for a row that matches your ALL your criteria. So the basics of AGGREGATE looks like this:
AGGREGATE(Formula #, Error/hidden handling #, Formula, parameter)
The hardest part of this is coming up with the right formula. In the numerator you put the thing you are looking for. In the denominator you place your TRUE/FALSE condition checks. Separate each condition check with *. * will act as an AND function. The thing that makes this work is that TRUE/FALSE convert to 1/0 when they are sent through a math operation. So anything you do not want is FALSE. and anything divided by FALSE becomes divide by 0 which in turn generates an error. Since AGGREGATE is set to ignore error, only things that meet your condition will exist in the list and since they are being divided by TRUE which is 1, your thing remains unchanged. So the aggregate function is going to start to look like:
AGGREGATE(14,6,ROW(some range)/((Condition 1)*Condition 2)*...*(Condition N)),1)
So as eluded to before, 14 set the AGGREGATE to sort a list in ascending order. 6 tells AGGREGATE to ignore errors, and the 1 tells AGGREGATE to return the first item in its sorted list. If it was 2 instead of 1 it would return the 2nd position. If you ask for a position that is greater than the number of items in the list, there will be an error produced by AGGREGATE which does not get ignored.
So now that there is some understanding of what AGGREGATE does lets see how we can apply this to your data. For starters lets assume your data is in rows 2:100 and row 1 is a header row. You will have to adjust the references to suit your data.
CONDITION 1
LEFT($A$2:$A$100,2)="PG"
Checks to see if the first two characters are PG. based on the data in your screen shot, PG was either to the left of the / or was the only entry. There was also an observation that there was only one / in the cells of column A. If you also need to check if it after the / and with the assumption that it can only be on one side and not both at the same time you could use this alternative for your condition check:
(LEFT($A$2:$A$100,2)="PG")+(RIGHT($A$2:$A$100,2)="PG")
In this case the + is performing the task of an OR function. The caveat mentioned earlier is important because if both sides are TRUE then you wind up with TRUE+TRUE which becomes 1+1 which is 2 and we only want to divide by 1 or 0. Though to counter that you could go with:
MIN((LEFT($A$2:$A$100,2)="PG")+(RIGHT($A$2:$A$100,2)="PG"),1)
CONDITION 2
Check that the salary in C is less than or equal a value 80000.
($C$2:$C$100<=80000)
CONDITION 3
Check that the salary in C is greater than or equal a value 71000.
($C$2:$C$100>=71000)
Now lets put this all together to get a list of row numbers that meet your conditions:
AGGREGATE(14,6,ROW($A$2:$A$100)/MIN((LEFT($A$2:$A$100,2)="PG")+(RIGHT($A$2:$A$100,2)="PG"),1)*($C$2:$C$100<=80000)*($C$2:$C$100>=71000),ROW(A1))
Now provided I did not screw up the bracketing in that formula, you can place that formula in a cell and copy it down until it produces errors. As you copy it down, the only thing that will change is the A1 in ROW(A1). It acts like a counter. 1,2,3 etc. so you will get a list of row numbers that meet your criteria. Now we need to convert those row numbers to names.
To find the names, the INDEX function is your friend here. Because it is not part of an array formula or inside a function performing array like calculations, full column reference can be used. So we take our formula that is generating row numbers and place it inside the INDEX function to give:
INDEX(B:B,Row Number)
INDEX(B:B,AGGREGATE(14,6,ROW($A$2:$A$100)/MIN((LEFT($A$2:$A$100,2)="PG")+(RIGHT($A$2:$A$100,2)="PG"),1)*($C$2:$C$100<=80000)*($C$2:$C$100>=71000),ROW(A1)))
Now if you hate seeing error codes when you have copied down further then results you can place the whole thing inside and IFERROR function to give:
IFERROR(formula,What to display in case of an error)
So for blank entries:
IFERROR(INDEX(B:B,AGGREGATE(14,6,ROW($A$2:$A$100)/MIN((LEFT($A$2:$A$100,2)="PG")+(RIGHT($A$2:$A$100,2)="PG"),1)*($C$2:$C$100<=80000)*($C$2:$C$100>=71000),ROW(A1))),"")
and custom message:
IFERROR(INDEX(B:B,AGGREGATE(14,6,ROW($A$2:$A$100)/MIN((LEFT($A$2:$A$100,2)="PG")+(RIGHT($A$2:$A$100,2)="PG"),1)*($C$2:$C$100<=80000)*($C$2:$C$100>=71000),ROW(A1))),"NOT FOUND")
So now you just need to adjust the references to suit your data. If your data is located on another sheet remember to include the sheet name. A reference to B3:C4 would become:
Sheet1!B3:C4
and if the sheet name has a space in it:
'Space Name'!B3:C4

