I actually want To display Full documents Without duplication
When I use distinct i can only display one particular field
How to display all fields without selecting that document which is repeated
Each document in MongoDB contains an _id field which must be unique in the collection. Hence, it is not possible to have two identical documents in a collection. Ergo, iterating a collection with no conditions will return all unique documents (which are all documents in the collection).
I have a collection which stores document that can have multiple subdocument (e.g. a group collection with multiple votings). My goal is to delete certain subdocuments on a certain date. I thought about using a package like "agenda" to cron-like delete certain subdocuments. Are there any more efficient or easier ways to do that
I'm new to Firestore so I have a simple question:
Suppose I have a collection of users and a collection of groups. users have an array field of groupReferences to mark what groups it is a part of.
Now I want to query a subset of the collection of groups that matches those that a particular user is within.
Do I:
Pull all groups and somehow compare the references in the user, filtering out any that match?
Iterate through the user's references and pull each group one at a time?
Thanks for your help!
I have collection of Users with unique property UserName. I need to insert in this collection array of Users. But if UserNames are equal I need to replace old document with the new one. (for each user)
Can be done this by one operation?
i need to develop a search application , where many documents are indexed with different fields and a id field which is unique for each of the document . Fields are not stored just indexed except for id field
i need to find out for each document , the documents similar to this, here all i have is unique id field of current document , i dont have any other fields of current document to form Terms and query the index for finding similar documents like current one.
How do i do this ? any help greatly appreciated .
I believe the simplest way to do this is to use Solr, and use Solr's MoreLikeThisHandler.
You can use a query likehttp://localhost:8983/solr/select?q=unique_id:2722&mlt=true&mlt.fl=manu,cat&mlt.mindf=1&mlt.mintf=1&fl=id,score
Do you have any control over how these documents are indexed? You can index with term vectors, and at query time, look up the term vector for the document, construct a query using the terms, and submit the query.