Download a zip file using Groovy - groovy

Question

I need to download a zip file from a url using groovy.
Test url: https://gist.github.com/daicham/5ac8461b8b49385244aa0977638c3420/archive/17a929502e6dda24d0ecfd5bb816c78a2bd5a088.zip
What I've done so far:
def static downloadArtifacts(url,filename) {
new URL(url).openConnection().with { conn ->
conn.setRequestProperty("PRIVATE-TOKEN", "xxxx")
url = conn.getHeaderField( "Location" )
if( !url ) {
new File((String)filename ).withOutputStream { out ->
conn.inputStream.with { inp ->
out << inp
inp.close()
}
}
}
}
}
But while opening the downloaded zip file I get an error "An error occurred while loading the archive".
Any help is appreciated.

Answer 1

URL url2download = new URL(url)
File file = new File(filename)
file.bytes = url2download.bytes

Answer 2

You can do it with HttpBuilder-NG:
// https://http-builder-ng.github.io/http-builder-ng/
#Grab('io.github.http-builder-ng:http-builder-ng-core:1.0.3')
import groovyx.net.http.HttpBuilder
import groovyx.net.http.optional.Download
def target = 'https://gist.github.com/daicham/5ac8461b8b49385244aa0977638c3420/archive/17a929502e6dda24d0ecfd5bb816c78a2bd5a088.zip'
File file = HttpBuilder.configure {
request.uri = target
}.get {
Download.toFile(delegate, new File('a.zip'))
}

Answer 3

You can do it:
import java.util.zip.ZipEntry
import java.util.zip.ZipOutputStream
class SampleZipController {
def index() { }
def downloadSampleZip() {
response.setContentType('APPLICATION/OCTET-STREAM')
response.setHeader('Content-Disposition', 'Attachment;Filename="example.zip"')
ZipOutputStream zip = new ZipOutputStream(response.outputStream);
def file1Entry = new ZipEntry('first_file.txt');
zip.putNextEntry(file1Entry);
zip.write("This is the content of the first file".bytes);
def file2Entry = new ZipEntry('second_file.txt');
zip.putNextEntry(file2Entry);
zip.write("This is the content of the second file".bytes);
zip.close();
}
}