Returning all possible values instead of a VLOOKUP

So I've looked up tutorials on how to do this, and I'm still struggling, so I could use some expert help. I know it involves a very complex nested formula with things like SMALL, ROW, INDEX, etc...
So here are two screenshots that provide a sample of what I'm looking for. In realities there is over 1000 rows, but this makes it easier for you guys.
So here is my first example, lets call this Sheet1!:
Code, ID_1 and ID_2. So as you can see (and just focus on the input in A2) there will be two separate IDs in the linked workbook. That sheet, or at least a tiny sample of it, looks like this:
In the first column we see the code we're looking for (which is what we have in A2 of the first one), each of them with different IDs. So as I'm sure you can tell by now, I'm looking for a formula that will allow me to return those values in ID_1 and ID_2 in the first sheet.
I have been going at this for an hour and I'm stumped, so I would greatly appreciate any help provided!
This is a more generic code if the ids are NOT listed consecutively: Obviously I have done this as an example to take in a more general case where the ids occur anywhere throughout the second dataset, AND where there are potentially several.
IFERROR(INDEX($V$2:$V$15, SMALL(IF($U$2:$U$15=$M2, ROW($U$2:$U$15), FALSE), COLUMNS($N2:N2))-ROW($V$1), 1), "")
This formula must be entered with Ctrl-Shift-Enter before copying across and down! Note all absolute and relative referencing/locking ($ signs)
The logical steps in constructing such a formula:
1) We use IF function to test if the values in the column U match the value in column M.
2) In the 'value-if-true' parameter, we will get the corresponding row number of values in column U. These numbers will be fed later in the SMALL function.
3) In the value-if-false part, we just return false, as that will later be used as a non-number in the SMALL function
Above 3 steps in the part: IF($U$2:$U$15=$M2, ROW($U$2:$U$15), FALSE)
4 ) We have now an array of mixed row numbers and FALSE values, which we want to feed to the INDEX function to simply get the corresponding value in column V(our second datset). BUT as we wish to retrieve the different row matches for each code, we have to fish them out of the mixed array with the SMALL function.
5) using our columns as an incrementer, we apply the SMALL function to the array with a varying k parameter. We USE the COLUMNS function (note carefully the different $ sign usage), so that as we drag the formula across, the column count increments: COLUMNS($N2:N2) - giving K values of 1, 2, 3, 4 as we drag the formula across from column N to column Q. Note that it is useful that the SMALL function disregards FALSE values when looking through the array for the values by size.
6) There is an adjustment to account for the fact that the rows are relative to the 'Ids' range which we will feed into the INDEX function to retrieve the different ids. SMALL(IF($U$2:$U$15=$M2, ROW($U$2:$U$15), FALSE), COLUMNS($N2:N2))-ROW($V$1).
This can be avoided if we use the entire column V as the look-up array parameter in the INDEX function, but that's another way...
7) This resulting value can now be passed to the INDEX function to obtain the various ids. The column_num parameter of 1 which I put in the function isn't necessary in a single-column look-up array, but is there for completeness.
8) The entire construction is then wrapped in an IFERROR function to give an empty string if there is no match, but some people may wish to have error outputs there...
well if the two ID will be consecutive in the second list try this:
=index('workbookname'SheetName!columnrangeofserialnumbers,match(A2,'workbookname'Sheetname!columnrangeofIDs,0))
Assuming your other workbook is called Serials, and all the info is on sheet1 you would enter the follow in B2:
=index('serials'sheet1!$B$2:$B$1000,match(A2,'serials'sheet1!$B$2:$B$1000,0))
in C2 enter the following (assuming ids will show up consecutively)
=index('serials'sheet1!$B$2:$B$1000,match(A2,'serials'sheet1!$B$2:$B$1000,0)+1)
This only works if the other workbook is open as far as I know and with the understanding that the two ID will be listed consecutively in the list.

