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I hope that you can help me with the following problem: I want to implement a script that requires that $PATH variables has missing . value changes in it.
The point of the script is to find requested files and copy them to parent directory. I can do this using -execdir, but the problem is that . is defined in the $PATH.
Can you please tell me how can I provide a temporary replacement for the $PATH variable that can be valid only for the script execution.
Thanks
The shell allows you to set environment variables of an executable by passing them to the invocation. Like this:
PATH="/foo/bar" program
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I want to print the line which has below value in my text file(ex: file.txt).
I have tried multiple ways but no luck. Can someone please help me the right command.
selector="((Source IN ('VPS','VPSLegacy')) OR (JMS_TIBCO_SENDER='rig'))"
Please note that i need to use entire above value to check in the file.
The easiest way to assign a literal (potentially containing quotes or other shell syntax) to a variable, even though it comes with a performance penalty, is to use a quoted heredoc:
content=$(cat <<'EOF'
selector="((Source IN ('VPS','VPSLegacy')) OR (JMS_TIBCO_SENDER='rig'))"
EOF
)
echo "Value is: <$content>"
...correctly emits as output:
Value is: <selector="((Source IN ('VPS','VPSLegacy')) OR (JMS_TIBCO_SENDER='rig'))">
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I have a code that looks for png files with a specific pattern on the desktop and moves them to another directory.
While going over the files, I want to check if there is the pattern in the name.
This is how I did it:
for %%f in (C:\Users\user\Desktop\*.png) do (
if %%f==Hearthstone Screenshot*.png (
move %%f C:\destination\
)
)
Note: All the needed files start with Hearthstone Screenshot then some numbers.
My main problem is in line 2. I can't make it work.
Depending upon you needs, perhaps this is what you're looking for…
#RoboCopy "%UserProfile%\Desktop" "%UserProfile%\Desktop\HearthStone_Screenshots" "HearthStone Screenshot*.png" /MOV>Nul 2>&1
This should automatically create the holding directory, HearthStone_Screenshots if it doesn't already exist.
Note:I have corrected what I'm assuming to be your very poor spelling issues. If those files and directories should be named using ea instead of ee please re-adjust as necessary.
What's wrong with this:
move C:\Users\user\Desktop\HearthstoneScreanshot*.png C:\Users\user\Desktop\Hearthstonescreanshot\
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I am writing a shell script that is extracting the data from a command:
I have tried running the script in both the vi and vim editor. But everything in vain.
Please help me out. And how write the output of this in a file.
It may be noted that this is just a starting point so the script will produce multiple files so
I cannot write:
Script_name > filename
I think this question is fine now, the input file is good enough after edit, I can fully understand what you ask for now.
With awk, you need learn to use 2-d array, it will simplify the code.
awk 'BEGIN{print "Instance id Name Owner Cost.centre"}
/TAG/{split($0,a,FS);a[4]=tolower(a[4]);$1=$2=$3=$4="";b[a[3],a[4]]=$0;c[a[3]]}
END{for (i in c) printf "%-18s%-26s%-14s%-20s\n",i,b[i,"name"],b[i,"owner"],b[i,"cost.center"]}' file
Instance id Name Owner Cost.centre
i-e1cfc499 Memcached
i-7f4b9300 Test_LB01_Sachin
i-c4260db8 Rishi_Win_SAML Rishi Pandey
i-fb5ca283 CLIQR-DO NOT TOUCH mataa 1234
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I created a few .sh files and put them under one of the directories under $PATH. Unfortunately every time I start a new session I have to source them if I want to use them. I did a google search and couldn't really find what I am looking for to not having to source these files.
I guess I can place a source all command at ~/.bashrc but there should be a way to get this done in a simple way.
Thanks
Let's say all of your scripts are under the ~/.functions directory. Put this in your $HOME/.bashrc:
for file in ~/.functions/*
do
. $file
done
This will source in all files in the ~/.functions directory whenever you start a new shell.
Sourcing all commands in .bashrc is the simple way.
You may want a sophisticated way of sourcing your start scripts by creating a specific directory, say ~/.start_scripts, where you put all your commands, and write a loop in your .bashrc that sources whatever executable is in this directory. That way, you no longer have to edit .bashrc each time a new command is put in the .start_scripts directory.
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I don't have .bashrc file, I want to create one but how? And what does a basic .bashrc file contains? I am on Linux Mint 12
I want to have a .bashrc file, because i have created a folder for virtualenv and I want to load virtualenvwrapper
Why do you want one if you don't know what to put in there? You only need a .bashrc (or .profile or .bash_profile) if you actually have something you want to execute in every shell (or login shell).
But you can basically put any bash commands in those files.
A .bashrc file contains whatever default settings you want to use when you are using bash. If you don't have any particular preferences then leave it blank for now.
Typical contents of a .bashrc file includes aliases of commands you find yourself using a lot.