I just want to convert my midi files to mp3 by using midi2audio, i use this code:
----------
from midi2audio import FluidSynth
FluidSynth().midi_to_audio('test.mid','test.mp3')
---------- or
from midi2audio import FluidSynth
FluidSynth().play_midi('test.mid')
but i got the same result:
----------
/Library/Frameworks/Python.framework/Versions/3.6/bin/python3.6 /Users/blake/Desktop/Bsmart_music/test/t_p/1.py
Traceback (most recent call last):
File "/Users/blake/Desktop/Bsmart_music/test/t_p/1.py", line 5, in <module>
FluidSynth().play_midi('test.mid')
File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/site-packages/midi2audio.py", line 49, in play_midi
subprocess.call(['fluidsynth', '-i', self.sound_font, midi_file, '-r', str(self.sample_rate)])
File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/subprocess.py", line 267, in call
with Popen(*popenargs, **kwargs) as p:
File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/subprocess.py", line 709, in __init__
restore_signals, start_new_session)
File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/subprocess.py", line 1344, in _execute_child
raise child_exception_type(errno_num, err_msg, err_filename)
FileNotFoundError: [Errno 2] No such file or directory: 'fluidsynth': 'fluidsynth'
Process finished with exit code 1
----------
So, i try to copy the fold "fluidsynth" to "midi2audio", but it still doesn't work. I have installed both midi2audio and fluidsynth, who knows what happened?
you must copy "fluidsynth" in some folder pointed by your PATH environ variable
( type "echo $PATH" in terminal app to see what is registered actually ).
On unix-like systems python will usually find fluidsynth located at /usr/bin/fluidsynth ( as /usr/bin is listed in the PATH ). on Os X things are not much different any documentation should fit. A common practice is to use /usr/local/bin folder for adding custom programs.
Maybe you should install fluidsynth first
for ubuntu:
sudo apt-get install fluidsynth
Related
I have the following script. It works when I run it in command line, and it works when I run it in cron.
The variable 'apath' is the absolute path of the file.
cat=['a','a','a','a','a','b','b','b','b','b']
val=[1,2,3,4,5,6,7,8,9,10]
columns=['cat','val']
data=[cat,val]
dict={key:value for key,value in zip(columns,data)}
statedata_raw=pd.DataFrame(data=dict)
statedata_raw.to_csv(apath+'state_data.csv',index=False)
statedata_raw2=pd.read_csv(apath+'state_data.csv')
statedata_raw2.to_csv(apath+'state_data2.csv',index=False)
But when I try to run the first part manually, creating the first csv, and then run the second part through cron, the second read_csv statement fails. I checked the permissions on the state_data.csv file and they are fine. It's set to -rwxr-xr-x
To be specific: I first run this script manually through command line. It executes and creates state_data.csv. Then I check the permissions of state_csv, and they are -rwxr-xr-x
cat=['a','a','a','a','a','b','b','b','b','b']
val=[1,2,3,4,5,6,7,8,9,10]
columns=['cat','val']
data=[cat,val]
dict={key:value for key,value in zip(columns,data)}
statedata_raw=pd.DataFrame(data=dict)
statedata_raw.to_csv(apath+'state_data.csv',index=False)
and then this script via cron, which fails, and gives the error message below
statedata_raw2=pd.read_csv(apath+'state_data.csv')
statedata_raw2.to_csv(apath+'state_data2.csv',index=False)
This is the error that I get from the system
Traceback (most recent call last):
File "/users/michaelmader/wdtest.py", line 39, in <module>
statedata_raw2=pd.read_csv(apath+'state_data.csv')
File "/opt/miniconda3/lib/python3.7/site-packages/pandas/io/parsers.py", line 676, in parser_f
return _read(filepath_or_buffer, kwds)
File "/opt/miniconda3/lib/python3.7/site-packages/pandas/io/parsers.py", line 448, in _read
parser = TextFileReader(fp_or_buf, **kwds)
File "/opt/miniconda3/lib/python3.7/site-packages/pandas/io/parsers.py", line 880, in __init__
self._make_engine(self.engine)
File "/opt/miniconda3/lib/python3.7/site-packages/pandas/io/parsers.py", line 1114, in _make_engine
self._engine = CParserWrapper(self.f, **self.options)
File "/opt/miniconda3/lib/python3.7/site-packages/pandas/io/parsers.py", line 1891, in __init__
self._reader = parsers.TextReader(src, **kwds)
File "pandas/_libs/parsers.pyx", line 374, in pandas._libs.parsers.TextReader.__cinit__
File "pandas/_libs/parsers.pyx", line 678, in pandas._libs.parsers.TextReader._setup_parser_source
OSError: Initializing from file failed
To summarize
Run complete script through Terminal: state_data2.csv is created: pass
Run complete script through cron: state_data2.csv is created: pass
Run first part through Terminal, second part through cron: fail
I am on MacOS and I already gave crontab full disk access in system preferences.
I figured out the problem. The issue was the permissions that were granted to cron in MacOS. I thought I had solved it by giving \usr\bin\crontab full disk access, but I actually needed to give full disk access to usr\sbin\cron
The steps for doing this can be found here: https://blog.bejarano.io/fixing-cron-jobs-in-mojave/.
Once I made that change everything worked fine.
i can't find solution for this problem code below:
import subprocess
subprocess.call(['./eu_presun.sh'])
shell script is in the same dir as main.py i will use python then i want use this shell script
I'm getting this error.