Sort Order formula to alphabetise in Excel

I am currently drawing up a spreadsheet that will automatically remove duplicates and alphabetize a list:
I am using the COUNTIF() function in column G to create a sort order and then VLOOKUP() to find the sort in column J.
The problem I am having is that I can't seem to get my SortOrder column to function properly. At the moment it creates an index for two number 1's meaning the cell highlighted in yellow is missed out and the last entry in the sorted list is null:
If anyone can find and rectify this mistake for me I'll be very grateful as it has been driving me insane all day! Many thanks.
I'll provide my usual method for doing an automatic pulling-in of raw data into a sorted, duplicate-removed list:
Assume raw data is in column A. In column B, use this formula to increase the counter each time the row shows a non-duplicate item in column A. Hardcord B2 to be "1", and use this formula in B3 and drag down.
=if(iserror(match(A3,$A$2:A2,0)),B2+1,B2)
This takes advantage of the fact that when we refer to this row counter in our revised list, we will use the match function, which only checks for the first matching number. Then say you want your new list of data on column D (usually I do this for display purposes, so either 'group-out' [hide] columns that form the formulas, or do this on another tab). You can avoid this step, but if you are already using helper columns I usually do each step in a different column - easier to document. In column C, starting in C3 [C2 hardcoded to 1] and drag down, just have a simple counter, which error-checks to the stop at the end of your list:
=if(C2<max(B:B),C2+1," ")
Then in column D, starting at D2 and dragged down:
=iferror(index(A:A,match(C2,B:B,0)),"")
The index function is like half of the vlookup function - it pulls the result out of a given array, when you provide it with a row number. The match function is like the other half of the vlookup function - it provides you with the row number where an item appears in a given array.
Hope this helps you in the future as well.
The actual reason that this is going wrong as implied by Jeeped's comment is that you can't meaningfully compare a string to a number unless you do a conversion because they are stored differently. So COUNTIF counts numbers and text separately.
20212 will give a count of 1 because it is the only (or lowest) number.
CS10Z002 will give a count of 1 because it is the first text string in alphabetical order.
Another approach is to add the count of numbers to the count if the current cell contains text:-
=COUNTIF(INDIRECT("$D$2:$D$"&$F$3),"<="&D2)+ISTEXT(D2)*COUNT(INDIRECT("$D$2:$D$"&$F$3))
It's easier to show the result of three different conversions with some test data:-
(0) No conversion - just use COUNTIF
=COUNTIF(D$2:D$7,"<="&D2)
"999"<"abc"<"def", 999<1000
(1) Count everything as text
=SUMPRODUCT(--(D$2:D$7&""<=D2&""))
"1000"<"999"
(2) Count numbers before text
=COUNTIF(D$2:D$7,"<="&D2)+ISTEXT(D2)*COUNT(D$2:D$7)
999<1000<"999"
(3) Count everything as text but convert numbers with leading zeroes
=SUMPRODUCT(--(TEXT(D$2:D$7,"000000")<=TEXT(D2,"000000")))
"000999" = "000999", "000999"<"001000"

Lookup Multiple Items

I have a list of names and numbers
NAME | Number
Joe | 1
Jane | 0
Jack | 1
Jill | 0
John | 1
I'm trying to look up the numbers and find out the corresponding name
The formula I have is
{=index($A$2:$B$6, SMALL(IF($B$2:$B$6 = 1, ROW ($B$2:$B$6)), Row(1:1)), 1)}
As I understand the formula:
First Excel runs the index function. It runs the index function on the array A2 through B6.
For the row number in the index function, it uses the function SMALL(IF($B$2:$B$6 = 1, ROW ($B$2:$B$6)), Row(1:1). This examines an array, b2:b6, and if the element under consideration in B2:B6 is a 1, it returns the row number of b2:b6. In this case, it would return a 2.
At this point I'm kind of stuck. I'm guessing that the second ROW function returns first case of the 1 derived from the small function
Lastly, the index function finds the name located in column 1 for the index found.
Your understanding of this formula is pretty good. I assume that you are going to copy it down enough rows to get all the values reported? If so, here is what is happening:
INDEX needs to know what row to go retrieve. In order to do this, we are going to give it a row number.
In order to get a row number we need to know which items meet the condition. We use the IF conditional to report a row number if the condition is met (otherwise we get FALSE).
Since that will give us an array of row numbers, we then use the SMALL function to give us a single value. That satisfies the INDEX function which needs a single row to retrieve.
So which value do we choose from SMALL? Well, we just give it a sequence of 1-2-3-... by using ROW(1:1). When this is copied down, it will become ROW(2:2), ROW(3:3), etc. Each of these will return 1, 2, 3, respectively so we get the next entry. Note that SMALL skips FALSE so it works for the output of the IF call.
So the first call to ROW (inside the IF) is used to determine the row of the values in the array that match the condition.
The second call to ROW(1:1) is just used to get an incrementing sequence once the formula is copied down.
The final thing to note is that your formula will be off by one row on the answers because ROW($B$2:$B$6) will return the absolute row number of those rows and not one that is relative to the starting corner of the array of interest. In this case, you will need to subtract 1 to get it to work (since it starts in row 2). In the general case, use a formula like this which accounts for the offset of the array:
=INDEX($A$2:$A$6,SMALL(IF($B$2:$B$6=1,ROW($B$2:$B$6)-ROW($B$2)+1),ROW(1:1)))
That is an array formula like you have (enter with CTRL+SHIFT+ENTER). The corresponding ranges look like:

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