i tried to extract the test.jar
command is executing successfully but no output.
user#host:home/test->ll
drwxr-xr-x 107 user abc 6040 Apr 4 09:55 ..
drwxr-xr-x 2 user abc 26 Apr 4 10:06 .
-rw-r--r-- 1 user abc 51241 Apr 4 10:06 test.jar
user#host:home/test->jar -xvf test.jar
user#host:home/test->ll
total 262
drwxr-xr-x 107 user abc 6040 Apr 4 09:55 ..
drwxr-xr-x 2 user abc 26 Apr 4 10:06 .
-rw-r--r-- 1 user abc 51241 Apr 4 10:06 test.jar
Kindly help me to resolve this
Actual Requirement:
Need to extract and access a resource in jar file.
According to Oracle Java toutorials:
https://docs.oracle.com/javase/tutorial/deployment/jar/unpack.html
You should unpack it with:
jar xfv test.jar
Without '-' sign.
x option indicates that you want to extract files from the JAR archive.
f options indicates that the JAR file from which files are to be extracted is specified on the command line, rather than through stdin.
v is verbose
try to this command also unzip test.jar and below commands help you view some file without extract all the files.
unzip -q -c test.jar META-INF/MANIFEST.MF
Related
I want to use wget to download multiple files at once in a script using wildcards, like this:
wget -r -nd --no-parent --no-remove-listing $ftpUrl -l1 -A file1*.txt &
wget -r -nd --no-parent --no-remove-listing $ftpUrl -l1 -A file2*.txt &
wget -r -nd --no-parent --no-remove-listing $ftpUrl -l1 -A file3*.txt &
The problem is that wget downloads .listing file everytime and because there are multiple instances running, sometimes the file is being downloaded when another instance is reading it.
Is there a way to lock .listing file or ask wget to not download it (I can do it manually as the first command)? I don't understand how it reads this .listing file since it's not a plain list of the URLs, but rather something like this:
drwxr-xr-x 3 4015 4015 16384 Dec 14 21:23 .
drwxr-xr-x 4 4015 4015 4096 Dec 14 21:23 ..
-rw-r--r-- 1 4015 4015 327 Feb 15 2022 file1-bla.txt
-rw-r--r-- 1 4015 4015 10716 Feb 15 2022 file2-bla.txt
-rw-r--r-- 1 4015 4015 163 Feb 15 2022 file2-bla.txt
If I try to use -i .listing (or even if I rename .listing to list.txt and use -i list.txt) I get an error saying that the URLs are not valid or something.
RFC 959 stipulates that
LIST (LIST) This command causes a list to be sent from the server to the passive DTP. If the pathname specifies a directory or other
group of files, the server should transfer a list of files in the
specified directory. If the pathname specifies a file then the server
should send current information on the file. A null argument implies
the user's current working or default directory. The data transfer is
over the data connection in type ASCII or type EBCDIC. (The user must
ensure that the TYPE is appropriately ASCII or EBCDIC). Since the
information on a file may vary widely from system to system, this
information may be hard to use automatically in a program, but may be
quite useful to a human user.
Observe that it does not impose formal requirement what exactly will be returned.
drwxr-xr-x 3 4015 4015 16384 Dec 14 21:23 .
drwxr-xr-x 4 4015 4015 4096 Dec 14 21:23 ..
-rw-r--r-- 1 4015 4015 327 Feb 15 2022 file1-bla.txt
-rw-r--r-- 1 4015 4015 10716 Feb 15 2022 file2-bla.txt
-rw-r--r-- 1 4015 4015 163 Feb 15 2022 file2-bla.txt
This looks akin to output of ls -lah command, if you are interested in using that to form URL list acceptable by wget then you should take last column (excluding . and ..) and prefix them with URL of FTP server, if that URL is ftp://ftp.example.com and you got list as above then your list of URLs should look as follows
ftp://ftp.example.com/file1-bla.txt
ftp://ftp.example.com/file2-bla.txt
ftp://ftp.example.com/file3-bla.txt
How do I list the files owned by a particular user in UNIX ?.
If I use ls - l command in a shared directory ,it lists all the files with the details .This shared directory contains many files created by many users in a group and I am in a situation where I want to see the files created only by a particular user. Is there any listing command to give username as the input.
Refer below example,
command : ls - l
drwxr-xr-x 2 user_1 main 4.0K Feb 12 16:43 proj_1
drwxrws--- 6 user_2 main 20M Feb 18 11:07 proj_2
drwxr-xr-x 3 user_1 main 1.3M Feb 18 00:18 proj_3
drwxrwsr-x 2 user_2 main 8.0K Dec 27 01:23 proj_4
drwxrwsr-x 2 user_3 main 8.1K Dec 27 01:23 proj_5
I am looking for a command to display only the files created by the user_2 with my expected output as below ,
drwxrws--- 6 user_2 main 20M Feb 18 11:07 proj_2
drwxrwsr-x 2 user_2 main 8.0K Dec 27 01:23 proj_4
Kindly let me know if there is a way .