Traceback (most recent call last):
File "~/_main.py", line 304, in <module>
subprocess.call(['sh eu_presun.sh'])
File "/usr/lib/python3.8/subprocess.py", line 340, in call
with Popen(*popenargs, **kwargs) as p:
File "/usr/lib/python3.8/subprocess.py", line 854, in __init__
self._execute_child(args, executable, preexec_fn, close_fds,
File "/usr/lib/python3.8/subprocess.py", line 1702, in _execute_child
raise child_exception_type(errno_num, err_msg, err_filename)
FileNotFoundError: [Errno 2] No such file or directory: './eu_presun.sh'
okey im bit tired
answer is
subprocess.call(['./eu_presun.sh']**,shell=True**)
also i have problems with this address and i had to add full path
I used pygame and mplayer library to play a m4a music file in python languages,but all failed. Is there a library i can use to play m4a file in python?
here is my code:
pipes = dict(stdin=PIPE, stdout=PIPE, stderr=PIPE)
mplayer = Popen(["mplayer", r"C:\Users\sam\PycharmProjects\untitled\music.m4a"], **pipes)
# to control u can use Popen.communicate
mplayer.communicate(input=b">")
sys.stdout.flush()
i used the pycharm ,and the result is :
Traceback (most recent call last):
File "C:/Users/sam/PycharmProjects/untitled/tt.py", line 23, in
mplayer = Popen(["mplayer", r"C:\Users\sam\PycharmProjects\untitled\music.m4a"], **pipes)
File "C:\Users\sam\AppData\Local\Programs\Python\Python36-32\lib\subprocess.py", line 707, in init
restore_signals, start_new_session)
File "C:\Users\sam\AppData\Local\Programs\Python\Python36-32\lib\subprocess.py", line 990, in _execute_child
startupinfo)
FileNotFoundError: [WinError 2] 系统找不到指定的文件。
Here is a link to a good thread that I believe answers the exact same thing that you are having issues with.
Play m4a in python script with mplayer
I am trying to make list of every command available on my linux (Lubuntu) machine. I would like to further work with that list in Python. Normally to list the commands in the console I would write "compgen -c" and it would print the results to stdout.
I would like to execute that command using Python subprocess library but it gives me an error and I don't know why.
Here is the code:
#!/usr/bin/python
import subprocess
#get list of available linux commands
l_commands = subprocess.Popen(['compgen', '-c'])
print l_commands
Here is the error I'm getting:
Traceback (most recent call last):
File "commands.py", line 6, in <module>
l_commands = subprocess.Popen(['compgen', '-c'])
File "/usr/lib/python2.7/subprocess.py", line 679, in __init__
errread, errwrite)
File "/usr/lib/python2.7/subprocess.py", line 1249, in _execute_child
raise child_exception
OSError: [Errno 2] No such file or directory
I'm stuck. Could you guys help me with this? How to I execute the compgen command using subprocess?
compgen is a builtin bash command, run it in the shell:
from subprocess import check_output
output = check_output('compgen -c', shell=True, executable='/bin/bash')
commands = output.splitlines()
You could also write it as:
output = check_output(['/bin/bash', '-c', 'compgen -c'])
But it puts the essential part (compgen) last, so I prefer the first variant.
I'm not sure what compgen is, but that path needs to be absolute. When I use subprocess, I spell out the exact page /absolute/path/to/compgen
I have python script which prints out long list through statistical R (by PypeR). This python script is working absolutely fine.
Now I am trying to run this script from NodeJS through spawn functionality of child_process but it fails with following error:-
Traceback (most recent call last):
File "pyper_sample.py", line 5, in <module>
r=R()
File "/home/mehtam/pyper.py", line 582, in __init__
'prog' : Popen(RCMD, stdin=PIPE, stdout=PIPE, stderr=return_err and _STDOUT or childstderr, startupinfo=info),
File "/usr/lib64/python2.6/subprocess.py", line 642, in __init__
errread, errwrite)
File "/usr/lib64/python2.6/subprocess.py", line 1234, in _execute_child
raise child_exception
OSError: [Errno 2] No such file or directory
./temp.sh: line 1: 27500 Segmentation fault (core dumped) python pyper_sample.py o1dn01.tsv cpu_overall
child process exited with code : 139
Note: My python script is working perfectly. I already tested it manually.
My python script is working perfectly. I already tested it manually.
The output clearly shows that OSError: No such file or directory exception happened during Popen() call.
It means that the program is not found e.g.,
>>> from subprocess import Popen
>>> p = Popen(["ls", "-l"]) # OK
>>> total 0
>>> p = Popen(["no-such-program-in-current-path"])
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/lib/python2.7/subprocess.py", line 679, in __init__
errread, errwrite)
File "/usr/lib/python2.7/subprocess.py", line 1249, in _execute_child
raise child_exception
OSError: [Errno 2] No such file or directory
Also, passing the whole command as a string instead of a list (shell=False by default) is a common error:
>>> p = Popen("ls -l")
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/lib/python2.7/subprocess.py", line 679, in __init__
errread, errwrite)
File "/usr/lib/python2.7/subprocess.py", line 1249, in _execute_child
raise child_exception
OSError: [Errno 2] No such file or directory
Make sure:
your (child) program can be found in current $PATH
use a list argument instead of a string
test whether it works if you run it manually from a different working directory, different user, etc
Note: your Popen() call passes startupinfo that is Windows only. A string command with several arguments that would work on Windows fails with the "No such file or directory" error on Unix.