I'm trying to calculate the result from two bytes returned from a string.
I know that the expected value should = 250 and the two bytes have values of [3E, 80]
When working this out on a calculator do I use the 3E value and move it 8 bits to the left using the RoL function? If so how do I then use the result combined with the 80 value? Add the two values together?
Thanks.
Related
I've got the table whereby:
The left number of * contains the count of something, the right is the value of it.
I'm trying to figure out the sum of all the counts, irrespective of value. The result that I'm trying to work towards is under the "result" header.
Raw
Result
1*2+2*3+3*4+3*5+5*6
14
882*1
882
321*2+112*128
433
Trying out using names within excel for to evaluate it, but I'm unsure if you can iterate and get each position of the numbers on the left of the " * ".
Assuming the only operations are addition and multiplication, for Office 365:
=BYROW(A1:A3,LAMBDA(ζ,SUM(INDEX(0+TEXTSPLIT(ζ,"*","+"),,1))))
I would like to count '01' sequence in 5760 binary bits.
First, I would like to combine several binary numbers then count # of '01' occurrences.
For example, I have 64 bits integer. Say, 6291456. Then I convert it into binary. Most significant 4 bits are not used. So I'll get 60 bits binary 000...000011000000000000000000000
Then I need to combine(just put bits together since I only need to count '01') first 60 bits + second 60 bits + ...so 96 of 60 bits are stitched together.
Finally, I want to count how many '01' appears.
s = binToString(5760 binary bits)
cnt = s.count('01');
num = 6291226
binary = format(num, 'b')
print(binary)
print(binary.count('01'))
If I use number given by you i.e 6291456 it's binary representation is 11000000000000000000000 which gives 0 occurrences of '01'.
If you always want your number to be 60 bits in length you can use
binary = format(num,'060b')
It will add leading 0 to make it of given length
Say that nums is your list of 96 numbers, each of which can be stored in 64 bits. Since you want to throw away the most 4 significant bits, you are really taking the number modulo 2**60. Thus, to count the number of 01 in the resulting string, using the idea of #ShrikantShete to use the format function, you can do it all in one line:
''.join(format(n%2**60,'060b') for n in nums).count('01')
I am trying to add in cell data validation for a string length to be between 8 and 16 and the max byte length less than 40(UTF8 encoding).
I created a data validation using the excel active support:
Data validation(data tab -> Data Validation (between Remove Duplicates and Consolidate in excel 2016 mac)), In Settings tab, there is validation
criteria:
Validation Criteria:
Allow: Text Length
Data : between
Min : 8 & Max : 16
Though the above validation satisfies all the restrictions i have(8
For other languages(say Japanese), though the string length is being counted though physical length(Eg : "こんにちはこんにちはこんにちは", hellohellohello in Japanese), the UTF8 byte value is 45 bytes, which is the violation of the 40 bytes, thought the length is only 15.
I found "LENB" function in excel, but it is giving the value as 30(instead of 45). I think it is based on different encoding(ansi maybe)
I found the UNICODE function which gives the unicode number of the first character(12371) in the above case. But i don't see how can i get the byte value from this number(3 bytes is the value for the first character(こ)).
Any help in this regard will be greatly appreciated.
I faced the same issue and here is the solution without VBA based on the answer above + this article. Assuming you have a string in A1:
=SUM(
IF(UNICODE(MID(A1,ROW(INDIRECT("1:"&LEN(A1))),1))<128, 1,
IF(UNICODE(MID(A1,ROW(INDIRECT("1:"&LEN(A1))),1))<2048, 2,
IF(UNICODE(MID(A1,ROW(INDIRECT("1:"&LEN(A1))),1))<65536, 3, 4
))))
Don't forget to use array function (CTRL+SHIFT+ENTER) when leaving the cell :)
With the Unicode value, you can compute how many bytes a particular one will take. <128 is 1 byte, else <2048 is 2, else <65536 is 3, else 4.
I'm trying to write a simple program in Easy68k that stores to negative values, adds them together, and then outputs them in the console. I am having trouble figuring out how to represent the negative numbers. We are asked that they be in hex format and output in decimal. Everything seems correct but the values themselves. I used 2s complement and then converted the two numbers to hex.
First decimal number = -102
Second decimal number = -87
Using 2s complement I converted the two numbers to hex (though I'm not sure if this is even correct):
-102 -> 1A
-87 -> 29
Here's my code so far:
addr EQU $7CE0
data1 EQU $1A
data2 EQU $29
ORG $1000
START: ; first instruction of program
* Put program code here
MOVE #data2,D1
MOVEA.W #addr,A0
ADD #data1,D1
MOVE D1,(A0)
MOVE.B #3,D0
TRAP #15
* Variables and Strings
* Put variables and constants here
END START ; last line of source
I even tried to just convert binary versions of the negative numbers straight to hex:
-102 -> 11100110 -> E6
-87 -> 11010111 -> D7
Which didn't work either. I also tried storing the binary version and adding them, but got the same result.
Here's the question:
Write a program in assembly to add the two numbers (-102 and -87). Inputs should be in hexadecimal format. Store the result in hexadecimal at an address $7CE0. Print out the result in decimal.(Hint: use the track function task #3). If an error happens, you should also print out the error message as well.
I know I am misrepresenting the two negative numbers, but I just can't figure out how to do it right. I've looked everywhere and found nothing on how to store/add/output negative numbers in 68k. Any help is appreciated, this is for an assignment so I'm not expecting direct answers. Thanks!
I have a buffer that is filled with data and begins with < Buffer 52 49 ...>
Assuming this buffer is defined as buf, if I run buf.readInt16LE(0) the following is returned:
18770
Now, the binary representation of hex values 52 and 49 are:
01010010 01001001
If I were to convert the first 15 bits to decimal, omitting the 16th bit for two's complement I would get the following:
21065
Why didn't my results give me the value of 18770?
18770 is 01001001 01010010 which is your 2 bytes reversed, which is what the readInt*LE functions are going to do.
Use readInt16BE.
You could do this: parseInt("0x" + buf.toString("hex")). Probably a lot slower but would do in a pinch.