It should be possible to use awk togheter with ls -l
ls -l | awk '$3=="user_2" { print $0 }'
this will print all lines where third field (user) matches "user_2"
You simply can use the findcommand like this:
find . -maxdepth 1 -user some_user -exec ls -lsad {} \;
Why the options are used:
maxdepth we only want to see current directory level
user we only want to see files owned by given user
exec lets do something with the found file
What we want do with the file:
ls -lsad gives you the long list of current file, if it is a directory, don't go into it.
How do I list matched results in a specified directory?
On my Ubuntu server if I list the contents of a directory it correctly lists it. My working directory is /var/crash.
#pwd
/var/crash
# ls -l
-rw-r--r-- 1 bob bob 121876 Aug 8 2015 results.xml
-rw-rw-r-- 1 bob bob 126 Nov 3 2015 start.txt
-rw-rw-r-- 1 bob bob 43 Jul 28 2015 exit.txt
Let's say I want to list all files that contain 'tar'. In this example there should only be one match i.e. start.txt
# ls -l *tar*
-rw-rw-r-- 1 bob bob 126 Nov 3 2015 start.txt
All's good so far. However if I include the directory (/var/crash) it lists all files.
# ls -l *tar* /var/crash
-rw-r--r-- 1 bob bob 121876 Aug 8 2015 results.xml
-rw-rw-r-- 1 bob bob 126 Nov 3 2015 start.txt
-rw-rw-r-- 1 bob bob 43 Jul 28 2015 exit.txt
I'm guessing my syntax is telling ls to list all matches of tar AND everything in /var/crash. What is the correct syntax to list matches in a specified directory?
You need to specify the pattern together with the directory:
ls -l /var/crash/*tar*
Otherwise, with ls -l *tar* /var/crash you are telling ls to act against two parameters: /var/crash and *tar*. In fact, *tar* will be expanded before ls reaches it, so there might be more parameters for ls.
I am trying to obtain a backup of 'newly' added files to a Fedora system. Files can be copied through a Windows Samba share and appear to retain the original created timestamp. However, because it retains this timestamp I am having issues identifying which files were newly added to the system.
Currently, the only way I can think of doing this is to have a master list snapshot of all the files on the system at a specific time. Then when I perform the backup I compare the previous snapshot with a current snapshot. It would detect files that were removed from the system but it seems excessive and I was thinking there must be an easier way to backup newly added files.
Terry
Try using find. Something like this:
find . -ctime -10
That will give you a list of files and directories, starting from within your current directory, that has had its state changed within the last 10 days.
Example:
My Downloads directory looks like this:
kobus#akira:~/Downloads$ ll
total 2025284
drwxr-xr-x 4 kobus kobus 4096 Nov 4 11:25 ./
drwxr-xr-x 41 kobus kobus 4096 Oct 30 09:26 ../
-rw-rw-r-- 1 kobus kobus 8042383 Oct 28 14:08 apache-maven-3.3.3- bin.tar.gz
drwxrwxr-x 2 kobus kobus 4096 Oct 14 09:55 ELKImages/
-rw-rw-r-- 1 kobus kobus 1469054976 Nov 4 11:25 Fedora-Live-Workstation-x86_64-23-10.iso
-rw------- 1 kobus kobus 351004 Sep 21 14:07 GrokConstructor-master.zip
drwxrwxr-x 11 kobus kobus 4096 Jul 11 2014 jboss-eap-6.3/
-rw-rw-r-- 1 kobus kobus 183399393 Oct 19 16:26 jboss-eap-6.3.0-installer.jar
-rw-rw-r-- 1 kobus kobus 158177216 Oct 19 16:26 jboss-eap-6.3.0.zip
-rw-rw-r-- 1 kobus kobus 71680110 Oct 13 13:51 jre-8u60-linux-x64.tar.gz
-rw-r--r-- 1 kobus kobus 4680 Oct 12 12:34 nginx-release-centos-7-0.el7.ngx.noarch.rpm
-rw-r--r-- 1 kobus kobus 3479765 Oct 12 14:22 ngx_openresty-1.9.3.1.tar.gz
-rw------- 1 kobus kobus 16874455 Sep 15 16:49 Oracle_VM_VirtualBox_Extension_Pack-5.0.4-102546.vbox-extpack
-rw-r--r-- 1 kobus kobus 7505310 Oct 6 10:29 sublime_text_3_build_3083_x64.tar.bz2
-rw------- 1 kobus kobus 41467245 Sep 7 10:37 tagspaces-1.12.0-linux64.tar.gz
-rw-rw-r-- 1 kobus kobus 42658300 Nov 4 10:14 tagspaces-2.0.1-linux64.tar.gz
-rw------- 1 kobus kobus 70046668 Sep 15 16:49 VirtualBox-5.0-5.0.4_102546_el7-1.x86_64.rpm
Here's what the find returns:
kobus#akira:~/Downloads$ find . -ctime -10
.
./tagspaces-2.0.1-linux64.tar.gz
./apache-maven-3.3.3-bin.tar.gz
./Fedora-Live-Workstation-x86_64-23-10.iso
kobus#akira:~/Downloads$
Most unices do not have a concept of file creation time. You can't make ls print it because the information is not recorded. If you need creation time, use a version control system: define creation time as the check-in time.
If your unix variant has a creation time, look at its documentation. For example, on Mac OS X (the only example I know of¹), use ls -tU. Windows also stores a creation time, but it's not always exposed to ports of unix utilities, for example Cygwin ls doesn't have an option to show it. The stat utility can show the creation time, called “birth time” in GNU utilities, so under Cygwin you can show files sorted by birth time with stat -c '%W %n' * | sort -k1n.
Note that the ctime (ls -lc) is not the file creation time, it's the inode change time. The inode change time is updated whenever anything about the file changes (contents or metadata) except that the ctime isn't updated when the file is merely read (even if the atime is updated). In particular, the ctime is always more recent than the mtime (file content modification time) unless the mtime has been explicitly set to a date in the future.
"Newly added files, Fedora" : The below examples will show a list with date and time.
Example, all installed packages : $ rpm -qa --last
Example, the latest 100 packages : $ rpm -qa --last | head -100
Example, create a text file : $ rpm -qa --last | head -100 >> last-100-packages.txt
Does SCP have a problem setting file permissions or have I misconfiguration my server?
Use case:
There is a file on a server that I want to edit called "importantFile.txt". The file has owner and group of "master":
ls -l importantFile.txt:
-rw-rw-r-- 1 master master 7 Mar 18 08:11 importantFile.txt
I am called "slave" but luckily, I am in group "master" so I can edit the file as I see fit. However, I'm a lazy slave and can't be bothered to edit the file on the server, I'd prefer to edit the file on my local machine and SCP it to the server:
echo "bored slave info" > importantFile.txt
scp importantFile.txt slave#theServerAddress:/pathToFile/importantFile.txt
If I do this, the contents of the file on the server are uploaded fine and the timestamp of the file is updated but the permissions of the file don't change, the file is still owned by "master". This is a problem because if "slave" uploaded bad content, no one would know it was "slave" who caused the problem, "master" would look guilty.
Perhaps I have to set a umask? if so where? I tried .bash_profile without success and haven't found anything on Google about umask in /etc/ssh/sshd_config.
That's nothing special about scp - try logging on to the server as slave, and editing the file using your favourite text editor... You'll find the same behaviour occurs... Writing to a file does not make you the owner of the file.
Example:
as root
#cd /tmp
#mkdir fubar
#chgrp vboxusers fubar
#cd fubar/
#touch testfile
#chgrp vboxusers testfile
#chmod g+w . testfile
#ls -al
total 16
drwxrwxr-x 2 root vboxusers 4096 2009-03-19 10:30 .
drwxrwxrwt 15 root root 12288 2009-03-19 10:29 ..
-rw-rw-r-- 1 root vboxusers 0 2009-03-19 10:30 testfile
#echo foo > testfile
#ls -al
total 20
drwxrwxr-x 2 root vboxusers 4096 2009-03-19 10:30 .
drwxrwxrwt 15 root root 12288 2009-03-19 10:29 ..
-rw-rw-r-- 1 root vboxusers 4 2009-03-19 10:30 testfile
as user (in vboxusers group)
>cd /tmp/fubar
>ls -al
total 20
drwxrwxr-x 2 root vboxusers 4096 2009-03-19 10:30 .
drwxrwxrwt 15 root root 12288 2009-03-19 10:29 ..
-rw-rw-r-- 1 root vboxusers 4 2009-03-19 10:30 testfile
>echo bar >> testfile
>ls -al
total 20
drwxrwxr-x 2 root vboxusers 4096 2009-03-19 10:30 .
drwxrwxrwt 15 root root 12288 2009-03-19 10:29 ..
-rw-rw-r-- 1 root vboxusers 8 2009-03-19 10:31 testfile
>vim testfile
>ls -al
total 20
drwxrwxr-x 2 root vboxusers 4096 2009-03-19 10:31 .
drwxrwxrwt 15 root root 12288 2009-03-19 10:31 ..
-rw-rw-r-- 1 root vboxusers 12 2009-03-19 10:31 testfile
>cat testfile
foo
bar
baz
You have to delete the file to overwrite it. Wether you are able to do that depends on the directory's permissions and ownership. Hijacking ownership of an already existing file is not possible. The write permission you have is only applied on the contents of the file.
It seems you can configure how Emacs deals with this through the backup-by-copying-when-mismatch variable (see the Emacs Manual or type C-h-v backup-by-copying-when-mismatch in Emacs).
I actually filed a bug report about this, because I thought it was a bug in Tramp.
I had misunderstood the way files work, modifying file contents do not change ownership or group.
Why the confusion? EMACS - Whenever I was editing a file I was using Emacs and Emacs does change the owner and group to the current user. It does this because it makes a backup file at save time by moving the "filename" to "filename~" and creating a new file called "filename" - because it's a new file, it has the current users file permissions. I guess this is 1up to VI fans?